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Part II – Short questions 7 points You will have to write your answers directly in your answer sheet Problem 7: 2 points 15 a Rewrite mixed number 19 to fraction.. b Rewrite percent 0.04[r]

ĐỀ KIỂM TRA CHẤT LƯỢNG NĂM HỌC 2015-2016 SỞ GD & ĐT VĨNH PHÚC MÔN TOÁN SONG NGỮ; LỚP ĐỀ CHÍNH THỨC Thời gian làm bài: 90 phút ( Không kể thời gian giao đề) Part I Multiple choice (Each questions worth 0,5 mark) Complete each of the following problems by choosing the best option A, B, C or D then write it in your answer sheet Problem 1:The fraction is read as A five – three B five – third C five – thirds D fifth – three  63 Problem 2: Reduce the fraction 81 , we have A 7 B  21 C 27 14 D 18  C  D 3 C 10 3 D Problem 3: What statement is a proportion?  A  B 8  Problem 4: The sum of two fractions  25 25 is 15 A 50 1 B x  , then we have Problem 5: If 14 x A x 14 B C x D Problem 6: The ray Ot is bisector ray of angle xOy when:      A xOy yOt B xOt  tOy xOy  xOt  xOy      C xOt  tOy xOy and xOt yOt D x 21 Part II – Short questions (7 points) (You will have to write your answers directly in your answer sheet) Problem 7: (2 points) 15 a) Rewrite mixed number 19 to fraction b) Rewrite percent 0.045% to decimal fraction 147 c) Rewrite fraction 28 to mixed number 1 and d) Multiply two fractions below: Problem 8: (1 point) Calculate ( Reduce result to the simplest form) 79  60 15 a) 26 22  27 27 b) Problem 9: (1 point) There are 80 sixth-grade students at Howard Elementary School If 25% of the students have green eyes, how many sixth-grade students have green eyes? Problem 10: (2.25 points) In the half of plane with edge containing ray OA, draw   0 two rays OB and OC such that BOA 130 and COA 50 a) Calculate the degrees of angle BOC; b) OD is opposite ray of OB, calculate degrees of AOD; c) Is OA bisector of angle COD? Why? Problem 11: (0.75 point) Samuel picked 150 strawberries at the strawberry patch He gave away all the strawberries to friends If Samuel gave the same number of strawberries to each friend, how many strawberries did each friend receive? …………The end……… ( Students not use calculator) SOLUTIONS AND POINTS Part I Multiple choice (3 points) Each questions worth 0,5 mark Problem Answer C B C D A C Part II – Short questions (7 points) Problem Contents a We have 15 148  19 19 0.5 b We have 0.045% = 20000 0.5 c 147 5 We have 28 0.5 d 1 1   We have 12 0.5 a 79 79 28    60 15 60 60 0.25 51 17  60 20 0.25 26 22 48   27 27 27 0.25 16  0.25 We have : 80x25%=20 0,25 Thus, the number of sixth – grade students have green eyes is 20 students 0.75 b Point B C a O A 0.25 D In the half of plane which includes ray OA, we have   AOC  BOA 500  1300 so the ray OC is between two 0.25 rays OA and OB, hence   BOC AOB  AOC 1300  50 800 0.25  BOC  80 Thus,  b 10 c 11  Because the ray OD is opposite ray of OB, angle BOD is straight angle Hence angle AOD and angle AOB are adjacent – supplemetary angles We have AOD 1800  AOB 180  1300 50 0.25 0.25  Thus, AOD 50 0.25 We see two angles BOC and DOC are two adjacentsupplementary angles so   DOC 1800  BOC 1800  80 1000  AOC  AOD COD  500 500 100      Hence, 0.25 Thus, the ray OA is bisector of angle COD 0.25 Since Samuel gave the same number of strawberries to each friend then we have: 0.25 150 : = 30 0.25 0.25 0.25 Thus, Each friend of Samuel received 30 strawberries - Nếu học sinh sử dụng từ cấu trúc sai phần nào thì trừ 0.25 điểm phần đó