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2 2 unitary and applied heat pumps electrically operated minimum efficiency requirements

APPLIED MYCOLOGY AND BIOTECHNOLOGY VOLUME 2  AGRICULTURE AND FOOD PRODUCTION

APPLIED MYCOLOGY AND BIOTECHNOLOGY VOLUME 2 AGRICULTURE AND FOOD PRODUCTION

Môi trường

... Chromosome F- 12 F -21 F -25 G-1 E-1 F -23 2 3 II 2 2 III 2 2 2 IV 2 3 V 2 3 or VI 2 4 VII or 4 or 2 or VIII 2 3 IX 2 2 3 X 2 2 XI 2 3 or XII 2 XIII 3 4 or more XIV 2 2 XV 2 3 XVI 2 2 Modified from ... Strains E-1 F- 12 F -21 F -23 F -25 G-1 Percentage of sporulation (20 days) 15.9 30.6 10.4 16.6 6 .2 8.3 Spore viabiUty (%) jSt /^nd ord Gener^ 47.7(11) 10.0 (20 ) 9.0 (45) 23 .2( 28) 2. 3 (22 ) 0.0( 12) Gener^ ... B B B B Br Br V V V V Ploidy (n) 1.5 2. 5 2. 7 2. 6 1.3 2. 7 2. 7 1.9 1.9 1.6 1.3 1.3 1.6 1.6 2. 2 1.3 -2 1.3 -2 1.7 -2 A : Modified from [29 ]; B: Modified from [ 12] G genetic line; B bakers'; W = wine,...
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Convection and Conduction Heat Transfer Part 2 ppt

Convection and Conduction Heat Transfer Part 2 ppt

Kĩ thuật Viễn thông

... Heater Heater NU 20 15 10 t 10 30 12 14 30 Re = 10, d = Re = 100, d = Heater Heater 25 Heater Heater 25 20 NU NU 20 15 15 10 10 5 10 15 t 20 10 15 t 20 30 Re = 1000, d = Heater Heater 25 NU 20 ... Re =1 and γ = 45° and 90° 24 Convection and Conduction Heat Transfer 30 30 Re = 100, d = Re = 10, d = 25 20 20 NU NU Heater Heater 25 Heater Heater 15 10 15 10 5 10 12 14 t t 10 12 14 30 25 Re ... 10 15 t 25 20 30 30 Re = 100, d = Re = 10, d = Heater Heater 25 Heater Heater 20 NU NU 20 15 15 10 10 5 10 15 t 20 10 t 15 20 30 Re = 1000, d = Heater Heater 25 NU 20 15 10 5 10 t 15 20 Fig 17...
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Gear Geometry and Applied Theory Episode 2 Part 1 pot

Gear Geometry and Applied Theory Episode 2 Part 1 pot

Kĩ thuật Viễn thông

... 2 + rac cos(φc − 2 + ) + E c sin 2 = −ra2 sin wa2 2ra2 wa2 ) + E c cos 2 = ra2 cos 2ra2 (11.3.8) P1: JTH CB6 72- 11 CB6 72/ Litvin CB6 72/ Litvin-v2.cls February 27 , 20 04 0 :24 3 12 Internal Involute ... 11.3.3) x2 = −ra2 sin wa2 2ra2 , y2 = ra2 cos wa2 2ra2 (11.3.6) Using Eqs (11 .2. 11), we represent the extended hypocycloid by the equations x2 = −r ac sin(φc − 2 + y2 = r ac cos(φc − 2 + N − ... and (11 .2. 5) yield (M) r2 ( 2 , E c ) = (−rac sin(φc − 2 + ) + E c sin 2 )i2 + (rac cos(φc − 2 + ) + E c cos 2 )j2 (11 .2. 11) where φc = 2 (N /Nc ) (M) Using vector-function r2 ( 2 , E c...
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Gear Geometry and Applied Theory Episode 2 Part 2 doc

Gear Geometry and Applied Theory Episode 2 Part 2 doc

Kĩ thuật Viễn thông

... dr i dφi ( 12. 2.4) Equations ( 12. 2.1), ( 12. 2.3), and ( 12. 2.4) yield tan µ1 = − m 12 (φ1 ) ± m 12 (φ1 ) ( 12. 2.5) tan 2 = ± m 12 (φ1 ) ± m 12 (φ1 ) ( 12. 2.6) Here, m 12 = (∂/∂φ1 )[m 12 (φ1 )] Function ... m 12 = dφ1 k1 = d 2 k yx ( 12. 2.8) P1: GDZ/SPH CB6 72- 12 P2: GDZ CB6 72/ Litvin CB6 72/ Litvin-v2.cls February 27 , 20 04 0: 32 12. 3 Closed Centrodes 323 where yx = dy/dx; yx (x) ∈ C , and x1 ≤ x ≤ x2 ... (Fig 12. 3.1) Figure 12. 3.1: Elliptical centrode ( 12. 3.5) P1: GDZ/SPH CB6 72- 12 P2: GDZ CB6 72/ Litvin CB6 72/ Litvin-v2.cls February 27 , 20 04 0: 32 12. 3 Closed Centrodes 325 Equation ( 12. 3.4) yields 2 ...
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Gear Geometry and Applied Theory Episode 2 Part 3 pot

Gear Geometry and Applied Theory Episode 2 Part 3 pot

Kĩ thuật Viễn thông

... equation rt ( 2 , 2 ) = Mt2 ( 2 )r2 ( 2 ), (13.6.5) which yields 2 ≥ 90◦ , 2 = 2( 2 − 90◦ ) xt = −r ( 2 − sin 2 ) + 2 sin( 22 ) (13.6.6) yt = −r (1 − cos 2 ) − 2 cos( 22 ) Axis yt is ... Fig 12. 12. 1, we have α 12 (θ1 ) = µ1 (θ1 ) + αc − Figure 12. 12. 1: Pressure angle of noncircular gears π ( 12. 12. 1) P1: GDZ/SPH CB6 72- 12 P2: GDZ CB6 72/ Litvin CB6 72/ Litvin-v2.cls February 27 , 20 04 ... represented in S by the equations 2 ( 2 ) = 2 [sin 2 n2 = [sin 2 − cos 2 − cos 2 1]T 0] T ( 12. B.1) ( 12. B .2) The coordinate transformations from S and S to S f (Fig 12. B .2) are based on the following...
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Gear Geometry and Applied Theory Episode 2 Part 4 pdf

Gear Geometry and Applied Theory Episode 2 Part 4 pdf

Kĩ thuật Viễn thông

... cos λb2 sin( 22 ) y2 = −r b2 sin( 22 ) + u cos λb2 cos( 22 ) (14.3.15) z = u sin λb2 − p2 2 n2 = [sin λb2 sin( 22 ) sin λb2 cos( 22 ) − cos λb2 ]T (14.3.16) Angle 2 is measured ... Left-hand gear 2, side-surface II (Fig 14.3.3): x2 = r b2 cos( 22 ) + u cos λb2 sin( 22 ) y2 = −r b2 sin( 22 ) + u cos λb2 cos( 22 ) (14.3.17) z = −u sin λb2 + p2 2 n2 = [sin λb2 ... Left-hand gear 2, side-surface I (Fig 14.3.3): x2 = r b2 cos( 22 ) + u cos λb2 sin( 22 ) y2 = r b2 sin( 22 ) − u cos λb2 cos( 22 ) (14.3.19) z = u sin λb2 − p2 2 n2 = [sin λb2 sin(θ2...
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Gear Geometry and Applied Theory Episode 2 Part 5 pptx

Gear Geometry and Applied Theory Episode 2 Part 5 pptx

Kĩ thuật Viễn thông

... Q (15 .2. 4) P1: GDZ/SPH CB6 72- 15 P2: GDZ CB6 72/ Litvin CB6 72/ Litvin-v2.cls February 27 , 20 04 0:44 15 .2 Axodes of Helical Gears and Rack-Cutters 409 Figure 15 .2. 2: Normal sections of pinion and gear ... P1: GDZ/SPH CB6 72- 15 P2: GDZ CB6 72/ Litvin CB6 72/ Litvin-v2.cls February 27 , 20 04 0:44 15 .2 Axodes of Helical Gears and Rack-Cutters 407 - Figure 15 .2. 1: Axodes of pinion, gear, and rack-cutter: ... c and t ; φσ and 2 are the angles of rotation of the P1: GDZ/SPH CB6 72- 15 P2: GDZ CB6 72/ Litvin CB6 72/ Litvin-v2.cls February 27 , 20 04 0:44 418 Modified Involute Gears profile-crowned pinion and...
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Gear Geometry and Applied Theory Episode 2 Part 6 ppsx

Gear Geometry and Applied Theory Episode 2 Part 6 ppsx

Kĩ thuật Viễn thông

... +7.653e+ 02 +6.888e+ 02 +6. 122 e+ 02 +5.357e+ 02 +4.592e+ 02 +3. 827 e+ 02 +3.061e+ 02 +2. 296e+ 02 +1.531e+ 02 +7.653e+01 +2. 724 e-03 February 27 , 20 04 0:44 Bending Stress: 136.8 MPa Figure 15.9.3: Contact and ... +9.000e+ 02 +8 .25 0e+ 02 +7.500e+ 02 +6.750e+ 02 +6.000e+ 02 +5 .25 0e+ 02 +4.500e+ 02 +3.750e+ 02 +3.000e+ 02 +2. 250e+ 02 +1.500e+ 02 +7.500e+01 +4.956e-04 439 Bending Stress: 76.9 MPa Figure 15.9.5: Contact and ... CB6 72- 15 P2: GDZ CB6 72/ Litvin CB6 72/ Litvin-v2.cls February 27 , 20 04 0:44 440 Modified Involute Gears S, Mises (MPa) (Ave Crit.: 75%) +1.106e+03 +1.014e+03 +9 .21 5e+ 02 +8 .29 3e+ 02 +7.372e+ 02 +6.450e+ 02 +5. 529 e+02...
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Gear Geometry and Applied Theory Episode 2 Part 7 pps

Gear Geometry and Applied Theory Episode 2 Part 7 pps

Kĩ thuật Viễn thông

... cos λo2 (16.B.8) sin2 γo cos2 αon = cos2 λb1 sin2 λo2 ± cos λb1 cos λb2 sin λo1 sin λo2 + cos2 λb2 sin2 λo1 = cos2 λb1 ± cos λb1 cos λb2 sin λo1 sin λo2 + cos2 λb2 − cos2 λb1 cos2 λb2 cos2 αon ... February 27 , 20 04 0:51 16.6 Stress Analysis 469 S, Pressure (MPa) (Ave Crit.: 75%) +8. 927 e+ 02 +8 .20 4e+ 02 +7.481e+ 02 +6.758e+ 02 +6.035e+ 02 +5.311e+ 02 +4.588e+ 02 +3.865e+ 02 +3.142e+ 02 +2. 419e+ 02 +1.696e+ 02 ... Pressure (MPa) (Ave Crit.: 75%) +8.714e+ 02 +8.008e+ 02 +7.303e+ 02 +6.598e+ 02 +5.892e+ 02 +5.187e+ 02 +4.482e+ 02 +3.776e+ 02 +3.071e+ 02 +2. 366e+ 02 +1.661e+ 02 +9.553e+01 +2. 500e+01 -8.935e+01 Figure 16.6.5:...
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Gear Geometry and Applied Theory Episode 2 Part 8 pps

Gear Geometry and Applied Theory Episode 2 Part 8 pps

Kĩ thuật Viễn thông

... γ1 and 2 that are determined with the equations (see Section 3.4) cot γ1 = m 12 + cos γ , sin γ cot 2 = + m 12 cos γ m21 + cos γ = sin γ m 12 sin γ (18 .2. 2) P1: JXR CB6 72- 18 CB6 72/ Litvin CB6 72/ Litvin-v2.cls ... Figure 18.6 .2: Illustration of limiting tooth dimensions L1 and L2 of face-gear P1: JXR CB6 72- 18 CB6 72/ Litvin CB6 72/ Litvin-v2.cls February 27 , 20 04 1:5 522 Face-Gear Drives equation 0.5 2 r as − ... 2, ” “s ” and “1, ” and “1” and 2 are considered Angle γs that is formed between the shaper axis and IAs is P1: JXR CB6 72- 18 CB6 72/ Litvin CB6 72/ Litvin-v2.cls February 27 , 20 04 1:5 514 Face-Gear...
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Gear Geometry and Applied Theory Episode 2 Part 9 pps

Gear Geometry and Applied Theory Episode 2 Part 9 pps

Kĩ thuật Viễn thông

... = 25 Ns = 28 N2 = 160 m = 6.35 mm αd = 25 .0o αc = 25 .0o γm = 90.0o 471.0 mm 559.0 mm P1: JXR CB6 72- 18 CB6 72/ Litvin CB6 72/ Litvin-v2.cls February 27 , 20 04 1:5 5 42 Face-Gear Drives Table 18.15 .2: ... CB6 72- 18 CB6 72/ Litvin CB6 72/ Litvin-v2.cls February 27 , 20 04 1:5 524 Face-Gear Drives Step 2: Determination of magnitude L2 (Fig 18.6 .2) Figure 18.7 .2 yields ∗ Oa I = Ns cos α0 rbs = cos α 2Pd ... CB6 72- 18 CB6 72/ Litvin CB6 72/ Litvin-v2.cls February 27 , 20 04 1:5 18.15 Stress Analysis S, Mises (Ave Crit.: 75%) +1.453e+06 +5.000e+05 +4.545e+05 +4.091e+05 +3.636e+05 +3.182e+05 +2. 727 e+05 +2. 273e+05...
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Gear Geometry and Applied Theory Episode 2 Part 10 doc

Gear Geometry and Applied Theory Episode 2 Part 10 doc

Kĩ thuật Viễn thông

... CB6 72/ Litvin-v2.cls February 27 , 20 04 1 :28 19.3 Design Parameters and Their Relations 555 Representation of m21 in Terms of N1 and N2 The gear ratio m21 was represented for the right-hand and ... δ and sin δ: cos δ = (cos2 α + sin2 α sin2 λp )0.5 , Equations (19.5.7) are confirmed sin δ = (1 − cos2 δ)0.5 = sin α cos λp P1: JsY CB6 72- 19 CB6 72/ Litvin CB6 72/ Litvin-v2.cls February 27 , 20 04 ... cos2 γ sin2 τ sin αn cos γ cos τ − sin γ cos λb (19.6 .22 ) − sin2 λp cos2 αn cos γ cos τ cos λb + sin γ sin λb sin αt − cos2 γ sin2 τ cos γ cos τ cos λb + sin γ sin αn − sin2 λp cos2 αn (19.6 .23 )...
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Gear Geometry and Applied Theory Episode 3 Part 2 pptx

Gear Geometry and Applied Theory Episode 3 Part 2 pptx

Kĩ thuật Viễn thông

... XD2 XB2 E m2 γm2 m2c ρw (Fig 21 .3.3) (Fig 21 .3.3) (Fig 21 .3.3) (Fig 21 .3.3) (Fig 21 .3 .2) (Fig 21 .3 .2) (Fig 21 .3 .2) (Fig 21 .3 .2) (Fig 21 .3 .2) (Fig 21 .3 .2) [Eq (21 .3.1)] (Fig 21 .3.3) rotation of ... Figs 20 .2. 1 and 20 .2. 2 correspond to the case of generation of a right-hand worm 614 P1: GDZ/SPH CB6 72- 20 P2: GDZ CB6 72/ Litvin CB6 72/ Litvin-v2.cls April 15, 20 04 16:11 20 .2 Generation of Worm and ... m21 = ω (2) N1 = ω(1) N2 where N1 and N2 are the numbers of worm threads and gear teeth Figure 20 .2. 2: Coordinate systems applied for worm generation (20 .2. 1) P1: GDZ/SPH CB6 72- 20 P2: GDZ CB6 72/ Litvin...
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Know and Understand Centrifugal Pumps Episode 2 pdf

Know and Understand Centrifugal Pumps Episode 2 pdf

Kĩ thuật Viễn thông

... 14 .2 13.9 13.7 13.4 13 .2 12. 9 12. 7 12. 4 12. 2 12. 0 11.8 11.5 11.3 11.1 10.9 10.7 10.5 10.3 10.1 8.3 35 .2 34.6 33.9 33.3 32. 8 32. 1 31.5 31.0 30.4 29 .8 29 .2 28.8 28 .2 27.6 27 .2 26.7 26 .2 25.7 25 .2 ... -1 52. 4 0.0 +1 52. 4 304.8 457 .2 609.6 7 62. 0 91 4.4 1066.8 121 9 .2 1371.6 1 524 .0 1676.4 1 828 .8 1981 .2 2133.6 22 86.0 24 38.4 25 90.8 27 43 .2 2895.6 3048.0 45 72. 0 31 O 30.5 29 .9 29 .4 28 .9 28 .3 27 .8 27 .3 ... 27 .8 27 .3 26 .8 26 .3 25 .8 25 .4 24 .9 24 .4 24 .0 23 .5 23 .1 22 .7 22 .2 21.8 21 .4 21 o 20 .6 16.9 788 775 760 747 734 71 706 694 68 668 655 645 633 620 610 597 587 577 564 554 544 533 523 429 15 .2 15.0...
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RESEARCH ON THE CHANGE OF 2-AP AND OTHER VOLATILE COMPOUNDS IN PROCESSING BUN FROM RICE

RESEARCH ON THE CHANGE OF 2-AP AND OTHER VOLATILE COMPOUNDS IN PROCESSING BUN FROM RICE

Sinh học

... 400C to 22 00C at a rate of 30C/min and finally maintained at 22 00C for min; - For SPME: from 40°C to 115°C at a rate of 3°C/min then from115°C to 22 0°C at 30°C/min and finally maintained at 22 0◦C ... 2- AP will be used as a standard to identify and quantify 2- AP in aromatic rice (Phan Phuoc Hien, 20 09; 20 10; 20 11) Quantification of 2- AP in pandan leaf: Fig System of the SPME extraction 7 32 ... (Table 2) Table Peak areas of collidine and 2- AP in pandan leaves recorded by GC-FID and GCMS Samples Peaks’areas (pA*s) Collidine 14009069 2- AP in young pandan leaf 581578 62 2-AP in mature pandan...
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Evaluation of heat pumps usage and energy savings in residential buildings

Evaluation of heat pumps usage and energy savings in residential buildings

Môi trường

... orientation Heating temperature 2. 28 2. 73 1.57 4.61 4.5 70.76 Mean Other Heating Methods (2) 2. 62 2.80 1. 82 5.63 69.60 Mean difference (1 -2) -0.35 -0.07 -0 .25 -1. 02 -0.5 1.16 P-Value 0.015** 0. 827 0.0 72* ... R2 Adj R2 Panel A 451.1 (0 .29 9) 509.3 (2. 164)** 1749 (1.345)** 1596 (1. 326 )** - 126 4 (-0.619) - 120 1 (-0.341) 5977 (0.584) -3380 ( -2. 618)*** 4.740 0.000*** 0. 322 0 .25 1 Panel B 448.1 (0.6303) 5 92. 4 ... perspectives on performance from measured data Energy and Buildings 20 09, 41, 5 12 20 20 01.pdf ISSN 20 76 -28 95 (Print), ISSN 20 76 -29 09 (Online) 20 12 International Energy & Environment Foundation All...
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Module 2: Architecture and Structural Design Patterns

Module 2: Architecture and Structural Design Patterns

Chứng chỉ quốc tế

... funding, execution, and review ! IT/Business Performance Evaluated on the basis of spending and results Is good value received for every dollar spent? 22 Module 2: Architecture and Structural Design ... creational and structural design patterns can be used to define an architectural template This section discusses creational and structural design patterns and their uses Module 2: Architecture and ... following materials: ! Microsoft® PowerPoint® file 1910A_ 02. ppt ! Module 2: Architecture and Structural Design Patterns ! Lab 2: Architecture and Structural Design Patterns Preparation Tasks To prepare...
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Module 2: Installing and Maintaining ISA Server

Module 2: Installing and Maintaining ISA Server

Hệ điều hành

... internal addresses These addresses include 10.0.0.0 to 10 .25 5 .25 5 .25 5, 1 92. 168.0.0 to 1 92. 168 .25 5 .25 5, and 1 72. 16.0.0 to 1 72. 31 .25 5 .25 5 Add private IP addresses to the LAT only if you use private ... Card MS LoopBack Driver 3Com EtherLink PCI (Micros… IP Addresses 169 .25 4 .25 . 129 1 92. 168.1 .20 0 Add-> 25 5 25 5 To 1 92 To 1 92. 168.1 .20 0 168 Local Address Table Remove-> To construct a local address ... ranges: Edit From From 1 92 200 168 1 92. 168 .25 5 Add the following private ranges: 10.xxx, 1 92. 168.xx and 1 72. 16.xx173.31.xx and 169 .25 4.xx Add address ranges based on the Windows 20 00 Routing Table...
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Tài liệu Chapter 2 Atoms and Elements

Tài liệu Chapter 2 Atoms and Elements

Hóa học

... 1.541 contains 22 .99 g of sodium and mass of Na 22 .99 g 35.44 g of chlorine Chemistry, Julia Burdge, 2nd e., McGraw Hill 11 Law of Multiple Proportions • When two elements, (call them A and B), form ... Julia Burdge, 2nd e., McGraw Hill 22 Millikan’s Oil Drop Experiment Tro, Chemistry: A Molecular Approach 23 Millikan’s Oil Drop Experiment Tro, Chemistry: A Molecular Approach 24 Electrons • ... +1.60 x 1019 C  mass = 1.6 726 2 x 10 -24 g • since protons and electrons have the same amount of charge, for the atom to be neutral there must be equal numbers of protons and electrons Tro, Chemistry:...
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