1 50 kev of the x ray anomalous dispersion factors
Cardiac Pacing and ICDs - Fourth Edition pptx
Ngày tải lên :
29/06/2014, 11:20
... REFERENCES 10 11 12 13 14 15 16 Mozumder, A Fundamentals of Radiation Chemistry; Academic Press: San Diego, 19 99 Lind, S.C Radiation Chemistry of Gases; Reinhold Publishing Corporation: New York, 19 61 ... oscillator strengths of transitions The Bragg rule refers only to the stopping of the incident particle 2.2 Bethe’s Theory and Extensions The first (and still the foremost) quantum theory of stopping, ... through the Einstein A—coefficient as fn ¼ ð8pmv=e2 hÞgn hnje Sj xj j0i2 Here gn is the degeneracy of the excited state (the ground state is taken as nondegenerate), xj is the x component of the position...
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Simulation and Monte Carlo With applications in finance and MCMC pdf
Ngày tải lên :
07/03/2014, 15:20
... as the last b bits of aXi 1 + c For example, in the generator (2 .1) X7 = × 13 + mod 16 In binary arithmetic, X7 = 11 01 + 11 = 10 01 × 11 01 + 11 011 0 10 00 0000 11 01 0000 0 011 011 1 10 00 + mod 10 000 ... Section 2 .1. 1 Problems 33 Consider the maximum period prime modulus generator Xi +1 = 10 0 010 1Xi mod 10 12 − 11 with X0 = 5354 7507 752 Compute by hand 10 0 010 1X0 mod 10 0 010 1X0 /10 12 Hence find X1 by ... 6.7 Problems 10 7 10 8 10 9 11 1 11 3 11 4 11 5 11 5 11 6 11 8 11 8 11 9 12 3 12 6 13 0 Discrete event simulation 7 .1 Poisson process 7.2 Time-dependent Poisson process 7.3 Poisson processes in the plane 7.4...
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Spectral Theory and Nonlinear Analysis with Applications to Spatial Ecology pot
Ngày tải lên :
23/03/2014, 01:20
... solution of Problem ( ) follows from Theorem 4 .1 Now, ~ Theorem 3 .1 and Theorem 3.2 complete the proof of the result The following result is the adapted version of Theorem 1. 1, for the particular ... from zero in fi of Problem ( ) ~ This completes the proof Now, we are ready to prove Theorem 1. 1 Proof of Theorem 1. 1 The necessary condition for the existence of positive solution of Problem ( ... neighbourhood of ro, and L (X) is an adequate regular ? extension of the operator L (X) from R to The remainder of the proof is obtained, arguing as in the case of Problem (1) x This completes the proof In...
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Algorithms and data structures with applications to graphics and geometry
Ngày tải lên :
08/05/2014, 18:16
... 11 3 12 .6 Random numbers 10 7 11 0 11 1 11 2 11 6 13 REALS 11 9 13 .1 Floating point numbers 13 .2 Some dangers 13 .3 Homer's method 13 .4 Bisection 13 .5 Newton's method for computing the square root 11 9 ... undecidable 15 .4 Computable, yet unknown 15 .5 Multiplication of complex numbers 15 2 15 3 15 4 15 6 14 8 Contents 15 .6 ix Complexity of matrix multiplication 15 7 16 THE MATHEMATICS OF ALGORITHM ANALYSIS 16 .1 ... 11 9 12 1 12 3 12 4 14 STRAIGHT LINES AND CIRCLES 12 5 12 9 14 .1 Intersection 14 .2 Clipping 14 .3 Drawing digitized lines 14 .4 The riddle of the braiding straight lines 14 .5 Digitized circles 12 9 13 2 13 4...
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online storage systems and transportation problems with applications
Ngày tải lên :
01/06/2014, 10:31
... Experiments 5.3 Summary ix 95 99 10 0 10 3 10 4 10 4 10 4 10 5 10 6 10 9 11 0 11 0 11 1 11 1 11 2 11 4 11 5 11 6 11 7 12 0 12 1 12 1 12 5 12 5 12 5 12 6 12 6 12 9 13 4 13 9 13 9 14 1 14 3 14 4 14 6 x Online Storage Systems and ... CIH and SA 15 5 15 5 15 5 18 0 18 7 18 7 18 7 18 8 18 9 18 9 19 0 19 1 19 1 19 5 19 5 200 References 213 Index 2 21 Preface This book covers the analysis and development of online algorithms involving exact optimization ... assigned to the layers In the objective is to minimize the maximum number of objects of the same color on the same layer Finally, aims to minimize the sum of the maximum number of objects of the same...
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tom m apostol calculus, vol 2 multi-variable calculus and linear algebra with applications 1969
Ngày tải lên :
12/06/2014, 16:22
... 369 11 .14 Worked examples 3 71 11 I5 Exercises 373 11 .16 Further applications of double integrals 376 11 .17 Two theorems of Pappus 377 11 .18 Exercises 11 .3 11 .4 Contents xv 111 11 .19 Green’s theorem ... Frobenius 6.23 The Bessel equation 6.24 Exercises 14 2 14 3 14 4 14 5 14 7 14 7 14 8 15 0 15 4 15 6 15 7 16 1 16 3 16 3 16 6 16 7 16 9 17 1 17 4 17 6 17 7 18 0 18 2 18 8 SYSTEMS OF DIFFERENTIAL EQUATIONS 7 .1 Introduction ... (y19y2) = (x1 +y1 ,x2 +y,), (b) (-9 9x2 ) cc> (Xl, (4 @1, x2 ) + (y1,y,) x2 ) + cy1,y2> + (yl,y2) = ( ~1 4X1 ,X, ) +yl,O), = (Xl, = (Ix, + x, l,ly1 = (ax,, ax,> 4x1 , x2 +y2>9 +y,l)t x2 > = ( ~17 QX2> 4x1 , x2 ) =...
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Matematik simulation and monte carlo with applications in finance and mcmc phần 1 pps
Ngày tải lên :
09/08/2014, 16:21
... 6.7 Problems 10 7 10 8 10 9 11 1 11 3 11 4 11 5 11 5 11 6 11 8 11 8 11 9 12 3 12 6 13 0 Discrete event simulation 7 .1 Poisson process 7.2 Time-dependent Poisson process 7.3 Poisson processes in the plane 7.4 ... example consider the generator Xi = 9Xi 1 + mod 24 i =1 Choose X0 ∈ 15 , say X0 = Then X1 = 30 mod 24 = 14 X2 = 12 9 mod 24 = The following sequence for Ri is obtained: 14 12 15 10 13 11 16 16 16 ... 10 13 11 16 16 16 16 16 16 16 16 16 16 16 16 16 16 16 16 16 (2 .1) (2.2) The period of a generator is the smallest integer such that X = X0 Here the sequence repeats itself on the seventeenth...
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Matematik simulation and monte carlo with applications in finance and mcmc phần 2 pdf
Ngày tải lên :
09/08/2014, 16:21
... as the last b bits of aXi 1 + c For example, in the generator (2 .1) X7 = × 13 + mod 16 In binary arithmetic, X7 = 11 01 + 11 = 10 01 × 11 01 + 11 011 0 10 00 0000 11 01 0000 0 011 011 1 10 00 + mod 10 000 ... Section 2 .1. 1 Problems 33 Consider the maximum period prime modulus generator Xi +1 = 10 0 010 1Xi mod 10 12 − 11 with X0 = 5354 7507 752 Compute by hand 10 0 010 1X0 mod 10 0 010 1X0 /10 12 Hence find X1 by ... using the code below: > with(numtheory): a =10 737 418 14 do; a =primroot a 2ˆ 31- 1 if a >10 737 418 34 then break end if; end do; a a a a a a a = 10 737 418 14 = 10 737 418 15 = 10 737 418 16 = 10 737 418 17 = 10 737 418 27...
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Matematik simulation and monte carlo with applications in finance and mcmc phần 3 ppsx
Ngày tải lên :
09/08/2014, 16:21
... x −w x2 Integrating over w, the marginal density of X is proportional to 1 x 1 1− −2 e−w /x w x + 1 dw = − x 1 − 1 e−a ax x + 1 x da ∝ 1 x 1 x 1 that is X has the required beta density Providing ... envelope g x ∝ r x where 1 r x =x and exp − x x≥0 < A suitable envelope is g x = Kr x where K = max x 0 hx rx = max exp − x 0 = exp − x+ x + x − Therefore an algorithm is: Sample X ∼ gamma If ... respect to , the function Var g hxfx gx = Eg = hxfx gx x support g − h2 x f x dx − gx (5 .12 ) 83 84 Variance reduction Note that if h x > x ∈ support hf then x support g < h2 x f x dx gx max x support...
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Matematik simulation and monte carlo with applications in finance and mcmc phần 4 pptx
Ngày tải lên :
09/08/2014, 16:21
... is b∗ = S 1 SXY XX where the ijth element of SXX is Xik − Xi Xjk − Xj N 1 N k =1 and the ith element of SXY is N k =1 Xik − Xi Yk − Y N 1 Now the estimator b∗ = Y − b∗ X − X (5.35) 99 10 0 Variance ... as (6.5) where a X t = X and b X t = X Let G = ln X Then G/ X = 1/ X G/ X = 1/ X , and G/ t = Using Itô’s lemma, G G G dX + dt + b2 dt X t X 2 dX X dt = − X 2X 2 Xdt + XdB dt = − X dG = = − dt + ... Here, = = Vx t t c t = x t x t x t = e−r T −t = e−r T −t = e−rf T −t e−r T −t − x − K + fXr−r f x − K fXr−r x t K x t √ −drf + T −t f T X t =x t x x t dx T X t =x t x t e r−rf − x x t dx /2 T −t...
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Matematik simulation and monte carlo with applications in finance and mcmc phần 5 ppsx
Ngày tải lên :
09/08/2014, 16:21
... 3 .16 1 013 255, 3.355203 918 ] [0. 310 5425825, 0.68 519 1 014 2, 1. 02 550 615 2, 1. 0363 014 99, 1. 247404803, 1. 370 810 129, 2.376 811 957, 2.37738 619 3, 2.56439 019 2, 3.436339776] [0.8 816 330302, 0.999 518 7699, 1. 733006037, ... y x This means that P y x =P X t ≤ y X t 1 = x X =x0 =P X t ≤ y X t 1 = x and P X t ≤ y X t 1 = x = P X ≤ y X = x for all x y ∈ S and for t = Note that X ≤ y denotes that Xi ≤ yi for i = The ... replicating the runs using antithetic random Simulating a hospital ward 14 9 Table 7 .1 Regenerative analysis of the M/M /1 queue 95% confidence interval p 0038 2 015 0 3 10 11 449 11 11 p L + a L...
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Matematik simulation and monte carlo with applications in finance and mcmc phần 6 doc
Ngày tải lên :
09/08/2014, 16:21
... r1 + r2 ≤ Then the joint density of R1 and X is r2 = x x fR1 X r1 X ∝ over support r1 x density of X is 1 x 1 r1 / < r1 < x < x < Integrating over r1 the marginal fX x ∝ x 1 ∝ x 1 =x ... density of X is x 1 x fX x ∝ x 1 x ∝ =x 1 1 1 x 1 x dy dx − − +2 1 1 x as required 10 The joint density is fX Y x y = f The f marginal x2 + y / density of X x2 + y / is − f x2 + y x2 + y / on ... not exceed a, so slice sampling will be tried Now f x ∝ f1 x f2 x where f1 x = x 1 and f2 x = e x Therefore, D = x u1 ≤ x 1 u2 ≤ e x x > a 1 1/ = x x ≥ u1 1/ = x max u1 x ≤ − ln u2 x > a −1...
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Matematik simulation and monte carlo with applications in finance and mcmc phần 7 ppt
Ngày tải lên :
09/08/2014, 16:21
... e.s.e 1 = 0 219 = 0073 11 (a) If x i is the current point then 1 x i R1 1 x i − ln R1 , 1/ x i +1 ∼ U max − − x i R2 1/ where R1 R2 ∼ U (b) x i +1 ∼ U max R3 x i + y i − y i y i +1 ∼ U max R3 x i +1 ... that the current FTSE is at x t Then ⎧ X T 1
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Matematik simulation and monte carlo with applications in finance and mcmc phần 8 pot
Ngày tải lên :
09/08/2014, 16:21
... ratioaccep:=proc(h::procedure ,x1 ,x2 ,xinit,xinit1,xinit2) 6 local u,u1,v1,v 11, v2,v22,acc; 6 u:=NLPSolve(h (x) , 6 x= x1 x2 ,initialpoint= {x= xinit},maximize);u1:=sqrt(op (1, u)); 6 if x1 0 then 6 v2:=NLPSolve (x* x*h (x) , 6 x= 0 x2 ,initialpoint= {x= xinit2},maximize); 6 v22:=sqrt(op (1, v2)); 6 else...
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Matematik simulation and monte carlo with applications in finance and mcmc phần 9 ppt
Ngày tải lên :
09/08/2014, 16:21
... xav:=0; for i1 from to n do; xi:=q[i1] *x[ i1]*exp((r-0.5*sigma[i1]^2)*(T-t)+sigma[i1]* sqrt(T-t)*w[i1]); xav:=xav+xi; end do; theta:=max(0,xav-K)*exp(-r*T-t)); c1:=c1+theta; c2:=c2+theta^2; end ... # 6 x0 :=0;T1:=sqrt(T-t); 6 for i1 from to n do; 6 x0 : =x0 +q[i1] *x[ i1]*exp((r-0.5*sigma[i1]^2)*(T-t)); 6 end do; 6 for i1 from to n do; 6 w[i1]:=q[i1] *x[ i1]*exp((r-0.5*sigma[i1]^2)*(T-t)) /x0 ; 6 ... numbers in ‘gg1’ by 1 U(0 ,1) random numbers, i.e perform antithetic replications > gg1 (1, 2 ,1, 1 ,10 000,246978, 715 86); print(" _ 6 _"); 6 gg1 (1, 1.5 ,1, 1 ,10 000,246978, 715 86);...
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Matematik simulation and monte carlo with applications in finance and mcmc phần 10 potx
Ngày tải lên :
09/08/2014, 16:21
... 317 , 10 66, 11 81, 923, 7756, 2656, 879, 12 32, 6 697, 3368, 486, 6767, 484, 438, 18 60, 11 3, 6062, 590, 6 16 33, 2425, 367, 712 , 953, 19 89, 768, 600, 30 41, 18 14, 6 14 1, 10 511 , 7796, 14 62]; 6 x :¼ ... [293, 19 02, 12 72, 2987, 469, 318 5, 17 11, 8277, 356, 822, 2303, 317 , 10 66, 6 11 81, 923, 7756, 2656, 879, 12 32, 697, 3368, 486, 6767, 484, 438, 18 60, 11 3, 6062, 590, 16 33, 2425, 367, 712 , 953, 19 89, ... required for i =1 q a1:=a;b1:=b; C:=Matrix(k,q+2); # Compute log likelihood (L1) for current point (a1,b1); xp: =1; sp:=0; for u from to n do; xp:=xp *x[ u]; sp:=sp +x[ u]^a1; end do; xp:=ln(xp); L1:=evalf(n*ln(a1/b1^a1)+(a1 -1) *xp-sp/b1^a1);...
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Study on chemical constituents and biological activities of some plants of boerhaavia genus (nyctaginaceae)
Ngày tải lên :
24/08/2015, 12:40
... 13 1.3 11 7.6 15 5 .1 61. 7 76.5 15 2.2 12 9.6 16 1.8 94.3 16 1.5 10 1.6 19 3 .1 66.4 61. 6 56.5 – Compound 55 (Chloroform-d) 13 2.6 12 0.9 12 1.4 13 1 .1 117 .6 15 5.8 62.2 76.9 16 1.2 91. 3 16 6.5 10 6.3 16 2.2 98.5 19 5.3 ... 16 1.5 91. 6 16 6.9 10 6.8 16 2.7 10 3.0 19 5.6 67.2 11 6.8 12 1.4 12 2.7 12 1.6 14 6.6 14 3.8 62.3 78.9 16 2.8 94.3 16 8.8 96 .1 166.2 10 2.9 19 5.0 66.8 10 -Demethyl [50] -boeravinone C (Acetone-d6) 11 6.8 12 1.5 ... 12 2.7 12 1.5 12 1.6 11 6.7 14 6.6 14 3.9 62.3 77.0 16 1.2 91. 2 16 6.4 10 6.3 16 2.2 10 2.5 19 5.2 66.8 Boeravinone C Compound 21 [36] (Acetone-d ) (Acetone-d6) 12 3.2 12 1.9 12 2.0 11 7 .1 147.0 14 4.2 62.7 77.4 16 1.5...
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Study on chemical constituents and biological activities of the lichen parmotrema Praesorediosum(NYL ) hale(parmeliaceaf)
Ngày tải lên :
15/12/2015, 15:22
... PRAES-C14 211 Appendices 13 7 -14 1: NMR spectra of PRAES-C12 214 Appendices 14 2 -14 7: MS and NMR spectra of PRAES-C5 216 Appendices 14 8 -15 5: IR, MS and NMR spectra of PRAES-C15 219 Appendices 15 6 -16 3: ... correlations of PRAES-C28 11 1 Figure 3.35 HMBC correlations of PRAES-E17 11 2 Figure 3.36 HMBC correlations of PRAES-E13 11 4 Figure 3.37 COSY and HMBC correlations of PRAES-E15 11 8 xv LIST OF APPENDICES ... Table 3 .17 NMR data of PRAES-C27 and PRAES-C28 (CDCl3) 10 6 11 0 xii Table 3 .18 NMR data of PRAES-E17, PRAES-E6, PRAES-E13 and 1 ,3βDiacetoxyhopan-22-ol Table 3 .19 NMR data of PRAES-E15 11 5 12 0 Table...
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Extreme value and related models with applications in engineering and science
Ngày tải lên :
17/02/2016, 14:36
... 5.7 .1 The Maximum Likelihood Method 5.7.2 The Weighted Least Squares CDF Method 10 7 10 8 10 8 11 0 11 2 11 3 11 4 11 7 11 7 11 9 12 0 12 1 12 2 12 3 12 3 12 3 12 5 CONTENTS x 5.7.3 The Elemental ... 1. 5.3 The Maximum Car Speed Data 3 vii 5 7 8 9 9 10 10 10 11 12 12 12 13 13 13 15 15 15 15 vlll CONTENTS I1 Probabilistic Models Useful for Extremes 19 Discrete Probabilistic ... Discrete Models h= 1 IL3 L X P (X) 10 X 10 12 X 10 12 14 16 20 X Figure 2.5: Sorne examples of probability mass furlctions of the Poisson random variable with four different values of A into a very...
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