... Chromosome F- 12 F -21 F -25 G-1 E-1 F -23 2 3 II 22 III 222 IV 2 3 V 2 3 or VI 2 4 VII or 4 or 2 or VIII 2 3 IX 22 3 X 22 XI 2 3 or XII 2 XIII 3 4 or more XIV 22 XV 2 3 XVI 22 Modified from ... Strains E-1 F- 12 F -21 F -23 F -25 G-1 Percentage of sporulation (20 days) 15.9 30.6 10.4 16.6 6 .2 8.3 Spore viabiUty (%) jSt /^nd ord Gener^ 47.7(11) 10.0 (20 ) 9.0 (45) 23 .2( 28) 2. 3 (22 ) 0.0( 12) Gener^ ... B B B B Br Br V V V V Ploidy (n) 1.5 2. 5 2. 7 2. 6 1.3 2. 7 2. 7 1.9 1.9 1.6 1.3 1.3 1.6 1.6 2.2 1.3 -2 1.3 -2 1.7 -2 A : Modified from [29 ]; B: Modified from [ 12] G genetic line; B bakers'; W = wine,...
... Heater Heater NU 20 15 10 t 10 30 12 14 30 Re = 10, d = Re = 100, d = Heater Heater 25 Heater Heater 25 20 NU NU 20 15 15 10 10 5 10 15 t 20 10 15 t 20 30 Re = 1000, d = Heater Heater 25 NU 20 ... Re =1 and γ = 45° and 90° 24 Convection and Conduction Heat Transfer 30 30 Re = 100, d = Re = 10, d = 25 20 20 NU NU Heater Heater 25 Heater Heater 15 10 15 10 5 10 12 14 t t 10 12 14 30 25 Re ... 10 15 t 25 20 30 30 Re = 100, d = Re = 10, d = Heater Heater 25 Heater Heater 20 NU NU 20 15 15 10 10 5 10 15 t 20 10 t 15 20 30 Re = 1000, d = Heater Heater 25 NU 20 15 10 5 10 t 15 20 Fig 17...
... 2 + rac cos(φc − 2 + ) + E c sin 2 = −ra2 sin wa2 2ra2 wa2 ) + E c cos 2 = ra2 cos 2ra2 (11.3.8) P1: JTH CB6 72- 11 CB6 72/ Litvin CB6 72/ Litvin-v2.cls February 27 , 20 04 0 :24 3 12 Internal Involute ... 11.3.3) x2 = −ra2 sin wa2 2ra2 , y2 = ra2 cos wa2 2ra2 (11.3.6) Using Eqs (11 .2. 11), we represent the extended hypocycloid by the equations x2 = −r ac sin(φc − 2 + y2 = r ac cos(φc − 2 + N − ... and (11 .2. 5) yield (M) r2 ( 2 , E c ) = (−rac sin(φc − 2 + ) + E c sin 2 )i2 + (rac cos(φc − 2 + ) + E c cos 2 )j2 (11 .2. 11) where φc = 2 (N /Nc ) (M) Using vector-function r2 ( 2 , E c...
... γ1 and2 that are determined with the equations (see Section 3.4) cot γ1 = m 12 + cos γ , sin γ cot 2 = + m 12 cos γ m21 + cos γ = sin γ m 12 sin γ (18 .2. 2) P1: JXR CB6 72- 18 CB6 72/ Litvin CB6 72/ Litvin-v2.cls ... Figure 18.6 .2: Illustration of limiting tooth dimensions L1 and L2 of face-gear P1: JXR CB6 72- 18 CB6 72/ Litvin CB6 72/ Litvin-v2.cls February 27 , 20 04 1:5 522 Face-Gear Drives equation 0.5 2 r as − ... 2, ” “s ” and “1, ” and “1” and2 are considered Angle γs that is formed between the shaper axis and IAs is P1: JXR CB6 72- 18 CB6 72/ Litvin CB6 72/ Litvin-v2.cls February 27 , 20 04 1:5 514 Face-Gear...
... CB6 72/ Litvin-v2.cls February 27 , 20 04 1 :28 19.3 Design Parameters and Their Relations 555 Representation of m21 in Terms of N1 and N2 The gear ratio m21 was represented for the right-hand and ... δ and sin δ: cos δ = (cos2 α + sin2 α sin2 λp )0.5 , Equations (19.5.7) are confirmed sin δ = (1 − cos2 δ)0.5 = sin α cos λp P1: JsY CB6 72- 19 CB6 72/ Litvin CB6 72/ Litvin-v2.cls February 27 , 20 04 ... cos2 γ sin2 τ sin αn cos γ cos τ − sin γ cos λb (19.6 .22 ) − sin2 λp cos2 αn cos γ cos τ cos λb + sin γ sin λb sin αt − cos2 γ sin2 τ cos γ cos τ cos λb + sin γ sin αn − sin2 λp cos2 αn (19.6 .23 )...
... 400C to 22 00C at a rate of 30C/min and finally maintained at 22 00C for min; - For SPME: from 40°C to 115°C at a rate of 3°C/min then from115°C to 22 0°C at 30°C/min and finally maintained at 22 0◦C ... 2- AP will be used as a standard to identify and quantify 2- AP in aromatic rice (Phan Phuoc Hien, 20 09; 20 10; 20 11) Quantification of 2- AP in pandan leaf: Fig System of the SPME extraction 7 32 ... (Table 2) Table Peak areas of collidine and 2- AP in pandan leaves recorded by GC-FID and GCMS Samples Peaks’areas (pA*s) Collidine 14009069 2- AP in young pandan leaf 581578 62 2-AP in mature pandan...
... funding, execution, and review ! IT/Business Performance Evaluated on the basis of spending and results Is good value received for every dollar spent? 22 Module 2: Architecture and Structural Design ... creational and structural design patterns can be used to define an architectural template This section discusses creational and structural design patterns and their uses Module 2: Architecture and ... following materials: ! Microsoft® PowerPoint® file 1910A_ 02. ppt ! Module 2: Architecture and Structural Design Patterns ! Lab 2: Architecture and Structural Design Patterns Preparation Tasks To prepare...
... internal addresses These addresses include 10.0.0.0 to 10 .25 5 .25 5 .25 5, 1 92. 168.0.0 to 1 92. 168 .25 5 .25 5, and 1 72. 16.0.0 to 1 72. 31 .25 5 .25 5 Add private IP addresses to the LAT only if you use private ... Card MS LoopBack Driver 3Com EtherLink PCI (Micros… IP Addresses 169 .25 4 .25 . 129 1 92. 168.1 .20 0 Add-> 25 5 25 5 To 1 92 To 1 92. 168.1 .20 0 168 Local Address Table Remove-> To construct a local address ... ranges: Edit From From 1 92 200 168 1 92. 168 .25 5 Add the following private ranges: 10.xxx, 1 92. 168.xx and 1 72. 16.xx173.31.xx and 169 .25 4.xx Add address ranges based on the Windows 20 00 Routing Table...
... 1.541 contains 22 .99 g of sodium and mass of Na 22 .99 g 35.44 g of chlorine Chemistry, Julia Burdge, 2nd e., McGraw Hill 11 Law of Multiple Proportions • When two elements, (call them A and B), form ... Julia Burdge, 2nd e., McGraw Hill 22 Millikan’s Oil Drop Experiment Tro, Chemistry: A Molecular Approach 23 Millikan’s Oil Drop Experiment Tro, Chemistry: A Molecular Approach 24 Electrons • ... +1.60 x 1019 C mass = 1.6 726 2 x 10 -24 g • since protons and electrons have the same amount of charge, for the atom to be neutral there must be equal numbers of protons and electrons Tro, Chemistry:...