4 3 solution of the final coupled problem

... reduce the reliability of the test scores On the basis of these results, the author provides some suggestions towards the improvement of the test quality The reliability of the final achievement MCQs ... in final achievement test construction 2 .3 MCQs test 2 .3. 1 Definition 2 .3. 2 Benefits of MCQs test 2 .3. 3 Limitations of MCQs test 2 .3 .4 Principles on designing a good MCQs test 2 .4 Reliability of ... discrimination value 5 .3 The attitude of students towards the MCQs test 5 .4 Pedagogical implications and suggestions on improvements of the 23 24 26 27 27 27 29 34 existing final achievement computer-based...

Ngày tải lên: 18/12/2014, 08:38

... (%) 1500 145 1 140 8 13 54 13 04 1 248 1197 1 1 43 10 93 - - - 0.2 74 0.2 54 0.2 84 0.259 0.2 74 - 0.269 4. 55 - - - 1516 15 04 1528 15 03 1521 - 15 14 0.72 Time (min) 20.25 25 30 .25 36 42 .25 60 ... 200 40 0 144 0 Dial Reading (x 10 -4 in) in = 25 .4 mm 1 0 43 999 956 922 892 830 765 722 6 93 642 1.201 1 .31 3 1 .42 2 1.509 1.585 1. 742 1.908 2.017 2.090 2.220 1.6 74 1.717 1.780 1.791 1.806 1.8 64 1.911 ... δp4 = 1.791 mm δp3 = 1.6 74 mm f(δp ) 0.1 -0.2 600 time (min) Dial Reading -4 (25 .4 x 10 mm) (1) (2) 1.00 2.25 140 8 13 54 (3) (4) 20.25 36 .00 1 042 922 700 800 900 1000 δp , x10 in (1 in =25 .4 mm)...

Ngày tải lên: 21/03/2013, 14:09

... reduce the reliability of the test scores On the basis of these results, the author provides some suggestions towards the improvement of the test quality The reliability of the final achievement MCQs ... in final achievement test construction 2 .3 MCQs test 2 .3. 1 Definition 2 .3. 2 Benefits of MCQs test 2 .3. 3 Limitations of MCQs test 2 .3 .4 Principles on designing a good MCQs test 2 .4 Reliability of ... discrimination value 5 .3 The attitude of students towards the MCQs test 5 .4 Pedagogical implications and suggestions on improvements of the 23 24 26 27 27 27 29 34 existing final achievement computer-based...

Ngày tải lên: 10/04/2013, 14:46

... 22 Activity 4. 3: Value of Information Models Exercise 1: Identifying the Value of Information Models ! Identify the value of information models Think of how you have used information ... design work Brainstorm as a class the value that informational modeling provides to the design process and specifically to the analysis step of conceptual design The instructor will write your answers...

Ngày tải lên: 10/12/2013, 16:16

... [22] In the traumatically injured brain, however, the synthesis of MT1 and MT2, as well as the synthesis of GIF, are up-regulated by reactive astrocytes in the vicinity of the lesion [ 23] This ... (1997) Disruption of the metallothionein- FEBS Journal 277 (2010) 2 931 –2 939 ª 2010 The Authors Journal compilation ª 2010 FEBS C Howells et al 29 30 31 32 33 III gene in mice: analysis of brain zinc, ... Neurobiol Dis 13, 22 36 ´ 22 Hidalgo J, Aschner M, Zatta P & Vasak M (2001) Roles of the metallothionein family of proteins in the central nervous system Brain Res Bull 55, 133 – 145 23 Chung RS,...

Ngày tải lên: 16/02/2014, 15:20

... PKC substrate, 80K/MARCKS, 3 64 G Wein et al (Eur J Biochem 270) 24 25 26 27 28 29 30 31 32 33 34 35 36 37 38 39 40 41 42 increases sharply when Swiss 3T3 cells move out of cycle and enter G0 Proc ... orientation 35 6 G Wein et al (Eur J Biochem 270) Ó FEBS 20 03 Fig Formation of two major complexes between Swiss 3T3 proteins and the 3 -UTR of the MARCKS mRNA (A) The MARCKS 3 -UTR, the stop codon UAA of ... (complete 3 -UTR of MARCKS); pDK2: 131 0– 230 9 bp; pDK8: 131 0–1562 bp The poly(A) signal of the bovine growth hormone was provided by the pcDNA3 vector (B) Luciferase activity of transfected Swiss 3T3...

Ngày tải lên: 08/03/2014, 08:20

... for the two star crossed lovers only in the daylight The final scene, when Sebastian slowly walks up the stairs to his death, he walks into the light of the house (like walking into the light of ... become shadows themselves Again, when Alicia staggers to the door of the room, the two shadows of Sebastian and his mother on the door merge to her blurry vision In this shot, the audience gets ... Sebastian and his mother, and the lighting in the room becomes opposite to what it previously was, lighting up the window behind them, and throwing Sebastian and his mother into shadow The two characters...

Ngày tải lên: 21/03/2014, 21:56

... for the two star crossed lovers only in the daylight The final scene, when Sebastian slowly walks up the stairs to his death, he walks into the light of the house (like walking into the light of ... become shadows themselves Again, when Alicia staggers to the door of the room, the two shadows of Sebastian and his mother on the door merge to her blurry vision In this shot, the audience gets ... Sebastian and his mother, and the lighting in the room becomes opposite to what it previously was, lighting up the window behind them, and throwing Sebastian and his mother into shadow The two characters...

Ngày tải lên: 21/03/2014, 21:56

... Under the assumptions (3. 9) (3. 10), the term on the right side of (4. 28) is much smaller than the accuracy we need for Theorem 3. 1 Therefore this condition will be imposed for the rest of the paper ... |p3 |) 40 2 HORNG-TZER YAU Then |p1 − p3 | ≤ 4| p1 + p3 | From the Schwarz inequality (6.7) dµn+1 (pn+1 ) |p1 − p3 | ≤ 4| p1 + p3 | × Θκ (pn+1 ) (eir1 − e−ir3 )(eir2 − e−ir3 ) 2τ 2τ × FG (p1 + p3 ... = 2 /3 + 1 /3 = 1, κ2N 3 = 2 /3 + 1/12, κ2N −2 = 2 /3 − 1/6, · · · , κ2 = 2 /3 − 2−2N +3 /3 With this choice of κn , a similar argument proves the upper bound This concludes the proof of Theorem 1.2...

Ngày tải lên: 22/03/2014, 16:20

Ngày tải lên: 11/06/2014, 15:46

... 43 * * * * ($95, 230 ) * 2 93, 7 64 * ($6 04, 815) 562,060 218,287 141 ,30 6 ($221,9 94) 157,866 60,5 04 3, 6 24 ( $4, 691,862) 3 ,42 8, 147 1, 242 ,805 20,910 Page ($ 64, 36 8) 157,866 60,5 04 3, 6 24 * * * * ($87 ,33 1) ... Fringe Benefits Activities - Other - Nonlabor $51,256 0 $2, 2 43 ,289 0 $32 8,2 63 0 ($102, 644 ) 62, 133 23, 1 73 17 ,33 8 ($1 , 43 3, 045 ) 49 2 ,31 2 170,265 770 ,46 8 ( $46 2 ,31 3) 295,200 99,0 23 68,090 Increase (Decrease) ... ($2, 046 ) 2, 046 ( $33 , 43 6) (12,706) 46 , 142 ( $3, 396) 3, 396 Increase (Decrease) Provider Number Page $2,058,700 * (47 7,988) * ( $47 9,965) * 2,060,677 * $768 ,42 2 * 812,290 * $3, 3 94, 711 * 1, 230 ,099 * (41 ,189)...

Ngày tải lên: 20/06/2014, 03:20

... determination 42 CFR 41 3. 20 and 41 3. 24 CMS Pub 15-1, Sections 230 0, 230 2 .4 and 230 2.8 * * * * * * * * * * * * * * $21,626 44 ,117 16 ,45 4 12 ,31 1 (21,626) $ 34 9 ,5 64 120,896 1, 835 ,666 (62, 837 ) $3, 3 94, 711 1, 230 ,099 ... 4, 867 862 2, 0 43 10,808 3, 9 43 96 1,169 200 10,026 43 ,799 34 , 0 14 62,920 62,058 Increase (Decrease) Provider Number Page 11 4, 867 862 2, 0 43 10,808 3, 9 43 96 1,169 200 10,2 84 44, 057 54, 177 83, 0 83 ... (118,7 74) $62, 133 23, 1 73 17 ,33 8 (51 ,38 8) $49 2 ,31 2 170,265 2,058,700 (47 7,988) ($2, 249 ) 2, 249 ($118,7 74) 118,7 74 ($18,016) (6,719) (5,027) 29,762 ($ 142 , 748 ) (49 ,36 9) (217,0 34 ) 40 9,151 Increase (Decrease)...

Ngày tải lên: 20/06/2014, 03:20

... and the theory of the operators for integration and differentiation of fractional order Section is devoted to the study of the existence and uniqueness of positive solution for 1.2 utilizing the ... u2 then when l max0≤t≤1 solution u t ∈ S ≤ l|u1 − u2 |, 3. 10 G t, s ds < 1, the boundary value problem 1.2 has a unique positive Proof According to Theorem 3. 1, if the conditions in Theorem 3. 1 ... 130 0– 130 9, 2010 16 B Ahmad, “Existence of solutions for irregular boundary value problems of nonlinear fractional differential equations,” Applied Mathematics Letters, vol 23, no 4, pp 39 0 3 94, 2010...

Ngày tải lên: 21/06/2014, 07:20

... 10 4 4.88 × 10 4 7 .32 × 10 4 9.75 × 10 4 1.21 × 10 3 1 .45 × 10 3 1.69 × 10 3 1.92 × 10 3 j 33 |z2 ti − z ti | 6.10 × 10−5 1.22 × 10 4 1. 83 × 10 4 2 . 43 × 10 4 3. 04 × 10 4 3. 64 × 10 4 4. 23 × 10 4 ... 0.250 0 .37 5 0.5 0.625 0.750 0.875 j |z3 ti − z ti | 3. 81 × 10−6 3. 30 × 10−5 1. 13 × 10 4 2.69 × 10 4 5. 24 × 10 4 8.85 × 10 4 1 .30 × 10 3 1.52 × 10 3 j 17 |z3 ti − z ti | 1. 03 × 10−6 8 .42 × 10−6 ... 10−5 6.76 × 10−5 1 .31 × 10 4 2.21 × 10 4 3. 23 × 10 4 3. 75 × 10 4 j 33 |z3 ti − z ti | 2. 63 × 10−7 2.11 × 10−6 7. 14 × 10−6 1.69 × 10−5 3. 28 × 10−5 5. 53 × 10−5 8.07 × 10−5 9 .36 × 10−5 Table 2:...

Ngày tải lên: 21/06/2014, 10:20

... Example 4. 1 Let ⎛ A B Then tr AB 0.25 63 0.2588 0. 142 2 ⎜ ⎜0. 235 8 ⎝ 0.8 942 ⎛ 0.2587 ⎜ ⎜0.5 236 ⎝ 0.8 541 ⎞ ⎟ 2. 045 1 0 .41 77⎟, ⎠ 0.2 547 0.9852 ⎞ 0.5 236 0.8 541 ⎟ 1.12 54 0 .36 54 ⎠ 0 .36 54 1.2 541 4. 1 4. 9 933 ... side of 3. 3 Note that when S ≤ 0, by 3. 3 , we obtain 3 .4 immediately This completes the proof  14 Journal of Inequalities and Applications Remark 3. 2 From Remark 2.6 and Theorem 3. 1, we have the ... Bounds for the Solution of the Algebraic Riccati Equations Komaroff 19 94 in 16 obtained the following Let K be the positive semidefinite solution of the ARE 1 .4 Then the trace of K has the upper...

Ngày tải lên: 22/06/2014, 03:20

... 84 it > 30 0 56.01 16 69 .31 27 55. 13 12 60.88 14 55.85 14 54. 83 51. 93 12 48 .97 48 .40 51.55 10 45 .62 46 . 64 46.89 45 .56 42 .77 45 .27 35 .80 0 34 . 07 0 32 . 34 0 31 .32 0 av 5.15 5 .39 5.05 5.06 4. 97 4. 87 ... 4. 87 4. 70 4. 60 4. 55 4. 60 4. 41 4. 42 4. 23 4. 15 4. 03 3.97 3 .49 3. 23 2. 93 2.82 SDA SDA-DARE (RSDA ) > tol av 23 5.17 31 5 .42 28 5.15 47 5. 24 48 5.19 56 5.26 56 5.01 66 5. 13 70 5.09 68 5.17 72 4. 98 ... convergence (30 ) (31 ) (32 ) (33 ) The algorithm requires (44 /3) n3 flops: the matrix multiplications in (28) and (33 ) require about 2n3 flops each, the computation of the symmetric matrices in (31 ) and (32 )...

Ngày tải lên: 22/06/2014, 19:20

... dx (3. 34 ) From (3. 29), (3. 31), (3. 32), (3. 33) , and (3. 34 ) it follows that E + cR E ≥ E p+1 + fR , E(0) = 0, ≤ t ≤ T, (3. 35) E (0) = To investigate problem (3. 35), we will use the method of test ... virtue of (3. 10), the function u is the solution of (3. 12), and according to the unique solvability of that equation, u = v ≥ in the domain DT Thus the proof of Lemma 3. 3 is complete Remark 3 .4 As ... virtue of (3 .46 ), (3 .47 ), and (3 .48 ) there exists the number T = T0 > for which the right-hand side of inequality (3 .46 ) is negative, but this is impossible because the left-hand side of inequality...

Ngày tải lên: 23/06/2014, 00:20

... is the solution of ( 14) with the parameter δ/i (i = 1, , N + 1) Then, it is easy to obtain the following Theorem For the approximate solution in the form ( 24) for the original Problem (1) there ... H s−3i (Ω), yδ ∈ H s−3N (Ω) and yδ H (Ω) C1 , (16) C1 being independent of δ Proof Under the assumption of the theorem, by [5] there exists a unique solution u ∈ H s (Ω) of the problem ( 14) After ... of functions z = (w0 , ϕ)T , which is the solution of the equation (8) - (10) uniquely defines a function u which is the solution of the Problem (1) such that the relation (7) is valid Proof The...

Ngày tải lên: 06/08/2014, 05:20

... case, while the second subsection is devoted to the proof of the main theorem 4. 1 Definition of the solution In order to define the solution as in (1), we have to put an orientation on the chords ... journal of combinatorics 16 (2009), #R89 4 8 9 Figure 4: The transition from R to R′ The upper left corners of the elements of R0 are shaded in the left drawing Clearly, a solution y of the form ... consists of line segments with integer coordinates Clearly, a solution of the problem RSP is precisely the decomposition of P into the minimal number of rectangles In order to state the solution to the...

Ngày tải lên: 08/08/2014, 01:20

... T2 ,4, 0 = e2 T2,5,1 = f2 T2,6,2 = g2 T3,0,1 = a3 T3,1,0 = b3 T3,2,1 = c3 T3 ,3, 0 = d3 T3 ,4, 1 = e3 T3,5,0 = f3 T3,6,1 = g3 We have the determinant formula T2 ,3, 3 = T1 ,3, 2 T1 ,4, 3 T T = Q1 Q2 T1,2 ,3 ... R1,2 R1 ,3 R2,1 R1 ,3 R3,0 R2,1 R2,2 R1 ,3 R3,0 R2,2 2 R1,2 R3,1 R2,1 R3,0 , y7 = , y4,2 = , y3,1 = , y4,1 = (5 .4) y6 = R3,0 R3,1 R2,2 R3,1 R3,0 R2,2 R1 ,3 R3,0 R2,1 R1 ,3 R3,0 R1 ,3 The general solution ... one a3 a3 b3 c3 d3 e3 f3 g3 a2 b2 c2 d2 e2 f2 g2 a2 a1 b1 c1 d1 e1 f1 g1 a1 b3 c3 b2 b1 d3 c2 c1 d2 (a) e2 d1 X e3 e1 f3 g3 f2 f1 g2 g1 Y Z (c) (e) X (b) Y (d) (f) (g) (h) Z Figure 4. 10: The 6V...

Ngày tải lên: 08/08/2014, 12:22