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Lecture Cost management: Measuring, monitoring, and motivating performance (2e): Chapter 2 - Eldenburg, Wolcott’s

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Chapter 2 - The cost function. The following will be discussed in this chapter: What are the different ways to describe cost behavior? What process is used to estimate future costs? How are engineered estimates, account analysis, and two-point methods used to estimate cost functions?...

Cost Management Measuring, Monitoring, and Motivating Performance Chapter The Cost Function © John Wiley & Sons, Chapter 2: The Cost Function Slide # Chapter 2: The Cost Function Learning objectives • Q1: What are the different ways to describe cost behavior? • Q2: What process is used to estimate future costs? • • • • Q3: How are engineered estimates, account analysis, and two-point methods used to estimate cost functions? Q4: How does a scatter plot assist with categorizing a cost? Q5: How is regression analysis used to estimate a cost function? Q6: How are cost estimates used in decision making? © John Wiley & Sons, Chapter 2: The Cost Function Slide # Q1: Different Ways to Describe Costs • • • Costs can be defined by how they relate to a cost object, which is defined as any thing or activity for which we measure costs Costs can also be categorized as to how they are used in decision making Costs can also be distinguished by the way they change as activity or volume levels change © John Wiley & Sons, Chapter 2: The Cost Function Slide # Q1: Assigning Costs to a Cost Object Determining the costs that should attach to a cost object is called cost assignment cost tracing Direct Costs Cost Object ngi ss At s o C Indirect Costs © John Wiley & Sons, Direct costs are easily traced to the cost object Indirect costs are not easily traced to the cost object, and must be allocated cost allocation Chapter 2: The Cost Function Slide # Q1: Direct and Indirect Costs • In manufacturing: • • • • all materials costs that are easily traced to the product are called direct material costs all labor costs that are easily traced to the product are called direct labor costs all other production costs are called overhead costs Whether or not a cost is a direct cost depends upon: • the definition of the cost object • the precision of the bookkeeping system that tracks costs • the technology available to capture cost information • • whether the benefits of tracking the cost as direct exceed the resources expended to track the cost the nature of the operations that produce the product or service © John Wiley & Sons, Chapter 2: The Cost Function Slide # Q1: Linear Cost Behavior Terminology • • • • • Total fixed costs are costs that not change (in total) as activity levels change Total variable costs are costs that increase (in total) in proportion to the increase in activity levels Total costs equal total fixed costs plus total variable costs The relevant range is the span of activity levels for which the cost behavior patterns hold A cost driver is a measure of activity or volume level; increases in a cost driver cause total costs to increase © John Wiley & Sons, Chapter 2: The Cost Function Slide # Q1: Behavior of Total (Linear) Costs $ Total Costs If costs are linear, then total costs graphically look like this Cost Driver $ Total Fixed Costs Total fixed costs not change as the cost driver increases Higher total fixed costs are higher above the x axis Cost Driver © John Wiley & Sons, Chapter 2: The Cost Function Slide # Q1: Behavior of Total (Linear) Costs $ Total Costs If costs are linear, then total costs graphically look like this Cost Driver $ Total Variable Costs Total variable costs increase as the cost driver increases A steeper slope represents higher variable costs per unit of the cost driver Cost Driver © John Wiley & Sons, Chapter 2: The Cost Function Slide # Q1: Total Versus Per­unit (Average) Cost Behavior $ Total Variable Costs slope = $m/unit If total variable costs look like this Cost Driver $/unit Per-Unit Variable Costs then variable costs per unit look like this m Cost Driver © John Wiley & Sons, Chapter 2: The Cost Function Slide # Q1: Total Versus Per­Unit (Average) Cost Behavior $ Total Fixed Costs If total fixed costs look like this Cost Driver $/unit Per-Unit Fixed Costs then fixed costs per unit look like this Cost Driver © John Wiley & Sons, Chapter 2: The Cost Function Slide # 10 Q5: Regression Output Terminology:  p­value and t­statistic • Statistical significance of regression coefficients • • When running a regression we are concerned about whether the “true” (unknown) coefficients are non-zero Did we get a non-zero intercept (or slope coefficient) in the regression output only because of the particular data set we used? © John Wiley & Sons, Chapter 2: The Cost Function Slide # 37 Q5: Regression Output Terminology:  p­value and t­statistic • The t-statistic and the p-value both measure our confidence that the true coefficient is non-zero • • In general, if the t-statistic for the intercept (slope) term > 2, we can be about 95% confident (at least) that the true intercept (slope) term is not zero The p-value is more precise • it tells us the probability that the true coefficient being estimated is zero • if the p-value is less than 5%, we are more than 95% confident that the true coefficient is non-zero © John Wiley & Sons, Chapter 2: The Cost Function Slide # 38 Q5: Interpreting Regression Output Suppose we had 16 observations of total costs and activity levels (measured in machine hours) for each total cost If we regressed the total costs against the machine hours, we would get Regression Statistics Multiple R 0.885 R Square 0.783 Adjusted R Square 0.768 Standard Error 135.3 Observations 16 Std Coefficients Error t Stat P-value Intercept 2937 64.59 45.47 1.31E-16 Machine Hours 5.215 0.734 7.109 5.26E-06 The coefficients give you the parameters of the estimated cost function Predicted total costs = Total fixed costs are estimated at $2,937 © John Wiley & Sons, $2,937 + ($5.215/mach hr) x (# of mach hrs) Variable costs per machine hour are estimated at $5.215 Chapter 2: The Cost Function Slide # 39 Q5: Interpreting Regression Output Regression Statistics Multiple R 0.885 R Square 0.783 Adjusted R Square 0.768 Standard Error 135.3 Observations 16 Std Coefficients Error t Stat P-value Intercept 2937 64.59 45.47 1.31E-16 Machine Hours 5.215 0.734 7.109 5.26E-06 The regression line explains 76.8% of the variation in the total cost observations (5.26E-06 means 5.26 x 10-6, or 0.00000526) © John Wiley & Sons, The high t-statistics and the low p-values on both of the regression parameters tell us that the intercept and the slope coefficient are “statistically significant” Chapter 2: The Cost Function Slide # 40 Q5: Regression Interpretation Example Carole’s Coffee asked you to help determine its cost function for its chain of coffee shops Carole gave you 16 observations of total monthly costs and the number of customers served in the month The data is presented below, and the a portion of the output from the regression you ran is presented on the next slide Help Carole interpret this output Costs Customers $5,100 1,600 $10,800 3,200 $7,300 4,800 $17,050 6,400 $9,900 8,000 $16,800 9,600 $29,400 11,200 $26,900 12,800 $20,000 14,400 $24,700 16,000 $30,800 17,600 $26,300 19,200 $39,600 20,800 $42,000 22,400 $32,000 24,000 $37,500 25,600 © John Wiley & Sons, Carole's Coffee - Total Monthly Costs $40,000 $35,000 $30,000 $25,000 $20,000 $15,000 $10,000 $5,000 Customers Served $0 5,000 10,000 Chapter 2: The Cost Function 15,000 20,000 25,000 Slide # 41 Q5: Regression Interpretation Example Regression Statistics Multiple R 0.91 R Square 0.8281 Std Adjusted R Square 0.8158 Coefficients Error t Stat P-value Standard Error 4985.6 Intercept 4634 2614 1.7723 0.0980879 Observations 16 Customers 1.388 0.169 8.2131 1.007E-06 What is Carole’s estimated cost function? In a store that serves 10,000 customers, what would you predict for the store’s total monthly costs? $4,634 +  ($1.388/customer) = $4,634 + ($1.388/customer) x 10,000 customers = $18,514 Predicted total costs = Predicted total costs at 10,000 customers © John Wiley & Sons, Chapter 2: The Cost Function x (# of customers) Slide # 42 Q5: Regression Interpretation Example Regression Statistics Multiple R 0.91 R Square 0.8281 Std Adjusted R Square 0.8158 Coefficients Error t Stat P-value Standard Error 4985.6 Intercept 4634 2614 1.7723 0.0980879 Observations 16 Customers 1.388 0.169 8.2131 1.007E-06 What is the explanatory power of this model? Are the coefficients statistically significant or not? What does this mean about the cost function? The model The slope coefficient is significantly explains 81.58% different from zero This means we of the variation in can be pretty sure that the true total costs, which cost function includes nonzero is pretty good variable costs per customer The intercept is not significantly different from zero There’s a 9.8% probability that the true fixed costs are zero* *(Some would say the intercept is significant as long as the p-value is less than 10%, rather than 5%.) © John Wiley & Sons, Chapter 2: The Cost Function Slide # 43 • Q6: Considerations When Using Estimates of Future Costs The future is always unknown, so there are uncertainties when estimating future costs • • • • The estimated cost function may have misspecified the cost behavior The cost function may be using an incorrect cost driver Future cost behavior may not mimic past cost behavior Future costs may be different from past costs © John Wiley & Sons, Chapter 2: The Cost Function Slide # 44 • • Q6: Considerations When Using Estimates of Future Costs The data used to estimate past costs may not be of high-quality • The accounting system may aggregate costs in a way that mis-specifies cost behavior • Information from outside the accounting system may not be accurate The true cost function may not be in agreement with the cost function assumptions • For example, if variable costs per unit of the cost driver are not constant over any reasonable range of activity, the linearity of total cost assumption is violated © John Wiley & Sons, Chapter 2: The Cost Function Slide # 45 Appendix 2A: Multiple Regression Example We have 10 observations of total project cost, the number of machine hours used by the projects, and the number of machine set-ups the projects used $10,000 $10,000 Total Costs $8,000 $8,000 $6,000 $6,000 $4,000 $4,000 $2,000 Number of Set-ups $0 Total Costs $2,000 Number of Machine Hours $0 © John Wiley & Sons, 10 20 30 40 50 60 70 80 90 Chapter 2: The Cost Function Slide # 46 Appendix 2A: Multiple Regression Example Regress total costs on the number of set-ups to get the following output and estimated cost function: Regression Statistics Multiple R 0.788 R Square 0.621 Std Adjusted R Square 0.574 Coefficients Error t Stat P-value Standard Error 1804 Intercept 2925.6 1284 2.278 0.0523 Observations 10 # of Set-ups 1225.4 338 3.62 0.0068 Predicted project costs = $2,926 +  ($1,225/set-up) x (# set-ups) The explanatory power is 57.4% The # of set-ups is significant, but the intercept is not significant if we use a 5% limit for the p-value © John Wiley & Sons, Chapter 2: The Cost Function Slide # 47 Appendix 2A: Multiple Regression Example Regress total costs on the number of machine hours to get the following output and estimated cost function: Regression Statistics Multiple R 0.814 R Square 0.663 Std Adjusted R Square 0.621 Coefficients Error t Stat P-value Standard Error 1701 Intercept -173.8 1909 -0.09 0.9297 Observations 10 # Mach Hrs 112.65 28.4 3.968 0.0041 Predicted project costs = - $173 +  ($113/mach hr) x (# mach hrs) The explanatory power is 62.1% The intercept shows up negative, which is impossible as total fixed costs can not be negative However, the p-value on the intercept tells us that there is a 93% probability that the true intercept is zero The # of machine hours is significant © John Wiley & Sons, Chapter 2: The Cost Function Slide # 48 Appendix 2A: Multiple Regression Example Regress total costs on the # of set ups and the # of machine hours to get the following: Regression Statistics Multiple R 0.959 R Square 0.919 Coefficients Adjusted R Square 0.896 Intercept -1132 Standard Error 891.8 # of Set-ups 857.4 Observations 10 # of Mach Hrs 82.31 Std Error t Stat P-value 1021 -1.11 0.3044 182.4 4.7 0.0022 16.23 5.072 0.0014 Predicted project = - $1,132 +  ($857/set-up) x (# set-ups) +  ($82/mach hr) x (# mach hrs) costs The explanatory power is now 89.6% The p-values on both slope coefficients show that both are significant Since the intercept is not significant, project costs can be estimated based on the project’s usage of set-ups and machine hours © John Wiley & Sons, Chapter 2: The Cost Function Slide # 49 Appendix 2B: What is a Learning Curve? A learning curve is • the rate at which labor hours per unit decrease as the volume of activity increases • the relationship between cumulative average hours per unit and the cumulative number of units produced A learning curve can be represented mathematically as: Y = α Xr, where Y = cumulative average labor hours, α = time required for the first unit, X = cumulative number of units produced, r = an index for learning = ln(% learning)/ln(2), and ln is the natural logarithmic function © John Wiley & Sons, Chapter 2: The Cost Function Slide # 50 Appendix 2B: Learning Curve Example Deanna’s Designer Desks just designed a new solid wood desk for executives The first desk took her workforce 55 labor hours to make, but she estimates that each desk will require 75% of the time of the prior desk (i.e “% learning” = 75%) Compute the cumulative average time to make desks, and draw a learning curve First compute r: r = ln(75%)/ln(2) = -0.2877/0.693 = -0.4152 Then compute the cumulative average time for desks: 60 Y = 55 x 7(-0.4152) = 25.42 hrs 40 Cumulative Average Hours Per Desk 50 30 In order to draw a learning curve, you must compute the value of Y for all X values from to Hrs per Desk 20 10 Cumulative Number of Desks © John Wiley & Sons, Chapter 2: The Cost Function Slide # 51 ... Intercept -1 1 32 Standard Error 891.8 # of Set-ups 857.4 Observations 10 # of Mach Hrs 82. 31 Std Error t Stat P-value 1 021 -1 .11 0.3044 1 82. 4 4.7 0.0 022 16 .23 5.0 72 0.0014 Predicted project = - $1,1 32. .. 0.0 523 Observations 10 # of Set-ups 122 5.4 338 3. 62 0.0068 Predicted project costs = $2, 926 +  ($1 ,22 5/set-up) x (# set-ups) The explanatory power is 57.4% The # of set-ups is significant, but the... $37 ,20 0 $20 ,800 $20 ,800 = F 3 ,20 0 © John Wiley & Sons, 6 ,20 0 Units Chapter 2: The Cost Function Slide # 25 Q3: High­Low Method of Estimating a? ?Cost? ?Function • The high-low method is a two-point

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