Solution Manual for Statics and Mechanics of Materials 5th Edition by Hibbeler © 2017 Pearson Education, Inc., Hoboken, NJ All rights reserved This material is protected under all copyright laws as they currently exist No portion of this material may be reproduced, in any form or by any means, without permission in writing from the publisher Full file at https://TestbankDirect.eu/ 1–1 What is the weight in newtons of an object that has a mass of (a) kg, (b) 0.04 kg, (c) 760 Mg? Solution Ans (a) W = 9.81(8) = 78.5 N (b) W = 9.81(0.04) ( 10 -3 ) = 3.92 ( 10 ) N = 0.392 mN -4 Ans (c) W = 9.81(760) ( 103 ) = 7.46 ( 106 ) N = 7.46 MN Ans Ans: 78.5 N 0.392 mN 7.46 MN Full file at https://TestbankDirect.eu/ Solution Manual for Statics and Mechanics of Materials 5th Edition by Hibbeler © 2017 Pearson Education, Inc., Hoboken, NJ All rights reserved This material is protected under all copyright laws as they currently exist No portion of this material may be reproduced, in any form or by any means, without permission in writing from the publisher Full file at https://TestbankDirect.eu/ 1–2 Represent each of the following combinations of units in the correct SI form using an appropriate prefix: (a) kN>ms, (b) Mg>mN, (c) MN>(kg # ms) Solution (a) kN>ms = 103N> ( 10 - ) s = GN>s (b) Mg>mN = 10 g>10 -3 Ans Ans N = Gg>N (c) MN>(kg # ms) = 106 N>kg(10 - s) = GN>(kg # s) Ans Ans: GN>s Gg>N GN>(kg # s) Full file at https://TestbankDirect.eu/ Solution Manual for Statics and Mechanics of Materials 5th Edition by Hibbeler © 2017 Pearson Education, Inc., Hoboken, NJ All rights reserved This material is protected under all copyright laws as they currently exist No portion of this material may be reproduced, in any form or by any means, without permission in writing from the publisher Full file at https://TestbankDirect.eu/ 1–3 Represent each of the following combinations of units in the correct SI form: (a) Mg>ms, (b) N>mm, (c) mN>(kg # ms) Solution Mg (a) ms 103 kg 10-3 s = 106 kg>s = Gg>s Ans N 1N = = 103 N>m = kN>m mm 10-3 m Ans mN 10-3 N = = kN>(kg # s) # (kg ms) 10-6 kg # s Ans (b) (c) = Ans: Gg>s kN>m kN>(kg # s) Full file at https://TestbankDirect.eu/ Solution Manual for Statics and Mechanics of Materials 5th Edition by Hibbeler © 2017 Pearson Education, Inc., Hoboken, NJ All rights reserved This material is protected under all copyright laws as they currently exist No portion of this material may be reproduced, in any form or by any means, without permission in writing from the publisher Full file at https://TestbankDirect.eu/ *1–4 lb>ft33 to to kN>m kN>m33, , Convert: (a) Convert: (a) 200 200 lb # ft to N # m, (b) 350 lb>ft (c) ft>h ft>htotomm>s mm>s.Express Expressthe theresult resulttotothree threesignificant significant figures Use Use an an appropriate appropriateprefix prefix SOLUTION (a) (200 lb # ft) ¢ 4.4482 N 0.3048 m ≤¢ ≤ = 271 N # m lb ft Ans (b) ¢ 350 lb ft 4.4482 N ≤ = 55.0 kN>m3 ≤ ¢ 0.3048 m ≤ ¢ lb ft Ans (c) ¢ ft 1h 0.3048 m ≤¢ ≤¢ ≤ = 0.677 mm>s 1h 3600 s ft Ans Ans: 271 N # m 55.0 kN>m3 0.677 mm>s Full file at https://TestbankDirect.eu/ Solution Manual for Statics and Mechanics of Materials 5th Edition by Hibbeler © 2017 Pearson Education, Inc., Hoboken, NJ All rights reserved This material is protected under all copyright laws as they currently exist No portion of this material may be reproduced, in any form or by any means, without permission in writing from the publisher Full file at https://TestbankDirect.eu/ 1–5 Represent each of the following as a number between 0.1 and 1000 using an appropriate prefix: (a) 45 320 kN, (b) 568(105) mm, (c) 0.00563 mg Solution (a) 45 320 kN = 45.3 MN Ans (b) 568 ( 105 ) mm = 56.8 km Ans (c) 0.00563 mg = 5.63 mg Ans Ans: 45.3 MN 56.8 km 5.63 mg Full file at https://TestbankDirect.eu/ Solution Manual for Statics and Mechanics of Materials 5th Edition by Hibbeler © 2017 Pearson Education, Inc., Hoboken, NJ All rights reserved This material is protected under all copyright laws as they currently exist No portion of this material may be reproduced, in any form or by any means, without permission in writing from the publisher Full file at https://TestbankDirect.eu/ 1–6 Round off the following numbers to three significant figures: (a) (a)5858342 342 68.534 (c) N, 2553 N, and m, m, (b) (b) 68.534 s, (c)s,2553 (d) 7555 kg (d) 7555 kg SOLUTION (a) 58.3 km (b) 68.5 s (c) 2.55 kN Ans (d) 7.56 Mg Ans: 58.3 km 68.5 s 2.55 kN 7.56 Mg Full file at https://TestbankDirect.eu/ Solution Manual for Statics and Mechanics of Materials 5th Edition by Hibbeler © 2017 Pearson Education, Inc., Hoboken, NJ All rights reserved This material is protected under all copyright laws as they currently exist No portion of this material may be reproduced, in any form or by any means, without permission in writing from the publisher Full file at https://TestbankDirect.eu/ 1–7 Represent each following quantities the correct Represent each ofof thethe following quantities in the in correct SI form kg, SI form using an prefix: appropriate prefix: 431 ) N, using an appropriate (a) 0.000 431 kg,(a) (b)0.000 35.3 (10 (b) 35.3(10 ) N, and (c) 0.005 32 km (c) 0.005 32 km SOLUTION (a) 0.000 431 kg = 0.000 431 A 103 B g = 0.431 g Ans (b) 35.3 A 103 B N = 35.3 kN Ans (c) 0.005 32 km = 0.005 32 A 103 B m = 5.32 m Ans Ans: 0.431 g 35.3 kN 5.32 m Full file at https://TestbankDirect.eu/ Solution Manual for Statics and Mechanics of Materials 5th Edition by Hibbeler © 2017 Pearson Education, Inc., Hoboken, NJ All rights reserved This material is protected under all copyright laws as they currently exist No portion of this material may be reproduced, in any form or by any means, without permission in writing from the publisher Full file at https://TestbankDirect.eu/ *1–8 Represent each eachofofthe thefollowing following combinations of units in Represent combinations of units in the the correct SI form using appropriateprefix: prefix:(a) (a) Mg>mm, Mg/mm, correct SI form using ananappropriate (b) mN>ms, (c) (c) mm mm ## Mg Mg SOLUTION (a) Mg>mm = (b) mN>ms = 103 kg -3 10 m 10 - N 10 - s = 106 kg = Gg>m m Ans = 103 N = kN>s s Ans (c) mm # Mg = C 10 -6 m D # C 103 kg D = (10)-3 m # kg = mm # kg Ans Ans: Gg>m kN>s mm # kg Full file at https://TestbankDirect.eu/ Solution Manual for Statics and Mechanics of Materials 5th Edition by Hibbeler © 2017 Pearson Education, Inc., Hoboken, NJ All rights reserved This material is protected under all copyright laws as they currently exist No portion of this material may be reproduced, in any form or by any means, without permission in writing from the publisher Full file at https://TestbankDirect.eu/ 1–9 Represent each of the following combinations of units in m>ms, the correct SI form using an an appropriate appropriate prefix: prefix: (a) (a) m>ms, (b) mkm, (c) (c) ks>mg, ks>mg, (d) andkm (d)# mN km # mN SOLUTION (a) m>ms = ¢ 11023 m m = ¢ ≤ = km>s -3 ≤ s 1102 s Ans (b) mkm = 1102-611023 m = 1102-3 m = mm (c) ks>mg = (d) km # mN = 11023 s 1102-6 kg 10 m = 10 11029 s kg -6 Ans = Gs>kg N = 10 -3 Ans m # N = mm # N Ans Ans: km>s mm Gs>kg mm # N Full file at https://TestbankDirect.eu/ Solution Manual for Statics and Mechanics of Materials 5th Edition by Hibbeler © 2017 Pearson Education, Inc., Hoboken, NJ All rights reserved This material is protected under all copyright laws as they currently exist No portion of this material may be reproduced, in any form or by any means, without permission in writing from the publisher Full file at https://TestbankDirect.eu/ 1–10 Represent each of the following combinations of units in the correct SI form using an appropriate prefix: (a) GN # mm, (b) kg>mm, (c) N>ks2, and (d) kN>ms Solution (a) GN # mm = 109 ( 10-6 ) N # m = kN # m (b) kg>mm = 10 g>10 -6 Ans Ans m = Gg>m (c) N>ks2 = N>106 s2 = 10-6 N>s2 = mN>s2 -6 Ans Ans (d) kN>ms = 10 N>10 s = 10 N>s = GN>s Ans: kN # m Gg>m mN>s2 GN>s Full file at https://TestbankDirect.eu/ 10 Solution Manual for Statics and Mechanics of Materials 5th Edition by Hibbeler © 2017 Pearson Education, Inc., Hoboken, NJ All rights reserved This material is protected under all copyright laws as they currently exist No portion of this material may be reproduced, in any form or by any means, without permission in writing from the publisher Full file at https://TestbankDirect.eu/ 1–11 Represent each of the following with SI units having an appropriate prefix: (a) 8653 ms, (b) 8368 N, (c) 0.893 kg SOLUTION (a) 8653 ms = 8.653(10)3(10 -3) s = 8.653 s Ans (b) 8368 N = 8.368 kN Ans (c) 0.893 kg = 893(10 -3)(103) g = 893 g Ans Ans: 8.653 s 8.368 kN 893 g Full file at https://TestbankDirect.eu/ 11 Solution Manual for Statics and Mechanics of Materials 5th Edition by Hibbeler © 2017 Pearson Education, Inc., Hoboken, NJ All rights reserved This material is protected under all copyright laws as they currently exist No portion of this material may be reproduced, in any form or by any means, without permission in writing from the publisher Full file at https://TestbankDirect.eu/ *1–12 Evaluate each of the following to three significant figures and express each answer in SI units using using an an appropriate appropriate prefix: prefix: (a) mm2>143 ms2, (b) (128 ms210.0458 Mm2>1348 mg2, (a) (1684 684 mm) 28 ms)(0.0458 Mm) > (43 ms), (b) > (348 mg), (c) (2.68 mm)(426 Mg) SOLUTION (a) (684 mm)>43 ms = 684(10 -6) m -3 43(10 ) s = 15.9 mm>s = 15.9(10-3) m s Ans (b) (28 ms)(0.0458 Mm)>(348 mg) = = C 28(10-3) s D C 45.8(10-3)(10)6 m D 348(10-3)(10-3) kg 3.69(106) m # s = 3.69 Mm # s>kg kg Ans (c) (2.68 mm)(426 Mg) = C 2.68 A 10-3 B m D C 426 A 103 B kg D = 1.14 A 103 B m # kg = 1.14 km # kg Ans Ans: 15.9 mm>s 3.69 Mm # s>kg 1.14 km # kg Full file at https://TestbankDirect.eu/ 12 Solution Manual for Statics and Mechanics of Materials 5th Edition by Hibbeler © 2017 Pearson Education, Inc., Hoboken, NJ All rights reserved This material is protected under all copyright laws as they currently exist No portion of this material may be reproduced, in any form or by any means, without permission in writing from the publisher Full file at https://TestbankDirect.eu/ 1–13 Convert each the the following to three figures: eachof of following to significant three significant 3 # ft 20tolb #Nft # m # m,450 (a) (b) to 3kN>m , and 20 lb(a) figures to, N (b)lb>ft to kN>m , 450 lb>ft (c) 15 ft > h to mm > s (c) 15 ft>h to mm>s SOLUTION Using Table 1–2, we have (a) 20 lb # ft = (20 lb # ft)a = 27.1 N # m (b) 450 lb>ft3 = a 4.448 N 0.3048 m ba b lb ft Ans kN ft3 450 lb 4.448 N ba ba ba b lb 1000 N 0.30483 m3 ft = 70.7 kN>m3 (c) 15 ft>h = a Ans 15 ft 304.8 mm 1h ba ba b = 1.27 mm>s 1h ft 3600 s Ans Ans: 27.1 N # m 70.7 kN>m3 1.27 mm>s Full file at https://TestbankDirect.eu/ 13 Solution Manual for Statics and Mechanics of Materials 5th Edition by Hibbeler © 2017 Pearson Education, Inc., Hoboken, NJ All rights reserved This material is protected under all copyright laws as they currently exist No portion of this material may be reproduced, in any form or by any means, without permission in writing from the publisher Full file at https://TestbankDirect.eu/ 1–14 Evaluate each of the following to three significant figures and express each answer in SI units using an appropriate prefix: (a) (212 mN)2, (b) (52 800 ms)2, (c) [548(106)]1>2 ms Solution (a) (212 mN)2 = 212(10)-3 N (b) (52 800 ms) = = 0.0449 N2 = 44.9(10)-3 N2 52 800(10) s = 2788 s = 2.79 ( 10 -3 2 )s (c) 548(10)6 ms = (23 409)(10)-3 s = 23.4(10)3(10)-3 s = 23.4 s Ans Ans Ans Ans: 44.9(10)-3 N2 2.79 ( 103 ) s2 23.4 s Full file at https://TestbankDirect.eu/ 14 Solution Manual for Statics and Mechanics of Materials 5th Edition by Hibbeler © 2017 Pearson Education, Inc., Hoboken, NJ All rights reserved This material is protected under all copyright laws as they currently exist No portion of this material may be reproduced, in any form or by any means, without permission in writing from the publisher Full file at https://TestbankDirect.eu/ 1–15 Using the SI system of units, show that Eq 1–2 is a dimensionally dimen sionally homogeneous equation which gives F in newtons Determine to three significant figures the gravitational force acting between two spheres that are The mass of each sphere is 200 kg and touching each other The the radius is 300 mm SOLUTION Using Eq 1–2, F = G N = a m m2 r2 kg # kg kg # m m3 2b a b = # kg s m s2 F = G (Q.E.D.) m m2 r2 = 66.73 A 10 - 12 B c 200(200) 0.62 d = 7.41 A 10 - B N = 7.41 mN Ans Ans: 7.41 mN Full file at https://TestbankDirect.eu/ 15 Solution Manual for Statics and Mechanics of Materials 5th Edition by Hibbeler © 2017 Pearson Education, Inc., Hoboken, NJ All rights reserved This material is protected under all copyright laws as they currently exist No portion of this material may be reproduced, in any form or by any means, without permission in writing from the publisher Full file at https://TestbankDirect.eu/ *1–16 small unit of pressure To The pascal pascal (Pa) (Pa) isisactually actuallya avery very small unit of pressure 2 22 show this,this, convert Atmospheric To show convert1 Pa Atmosphere Pa= =1 N>m N>m lb>ft totolb>ft 14.7lb>in lb> in22 .How Howmany manypascals pascalsisisthis? this? pressure at at sea sealevel levelisis14.7 pressure SOLUTION Using Table 1–2, we have Pa = lb 0.30482 m2 1N a b = 20.9 A 10 - B lb>ft2 b a m2 4.4482 N ft2 ATM = Ans 144 in2 14.7 lb 4.448 N ft2 b a a b a b lb in2 ft2 0.30482 m2 = 101.3 A 103 B N>m2 Ans = 101 kPa Ans: 20.9 10-3 lb>ft 101 kPa Full file at https://TestbankDirect.eu/ 16 Solution Manual for Statics and Mechanics of Materials 5th Edition by Hibbeler © 2017 Pearson Education, Inc., Hoboken, NJ All rights reserved This material is protected under all copyright laws as they currently exist No portion of this material may be reproduced, in any form or by any means, without permission in writing from the publisher Full file at https://TestbankDirect.eu/ 1–17 What is the weight in newtons of an object that has a mass (a) 10 (b)0.5 (c)(c) 4.50 10kg, kg,(b) 0.5g,g, of: (a) and 4.50Mg? Mg?Express Expressthe the result result to three significant figures Use an appropriate prefix SOLUTION (a) W = A 9.81 m>s2 B (10 kg) = 98.1 N Ans (b) W = A 9.81 m>s2 B (0.5 g)(10 - kg>g) = 4.90 mN Ans (c) W = A 9.81 m>s2 B (4.5 Mg) A 103 kg>Mg B = 44.1 kN Ans Ans: 98.1 N 4.90 mN 44.1 kN Full file at https://TestbankDirect.eu/ 17 Solution Manual for Statics and Mechanics of Materials 5th Edition by Hibbeler © 2017 Pearson Education, Inc., Hoboken, NJ All rights reserved This material is protected under all copyright laws as they currently exist No portion of this material may be reproduced, in any form or by any means, without permission in writing from the publisher Full file at https://TestbankDirect.eu/ 1–18 Evaluate of the to three to significant and Evaluate each each of following the following three figures significant express Sl units using in an SI appropriate prefix: figures each and answer expressineach answer units using an (a) 354 mg(45prefix: km) > (0.0356 kN),mg(45 (b) (0.004 53 Mg) (201kN), ms), appropriate (a) 354 km)>(0.0356 and (0.004 (c) 43553MN > 23.2 mm (b) Mg)(201 ms), (c) 435 MN>23.2 mm SOLUTION (a) (354 mg)(45 km)>(0.0356 kN) = = C 354 A 10-3 B g D C 45 A 103 B m D 0.0356 A 103 B N 0.447 A 103 B g # m N = 0.447 kg # m>N Ans (b) (0.00453 Mg)(201 ms) = C 4.53 A 10-3 B A 103 B kg D C 201 A 10-3 B s D = 0.911 kg # s (c) 435 MN>23.2 mm = 435 A 106 B N 23.2 A 10-3 B m = Ans 18.75 A 109 B N m = 18.8 GN>m Ans Ans: 0.447 kg # m>N 0.911 kg # s 18.8 GN>m Full file at https://TestbankDirect.eu/ 18 Solution Manual for Statics and Mechanics of Materials 5th Edition by Hibbeler © 2017 Pearson Education, Inc., Hoboken, NJ All rights reserved This material is protected under all copyright laws as they currently exist No portion of this material may be reproduced, in any form or by any means, without permission in writing from the publisher Full file at https://TestbankDirect.eu/ 1–19 A concrete column has a diameter of 350 mm and aa length length of m If If the the density density 1mass>volume2 (mass>volume) of concrete is 2.45 Mg>m33, determine the the weight weight of ofthe thecolumn columnininpounds pounds SOLUTION V = pr2h = p A 0.35 m B (2 m) = 0.1924 m m = rV = ¢ 2.45(103)kg m3 ≤ A 0.1924 m3 B = 471.44 kg W = mg = (471.44 kg) A 9.81 m>s2 B = 4.6248 A 103 B N W = C 4.6248 A 103 B N D ¢ lb ≤ = 1.04 kip 4.4482 N Ans Ans: 1.04 kip Full file at https://TestbankDirect.eu/ 19 Solution Manual for Statics and Mechanics of Materials 5th Edition by Hibbeler © 2017 Pearson Education, Inc., Hoboken, NJ All rights reserved This material is protected under all copyright laws as they currently exist No portion of this material may be reproduced, in any form or by any means, without permission in writing from the publisher Full file at https://TestbankDirect.eu/ *1–20 Two particles have a mass of kg and 12 kg, respectively If they are are800 800mm mm apart, determine the force of gravity apart, determine the force of gravity acting acting between them Compare thiswith result the of weight between them Compare this result thewith weight each of each particle particle SOLUTION F = G m1 m2 r2 Where G = 66.73 A 10-12 B m3>(kg # s2) F = 66.73 A 10 - 12 B B 8(12) (0.8)2 R = 10.0 A 10 - B N = 10.0 nN Ans W1 = 8(9.81) = 78.5 N Ans W2 = 12(9.81) = 118 N Ans Ans: F = 10.0 nN W1 = 78.5 N W2 = 1 N Full file at https://TestbankDirect.eu/ 20 Solution Manual for Statics and Mechanics of Materials 5th Edition by Hibbeler © 2017 Pearson Education, Inc., Hoboken, NJ All rights reserved This material is protected under all copyright laws as they currently exist No portion of this material may be reproduced, in any form or by any means, without permission in writing from the publisher Full file at https://TestbankDirect.eu/ 1–21 If a man man weighs weighs 155 lb on earth, earth, specify (a) his mass in slugs, (b) his in kilograms, (c) If histhe weight kilograms, andmass (b) his weight in nand ewtons man in is newtons If the mantheis acceleration on the moon, on the moon, where due towhere gravitythe is acceleration to gravity(c) is his gm = 5.30 ft>s , determine weight in 2pounds, and gm = 5.30 ft>sdue , determine (d) his mass weight in pounds, and (e) his mass in kilograms (d) his in kilograms SOLUTION (a) m = 155 c 14.59 kg d = 70.2 kg 32.2 Ans Ans (b) W = 15514.44822 = 689 N 5.30 d = 25.5 lb 32.2 Ans 14.59 kg d = 70.2 kg 32.2 Ans (c) W = 155c (d) m = 155 c Also, m = 25.5 14.59 kg 5.30 Ans = 70.2 kg Ans: 70.2 kg 689 N 25.5 lb m = 70.2 kg Full file at https://TestbankDirect.eu/ 21 .. .Solution Manual for Statics and Mechanics of Materials 5th Edition by Hibbeler © 2017 Pearson Education, Inc., Hoboken, NJ All rights... GN>s Gg>N GN>(kg # s) Full file at https://TestbankDirect.eu/ Solution Manual for Statics and Mechanics of Materials 5th Edition by Hibbeler © 2017 Pearson Education, Inc., Hoboken, NJ All rights... Gg>s kN>m kN>(kg # s) Full file at https://TestbankDirect.eu/ Solution Manual for Statics and Mechanics of Materials 5th Edition by Hibbeler © 2017 Pearson Education, Inc., Hoboken, NJ All rights