baud rates for asynchronous mode brgh 0

... 1973, :48-57 10 Jenis LG, An HS, Gordin R: Foraminal stenosis of the lumbar spine: a review of 65 surgical cases Am J Orthop 200 1, 30: 205 -211 http://www.medsci.org Int J Med Sci 200 9, 105 11 Baba ... radicular disease Spine 200 0, 25: 905 - 909 15 Fessler RG, Khoo LT: Minimally invasive cervical microendoscopic foraminotomy: an initial clinical experience Neurosurgery 200 2, 51:S37-S45 16 Gala VC, ... J Bone Joint Surg Am 1971, 53:891- 903 Jenis LG, An HS: Spine update Lumbar foraminal stenosis Spine 200 0, 25:389-394 Jackson RP, Glah JJ: Foraminal and extraforaminal lumbar disc herniation: diagnosis...

Ngày tải lên: 03/11/2012, 11:17

... (forward) 0. 075 RSS PredErrors Resids 0. 0 50 006 0. 025 00 4 0. 000 -0. 025 00 2 -0. 0 50 1985 2 .0 19 90 1995 200 0 1985 1 .00 Chow test statistic 1.5 200 0 Chow test: p-value 0. 50 0.5 1995 0. 75 1 .0 19 90 ... graphs 0. 50 Recursive estimation (forward) Constant × 2*SE Dp × 2*SE 0. 25 0. 00 19 90 200 0 Dp* × 2*SE Dp_2 × 2*SE -1 19 90 2.5 200 0 Dp*_3 × 2*SE 19 90 15 200 0 Di × 2*SE 10 0 .0 -2 -2.5 19 90 10 200 0 19 90 ... 10 0 .0 -2 -2.5 19 90 10 200 0 19 90 Di*_2 × 2*SE 200 0 (i-i*)_1 × 2*SE -2.5 200 0 (v-p+p*)_1 × 2*SE -0. 5 -5 19 90 200 0 0. 0 0. 0 19 90 19 90 200 0 19 90 200 0 Figure reports the constancy statistics Panel...

Ngày tải lên: 15/02/2014, 05:20

... $7 50, 000 + 0. 10 zero 0. 10 0. 10 0 .08 0. 50 0. 50 1 .00 0. 88 0. 70 0. 30 0. 50 0. 80 0.68 0. 54 0. 10 0. 50 0. 60 0.47 0. 37 0. 10 0. 50 0. 60 0.47 0. 37 0. 10 0. 50 0. 60 0.47 0. 37 Rates are fixed $ 400 ,00 0 to $7 50, 000 ... Sterling ITSA interest rates will be £ 300 ,00 0+ 0. 10 0 .08 0. 10 0. 90 £1 50, 000 + 0. 10 0 .08 0. 10 1. 10 £75 ,00 0+ 0. 10 0 .08 0. 10 1. 40 £ 50, 000 + 0. 10 0 .08 0. 10 1.55 £ 10, 000 + 0. 10 0 .08 0. 10 2 .00 below the sterling ... €1, 100 ,00 0+ 0. 10 0 .08 0. 10 N/A € 500 ,00 0 to €1 ,09 9,999 0. 50 0. 40 0.49 0. 25 € 100 ,00 0 to €499,999 0. 25 0. 20 0.25 0. 50 € 50, 000 to €99,999 0. 10 0 .08 0. 10 0.75 €1 to €49,999 0. 10 0 .08 0. 10 1 .00 interest...

Ngày tải lên: 15/02/2014, 05:20

... August 201 1 zero 0. 10 0. 10 0 .08 £2 50, 000 to £ 500 ,00 0 0. 75 0. 50 1.25 1.13 0. 90 0. 50 0. 50 1 .00 0. 88 0. 70 0. 30 0. 50 0. 80 0.68 0. 54 0. 10 0. 50 0. 60 0.47 0. 37 0. 10 0. 50 0. 60 0.47 0. 37 Balance Gross Rate ... (variable) 0. 50 0. 50 1 .00 0. 74 0. 25 € 500 ,00 0 to €749,999 0. 40 0. 50 0. 90 0.64 0. 35 0. 25 0. 50 0.75 0. 49 0. 50 0. 10 0. 50 0. 60 0.35 0. 65 €1 to €49,999 August 201 2 Rates €7 50, 000 + € 50, 000 to €99,999 Rates ... Rate) $7 50, 000 + 0. 75 0. 50 1.25 1 .00 $ 500 ,00 0 to $749,999 0. 65 0. 50 1.15 0. 90 $ 100 ,00 0 to $499,999 0. 55 0. 50 1 .05 0. 80 $ 50, 000 to $99,999 0. 40 0. 50 0. 90 0.65 $1 to $49,999 0. 25 0. 50 0.75 0. 50 rate...

Ngày tải lên: 22/03/2014, 17:20

... $1, 100 ,00 0+ 0. 10 0. 10 €1, 100 ,00 0+ 0. 10 0. 10 0. 10 0. 10 N/A $ 500 ,00 0+ 1 .00 1 .00 € 500 ,00 0+ 1. 50 1.51 0. 75 0. 74 0. 25 $ 100 ,00 0+ 0. 75 0. 75 € 100 ,00 0+ 1.25 1.26 0. 50 0.49 0. 50 $ 50, 000 + 0. 50 0. 50 € 50, 000 + ... $3 50, 000 + 1. 70 1.71 0. 30 1. 20 1.21 0. 30 0. 70 0. 70 0. 30 $ 200 ,00 0+ 1. 50 1.51 0. 50 1 .00 1 .00 0. 50 0. 50 0. 50 0. 50 $ 100 ,00 0+ 1. 30 1.31 0. 70 0. 80 0. 80 0. 70 0. 30 0. 30 0. 70 $ 20, 000 + 0. 30 0. 30 1. 70 0 .00 ... €1 50, 000 + 1 .00 1 .00 0. 75 0. 75 0. 55 0. 55 0. 10 0. 10 € 50, 000 + 0. 65 0. 65 0. 40 0. 40 0. 20 0. 20 0. 10 0. 10 €15 ,00 0+ 0. 15 0. 15 0. 15 0. 15 0. 10 0. 10 0. 10 0. 10 €5 ,00 0+ 0. 10 0. 10 0. 10 0. 10 0. 10 0. 10 0. 10 0.10...

Ngày tải lên: 22/03/2014, 17:20

... 93.5 93 95 94.5 92.5 200 0 400 0 Training time (sec) 600 0 92 100 0 200 0 300 0 Training time (sec) 400 0 94 100 0 200 0 300 0 Training time (sec) 400 0 Figure 2: F-score curves on the MSR, CU, and PKU datasets: ... Jin, 1995; Chen and Bai, 1998; Wu and Jiang, 200 0; Peng et al., 200 4; Chen and Ma, 200 2; Zhou, 200 5; Goh et al., 200 3; Fu and Luke, 200 4; Wu et al., 201 1) New word detection is normally considered ... CU PKU Passes 50 50 50 10 50 50 50 10 50 50 50 10 Train-Time (sec) 4.7e3 1.2e4 1.2e4 2.3e3 2.9e3 7.5e3 7.5e3 1.5e3 2.2e3 5.2e3 5.2e3 1.2e3 NWD Rec 72.6 75.3 78.2 77.5 68.5 68 .0 68.8 68.8 77.2...

Ngày tải lên: 23/03/2014, 14:20

... 0. 05% 0. 05% 0. 10% 0. 10% 0. 10% 0. 10% 0. 10% 0. 10% 90 days notice 0. 05% 0. 05% 0. 05% 0. 05% 0. 10% 0. 10% 0. 10% 0. 10% 0. 10% 0. 10% year notice 0. 05% 0. 05% 0. 10% 0. 10% 0. 10% 0. 10% 0. 10% 0. 10% 0. 10% 0. 10% ... Balance £25+ Balance £25+ £25 ,00 0+ 33 days notice 1.76% 1.75% 33 days notice 0. 10% 0. 10% 0. 10% 0. 10% Rates effective from 24 June 200 9 90 days notice 0. 10% 0. 10% 0. 10% 0. 10% One payment only per month, ... Rates (AER) The bottom figures are Gross Savers Triodos Saver AER Gross AER Gross AER Gross AER Gross AER Gross Balance £ 500 + £2, 500 + £5 ,00 0+ £25 ,00 0+ £ 100 ,00 0+ 33 days notice 0. 05% 0. 05% 0. 05%...

Ngày tải lên: 29/03/2014, 01:20

... vol 3 40, no 2, pp 1249–1262, 200 8 11 Q.-P Zang, “A limit theorem for the moment of self-normalized sums,” Journal of Inequalities and Applications, vol 200 9, Article ID 95 705 6, 10 pages, 200 9 12 ... Applications, vol 201 0, Article ID 3 505 17, pages, 201 0 J G Yan and C Su, “Precise asymptotics of U-statistics,” Acta Mathematica Sinica, vol 50, no 3, pp 517–526, 200 7 Chinese 10 T.-X Pang, L.-X ... iterated logarithm and the complete convergence for uniform empirical process,” Statistics & Probability Letters, vol 78, no 9, pp 105 1– 105 5, 200 8 e e 13 M Csorg˝ and P R´ v´ sz, Strong Approximations...

Ngày tải lên: 21/06/2014, 07:20

... Sci Instrum 200 9, 80: 06 3 701 Agarwal P, De T, Salapaka MV: Real time of probe-loss using switching gain controller for high speed atomic force microscopy Rev Sci Instrum 200 9, 80: 103 701 Zhao B, ... Ultramicroscopy 201 0, 1 10( 9):1 205 -1214 Zhang Y, Fang Y, Yu J, Dong X: Note: a novel atomic force microscope fast imaging approach: variable-speed scanning Rev Sci Instrum 201 1, 82 :05 6 103 -6- Useinov ... speed for tapping -mode atomic force microscopy Rev Sci Instrum 200 2, 73(8):2928-2936 Kodera N, Sakashita M: Dynamic proportional-integral-differential controller for high-speed atomic force microscopy...

Ngày tải lên: 21/06/2014, 17:20

... 10 1 10 2 10 3 10 4 10 5 10 6 FNMR FNMR 10 4 10 3 10 2 10 1 100 100 10 1 10 2 10 3 10 4 10 5 10 6 10 7 10 8 Capacitive 10 4 10 3 FMR Optical FNMR FNMR 10 3 10 4 10 4 10 3 10 2 10 1 100 100 10 1 ... FNMRs) Sensor EER (full) EER (bal) FRR @0. 001 (full) Capacitive 0. 02 40 Optical 0. 006 4 0. 0138 0. 003 4 0. 0295 0. 007 5 FNMR @0. 001 (bal) 0. 0181 0. 004 0 in Figure for the full database The solid line represents ... Capacitive sensor 100 10 2 10 4 10 6 FNMR: 9+ 0. 02 0. 03 0. 05 0. 06 0. 08 0. 09 0. 11 0. 12 0. 14 Number of false non-matches Population proportion (a) Optical sensor 100 10 2 10 4 10 6 Number of false...

Ngày tải lên: 21/06/2014, 19:20

... 6 60 6 80 Idle LP 0 50 Idle 100 Data 1 50 700 BP BM 300 3 50 400 50 100 1 50 200 2 50 Time (μs) 300 3 50 400 300 3 50 400 300 3 50 400 TxEN (V) (b) TxD (V) uBus (V) Idle (a) 1.5 0. 5 0. 5 −1 −1.5 500 200 ... −1.5 500 200 2 50 Time (μs) Data (a) STBN (V) BP/BM (V) 3.5 0 50 100 1 50 200 2 50 Time (μs) (c) 5 20 5 40 5 60 5 80 600 6 20 Time (ns) 6 40 6 60 6 80 700 uBus Eye diagram mask 50 100 1 50 200 2 50 Time (μs) ... 500 5 20 5 40 5 60 5 80 600 6 20 Time (ns) 6 40 6 60 6 80 700 CANL, CANH (V) BP/BM (V) 3.5 2.5 1.5 BP/BM typical BP/BM best case BP/BM worst case 0. 05 0. 1 Measured Model fast 5 20 5 40 5 60 5 80 600 620...

Ngày tải lên: 21/06/2014, 20:20

... 0. 2 0 0.2 0. 4 0. 6 0. 8 Normalized frequency (×π rad/sample) 0. 2 0. 4 0. 6 0. 8 Normalized frequency (×π rad/sample) 50 0. 2 Phase (degrees) Imaginary part 0. 4 0. 4 0. 6 0. 8 −1 − 50 − 100 −1 0. 5 0. 5 ... 8, β = 20 10 1 0. 8 BER M = 8, β = 40 10 2 M = 8, β = 80 10 3 0. 6 M = 8, β = 1 60 0.4 0. 2 M = 8, β = 3 20 0.15 0. 2 0. 25 0. 3 0. 35 0. 4 0. 45 10 4 0. 5 10 12 14 16 Eb/N0 (dB) PWL histogram Rice Nakagami ... Computed BER Figure 4: Numerical computation and simulated BER for M = and β = 20, 40, 80, 1 60, 3 20 channel 3.5 2.5 1.5 0. 5 0. 2 0. 4 0. 6 0. 8 PWL histogram Rice Nakagami Figure 5: Approximation of...

Ngày tải lên: 21/06/2014, 20:20

... cycles) × 104 Execution time (memory cycles) × 104 6 1 10 1.3333 20 30 40 50 Additional computation load 60 70 Ideal 0 10 20 30 40 50 60 70 Additional computation load (processor cycles) processor processors ... time (memory cycles) 16 10 20 12 10 102 4-tap FIR 14 30 40 50 60 Computation load Partitioning an application among multiple processors in address-data mode typically outperforms a mapping using ... Execution time (memory cycles) × 104 12 Address gen (2%) Input port (5%) 10 Other (5%) Output FIFOs ( 10% ) Input FIFOs ( 10% ) SRAM (68%) 10 15 20 25 30 35 40 45 50 Address computation load (processor...

Ngày tải lên: 22/06/2014, 19:20

... 10 10 8 500 100 0 MMSE (y[n]) MMSE (y[n]) Algorithm 1 500 N 200 0 2 500 Algorithm CC-IFC algorithm MV receiver (c) MC system, NFR = dB 500 100 0 MMSE (y[n]) MMSE (y[n]) Algorithm 1 500 N 200 0 2 500 ... VPG system, NFR = 10 dB 22 20 20 18 18 Output SINR (dB) 24 22 Output SINR (dB) 24 16 14 12 16 14 12 10 10 8 500 100 0 1 500 N MMSE (y[n]) MMSE (y[n]) Algorithm 200 0 500 2 500 1 500 N MMSE (y[n]) MMSE ... Signal Processing 10 1 VPG system, NFR = dB 10 1 10 3 10 4 10 4 BER 10 2 10 3 BER 10 2 10 5 10 5 10 6 10 6 10 7  6  4  2 Input SNR (dB) MMSE (y[n]) MMSE (y[n]) Algorithm 10 10 7  6  4  2 12 Algorithm...

Ngày tải lên: 22/06/2014, 23:20

... desired user g1 and the variance of Intersymbol Detector for CDMA Networks 423 10 2 10 2 BER 10 1 BER 10 1 10 3 10 3 10 4 10 4 −4 −2 10 12 Eb /N0 (dB) Proposed (M = 7) Optimal (M = 7) Spatio-temporal ... detection for CDMA systems and advanced signal processing for wireless communication He has served as a researcher in Flextronics Asia Design Pte Ltd, Singapore, from 200 3 to 200 4 Since 200 4, he ... engineering from Xi’an Jiaotong University, Xi’an, China, in 200 0 Starting June 200 0, he became a Ph.D student in the Division of Information Engineering, School of Electrical and Electronic Engineering,...

Ngày tải lên: 23/06/2014, 00:20

... use a = 0. 000 01, ˜ ˜ and step sizes µ f = µb = 0. 2 in the training mode and ˜ ˜ µ f = µb = 0. 05 in the decision-directed mode Parameters in (22) of the RLS algorithm are λ = and δ = 0. 04 For comparison, ... with more feedback filter taps gives a better bit error rate performance Squared error 161 1.5 0. 5 REFERENCES 0 50 100 1 50 200 2 50 300 Update number in the adaptive algorithms RLS algorithm NLMS ... system (SU) 100 10 1 Bit error rate EURASIP Journal on Wireless Communications and Networking 10 2 10 3 10 4 10 5 2.5 3.5 4.5 5.5 6.5 Eb /N0 (dB) Detector1, iter Detector1, iter Detector1, 10 iter...

Ngày tải lên: 23/06/2014, 00:20

... correct acquisition 0. 9 Prob of correct acquisition 0. 7 0. 6 0. 5 0. 4 0. 3 0. 2 0. 8 0. 75 0. 7 0. 65 0. 6 0. 1 0. 85 0. 55 50 100 1 50 200 2 50 0.5 300 50 L number of training samples 1 50 200 2 50 300 LMS RLS Rank ... rank Rank 100 L number of training samples (a) (a) 1 0. 9 Prob of correct acquisition Prob of correct acquisition 0. 95 0. 9 0. 85 0. 8 0. 8 0. 7 0. 6 0. 5 0. 4 0. 3 0. 2 0. 75 0. 1 0. 7 50 100 1 50 200 L number ... Blind Code Synchronization 695 100 0. 8 0. 7 Acquisition error rate Prob of correct acquisition 0. 9 0. 6 0. 5 0. 4 0. 3 10 1 10 2 0. 2 0. 1 −5 10 15 20 25 30 10 3 10 20 30 SNR (dB) Conventional Full rank...

Ngày tải lên: 23/06/2014, 01:20

... on (0, T ), u (0) = u0 ∈ H0 (Ω), ∂A = (∇u(t) ⊗ ∇(u(t) − u∗ )) on (0, T ), ∂t A (0) = A0 ∈ L∞ (Ω), symmetric (0. 27) The system (0. 27) has a unique solution (u(t), A(t)) for all t They show that for ... equations ∂u − div(A∗ ∇u∗ ) = f ∗ a.e on (0, T ), ∂t u (0) = u0 ∈ H0 (Ω), ∂A = (∇u(t) ⊗ ∇(u(t) − u∗ )) a.e on (0, T ), ∂t A (0) = A0 ∈ L∞ (Ω), symmetric (0. 26) Here for u, v ∈ Rd , the (d × d)-matrix ... been proposed for solving them such as output least squares methods [6, 26, 27, 29, 30, 36, 37, 46, 53, 99, 100 ], regularization methods [42, 54, 62, 60, 61, 59, 91, 102 , 104 , 116, 1 20] , equation...

Ngày tải lên: 25/07/2014, 07:22

... (0. 1)– (0. 2) or (0. 3)– (0. 4) with ∥u − z δ ∥H (Ω) ≤ δ, (0. 5) δ > being given These problems are mathematical models in different topics of applied sciences, e.g aquifer analysis For practical models ... gravity For different kinds of the porous media, the diffusion coefficient varies in a large scale Gravels Sands Silts Clays Limestone 0. 1 to cm/sec 10 3 to 10 2 cm/sec 10 5 to 10 4 cm/sec 10 9 to 10 7 ... defined by (0. 6) and (0. 7) are used for identifying the coefficient q and a in (0. 1)– (0. 2) and (0. 3)– (0. 4), respectively √ We apply L2 -regularization to these functionals and obtain convergence rates...

Ngày tải lên: 25/07/2014, 07:22

... combinatorics 17 ( 201 0), #R141 15 References [1] Albert, M., and Atkinson, M Simple permutations, partial well-order, and enumeration In Proceedings of Permutation Patterns 200 3 ( 200 3), pp 5–9 [2] ... permutations Order 19, ( 200 2), 101 –113 ´ [3] Bona, M The limit of a Stanley-Wilf sequence is not always rational, and layered patterns beat monotone patterns J Combin Theory Ser A 1 10, ( 200 5), 223–235 ´ ... Information Processing [8] Marcus, A., and Tardos, G Excluded permutation matrices and the StanleyWilf conjecture J Combin Theory Ser A 107 , ( 200 4), 153–1 60 [9] Regev, A Asymptotic values for...

Ngày tải lên: 08/08/2014, 12:22