beginning c 3 0 an introduction to object oriented programming pdf download

Beginning C# 3.0: An Introduction to Object Oriented Programming pdf

Beginning C# 3.0: An Introduction to Object Oriented Programming pdf

... 4/7 /08 4: 53: 01 PM4/7 /08 4: 53: 01 PM ffirs.indd viffirs.indd vi 4/8 /08 1 : 30 :49 PM4/8 /08 1 : 30 :49 PM c0 1.indd 1 8c0 1.indd 18 4/7 /08 4: 53: 08 PM4/7 /08 4: 53: 08 PM Chapter 1: Getting Started 5 Suffice ... Object- oriented programming (Computer science) 2. C# (Computer program language) I. Title. QA76.64.P88 200 8 00 5. 13& apos ;3 dc22 200 801 105 6 No part of this publication may be reproduced, stored ... think you ’ ll find programming to be a truly enjoyable pastime. c0 1.indd 3c0 1.indd 3 4/7 /08 4: 53: 00 PM4/7 /08 4: 53: 00 PM

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beginning c# 3.0 an introduction to object oriented programming

beginning c# 3.0 an introduction to object oriented programming

... Files 32 9 Directories 32 9 The DriveInfo Class 33 0 Directory Class 33 0 DirectoryInfo Class 33 1 File Namespace 33 7 FileInfo Class 33 8 Types of Files 33 9 Textual Versus Binary Data Files 33 9 Reading ... Data 34 9 Sequential Versus Random Access Files 35 0 Sequential Files 35 0 Random Access Files 35 1 frmMain 35 6 Navigating the Records 36 3 Delete a Record 36 4 clsRandomAccess 36 4 Serialization and ... spade). To get an object of the class, you must press the cookie cutter (class template) into the cookie dough (computer memory) in order to get an actual cookie (object) . An object is an instance...

Ngày tải lên: 28/04/2014, 15:33

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An Introduction to Object-Oriented TM Programming with Java Fifth Edition docx

An Introduction to Object-Oriented TM Programming with Java Fifth Edition docx

... of 20 numbers. Aprogram written in machine language might look like this: 101 100 11 00 01 100 1 01 11 101 0 1 101 000 1 100 101 00 100 11111 00 01 100 1 01 011 100 1 101 000 1 100 100 00 101 1 101 1 1 101 000 1 100 101 10 One ... Account 908 .55 current balance minimum balance 100 .00 Jill’s : Account 1 30 4.98 current balance minimum balance 100 .00 Jack’s : Account 35 4 .00 current balance minimum balance 100 .00 Figure 1.9 Three Account ... values. John’s : Account 908 .55 current balance opening balance {frozen} 246 .00 Jill’s : Account 1 30 4.98 current balance opening balance {frozen} 50. 00 Account 100 .00 minimum balance account prefix {frozen} 6427 Jack’s...

Ngày tải lên: 08/03/2014, 02:20

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An Introduction to Financial Option Valuation_8 pdf

An Introduction to Financial Option Valuation_8 pdf

... 10 2 [0. 0469, 0. 1671] [0. 03 9 7, 0. 138 7] [0. 0569, 0. 18 13] M = 10 3 [0. 0961, 0. 134 7] [0. 0756, 0. 1 104 ] [0. 0726, 0. 104 6] M = 10 4 [0. 104 2, 0. 11 63] [0. 0997, 0. 1112] [0. 0926, 0. 1 03 8 ] M = 10 5 [0. 109 7, 0. 1 136 ] [0. 100 0, ... Optimal exercise boundary 177 0 50 100 1 50 200 2 50 1.795 1.8 1. 805 1.81 1.815 1.82 M American put 200 2 20 2 40 2 60 2 80 30 0 32 0 34 0 36 0 38 0 400 1.796 1.7965 1.797 1.7975 1.798 1.7985 M American put Fig. ... 35 0 400 0 0 .00 2 0. 004 0. 006 0. 008 0. 01 M Error in binomial method 100 200 400 10 −6 10 −4 10 −2 M Error in binomial method Fig. 18.2. Upper picture: Error in the binomial method for an American...

Ngày tải lên: 21/06/2014, 04:20

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An Introduction to Financial Option Valuation_11 pdf

An Introduction to Financial Option Valuation_11 pdf

... 1)h)         ∈ R N x −1 , 23. 5 FTCS and BTCS 245 0 5 10 15 0 20 40 60 80 100 −1.5 −1 0. 5 0 0.5 1 1.5 x FTCS: ν = 0. 63 t Fig. 23. 5. FTCS solution on the heat equation ( 23. 2), ( 23. 3) and ( 23. 4) with initial and boundary ... methods 0 5 10 15 0 50 100 1 50 200 0 0.2 0. 4 0. 6 0. 8 1 x FTCS: ν = 0 .3 t Fig. 23. 4. FTCS solution on the heat equation ( 23. 2), ( 23. 3) and ( 23. 4) with initial and boundary conditions ( 23. 5). Here ... N x = 50 and N t = 500 , so k = 2 ì 10 3 and h = 0. 2, we found that err 0 = 1.5 ì 10 3 for FTCS and err 0 = 1.7 ì 10 3 for BTCS. With Crank– Nicolson we were able to reduce N t to 50, so k = 2 ì 10 2 ,...

Ngày tải lên: 21/06/2014, 04:20

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Tài liệu Module 7: Essentials of Object-Oriented Programming pdf

Tài liệu Module 7: Essentials of Object-Oriented Programming pdf

... class CreateAccount { static BankAccount NewBankAccount( ) { BankAccount created = new BankAccount( ); // created.accNo = number; // created.accBal = balance; // created.accType ... 2. Compile the program. It will fail to compile. The error occurs in the CreateAccount class as shown: class CreateAccount { static BankAccount NewBankAccount( ) { BankAccount created ... Program { static void Main( ) { Bank.Account yours = new Bank.Account( ); } } class Bank { class Account { } } class Program { static void Main( ) { Bank.Account yours = new Bank.Account( ); } } class Bank { ...

Ngày tải lên: 10/12/2013, 16:16

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Lecture 1:Object Oriented Programming pdf

Lecture 1: Object Oriented Programming pdf

... support  Object is an instance of a class. Each object has a class which defines its data and behavior 1 Lecture 1: Object Oriented Programming 10 public class CreatePencil { public static void ... (parameter is an object reference) plainPencil plainPencil plainPencil p plainPencil p color: PLAIN - If you change any field of the object which the parameter refers to, the object is changed ... 0. 5f; } } Pencil.java CreatePencil.java %> javac Pencil.java %> javac CreatePencil.java CreatePencil.java:4: price has private access in Pencil p1.price = 0. 5f; ^ 13 Methods – Declaration  Method declaration:...

Ngày tải lên: 31/03/2014, 20:20

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C++ - I/O Streams as an Introduction to Objects and Classes

C++ - I/O Streams as an Introduction to Objects and Classes

... stream means connecting it to a file  The value of the stream variable can be thought of as the file it is connected to  Can have its value changed  Changing a stream value means disconnecting ... â 200 7 Pearson Education, Inc. Publishing as Pearson Addison-Wesley Streams and Assignment  A stream is a special kind of variable called an object  Objects can use special functions to complete ... stream object  Output can be to  The screen  A file Slide 6- 25 Copyright â 200 7 Pearson Education, Inc. Publishing as Pearson Addison-Wesley Calling object Dot operator Member function Calling a Member Function  Calling...

Ngày tải lên: 12/09/2012, 22:49

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Tài liệu An Introduction to the C shell docx

Tài liệu An Introduction to the C shell docx

... /usr/bill/rc 0. 0u 0. 1s 0: 01 8% 2+1k 3+ 2io 1pf+0w %time wc /etc/rc /usr/bill/rc 52 178 134 7 /etc/rc 52 178 134 7 /usr/bill/rc 104 35 6 2694 total 0. 1u 0. 1s 0: 00 13% 3+ 3k 5+3io 7pf+0w % indicates that the cp ... (2.5). directory A structure which contains files. At anytime you are in one particular directory whose names can be printed by the command pwd .The chdir command will change you to another directory ,and ... in a change to the .cshrc file which you wish to takeeffect right away. The time command can be used to cause a command to be timed no matter howmuch CPU time it takes. Thus %time cp /etc/rc /usr/bill/rc 0. 0u...

Ngày tải lên: 15/12/2013, 20:15

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An introduction to java programming 3 pdf

An introduction to java programming 3 pdf

... Java Tutorial // http://java.sun.com/docs/books/tutorial/java/generics/generics.html public class Box { private Object object; public void add( Object object ) { this . object = object; ... of classes in an application before such an interface is constructed. On the output side of an application, object streams can be used to write objects out to a file so that the data associated ... compiler can promise is to return an object of the Object class when the readObject method of the ObjectInputStream class is invoked; it does not know – at compile time – what type of object...

Ngày tải lên: 18/03/2014, 02:20

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An Introduction to Design Patterns in C++ with Qt™, 2nd Edition doc

An Introduction to Design Patterns in C++ with Qt™, 2nd Edition doc

... Reflective Programming 37 8 12.1 QMetaObject—The MetaObject Pattern 37 8 12.2 Type Identification and qobject_cast 38 0 12 .3 Q_PROPERTY Macro—Describing QObject Properties 38 3 12.4 QVariant Class: Accessing ... pointer to type T . www.it-ebooks.info ptg 704 139 5 28 Chapter 1 C+ + Introduction Output: 4451 929 234 5 1 true 135 7 + 135 7 + 135 7 .00 +1 234 .57 +1 234 .567 800 +1. 234 568e+ 03 1. 234 568e+ 03 It is easy to ... Windows and Actions 35 2 10. 8 Review Questions 35 3 Chapter 11: Generics and Containers 35 5 11.1 Generics and Templates 35 5 11.2 Generics, Algorithms, and Operators 36 2 11 .3 Sorted Map Example 36 5 11.4...

Ngày tải lên: 24/03/2014, 01:21

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AN INTRODUCTION TO MATHEMATICAL OPTIMAL CONTROL THEORY VERSION 0.1 pptx

AN INTRODUCTION TO MATHEMATICAL OPTIMAL CONTROL THEORY VERSION 0.1 pptx

... control α(·) back and forth between the values ±1, causing the trajectory to switch between lying on circles centered at (±1, 0) . The switches occur each π units of time. 39 Note very carefully that ... 0) . Now x(t)=X(t)x 0 = e tM x 0 . Thus Ne tM x 0 =0 (t ≥ 0) . Let t = 0, to find Nx 0 = 0. Then differentiate this expression k times in t and let t =0, to discover as well that NM k x 0 =0 for k =0, 1, 2, Hence ... −  τ ∗ 0 X −1 (s)Nα ∗ (s) ds because α ∗ (s)=0fors ≥ τ ∗ . Hence x 0 C( τ ∗ ), and therefore α ∗ (·) is optimal. According to Theorem 2. 10 there in fact exists an opimal bang-bang control.  3. 2...

Ngày tải lên: 24/03/2014, 12:20

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