beförderung und versendung in die gebiete nach § 1 abs 3 ustg

Friction and Lubrication in Mechanical Design Episode 1 Part 3 docx

Ngày tải lên : 05/08/2014, 09:20

... Figure 2.22 Discrete forces 10 3 10 2 01 H,=5 in - - 008 1 - - OM2 h " 01 W K K 10 -2 t , - 004 10 -3 10 4 - 002 10 -5 10 -6 I I I 111 11 I I I 111 111 I 1 Ill 11 I I I 11 111 I I I L U0 L ration The Contact ... of the contact problem is given in Refs 21- 39 REFERENCES 10 11 12 13 14 15 16 17 Timoshenko, S.P., Theory of Elasticity, McGraw Hill Book Company, New York, 19 51 Love, A E H., A Treatise on the ... for the load intensity at the interface is: PB (cosh 2A + cos 2E + 2) cosh , cos @U ! ? U q = k1z1 = - [ sinh 2A + sin 21 (cosh i - COS 2A) sinh /!?x /!?.U sin (sinh 2 ;1+ sin 2A) - sinh B x cos...

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Atomic Force Microscopy in Cell Biology Episode 1 Part 3 pdf

Ngày tải lên : 06/08/2014, 02:20

... None Si3N4kN = 0. 03 Si3N4kN = 0.08 13 22 3T6 None Si3N4kN = 0. 01 23 3T3, NRK Glass cover slip Plastic dish None Si3N4kN = 0.08 14 NIH3T3 Glass dish Fibronectin Si3N4kN = 0. 018 24 NIH3T3 Glass ... slow ( >10 min) and fast (

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Computational Intelligence in Automotive Applications Episode 1 Part 3 ppt

Ngày tải lên : 07/08/2014, 09:23

... 15 0 + 16 0) 39 0 + 452) 75 + 13 5) 31 0 + 36 3) Alertness behavior time (s) Total time (s) 516 210 240 17 5 39 3 37 0 6 31 765 255 612 910 30 0 240 33 0 5 53 550 9 41 1,607 465 1, 285 Visual Monitoring of ... (s) 10 39 4 (two intervals: 90 (one interval) 15 5 (one interval) 16 0 (one interval) 18 0 (one interval) 31 0 (two intervals: 842 (two intervals: 210 (two intervals: 6 73 (two intervals: 18 0 + 214 ) 15 0 ... Eye closure duration Blink freq Nodding freq Face position Fixed gaze DIL In In In In In In Out [0.0, 1. 0] [1. 0 30 .0] [1. 0 30 .0] [0.0–8.0] [0.0 1. 0] [0.0–0.5] [0.0 1. 0] 3 5 Linguistic terms Small,...

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Slide tiếng anh 6 Unit 6 Places Lesson 3 B. In the city B.(1-2-3-4-5) _Thị Khánh

Ngày tải lên : 09/07/2015, 13:40

... questioncontinuing questioncontinuing completely continue continue Submit Submit Clear Clear UNIT : PLACES - Period 33 - Lesson : B In the city B. (1, 2 ,3, 4,5) Read exercise B1 again Then complete ... PLACES - Period 33 - Lesson : B In the city B. (1, 2 ,3, 4,5) Exercise: Make question for underlined words by choosing the correct sentences 1. They work in a school I live in a town He eats in a small ... questioncontinuing questioncontinuing completely continue continue Submit Submit Clear Clear UNIT : PLACES - Period 33 - Lesson : B In the city B. (1, 2 ,3, 4,5) Exercise: Choose True (T) or False (F) a) Minh...

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Báo cáo y học: "HIV DNA and Dementia in Treatment-Naïve HIV-1-Infected Individuals in Bangkok, Thailand"

Ngày tải lên : 31/10/2012, 15:34

... 1. 59X10-4 1. 23X108 3 .15 X106 9 .38 X1 03 >1 HAD 2.00X10-2 1. 24X10-2 5 .30 X10-4 1. 08X108 1. 79X106 5.72X104 >1 HAD 3. 35X10-2 5.75X10-2 2 .16 X10-4 2.41X108 4.85X107 7.78X104 >1 Non-HAD 1. 89X10-4 9 .10 X10-6 1. 56X10-4 ... 1. 56X10-4 1. 25X106 7.46X102 1. 03X106

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Integrating short stories and poems in developing the reading skills for 2nd year students in haiphong university part 1

Ngày tải lên : 07/11/2012, 14:21

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English Collocation in Use ( Advanced) PART 1

Ngày tải lên : 12/04/2013, 10:08

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XÂY DỰNG PHƯƠNG ÁN CUNG CẤP ĐIỆN CHO 1 KHU VỰC GỒM 1 ĐƯỜNG DÂY KÉP VÀ 1 TRẠM BIẾN ÁP

Ngày tải lên : 24/04/2013, 15:47

... 51P1,51P2,51N1,51Q1,51Q2, (51P1TC,51P2TC,51N1TC,51G, 51P1T,51P2T,51N1T,51G1T,51Q1T,51Q2T, 51Q1TC,51Q2TC ) Trip logic ( TR, ULTR ) Close logic ( 52A,CL,ULCL ) 51P1R,51P2R,51N1R,51G1R,51Q1R,51Q2R ... N15)P = Với: I cb1 X ∑ + X ∆ (1) X1∑ = X 2∑ = 0 ,1 X = X + X 0∑ = 0 ,1 + 0 ,1 = 0,2 (1) ∆ 1 (1) →I N54 P = 0,502 =1, 6 73( KA) 0 ,1 + 0,2 Vậy dòng ngắn mạch pha: ( ( ) ( I N15) = I 01N = 3I N15)P ... (1, 1) 0 ,1 0 ,1 I = 1 × I = 1 × 3, 346 = 5, 018 (KA) N5 P (X 2∑ + X0∑ ) (0 ,1+ 0 ,1) (1, 1) N5 (1, 1) Vậy để kiểm tra độ nhạy ta chọn I N = 5, 018 ( KA) SVTH: Nguyễn Phan Thanh Lâm Trang 44/63...

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Tài liệu Giáo trình Máy điện - Phần 1 docx

Ngày tải lên : 23/12/2013, 13:15

... ứng ́  Đối với rãnh chữ nhật: t1 t  10  K  br1 b r1  10   D ö t1 = bước của phầ n ứng Z Z: số ranh phầ n ứng ̃ br1: chiề u rô ̣ng của đinh ̉ III ́ ̀ ́ SƯC TƯ RỘNG TRÊN RĂNG ... ̣ng ở đô ̣ cao x Kc: ̣ số ép chă ̣t của lõi thép K c = 0, 93  0,95 t1 Krăngx: ̣ số ở đô ̣ cao x t x   brăng1 Krăngx = 1 b raêngx .K c brăngx răngtb tx: bước ở đô ̣ cao x x Dựa vào ... khe thông gió hướng kin ́ ng : số ranh thông gió hướng kín ̃ Trang Giáo trình Máy điện ’ = .K chiề u rô ̣ng tinh toán của khe hở không khí ́ K : ̣ số tinh toán của khe hở...

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Tài liệu Bài giảng nguyên lí điện tử 1 doc

Ngày tải lên : 24/12/2013, 15:16

... chuẩn Mạch Darlingtơn bù IC =β1IB1 + β2IB2 = β1IB1 + β2 (1+ 1) IB1 1, β2 hệ số khuếch đại dòng T T2 Hệ số khuếch đại sơ đồ β = 1 β2 điện áp vào mạch là: UBE = IB1rv1 + (1+ 1) IB1rv2 Điện trở R ... đại có hồi tiếp chia làm loại 30 U1K U1 U U1ht Kht U1 U2 U1ht U2ht K U1K U2K U1 U U1ht Kht Kht U2ht b a U1K U2K K U1K U2K K U2ht K U2K U1 U2 U1ht c Kht U2ht d Hình 2 .18 Các loại mạch hồi tiếp a) ... phải uC*(t) =1 => uC(t) = −t Ae τ +1 t=0 uc(0) =0 => A= -1 h(t) = uC(t) =1- e −t τ t=0 h(t) =0 t=∞ h(t) =1 lối sau thời gian nhảy bậc đơn vị 3) Đặc trưing độ lối điện trở h(t) =uR(t) =1 –uC(t) =>...

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Tài liệu How to Do Business in 12 Asian Countries 1 pdf

Ngày tải lên : 21/01/2014, 23:20

... Appendix G International Electrical Adaptors Index About the Authors 202 205 208 210 212 216 218 2 21 110 12 5 14 3 15 5 17 1 18 3 Singapore South Korea Sri Lanka Taiwan Thailand Vietnam Preface In the ... 57 Littlefield Street Avon, MA 0 232 2 www.adamsmedia.com ISBN 10 : 1- 59869- 216 -X ISBN 13 : 978 -1- 59869- 216 -7 (paperback) ISBN 13 : 978 -1- 60550-852-8 (EPUB) Printed in the United States of America ... bulk purchases For information, please call 1- 800-289-09 63 Contents vi viii xi xviii Preface Introduction Cultural Orientation Map of Asia 16 21 35 56 74 94 China Hong Kong India Indonesia Japan...

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Tài liệu Báo cáo khoa học: Electrostatic contacts in the activator protein-1 coiled coil enhance stability predominantly by decreasing the unfolding rate docx

Ngày tải lên : 18/02/2014, 13:20

... displayed in Fig kf1 (M )1 s )1) mumt1 (calặmol )1 ặM )1) kf2 (s )1) mImt2 (calặmol )1 ặM )1) ku1 (s )1) mfmt2 (calặmol )1 ặM )1) mImt1 (calặmol )1 ặM )1) ku2 (s )1) DGkin (kcal ặmol )1) cJunFosW 5.8e6 1. 3e6 )1. 4 ... 2 .3 0.5 )0.2 0.2 0.046 0. 01 1.0 0 .1 0.92a 4.2b ?? 6 cJun(R)FosW(E) 7.1e 1. 6e )1. 9 0.2 4.0 0.7 )1. 0 0 .1 0.00 01 0.00 01 2.5 0. 21 0.0 018 0.0002 1. 41 0.027 )19 .0 a b Estimated from kinetic ... )1. 45 ( )1. 5) EK = )1. 15 ( )1. 5) RQ = )0.7 ( )1) QT = ? (?) )4.9 + TQ ER = ER = ER = RE = RE = RE = )8.7 )1. 45 )1. 45 )1. 45 )1. 45 )1. 45 )1. 45 ( )1. 5) ( )1. 5) ( )1. 5) ( )1. 5) ( )1. 5) ( )1. 5) m-values m-values...

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Tài liệu Báo cáo khoa học: Role for nectin-1 in herpes simplex virus 1 entry and spread in human retinal pigment epithelial cells docx

Ngày tải lên : 18/02/2014, 14:20

... RPE cells FITC stained CHO-HVEM RPE D Events B 11 4 A C 10 1 10 2 11 9 10 0 10 3 10 4 FITC stained CHO-nectin -1 Events RPE 10 0 10 1 10 2 FITC 10 3 10 4 Fig Expression of HSV -1 gD receptors in RPE cells (A) ... 11 6, 12 73 12 81 Spillmann D (20 01) Heparan sulfate: anchor for viral intruders? Biochimie 83, 811 – 817 WuDunn D & Spear PG (19 89) Initial interaction of herpes simplex virus with cells is binding ... stained with FITC-conjugated secondary anti-(rabbit IgG) were used as a background control A B C 750 No Ab Si RNA (nectin -1) Si RNA (control) Counts 562 37 5 18 7 10 0 10 1 10 2 10 3 10 4 FL Log [34 36 ]...

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Báo cáo khoa học: A Caenorhabditis elegans model of orotic aciduria reveals enlarged lysosome-related organelles in embryos lacking umps-1 function potx

Ngày tải lên : 06/03/2014, 09:22

... 0 0 10 0 32 10 0 0 0 0 0 0 70 31 59 92 90 53 36 54 26 28 0 0 12 5 68 10 0 96 10 0 75 0 0 0 0 0 0 0 16 0 > 2000 73 50 30 227 58 32 52 53 0 0 43 31 0 57 81 63 36 0 10 0 0 43 0 0 0 0 27 0 19 17 0 0 59 ... alx -1( gk275), apt-6(ok429), glo -1( zu 437 ), mrp-4(ok1095), pgp-2(kx55), ppk -3( n2668), ppk -3( ok 115 0), ppk -3( zu4 43) , rab -10 (dx2), rde -1( ne 219 ), rme -1( b1045), rrf -1( pk14 71) , rrf -3( pk1426), tat -1( kr15), ... ppk -3( ok 115 0)b ppk -3( zu4 43) rab -10 (dx2) rme -1( b1045) tat -1( kr15) V-ATPase unc -32 (f1 21) c unc -32 (f1 23) c De novo pyrimidine biosynthesis umps -1( zu456) umps -1( zu456) + mgÆmL )1 uracil umps -1( zu456)...

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In-car Technology Lesson 1: Automotive Sensors docx

Ngày tải lên : 07/03/2014, 11:20

... own award-winning apprenticeship programme By working through the lessons, you will take a journey from learning about the principles of electrical theory, to developing an understanding of the ... Distance Control BMW first introduced Park Distance Control (PDC) on the series (E32) in 19 92 PDC is a driver assistance system that facilitates parking and manoeuvring in confined spaces The rear ... animals, including dogs, dolphins and some insects can hear ultrasound Bats have the best hearing capabilities as they not only hear ultrasound but they also generate it and can determine their...

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What’s New in VMware vCloud™ Director 1.5 pot

Ngày tải lên : 08/03/2014, 19:20

... Fast Provisioning Using Linked Clones In VMware vCloud Director 1. 0, virtual machine provisioning operations resulted in the creation of full clones, delivered to users within minutes through ... Simplifying construction of an inventory of the cloud – Simplifying the process of zeroing -in on specific objects in the inventory using the API query service • Building better scripting/automation ... Director 1. 5 What’s New Guide” in the subject line Thank you for your help in making this guide a valuable resource VMware, Inc 34 01 Hillview Avenue Palo Alto CA 9 430 4 USA Tel 877-486-92 73 Fax 650-427-5001...

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A Problem Course in Mathematical Logic Version 1.6 doc

Ngày tải lên : 14/03/2014, 17:20

... Chapter 14 Characterizing Computability 95 iii iv CONTENTS Hints for Chapters 10 14 10 1 Part IV Incompleteness 10 9 Chapter 15 Preliminaries 11 1 Chapter 16 Coding First-Order Logic 11 3 Chapter 17 Deﬁning ... Chapter 17 Deﬁning Recursive Functions In Arithmetic 11 7 Chapter 18 The Incompleteness Theorem 12 3 Hints for Chapters 15 18 12 7 Appendices 13 1 Appendix A A Little Set Theory 13 3 Appendix B The ... from Σ ∪ {α} 3. 9 Again, don’t take these hints as gospel Try using the Deduction Theorem in each case, plus (1) A3 (2) A3 and Problem 3. 3 (3) A3 (4) A3, Problem 3. 3, and Example 3. 2 (5) Some...

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Báo cáo khoa học: Alternative initiation of transcription of the humanpresenilin 1gene in SH-SY5Y and SK-N-SH cells The role of Ets factors in the regulation ofpresenilin 1 pptx

Ngày tải lên : 16/03/2014, 18:20

... )11 9/ +14 3 )22/ +17 8 )22/+4 10 0 73 91 23 21 ± 10 ± 3. 4 ± 2.6 10 0 13 3 10 0 15 0 ± ± ± ± 12 10 10 m ± ± ± ± 30 20 20 70 70 28 ± ± ± ± 20 not examined which sequences in the )11 8/ )35 fragment aside from the ... F (19 98) Ó FEBS 2004 4494 M Pastorcic and H K Das (Eur J Biochem 2 71) 10 11 12 13 14 15 16 17 18 19 20 21 Deﬁciency of presenilin -1 inhibits the normal cleavage of amyloid precursor protein Nature ... 7 15 ) and +10 7/ +17 8 (lanes 16 –24) Either the wild type probes or the same fragments containing mutant Ets sites at positions )10 (lanes 4–6), +90 (lanes 10 12 ), +65 (lanes 13 15 ), +12 9 (lanes 19 – 21) ...

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Báo cáo khoa học: Functional expression of the quinoline 2-oxidoreductase genes (qorMSL) in Pseudomonas putida KT2440 pUF1 and in P. putida 86-1 Dqor pUF1 and analysis of the Qor proteins doc

Ngày tải lên : 17/03/2014, 10:20

... BioScale DEAE10 85 .3 87.4 71. 9 36 .5 36 96 516 76 17 .4 0.0 23 0 .17 0.95 2 .10 41 91 100 10 2 84 43 Conditions of Qor synthesis in wild-type P putida 86, P putida 86 -1 Dqor pUF1 and P putida 86 pJB6 53 Qor ... Speciﬁc activity (UÆmg )1) of Qor in crude extracts after growth on: Strain Succinate Benzoate < 0.0 01 0.0 01 < 0.0 01 0 .11 0 .10 0. 21 0 .18 –a Qor protein from P putida 86 -1 Dqor pUF1 Immunodetection ... activity (UÆmg )1) Puriﬁcation (-fold) Yield (%) Crude extract Ammonium sulfate ppt Phenyl Sepharose CL-4B BioScale DEAE10 31 2 2 71 299 206 30 45 416 78 9 .3 0 .10 0.65 3. 83 22 .1 6.4 37 .5 216 .7 10 0 87 96...

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