Blender master class
... Detail 18 3 18 4 18 5 18 5 18 5 18 7 18 8 18 9 18 9 19 1 19 1 19 6 19 6 20 0 20 0 2 01 20 3 20 3 2 04 2 04 20 7 20 7 20 7 20 9 20 9 21 1 21 1 21 1 21 3 21 3 21 3 2 14 21 5 21 5 21 6 21 6 21 8 21 8 21 9 ... 12 1 12 1 12 3 12 3 12 5 12 5 12 5 12 6 12 6 12 6 12 7 12 7 12 8 12 9 12 9 13 0 13 0 13 1 13 1 13 2 13 2 13 2 13 5 13 5 13 7 13 7 13 8 13 8 13 8 13 9 14 1 ... 10 9 11 0 11 0 11 1 11 2 11 3 11 3 11 3 11 4 11 4 11 5 11 5 11 5 11 7 11 7 11 8 11 8 11 8 11 9 11 9 11 9 12 0 12 1 ...
Ngày tải lên: 08/08/2014, 07:35
... 10 — 12 — 14 — 16 20 — 24 — 28 — 32 35 42 — 48 60 65 80 10 0 — 11 5 15 0 17 0 — 20 0 25 0 27 0 325 40 0 — — — — — 10 — 12 — 14 — 16 18 — 22 — 25 — 30 36 44 — 52 60 72 85 10 0 — 12 0 15 0 17 0 — 20 0 24 0 300 ... a1 a2 a3 a4 a5 a0 a1 a2 a3 a4 a5 ¼ 1. 37 323 ¼ 2: 069 62 ¼ À0 :45 3 21 9 ¼ À0:3 34 6 12 Â 10 1 ¼ À0: 745 9 01 Â 10 2 ¼ 0: 24 9 580 Â 10 2 ¼ 0:7857 24 ¼ 0:6 843 42 ¼ 0 :16 845 7 ¼ 0 :10 38 34 ¼ 0 :20 9 01 Â 10 1 ¼ 0:576 64 ... À0: 713 3 þ 0:6305w 24 i 24 h 0:6305 þ 0 :19 35ðReÞp ðReÞp log10 CD ¼ 1: 643 5 À 1: 1 24 2 w þ 0 :15 58w2 15 00 1: 5 Â 10 3 ðReÞp 1: 2 Â 10 4 log10 CD ¼ 2 :45 71 þ 2: 5558w À 0: 929 5w2 þ 0 :10 49 w3 1: 2 Â 10 4 ðReÞp 4: 4...
Ngày tải lên: 02/04/2014, 14:59
... 386 28 0 45 4 30.0 43 .5 17 .2 29 .4 2 81 44 2 11 4 28 7 42 6 670 17 3 43 6 Persistent inundation communities (average) Drainage (PDL) Heavy rainy (PHS) Stagnant (PSM) 543 679 500 44 9 36 .4 46.3 30.3 32. 6 41 0 ... community (NCD) 13 3 0.00 0.70 1. 00 Short-term inundation communities (average) Rainy (SRM) Heavy rainy (SHU) Drainage (SDG) 46 6 5 42 316 538 19 .8 27 .8 16 .4 15 .2 222 357 14 4 16 4 336 5 41 21 9 24 9 Long-term ... -0. 02 -0. 34 0 .44 0. 71* -0 .29 0 .19 -0.76* -0 .10 0.38 -0. 32 0.07 -0.79** 0. 31 0.85** -0.93** -0 . 14 0. 72* -0 .13 -0. 32 0.76* -0.73* 0.39 0.00 * Correlation is significant at the 0.05 level (2- tailed)...
Ngày tải lên: 05/09/2013, 10:15
Integration of energy and environmental systems in wastewater treatment plants
... Management, 20 04, Vol 71 (3), pp 20 7- 21 5 [6] Starkl, M., and Brunner, N Feasibility versus sustainability in urban water management, journal of environmental management, 20 04, Vol 71 (3), pp 24 5 -26 0 ... (EUI) (kBtu/MGD) Baseline total GHG emissions Influent BOD5 (mg/l) Value 58 58 $16 8,5 51. 61 3 .2 1. 949 8 2. 2 15 26 .69 20 0.0000 Multilinear regression analysis was employed to model and analyze the ... management, 20 09, Vol 91 (1) , pp 87 -10 1 [ 12 ] Mazumber, D Process evaluation and treatability study of wastewater in a textile dyeing industry, International Journal of Energy and Environment, 2 011 , Vol...
Ngày tải lên: 05/09/2013, 15:28
Spectroscopic and Microscopic Investigation of Gold NanoparticleFormation: Ligand and Temperature Effects on Rate and Particle Size
... Aikens, C M J Am Chem Soc 2 010 , 13 2, 8 21 0 –8 21 8 ( 12 ) Provorse, M R.; Aikens, C M J Am Chem Soc 2 010 , 13 2, 13 02 13 10 (13 ) Aikens, C M J Phys Chem C 20 08, 11 2, 19 797 19 800 ( 14 ) Bukasov, R.; Shumaker-Parry, ... 67 82 6786 (20 ) Kim, F.; Song, J H.; Yang, P J Am Chem Soc 20 02, 12 4, 14 316 14 317 818 9 dx.doi.org /10 .10 21 / ja107934h |J Am Chem Soc 2 011 , 13 3, 817 9– 819 0 Journal of the American Chemical Society ( 21 ) Millstone, ... Shumaker-Parry, J S Nano Lett 20 07, 7, 11 13 11 18 (15 ) Burda, C.; Chen, X.; Narayanan, R.; El-Sayed, M A Chem Rev 20 05, 10 5, 10 25 11 02 (16 ) El-Sayed, M A Acc Chem Res 20 01, 34, 25 7 2 64 (17 ) Habas, S E.; Lee,...
Ngày tải lên: 18/09/2013, 21:27
The 8051 microcontroller and embedded systems using assembly and c 2nd ed
... remainders Ex Convert 4 510 to hex 32 16 1 1 32 + + + = 45 4 510 = 0 010 11 0 12 = 2D16 Ex Convert 62 910 to hex 5 12 25 6 12 8 64 32 16 1 0 1 1 62 910 = 5 12 + 64+ 32 +16 +4 +1 = 0 010 011 1 010 12 = 27 516 HANEL Department ... hexadecimal equivalent of 896H HANEL Decimal 10 11 12 13 14 15 Binary 0000 00 01 0 010 0 011 010 0 010 1 011 0 011 1 10 00 10 01 1 010 10 11 110 0 11 01 111 0 11 11 Hex A B C D E F Department of Computer Science ... to decimal by summing the weight of all digits Ex 6B 21 6 = 011 0 10 11 0 010 2 10 24 5 12 25 6 12 8 64 32 16 1 1 1 0 10 24 + 5 12 + 12 8 + 32 + 16 + = 17 1 41 0 HANEL Department of Computer Science and Information...
Ngày tải lên: 04/10/2013, 19:10
Effect - Particle Systems
... size: 10 ; } } var durationSlider = Slider{ vertical: false; translateX: 20 translateY: 40 + 90 min: 10 max: 20 0 value: 10 0 width: 20 0 } var durationLabel = Label{ translateX: 22 translateY: 26 + ... translateX: 20 translateY: 40 + 60 min: max: 4. 0 value: 1. 0 width: 20 0 } var speedLabel = Label{ translateX: 22 translateY: 26 + 60 text: bind "Particle Speed: {speedSlider.value} pixels/step"; width: 20 0 ... accelerate downward The code in Listing 2 - 12 shows how this is implemented Figure 2 -10 Example 7, falling stars 46 CHAPTER ■ EFFECT: PARTICLE SYSTEMS Listing 2 - 12 Particle.fx (partial) //Other attributes...
Ngày tải lên: 05/10/2013, 12:20
Nano and Microelectromechanical Systems P4
... 5 .26 20 0 10 0 .10 1, 0 24 4.9 mV None 38 ±50 0 .13 1, 0 24 4.9 mV 76 25 0.06 1, 0 24 4.9 mV 2. 63 10 0 20 0.05 1, 0 24 4.9 mV 5 .26 20 0 10 0. 02 4, 096 1. 2 mV None 38 ±50 0.03 4, 096 1. 2 mV 76 25 0. 02 4, 096 ... Cf (µF) 10 Hz 76m/g 25 g 2. 0 20 0kΩ 0.00 82 0. 027 0.0 82 10 0m/g 20 g 2. 6 26 1kΩ 0.0056 0. 022 0.056 20 0m/g 10 g 5.3 536kΩ 0.0033 0. 010 0.033 40 0m/g ±5g 10 .5 1MΩ 0.0 015 0.0056 0. 015 Figure 20 One-Pole ... 2n SF FS System Converter Preamp in Range Resolution mV/Bit Gain mV/g in g’s in g’s (p-p) (5 V/2n) Bit 25 6 19 .5 mV None 38 ±50 0. 51 25 6 19 .5 mV 76 25 0 .26 25 6 19 .5 mV 2. 63 10 0 20 0 .20 25 6 19 .5...
Ngày tải lên: 17/10/2013, 11:15
Nano and Microelectromechanical Systems P6
... 4/ 3 − e − x , a bounded controller is found as 1 12 u as = − sin(RTθ rm )sat + 12 14 e + 2. 9e1 / + 6.1e + 4. 3e1 / , − s s 1 12 u bs = cos(RTθ rm )sat + 12 14 e + 2. 9e1 / + 6.1e + 4. 3e1 ... =0 2 +1 γ +1 x ( i +γ +1) i +γ +1 µ +1 µ +1 e ( i + µ +1) i + µ +1 T ς i +γ +1 K xi (t ) x 2 +1 + i =0 ∑ β +1 β +1 e ( i + β +1) i + β +1 T i + β +1 K ei (t )e β +1 ... x1 , x2 ) = (x Thus, V ( x1 , x2 ) > The total derivative is © 20 01 by CRC Press LLC ) + x2 ) dV ( x1 , x2 ) & & = x1 x1 + x2 x2 = − x 12 − x2 (1 + x2 ) dt dV ( x1 , x2 ) Therefore, < Hence,...
Ngày tải lên: 19/10/2013, 18:15
Nano and Microelectromechanical Systems P5
... & & & & &2 Γ = Lss q 12 + Lms q1q3 cos q5 − Lms q1q sin q5 + Lss q 2 & & & & &2 &2 &2 + Lms q q3 sin q5 + Lms q q cos q5 + L'rr q3 + L'rr q + Jq5 , Π=0, &2 &2 &2 &2 &2 D = rs q1 + rs q2 + rr' q3 ... (Lasbs + Lbsas )q1q2 + (Lascs + Lcsas )q1q3 2 &2 & & &2 + Lbsbs q2 + (Lbscs + Lcsbs )q2 q3 + Lc scs q3 ( ) ( ) & & & &2 + ψ m q1 sin q4 + ψ m q2 sin q4 − π + ψ m q3 sin q4 + π + Jq4 3 Then, we ... , (3 .4 . 12 ) dt dt dt T where rr' = N s2 rr N r2 Matrix equations (3 .4 . 12 ) in expanded form using (3 .4 .11 ) are rewritten as © 20 01 by CRC Press LLC dias di di − Lms bs − Lms cs dt dt dt 2 ' '...
Ngày tải lên: 19/10/2013, 18:15
The Future of Wireless Banking Implementation of Wireless Banking and Financial Systems
... will grow to 10 8 million by 20 02 Users Interest in Phones with E-Mail Current Potential Users Users Definitely Interested 8.3% 13 % Probably Interested 8.0% 13 % Maybe Interested 13 .3% 23 % Probably ... Forrester research, almost 12 0 million Europeans already use mobile phones, exchanging more than two billion wireless text messages each month • By 20 03, Forrester projects 21 9 million Europeans, ... 13 .3% 23 % Probably Not Interested 25 % 26 % Definitely Not Interested 45 % 25 % Source: The Strategis Group The Future of Wireless Banking Ron Ghani Little G History 1G is the first generation in mobile...
Ngày tải lên: 26/10/2013, 16:15
Darwinism, Design, and Complex Systems Dynamics
... Deamer, and Smith 19 91; Morowitz 19 92) Plausible P1: KAF/KAA P2: KaF 05 21 8 2 949 6c09.xml CY335B/Dembski 5 21 82 949 March 10 , 20 04 Darwinism, Design, and Complex Systems Dynamics 1: 5 18 3 sources for ... its DNA” (Behe 19 96, 19 2, emphasis added) The bacterial flagella that Behe considers have over forty P1: KAF/KAA P2: KaF 05 21 8 2 949 6c09.xml CY335B/Dembski 17 8 5 21 82 949 March 10 , 20 04 1: 5 Bruce H ... complex systems” (Behe 19 96, p 20 2) P1: KAF/KAA P2: KaF 05 21 8 2 949 6c09.xml CY335B/Dembski 5 21 82 949 March 10 , 20 04 1: 5 Darwinism, Design, and Complex Systems Dynamics 17 5 Behe’s argument from...
Ngày tải lên: 01/11/2013, 07:20
GSM, cdmaOne and 3G systems P1
... RADIO 22 00 state I 00 11 11 state II 10 10 00 01 state III 01 01 01 01 01 state IV 11 10 10 output coded symbol 01 11 00 00 01 00 Figure 1. 19: The trellis diagram for cc (2 3) input of or 0, respectively ... cdmaOne are H4 H4 H 32 H 32 H8 = H4 H4 H 32 H 32 (1. 46 ) " H 64 = # : (1. 47 ) Figure 4 .1 shows the set of 64 Walsh codes used in cdmaOne, where the numbering relates to W j j = : : : 63 1. 4. 3 The spread ... The 1. 4 THE CDMA RADIO INTERFACE 35 Hadamard matrix of order four is H4 = " # H2 H2 H2 H2 =6 1 1 1 1 1 1 1 1 7 (1. 45 ) where row and column are Walsh code 0, or w0 ; row and column are w1 ; row...
Ngày tải lên: 07/11/2013, 16:15
Tài liệu GSM, cdmaOne and 3G systems P3 doc
... 2 ln (10 ) 10 then dx = E 10 ζ =10 ] dζ p 2 (3 .18 ) σ ln (10 ) 1: 023 exp 10 = ( Q " ( Q p 2 ln (10 ) 10 (3 .17 ) ; σ ln (10 ) 1: 023 exp 10 p p Z 2 ln (10 ) 10 2 p2σ ln (10 ) exp )1= 2 (4 σ 10 = 15 9 x2 )# ... = Q( ) where Q(k) E 10 ζ =10 ] = = p1 Q (2) Z 2 ∞ k σ ln (10 ) 10 Z 2p2σ exp p p 10 2 ζ =10 2 exp( 2 =2) 1: 023 exp p 2 and 2 , then we rewrite Equa- Z 2p2σ 2 ln (10 ) =10 (3 . 14 ) p If we truncate the ... exp ζ =10 dζ: (3 .13 ) Setting 10 ζ =10 or exp(z) ζ ln (10 ) 10 = z = then h E 10 ζ =10 i Z = exp ζ 10 = ∞ 2 2 2 ln (10 ) ln (10 ) σ exp 10 p pζ 2 σ ln (10 ) 10 Z 10 2 dζ ∞ p pζ exp ln (10 ) 2 (4 2 )1= 2 ∞ exp...
Ngày tải lên: 14/12/2013, 23:15
Tài liệu GSM, cdmaOne and 3G systems P4 pdf
... 0000000 011 111 111 0000000 011 111 111 0000000 011 111 111 0000000 011 111 111 010 1 010 110 1 010 10 010 1 010 110 1 010 10 010 1 010 110 1 010 10 010 1 010 110 1 010 10 0 011 0 011 110 011 000 011 0 011 110 011 000 011 0 011 110 011 000 011 0 011 110 011 00 011 0 011 010 011 0 010 110 011 010 011 0 010 110 011 010 011 0 010 110 011 010 011 0 01 ... 0 011 0 011 0 011 0 011 0 011 0 011 0 011 0 011 0 011 0 011 0 011 0 011 0 011 0 011 0 011 0 011 011 0 011 0 011 0 011 0 011 0 011 0 011 0 011 0 011 0 011 0 011 0 011 0 011 0 011 0 011 0 011 0 000 011 110 00 011 110 00 011 110 00 011 110 00 011 110 00 011 110 00 011 110 00 011 11 010 110 10 010 110 10 010 110 10 010 110 10 010 110 10 010 110 10 010 110 10 010 110 10 ... 0 011 110 011 000 011 0 011 110 011 000 011 0 011 110 011 000 011 0 011 110 011 000 011 011 010 011 0 010 110 011 010 011 0 010 110 011 010 011 0 010 110 011 010 011 0 010 110 000000000000000 011 111 111 111 111 110 00000000000000 011 111 111 111 111 11...
Ngày tải lên: 14/12/2013, 23:15
Tài liệu GSM, cdmaOne and 3G systems P5 pdf
... i.e h E 10 ε 10 i Z = ε εln (10 ) exp 4 2 p e2 dε exp 10 ∞ 4 σe ∞ = exp σe ln (10 ) 10 = exp σe 2Z ln (10 ) 10 exp ∞ h ln (10 ) 2 e 10 i2 dε 4 2 e ∞ p pε 2 e p f1 Q ∞]g = exp σe ln (10 ) 10 (5. 51) ε where ... of the 10 10 is h ε i h h ε ii2 i2 n h ε ε = E 10 10 = var 10 10 E 10 10 h ε E 10 10 io2 E 10 10 (5. 52) : From Equation (5. 51) we have h var 10 ε 10 i = h E 10 " i ε σe ln (10 ) exp 10 # 2 (5.53) ... viE i =1 h ε 10 10 i = !2 2σe p ln (10 ) 10 i =1 h i ∑ vi var 10 i =1 p !23 N < 2 e ln (10 ) ∑ vi :exp i =1 p !4 39 ln (10 ) 2 e 5= exp N = ∑ vi exp N ε 10 : 10 (5 .10 5) (5 .10 6) In Equation (5 .10 1), the...
Ngày tải lên: 14/12/2013, 23:15
Tài liệu GSM, cdmaOne and 3G systems P6 pdf
... TELECOMMUNICATION SYSTEM c 16 ,8 c 16 ,8 -1 -1 -1 -1 -1 -1 -1 -1 43 5 -1 -1 -1 -1 -1 -1 -1 -1 c 8,3 × c 8,3 1 -1 -1 -1 -1 1 1 -1 -1 -1 -1 1 Σ of bits = Σ of bits = c 8 ,4 × c 8 ,4 -1 -1 -1 -1 -1 -1 -1 -1 Σ of bits ... However, the Phase 2+ CHAPTER EVOLUTION OF GSM AND CDMAONE TO 3G SYSTEMS 41 2 Table 6 .2: The MS multislot classes Multislot class 10 11 12 13 14 15 16 17 18 19 20 21 22 23 24 25 26 27 28 29 b= c= ( ( ... 15 secondary scrambling codes Eight sets 43 4 CHAPTER EVOLUTION OF GSM AND CDMAONE TO 3G SYSTEMS Cch ,4, 0= (1, 1 ,1, 1) Cch ,2, 0= (1, 1) Cch ,4 ,1= (1, 1, -1, -1) Cch ,1, 0 = (1) Cch ,4, 2= (1, -1, 1, -1) Cch ,2 ,1= ...
Ngày tải lên: 14/12/2013, 23:15
Tài liệu Robotics and Autonomous Systems docx
... Networks, ICANN, Paris, Vol 1, 19 95, pp 14 1 14 8 [4] R.A Brooks, A robust layered control system for a mobile robot, IEEE Journal of Robotics and Automation (1) (19 86) 14 23 [5] M Brunet, Process ... inferencing boards, Robotica 12 (19 94) 4 91 503 [ 24 ] J.M Renders, Biological metaphor applied to process control, Ph.D Dissertation, Université Libre de Bruxelles, 19 94 (in French) [25 ] D.E Rumelhart, G.E ... ICNN’ 94, Orlando, FL, Vol 1, 19 94, pp 600–605 [7] L Cordewener, D Meizel, On-line speed monitoring of mobile robots tasks, Engineering Applications of Artificial Intelligence (2) (19 94) 15 1 16 0...
Ngày tải lên: 22/12/2013, 21:18
Tài liệu GSM, cdmaOne and 3G Systems P4 docx
... 0000000 011 111 111 0000000 011 111 111 0000000 011 111 111 0000000 011 111 111 010 1 010 110 1 010 10 010 1 010 110 1 010 10 010 1 010 110 1 010 10 010 1 010 110 1 010 10 0 011 0 011 110 011 000 011 0 011 110 011 000 011 0 011 110 011 000 011 0 011 110 011 00 011 0 011 010 011 0 010 110 011 010 011 0 010 110 011 010 011 0 010 110 011 010 011 0 01 ... 0 011 0 011 0 011 0 011 0 011 0 011 0 011 0 011 0 011 0 011 0 011 0 011 0 011 0 011 0 011 0 011 011 0 011 0 011 0 011 0 011 0 011 0 011 0 011 0 011 0 011 0 011 0 011 0 011 0 011 0 011 0 011 0 000 011 110 00 011 110 00 011 110 00 011 110 00 011 110 00 011 110 00 011 110 00 011 11 010 110 10 010 110 10 010 110 10 010 110 10 010 110 10 010 110 10 010 110 10 010 110 10 ... 0 011 110 011 000 011 0 011 110 011 000 011 0 011 110 011 000 011 0 011 110 011 000 011 011 010 011 0 010 110 011 010 011 0 010 110 011 010 011 0 010 110 011 010 011 0 010 110 000000000000000 011 111 111 111 111 110 00000000000000 011 111 111 111 111 11...
Ngày tải lên: 23/12/2013, 17:15
Tài liệu GSM, cdmaOne and 3G Systems P5 pptx
... i.e h E 10 ε 10 i Z = ε εln (10 ) exp 4 2 p e2 dε exp 10 ∞ 4 σe ∞ = exp σe ln (10 ) 10 = exp σe 2Z ln (10 ) 10 exp ∞ h ln (10 ) 2 e 10 i2 dε 4 2 e ∞ p pε 2 e p f1 Q ∞]g = exp σe ln (10 ) 10 (5. 51) ε where ... of the 10 10 is h ε i h h ε ii2 i2 n h ε ε = E 10 10 = var 10 10 E 10 10 h ε E 10 10 io2 E 10 10 (5. 52) : From Equation (5. 51) we have h var 10 ε 10 i = h E 10 " i ε σe ln (10 ) exp 10 # 2 (5.53) ... viE i =1 h ε 10 10 i = !2 2σe p ln (10 ) 10 i =1 h i ∑ vi var 10 i =1 p !23 N < 2 e ln (10 ) ∑ vi :exp i =1 p !4 39 ln (10 ) 2 e 5= exp N = ∑ vi exp N ε 10 : 10 (5 .10 5) (5 .10 6) In Equation (5 .10 1), the...
Ngày tải lên: 23/12/2013, 17:15