4 đại cương về truyền động học trong máy công cụ

... - Vieclam.vn, PWC Jobs opportunities, viewed 19 March 20 14,

Ngày tải lên: 23/05/2016, 11:14

... (Z)−β-Carvotancetol 11-Dodecenol Carvarol β-Caryophyllene 980 990 1006 1028 1031 1 042 1053 1100 1 145 1189 1192 1210 1369 1371 141 4 trace 3.7 60.2 20.3 10.5 0.2 0.7 trace trace 0.9 0.1 0.1 0.3 0.2 0.5 97.8 ... linaloolifera from Vietnam, J Essent Oil Res., (1993) 45 1 [3] Nguyen Xuan Dung, Do Quang Huy, Pham Van Khien, etc, Pharmaceutical Journal, No .4, (1988) 13 [4] Hoang Hai Hiên, Le Thi Mai Hoa, Tran Dinh ... tonkinensis, Phytochemistry, 42 (4) (1996) 1167 [9] L Zhu, D Ding, B M Lawrence, The cinnamomum species in China: resouces for the present and future, Perfumer and Flavorist, 19 (19 94) 17 [10] R.P Adams,...

Ngày tải lên: 12/02/2014, 17:20

... analysis for the studied samples Sample NF NFC02 NFC 04 NFC06 NFC08 ν1 (cm-1) 596.15 595.20 595.37 596.78 593.02 ν2 (cm-1) 42 8.12 42 4.75 42 0.65 42 2.25 42 0.72 157 3500 3000 2500 2000 1500 Wavenumber ... 359 38.1 12 .4 6.9.103 740 49 .1 20.0 1.8.1 04 835 55.7 26 .4 2.3.1 04 871 60.1 27.1 2.6.105 158 N.K Dung, N.H Tuan / VNU Journal of Science, Mathematics - Physics 25 (2009) 153-159 3 .4 Magnetization ... of Ni1-xCoxFe2O4 ferrites Sample NF NFC02 NFC 04 NFC06 NFC08 Particle size (nm) 29 33 30 33 35 Lattice parameter (A0) 8.3 34 8. 343 8.362 8.371 8.382 X-ray density ‘DX’ (g/cm3) 5 .4 5 .4 5.3 5.3 5.3...

Ngày tải lên: 13/02/2014, 04:20

... Mathematics - Physics 25 (2009) 107-116 X ij (t ) = xi (t ) − x j (t ) i = N , i ≠ j 109 (4) Equations (2), (3), and (4) yield the following simultaneous equations, which uniquely determine xi (t): N ... ˆ ˆ ε i2 = [xi (t + τ ) − xi (t + τ )] K i ( 14) Because ensemble time is a weighted average of each clock times, the prediction error estimate ( 14) is biased, because each clock is a member of ... clocks and oscillators, IEEE Trans Ultrasonic, Ferroelectrics and Frequency Control vol 34, N0 (1987) 647 [2] M.A Weiss, D.W Allan, T.K Peppler, A Study of the NBS Time Scale Algorithm, IEEE Transactions...

Ngày tải lên: 13/02/2014, 04:20

... sequences in von Neumann algebras, Proc Amer Math Soc 94 (1985) 41 3 [18] F Moricz, Multiparametter Strong law of large numbers, Acta Sci Math 40 (1987) 143 ... increasing sequence of positive integers If nk ∞ tk n 4 k i) τ (|y1 |4) < ∞, i=1 k=1 nk ∞ tk n 4 k ii) τ (|¯i − τ (¯i )|2) x x i=2 k=1 j=1 tk n 4 k τ (¯i ) x < ∞, i=1 k=1 ∞ iv) τ (|¯j − τ (¯j )|2) ... ) 4  mk ∞ iv)   τ (|yi,j |4)  < ∞, nk v=1 j=2   j−1 τ (|¯i,j − τ (¯i,j |2) x x τ (|¯i,j − τ (¯i,j |2 x x ∞  m k nk τ (|¯i,v − τ (¯i,v )|2 x x nk i−1 τ (|¯u,v − τ (¯u,v |2 x x u=1 v=1 4...

Ngày tải lên: 13/02/2014, 04:20

Ngày tải lên: 13/02/2014, 12:20

Ngày tải lên: 13/02/2014, 12:20

... multifariousness of these river names 1.3.1 Vietnamese historical documents [QSQTN, t4 (1997), 2 54] , [NVS, (2003) 349 ] reveal that the Red River made its mark in old Chinese territory as Lan Thương, ... attested in classical accounts as follows: - Thao River[NVS, (2003) 349 ; QSQTN, Vo .4 (1997), 253] - Nh Hà/Nhĩ Hà River [QSQTN, Vo .4 (1997), 256] - Phú Lương River [QSQTN, Vo.3 (1997), 186] In fact, ... c River [QSQTN, Vo.3 (1997), 186; Vo .4 (1997), 253] - Tam i River [QSQTN, Vo.3 (1997), 186; Vo .4 (1997), 253] i Hoàng River [QSQTN, Vo.3 (1997), 186; Vo .4 (1997), 253] - Xích ng River ng river...

Ngày tải lên: 27/02/2014, 03:20

... English to Chinese Strongly Agree 10 43 .5% 4. 3% Agree Neutral Disagree 13.1% 10 43 .5% 39.1% 26.1% 4. 3% 17 .4% Strongly Disagree 0 8.7% 34. 8% 26.1% 17 .4% 21.7% 0 17 .4% 30 .4% 34. 8% 8.7% 8.7% jkl ... pictures (N= 24) M 47 .71 66.13 SD 19.659 21.963 t -3.061** High-level text only (N= 24) High-level text with pictures (N=23) 22.33 43 .22 15.717 18.591 - 4. 165*** Low-level text with pictures (N= 24) High-level ... 5=strongly agree, 4= agree, 3=neutral, 2=disagree, 1=strongly disagree The pictures improved my understanding of the passage 543 21 The pictures helped me guess the meanings of any words I 543 21...

Ngày tải lên: 05/03/2014, 12:20

... Kong, 19 94 [3] J.B Biggs, Assumptions underlying new approaches to assessment, Curriculum Forum, (1995) [4] S Messick, Validity and washback in language testing Language Testing 13 (1996) 241 [5] ... tư liệu khái niệm "kênh hồi đáp" gợi ý sư phạm Phan Di Tịnh Đại học Melbourne, Australia Phương thức mà kỳ thi ảnh hưởng tới việc dạy học thường miêu tả “kênh phản hồi” Đã có nhiều định nghĩa “kênh ... cognitive skills that the test is designed to measure” c) Consequential validity (Messick, 1989, 1996 [4, 14] ) Consequential validity encompasses concepts ranging from the uses of tests, the impacts of...

Ngày tải lên: 05/03/2014, 12:20

... −p1aq2a − p2aq2a − L q1 , q ′ , q”1, q2 , q2 , q ′ , ˙ ˙ (44 ) δH δH ; q2 = − ˙ , δp1 δp2 δH δH p1 = ˙ ; p2 = ˙ , δq1 δq2 q1 = − ˙ (45 ) (46 ) where ′ ¯ ¯ H = H q1 , q1 , q”1, q2 , q2 , q2 ˙ ′ is ... F = (48 ) σ=π (49 ) σ=0 ′ ′ ¯ dσ F q1 , q1 , q”1 , q2 , q2 , p1 , p2 (50) N.S Han / VNU Journal of Science, Mathematics - Physics 24 (2008) 111-118 117 Using Hamilton equations of motion (47 ) ... National Research Programme in National Science N 40 640 6 References [1] [2] [3] [4] [5] [6] [7] [8] [9] [10] [11] [12] T.Goto,Prog Theor Phys 46 (1971) 1560 Y Nambu, Lectures at the Copenhagen...

Ngày tải lên: 05/03/2014, 14:20

... 74 N.S Bay, T.T.A Hoa / VNU Journal of Science, Mathematics - Physics 24 (2008) 73-80 Preliminary lemmas Lemma Let system (1) be regular ... −A∗ (t)y ˙ (4) λ1 + α1 = 0, λn + αn = (5) According to the Perron theorem, we have If the maximal exponent λn of system (1) is upper - stable then the minimal exponent αn of system (4) is lower ... ; Q(t) = Q(t) + p22(t) 0 we have ˜ ˜ y = P (t)y + Q(t)y ˙ ( 14) Taking the linear transformation y = Sz with M1 δ S= M1 δ , from ( 14) we get the following equivalent equation ˜ ˜ ˜ ˜ z = S −1...

Ngày tải lên: 05/03/2014, 14:20

Ngày tải lên: 05/03/2014, 14:20

... the variable heating rate method Peak Energy (eV) Frequency factor (s−1 ) 0 .43 1.3x1 04 0.98 7.3x108 1.17 4. 1x109 1 .46 1.7x1010 shows TSL glow curves of LBCu irradiated x-ray at various heating ... Physics 24 (2008) 97-100 100 min 10 20 Black body 2.0x10 TSL a.u 6 1.5x10 1.0x10 C/s C/s C/s C/s C/s C/s 5.0x10 TSL a.u 1.0x10 2.5x10 5.0x10 1.5x10 0.0 50 100 150 200 250 300 350 40 0 45 0 Temperature ... and also for individual monitoring References [1] [2] [3] [4] [5] M Takenaga et al, Thermoluminescent material, United States Patent, 42 48731 (1981) R Visocekas, S Lorrain, G Marinello, Nucl Sci...

Ngày tải lên: 05/03/2014, 14:20

Ngày tải lên: 05/03/2014, 16:20

... sPE -4 3 .46 0.69 1st stage Mexp.∞ 2nd satge D Mexp.∞ - 14 -1 [10 m s ] [%] 6.88 2.21 0.96 D [10 m2s-1] 25.59 Mexp.∞ [%] 0.92 4. 07 1.05 23.85 1. 04 19.59 2 .49 4. 45 1.15 22.29 1. 14 22.29 2.70 - 14 77 ... 0.79 4. 96 1.63 [10- 14 m2s-1] [%] [10- 14 m2s-1] [%] sPE-2 3.19 0.30 3 .49 sPE-3 3 .41 0.33 sPE -4 4.39 0.38 HCl 20 mass% o o 40 C Polymer 80oC 60 C D Mexp.∞ D [10- 14 m2s-1] [%] [10- 14 m2s-1] [%] sPE-2 ... to those at 40 and 60 oC Table Diffusion characteristics in water 40 oC 60oC 80oC D Mexp.∞ D Mexp.∞ D Mexp.∞ [10- 14 m2s-1] [%] [10- 14 m2s-1] [%] [10- 14 m2s-1] [%] sPE-2 4. 21 0.30 4. 44 0.50 1.09...

Ngày tải lên: 14/03/2014, 13:20

Ngày tải lên: 14/03/2014, 13:20

... # t2n 4 or # t2n Let # t2n = # t2n−2 + # t2n 4 Putting t2n+1 = t2n−2 + 0 + 2n + 2n+1 , t2n−1 = t2n 4 + 2n−3 + 2n−2 + 2n−1 32n−1 3 3 Local dimension of fractal measure associated with 41 we ... t2n−2 , # t2n−1 ≥ 2# t2n 4 It follows that 2# t2n = 2# t2n−2 + 2# t2n 4 # t2n+1 + # t2n−1 # t2n # s2n+1 + # s2n−1 2# t2n−3 By Claims 2.5 and 2.7 we get 2# t2n 4# t2n−3 4# s2n−3 = # s2n−3 + 3# ... Then we have oj = k (2i + 1) + k + = (k + 1)(2k + 3) Since i=0 4( 1 − r) r k i=1 k i−k [ i=1 2(1 − r) k(k + 1) − k r 4( 1 − r) r 4i(1 − r) ] r ej k i, i=1 2(1 − r) k(k + 1) r Hence (k + 1)(2k +...

Ngày tải lên: 14/03/2014, 13:20

... + Q1Q3Q6 22 + 4. 23 + 22 + 4. 23 + 38 Q Q Q3 + Q2Q3Q6 22 + 4. 23 + 44 Q Q Q3 + Q3 Q4Q6 22 + 5.23 + 45 Q Q Q3 + Q Q Q Q6 22 + 5.23 + Q3 4 3 2 Circuit function in form of R3 1 F P 46 Q Q Q3 + Q Q ... + Q3Q4 22 + 1.23 + 13 Q Q Q3 + Q1Q3Q4 22 + 1.23 + 14 Q Q Q3 + Q2Q3Q4 22 + 1.23 + 20 Q Q Q3 + Q3Q5 22 + 2.23 + 21 Q Q Q3 + Q1Q3Q5 22 + 2.23 + 22 Q Q Q3 + Q2Q3Q5 22 + 2.23 + 28 Q Q Q3 + Q3 Q4Q5 ... have B = 19 = b6 25 + b5 24 + b4 23 + b3 22 + b2 21 + b1 20 = b6 32 + b5 16 + b4 + b3 + b2 + b1 = 0.32 + 1.16 + 0.8 + 0 .4 + 1.2 + 1.1 That factors b6, b4, b3 must equal to and b5 =...

Ngày tải lên: 14/03/2014, 13:20

... Prior brand attitudes Favorable Neutral attitude Unfavorable Prior relationship Strong Weak ∆ R1 ∆ B1 ∆ R4 ∆ B4 ∆ R2 ∆ B2 ∆ R5 ∆ B5 ∆ R3 ∆ B3 ∆ R6 ∆ B6 Note that: ∆ Ri indicats the degree of ... relationship is strong, then the recipient’s post-brand attitudes becomes more favorable (H3.1); and the post giverrecipient relationship will be less strong (H3.2) Hypothesis 4: When the gift ... in Consumer Research, 20, 1993, p 553-556 14 Feather, “A Structural Balance Model of Communication Effects”, Psychological Review, Vol 71, No .4, 19 64, p.291-313 15 Goodwin, Cathy, Kelly L Smith,...

Ngày tải lên: 14/03/2014, 14:20