2 3 consequential progression analysis across whole part part whole relationships

Unit 3 : A trip to the countryside. Part 1,2.

Unit 3 : A trip to the countryside. Part 1,2.

Ngày tải lên : 01/07/2013, 01:25
... school 3. If only he could visit me Suday/weekends 4.Lan wishes she could come home May 10, 20 09 5.I can talk to you .10 a.m to 12 a.m 6.We should have dinner 11 a.m and 11 .30 a.m 1.in/in ; 2. in ; 3. on ... 2. I am sorry,Last night,Iyour home late Shrine 3. They worshipped Le Loi in that Hero 4.There is a .tree at the entrance to the village Go boating 5.Last week, weon Ma River 1.hero 2. reached 3. shrine ... 7.What does Liz wish? She wishes she could visit Ba,s village again 1 Làm tập I,II,III,IV trang 33 ,34 sách ôn luyện Học thuộc từ mới, Cấu trúc ngữ pháp học ( So/ giới từ thời gian) Chuẩn bị học...
  • 14
  • 1K
  • 4
Longman Dictionarry of Common Errors_ Part 2.3

Longman Dictionarry of Common Errors_ Part 2.3

Ngày tải lên : 26/10/2013, 22:15
... controlled by a particular country: 'All the land from here to the stream belongs to the Pattersons.' 'Disagreements about land have led to many wars.' (2) (also the land) the part of the Earth's ... things by myself The diff~\enP2trns of ha,,~'got ~r~~ne8,rIY"
  • 24
  • 549
  • 2
 SEIMENS Win CC V4 Manual part 2/3

SEIMENS Win CC V4 Manual part 2/3

Ngày tải lên : 02/11/2013, 14:31
... C79000-G 827 6-C107-01 2- 2 2- 2 2- 3 2- 3 2- 9 2- 10 2- 10 2- 11 2- 11 2- 11 2- 12 2- 13 2- 13 2- 14 2- 14 2- 15 2- 16 2- 17 2- 17 2- 18 2- 21 2- 26 2- 30 2- 30 2- 32 2 -33 2- 34 2- 35 2- 37 2- 37 2- 37 2- 37 2- 37 2- 38 2- 38 i Graphics ... 2- 1 2. 1 2. 1.1 2. 1 .2 2 .2 2 .2. 1 2. 2 .2 2 .2. 3 2. 2.4 2. 2.5 2. 2.6 2. 3 2. 3. 1 2. 3 .2 2 .3. 3 2. 3. 4 2. 4 2. 4.1 2. 5 2. 6 2. 6.1 2. 6 .2 2.6 .3 2. 6.4 2. 6.5 2. 6.6 2. 6.7 2. 6.8 2. 7 2. 8 2. 8.1 2. 8 .2 2.8 .3 2. 8.4 2. 9 2. 10 ... 2- 39 2- 39 2- 39 2- 40 2- 40 2- 40 2- 50 2- 52 2-55 2- 56 2- 57 Configuring Actions 3- 1 3. 1 3 .2 3 .2. 1 3 .2. 1.1 3 .2. 1 .2 3 .2. 1 .2. 1 3 .2. 1 .2. 2 3 .2. 1 .2. 3 3 .2. 1 .2. 4 3 .2. 1 .2. 5 3 .2. 1 .2. 6 3 .2. 1 .2. 7 3 .2. 1.3...
  • 414
  • 334
  • 0
Tài liệu TOEFL STUDY GUIDE PART 2-3 LISTENING COMPREHENSION ppt

Tài liệu TOEFL STUDY GUIDE PART 2-3 LISTENING COMPREHENSION ppt

Ngày tải lên : 24/12/2013, 19:15
... used to dye my hair when I was younger" Longer Conversations Tips 32 - 34 Longer Conversations Tip 32 The difficulty of these Parts B & C is in remembering what was said long enough to answer ... package?" hole: an empty space "They dug a hole to put the post in for the fence" whole: entire "I read the whole book" by: near "I go by the baker's on my way home." buy: to purchase "I will ... You won't have trouble understanding what was said, just remembering it! Longer Conversations Tip 33 Anticipate the questions The questions that follow these talks are arranged in roughly the same...
  • 9
  • 527
  • 1
Power Quality Monitoring Analysis and Enhancement Part 2 potx

Power Quality Monitoring Analysis and Enhancement Part 2 potx

Ngày tải lên : 19/06/2014, 11:20
... z1,1   1− z1 ,2 z2 ,2  1− z34 ,2 z2 ,2  1− z41 ,2 z2 ,2  1−  1− z1 ,34 z34 ,34 z2 ,34 z34 ,34      1−  z41 ,34 z34 ,34 z1,41  z41,41   z2 ,41    1− z41,41      z34,41    1− ... Harmonics Interruption Notching Sag 25 0 C2 C3 C4 C5 0 0 23 0 16 0 0 25 0 0 23 0 0 0 Overall accuracy: 90 .29 % C6 C7 (%) 0 0 23 0 23 100 92 64 100 92 92 92 Table Classification results without ... 0 0 25 0 0 18 0 0 25 0 0 23 0 0 0 Overall accuracy: 92. 57 % Table Classification results using PCA algorithm C6 0 0 23 C7 0 23 (%) 100 100 72 100 92 92 92 34 Power Quality – Monitoring, Analysis...
  • 25
  • 280
  • 0
Power Quality Monitoring Analysis and Enhancement Part 3 docx

Power Quality Monitoring Analysis and Enhancement Part 3 docx

Ngày tải lên : 19/06/2014, 11:20
... I eT = 2 I r + I s2 + I t2 + I n = ( I + )2 + ( I − )2 + * ( I )2 ( ) Where , , are the line currents and Similarly, the effective voltage is: Ve = the neutral current 2 (Vr2 + Vs2 + Vt2 ) + (Vrs ... components These terms are: 2 S1 = (V1 I )2 = P 12 + Q1 And term ( 53) is composed by the rest of the terms present in Eq (51): 2 SN = (V1 I H )2 + (VH I )2 + (VH I H )2 = DI2 + DV + SH (54) Where the ... fundamental and harmonic terms: Ve2 = Ve21 + VeH (80) I e2 = I e21 + I eH (81) Where the fundamental terms are: Ve = 2 * (Vr21 + Vs2 + Vt2 ) + (Vrs + Vrt + Vts ) 1 18 (ε = 1) ( 82) 49 Power Quality Measurement...
  • 25
  • 376
  • 1
Intermarket Technical Analysis - Trading Strategies Part 3 ppt

Intermarket Technical Analysis - Trading Strategies Part 3 ppt

Ngày tải lên : 04/07/2014, 03:20
... CRB INDEX Gold's role as a leading indicator of the CRB Index can be seen in Figures 5. 12 and 5. 13 Figure 5. 12 shows gold leading major turns in the CRB Index at the 1985 bottom and the 1987 top ... 1989, short-term rates had peaked (see Figure 6 .2) Within two months the dollar started to weaken as a result Figure 6 .3 compares dollar trends to 30 -year Treasury bond yields While bond swings ... turn in the U.S dollar In the past decade, the dollar has made three 62 COMMODITIES AND THE U.S DOLLAR THE KEY ROLE OF GOLD 63 THE PROBLEM OF LEAD TIME FIGURE 5.6 THE DOLLAR VERSUS COMMODITIES...
  • 19
  • 167
  • 0
Cấu trúc dữ liệu : Cây 2-3-4 part 2 docx

Cấu trúc dữ liệu : Cây 2-3-4 part 2 docx

Ngày tải lên : 26/07/2014, 18:21
... gốc node Thêm vào 70, 30 , 50 30 , 50, 70 Thêm 40 Thêm vào 20 , 80 Thêm vào 25 , 90 Thêm vào 75 Thêm vào 10 Hình Minh họa thêm node vào 2- 3- 4 Biến đổi 2- 3- 4 sang Đỏ-Đen Một 2- 3- 4 biến đổi sang đỏ-đen ... node cha P hai node C1, C2 màu đỏ Hình 4.7 trình bày chuyển đổi Các node tô màu đỏ; tất node khác tô màu đen Hình Chuyển đổi từ 2- 3- 4 sang đỏ-đen 10 Hình 4.8 trình bày 2- 3- 4 đỏ-đen tương ứng với ... sang Đỏ-Đen Một 2- 3- 4 biến đổi sang đỏ-đen cách áp dụng luật sau: Biến đổi 2- node 2- 3- 4 sang node đen đỏ-đen Biến đổi 3- node sang node C (với hai nó) node cha P (với node C node khác) Không có...
  • 5
  • 491
  • 4
Cấu trúc dữ liệu : Cây 2-3-4 part 1 ppt

Cấu trúc dữ liệu : Cây 2-3-4 part 1 ppt

Ngày tải lên : 26/07/2014, 18:21
... trường hợp 2- 3- 4 Với node node chứa 1, mục liệu, node rỗng Một 2- 3- 4 có đến nên gọi nhiều nhánh bậc Trong 2- 3- 4 node có liên kết, trừ node (node liên kết nào) Hình trình bày trường hợp 2- 3- 4 Một ... Trong 2- 3- 4, nút nằm mức Các node mức thường không đầy đủ, nghĩa chúng chứa mục liệu thay mục Lưu ý 2- 3- 4 cân Nó giữ cân thêm vào phần tử có thứ tự (tăng dần giảm dần) Tìm kiếm Thao tác tìm kiếm 2- 3- 4 ... trình bày trường hợp 2- 3- 4 Một node với liên kết gọi 2node, node với liên kết gọi 3- node, node với liên kết gọi 4-node, node 1-node Tổ chức 2- 3- 4 Các mục liệu node xếp theo thứ tự tăng dần từ trái...
  • 6
  • 525
  • 3
Fundamentals of Structural Analysis Episode 1 Part 2 pot

Fundamentals of Structural Analysis Episode 1 Part 2 pot

Ngày tải lên : 05/08/2014, 09:20
... 0 − 33 .33 0⎤ ⎡ 33 .33 ⎢ 25 .00 − 25 .00 0 0⎥ ⎥ ⎢ 0 40. 53 − 9.60 − 33 .33 − 7 .20 9.60 ⎥ ⎢ − 25 .00 − 9.60 37 .80 0 9.60 − 12. 8⎥ ⎢ ⎢ 0 − 33 .33 33 .33 0 0⎥ ⎢ 0 0 25 .00 − 25 .00⎥ ⎥ ⎢ − 7 .20 9.60 0 40. 53 − ... ⎨ ⎬ = ⎢ ⎪ ⎪ ⎢0 ⎪ Fx ⎪ ⎢k 31 ⎪ ⎪ ⎢ ⎪ Fy ⎪ ⎢k 41 ⎩ ⎭ ⎣ 0 0 0 k11 k 21 k 31 k 41 k 12 k 22 k 32 k 42 k 13 k 23 k 33 k 43 0 0 0 k 13 k 23 0 k 12 k 22 0 k 32 k 42 0 0 0 k 33 k 43 ⎤ ⎧u1 ⎫ ⎥ ⎪ v1 ⎪ ⎥ ⎪ ⎪ ... 0 − 33 .33 33 .33 0 0⎥ ⎢ 0 0 25 .00 − 25 .00⎥ ⎥ ⎢ − 7 .20 9.60 0 40. 53 − 9.60⎥ ⎢ − 33 .33 ⎢ 0 9.60 − 12. 80 − 25 .00 − 9.60 37 .80⎥ ⎦ ⎣ For the second truss: 9.60 0 − 7 .20 − 9.60 − 33 .33 0⎤ ⎡ 40. 53 ⎢...
  • 20
  • 289
  • 0
Fundamentals of Structural Analysis Episode 1 Part 3 pps

Fundamentals of Structural Analysis Episode 1 Part 3 pps

Ngày tải lên : 05/08/2014, 09:20
... (2- a) 3m (2- b) (2- c) kN 1.5m kN kN 3m 3m 3m 2m 4m 4m (3- a) (3- b) 1 .2 m kN 4kN 5kN kN 1.6 m (4-a) 0.7 m 0.9 m 0.9 m 0.7 m 0.9 m 0.9 m 0.9 m 2m (3- c) 1 .2 m 1 .2 m 3m 3m (4-b) (4-c) kN kN 2m 2m kN ... equations: 36 Truss Analysis: Force Method, Part I by S T Mau Joint F2 Σ Fy = 0, F2(4/5)+0. 83= 0, F2= –1.04 kN F3 Σ Fx = 0, –F2 (3/ 5) – F3=0, F3= 0. 62 kN 0. 83 kN Joint Σ Fy = 0, F1(4/5)+0.17=0, F1= –0 .21 ... 0, F5 (3/ 5) – F4 (3/ 5) –F1= 0, F1= –6 kN 38 Truss Analysis: Force Method, Part I by S T Mau Joint Σ Fx = 0, 4 F6(4/5) + F3(4/5) =0, F3 = kN Σ Fy = 0, F6 F6 (3/ 5) – F3 (3/ 5) –F2= 0, F3 F2 F2= –6 kN...
  • 20
  • 357
  • 0
Fundamentals of Structural Analysis Episode 1 Part 3 pps

Fundamentals of Structural Analysis Episode 1 Part 3 pps

Ngày tải lên : 05/08/2014, 09:20
... (2- a) 3m (2- b) (2- c) kN 1.5m kN kN 3m 3m 3m 2m 4m 4m (3- a) (3- b) 1 .2 m kN 4kN 5kN kN 1.6 m (4-a) 0.7 m 0.9 m 0.9 m 0.7 m 0.9 m 0.9 m 0.9 m 2m (3- c) 1 .2 m 1 .2 m 3m 3m (4-b) (4-c) kN kN 2m 2m kN ... equations: 36 Truss Analysis: Force Method, Part I by S T Mau Joint F2 Σ Fy = 0, F2(4/5)+0. 83= 0, F2= –1.04 kN F3 Σ Fx = 0, –F2 (3/ 5) – F3=0, F3= 0. 62 kN 0. 83 kN Joint Σ Fy = 0, F1(4/5)+0.17=0, F1= –0 .21 ... 0, F5 (3/ 5) – F4 (3/ 5) –F1= 0, F1= –6 kN 38 Truss Analysis: Force Method, Part I by S T Mau Joint Σ Fx = 0, 4 F6(4/5) + F3(4/5) =0, F3 = kN Σ Fy = 0, F6 F6 (3/ 5) – F3 (3/ 5) –F2= 0, F3 F2 F2= –6 kN...
  • 20
  • 466
  • 0
Fundamentals Of Structural Analysis Episode 1 Part 2 docx

Fundamentals Of Structural Analysis Episode 1 Part 2 docx

Ngày tải lên : 05/08/2014, 11:20
... 0 − 33 .33 0⎤ ⎡ 33 .33 ⎢ 25 .00 − 25 .00 0 0⎥ ⎥ ⎢ 0 40. 53 − 9.60 − 33 .33 − 7 .20 9.60 ⎥ ⎢ − 25 .00 − 9.60 37 .80 0 9.60 − 12. 8⎥ ⎢ ⎢ 0 − 33 .33 33 .33 0 0⎥ ⎢ 0 0 25 .00 − 25 .00⎥ ⎥ ⎢ − 7 .20 9.60 0 40. 53 − ... ⎨ ⎬ = ⎢ ⎪ ⎪ ⎢0 ⎪ Fx ⎪ ⎢k 31 ⎪ ⎪ ⎢ ⎪ Fy ⎪ ⎢k 41 ⎩ ⎭ ⎣ 0 0 0 k11 k 21 k 31 k 41 k 12 k 22 k 32 k 42 k 13 k 23 k 33 k 43 0 0 0 k 13 k 23 0 k 12 k 22 0 k 32 k 42 0 0 0 k 33 k 43 ⎤ ⎧u1 ⎫ ⎥ ⎪ v1 ⎪ ⎥ ⎪ ⎪ ... 0 − 33 .33 33 .33 0 0⎥ ⎢ 0 0 25 .00 − 25 .00⎥ ⎥ ⎢ − 7 .20 9.60 0 40. 53 − 9.60⎥ ⎢ − 33 .33 ⎢ 0 9.60 − 12. 80 − 25 .00 − 9.60 37 .80⎥ ⎦ ⎣ For the second truss: 9.60 0 − 7 .20 − 9.60 − 33 .33 0⎤ ⎡ 40. 53 ⎢...
  • 20
  • 261
  • 0
Fundamentals Of Structural Analysis Episode 1 Part 3 doc

Fundamentals Of Structural Analysis Episode 1 Part 3 doc

Ngày tải lên : 05/08/2014, 11:20
... (2- a) 3m (2- b) (2- c) kN 1.5m kN kN 3m 3m 3m 2m 4m 4m (3- a) (3- b) 1 .2 m kN 4kN 5kN kN 1.6 m (4-a) 0.7 m 0.9 m 0.9 m 0.7 m 0.9 m 0.9 m 0.9 m 2m (3- c) 1 .2 m 1 .2 m 3m 3m (4-b) (4-c) kN kN 2m 2m kN ... equations: 36 Truss Analysis: Force Method, Part I by S T Mau Joint F2 Σ Fy = 0, F2(4/5)+0. 83= 0, F2= –1.04 kN F3 Σ Fx = 0, –F2 (3/ 5) – F3=0, F3= 0. 62 kN 0. 83 kN Joint Σ Fy = 0, F1(4/5)+0.17=0, F1= –0 .21 ... 0, F5 (3/ 5) – F4 (3/ 5) –F1= 0, F1= –6 kN 38 Truss Analysis: Force Method, Part I by S T Mau Joint Σ Fx = 0, 4 F6(4/5) + F3(4/5) =0, F3 = kN Σ Fy = 0, F6 F6 (3/ 5) – F3 (3/ 5) –F2= 0, F3 F2 F2= –6 kN...
  • 20
  • 263
  • 0
BEHAVIOR ANALYSIS in NEUROSCIENCE - PART 2 pot

BEHAVIOR ANALYSIS in NEUROSCIENCE - PART 2 pot

Ngày tải lên : 09/08/2014, 20:22
... 80 21 10 75 59 15 75 22 15 80 60 30 – 23 15 75 61 25 80 24 30 – 62 20 80 25 20 80 63 30 75 26 20 80 64 15 – 27 30 75 65 15 80 28 15 – 66 30 75 29 15 80 67 30 – 30 30 75 68 20 80 75 31 30 – 69 25 ... 25 32 20 80 70 30 – 33 25 75 71 30 80 34 30 – 72 15 75 35 30 80 73 30 80 36 15 75 74 20 – © 20 01 by CRC Press LLC 0704/C 02/ frame Page 40 Monday, July 17, 20 00 4 :39 PM Methods of Behavior Analysis ... – 47 20 80 10 20 75 48 15 – 11 20 80 49 10 80 12 15 – 50 25 – 13 10 80 51 30 75 14 25 – 52 25 – 15 30 75 53 25 80 16 25 – 54 20 75 17 25 80 55 10 – 18 20 75 56 30 80 19 10 – 57 10 75 20 30 80...
  • 22
  • 221
  • 0
BEHAVIOR ANALYSIS in NEUROSCIENCE - PART 3 ppsx

BEHAVIOR ANALYSIS in NEUROSCIENCE - PART 3 ppsx

Ngày tải lên : 09/08/2014, 20:22
... shown in Table 3 .2 TABLE 3 .2 Typical Acquisition Training Conditioned group Unconditioned control group Days 1–7 20 30 limited access to water 20 30 limited access to water Days 8–9 20 30 access to ... 20 20 10 10 0 Saline 6 .25 mg/kg 12. 5 mg/kg 25 mg/kg 20 -Day 100 40-Day 70 60 80 70 90 80 100 90 60 50 50 40 40 30 30 20 20 10 10 0 5-Day extinction periods FIGURE 3. 4 Mean saccharin preference score ... including © 20 01 by CRC Press LLC 0704/C 03/ frame Page 60 Monday, July 17, 20 00 4:47 PM Methods of Behavior Analysis in Neuroscience 60 serotonin agonists ,25 opiate agonists ,26 opiate antagonists ,27 cholecystokinin ,28 ...
  • 17
  • 254
  • 0
Strength Analysis in Geomechanics Part 2 ppt

Strength Analysis in Geomechanics Part 2 ppt

Ngày tải lên : 10/08/2014, 12:21
... state dU = dW and we derive from (1 .22 ) the value of a critical stress: q∗ = γs E/2l (1 . 23 ) The more detailed analysis of this theory will be given in Chaps 3 5 1.5 .3 The Bases of Ultimate Plastic ... have from (1.18), (1.19) d2 δQz /d 2 + (1 + qr3 /By E)δQz = The solution of this problem is well-known and according to periodity condition 1+qr3 /By E = n2 (n = 1, 2, 3, ) The minimum load takes ... expression tan2 Ψ = (1 − f tan Ψ)/(1 + f cot Ψ) from which it follows tan Ψ = −f + + f (1 .33 ) Prony threw equation (1 .33 ) in simpler form, viz cot(Ψ+ϕ) = tan Ψ which leads to Ψ = 0.5(π /2 − ϕ) (1 .34 ) All...
  • 20
  • 138
  • 0
Tổng hợp đề thi và đáp án mẫu ielts speaking part 1,2,3.

Tổng hợp đề thi và đáp án mẫu ielts speaking part 1,2,3.

Ngày tải lên : 28/03/2015, 13:27
... the gift is, and I could always see happy smiles on my friends’ faces.      19.      Parties         Do you like parties?        Yes, I do. I think it’s always nice to get together with friends occasionally.  It’s also nice to make friends at parties. However, we don’t have parties very  ... It’s also nice to make friends at parties. However, we don’t have parties very  often in China.       Where do people in your country hold parties?        At home or restaurants. I think most of the informal parties I attended were  ... Is there much difference between young people's parties and old(er) people's  parties?        I think so. Usually young people like playing games on parties and maybe  even play loud music, but old people usually like talking with each other and ...
  • 285
  • 7.1K
  • 96