De thi dai hoc nam 2015 lan 1 mon vat li cua Nhat Ban

De thi dai hoc nam 2015 lan 1 mon vat li cua Nhat Ban De thi dai hoc nam 2015 lan 1 mon vat li cua Nhat Ban De thi dai hoc nam 2015 lan 1 mon vat li cua Nhat Ban De thi dai hoc nam 2015 lan 1 mon vat li cua Nhat Ban De thi dai hoc nam 2015 lan 1 mon vat li cua Nhat Ban De thi dai hoc nam 2015 lan 1 mon vat li cua Nhat Ban De thi dai hoc nam 2015 lan 1 mon vat li cua Nhat Ban

A B C D E F (acceleration due to gravity) A AB m1 B D 2ℓ O AB d m2 AB θ 1 g G O A B O A m1 m2 ℓ cos θ + d sin θ ℓ ℓ ℓ cos θ − d sin θ ℓ cos θ + d sin θ ℓ cos θ − d sin θ ℓ cos θ + d tan θ ℓ ℓ ℓ cos θ − d tan θ ℓ cos θ + d tan θ ℓ cos θ − d tan θ B h L A v A B v √ g L h √ L √ g 2L h 2g h √ 2L 2g h C A B mB A v mA A B B A − 2mA mB v mA + mB − mA (mA − mB ) v mA + mB mA (mA − mB ) v mA + mB 2mA mB v mA + mB D m v kv k 4 mg k (mg)2 k mg k2 (mg)2 k2 E m A M B A B F A pA B pB pA pB m M √ m M √ M m M m F 1.0m 1.0kg P 9.8m/s 4.0m/s P N 6.2 9.8 16 26 N A A −20◦ C B C 100g 50 2.1J/(g·K) 3.3×10 J/g 10J 4.2J/(g·K) 2.3×10 J/g 50 7 B S n T0 k p0 T0 + ∆T ∆x CV nCV ∆T nCV ∆T + p0 S∆x nCV ∆T + k(∆x)2 nCV ∆T − k(∆x)2 nCV ∆T + p0 S∆x + k(∆x)2 nCV ∆T + p0 S∆x − k(∆x)2 C p-V A B C A A B C C A A 20 12 10 A A x B C 2m/s t=0s x [m] y [m] T [s] t = 0.1T y t x 10 y = −0.02 sin 2π(0.5t − x) y = 0.02 sin 2π(0.5t + x) y = −0.02 sin 2π(2t − x) y = 0.02 sin 2π(2t + x) 10 B S1 S1 S2 A S2 5.0m 12m B S1 P0 P0 S2 P0 P1 P2 2.5m P2 340m/s Hz 11 Hz 170 340 680 11 1360 C f a (< f ) b a b 12 b 12 A A B A C D E F B 13 13 B R1 R2 A B C D S1 S2 V S1 A Q A S1 Q S2 ′ Q′ Q 14 2 14 2 C 6.0V AB 10Ω I A A B 15 A −1.2 −0.80 −0.40 0.40 0.80 1.2 15 0.0 D xzy 2a xy O a A x I1 O I1 H I2 O I1 I2 A z O x y z 16 (0, H , H ) (H , 0, H ) (H , H , 0) ( 2H , , ) ( , 2H , ) ( , , 2H ) 16 E AB P Q CD P Q ABCD P Q I1 I2 17 P Q P Q P Q P Q 17 F A t B IA A B t IB B IB t 18 18 A −e A r v m m v2 e2 = k0 r r k0 nh mvr = − 2π v1 n = e v n h r n=1 v2 v1 v2 19 √ 2 √1 2 19 ... 12 m B S1 P0 P0 S2 P0 P1 P2 2.5m P2 340m/s Hz 11 Hz 17 0 340 680 11 13 60 C f a (< f ) b a b 12 b 12 A A B A C D E F B 13 13 B R1 R2 A B C D S1 S2 V S1 A Q A S1 Q S2 ′ Q′ Q 14 2 14 2 C 6.0V AB 10 Ω... P Q CD P Q ABCD P Q I1 I2 17 P Q P Q P Q P Q 17 F A t B IA A B t IB B IB t 18 18 A −e A r v m m v2 e2 = k0 r r k0 nh mvr = − 2π v1 n = e v n h r n =1 v2 v1 v2 19 √ 2 ? ?1 2 19 ... 10 Ω I A A B 15 A ? ?1. 2 −0.80 −0.40 0.40 0.80 1. 2 15 0.0 D xzy 2a xy O a A x I1 O I1 H I2 O I1 I2 A z O x y z 16 (0, H , H ) (H , 0, H ) (H , H , 0) ( 2H , , ) ( , 2H , ) ( , , 2H ) 16 E AB P Q