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ĐỀ THI THỬ ĐẠI HỌC MÔN VẬT LÍ NĂM 2012 Câu 1. ( ) = π !"#"#$%&#'( )*+#,*-+#. !/,01234! 5 6+# !07"#", '8449: !5;:234! 6<7"#"=>52?@4AB 5 ! 4!C D2 5 = 2 E2 5 F= 2 12 5 = 2 G2 5 F= Câu 2. 1#"HI6 JC 1 F5K L= µ M9;?NOE% DP 4 PE #*, 5F9 ; !Q R DE 2S'87)4!C D259;:2 E25;:2 125;;:2 G255;:2 Câu 3. ?"TU4 210 84 Po @A,H"!V!"T A Z X 216='W 7U44!XM5FK!2Y*#ZU4A<,4=# ; M21=% = Po m 209,9828u α =m 4,0015u = X m 205,9744u = 2 1u 931MeV / c − = 23 1 A N 6,02.10 mol 2[\4]'4< ,H"'A'W%4!C D2F^KF25; Y_`2 E2F5KF25; Y_`2 12FaKF25; Y_`2 G2FbKF25; Y_`2 Câu 4. ?"TU4 210 84 Po @A,H" cV!"T A Z X 21=% = Po m 209,9828u α =m 4,0015u = X m 205,9744u = 2 1u 931MeV / c − = 23 1 A N 6,02.10 mol 2*\7"Td4!C D2;aeY_`2 E2;beY_`2 12;5eY_`2 G2;^eY_`2 Câu 5.3_4_'(fg"0h@6\47Ai'H8=(@ 5F^ P _` = − R M5OOFj23_4_''Ai'Vhfg"0hM Ifg"0hM56Ai' ,=R, 5 λ 23_4_'Vhfg"0hMe Ifg"0hM6Ai',=R, λ 2 Y4AB 5 λ ! λ 4!C D2 5 F λ = λ 2 E2 5 9λ = λ 2 12 5 eλ = λ 2 G2 5 5bλ = λ Câu 6.?"T 5; Ke U@A6,H"c,H",*\7"c D24Rk*\7"T2 E2l,V]k=>*\7"T2 12=>*\7"T2 G2]k*\7"T2 Câu 7.1mTn2?f0Z4!C D2#*<'(!0Z%212S+#'(7#*<=W0Z%2 E2S+#'(7#4"%2G2X'I0Z_f#*=< o2 Câu 8.X'Ai'=pE4!' ; M9F25; q55 #2r#*'"pp7Ai'_4_'V *'Afg"0h,=p'M5F925; q5; #2sg",,Am4!fg"0hC D2.2 E2t2 12[2 G2Y Câu 9. Y*0T,0puM^;# fI R v; w'#*T23'h'xI E 25; X − = 2X'/f7 , Rx+#@h4nM;%0T,R7+#@ h E ur 2EV@hHAf0T4!C D2 9 5e25; e; − π ÷ Φ = π − y=2 E2 ( ) 9 525; e; − Φ = π y=2 12 9 5e25; e; − π ÷ Φ = π + y=2 G2 ( ) 9 525; e; − Φ = π +π y=2 Câu 10.Y*<V#0*I!0m_'/tH23<V#f 8'pT=>6*7,4!;#z23< V#,*5;#z67,,*4R4!e; F #z 2EA*0*7<V#4!C D29#2 E25;#2 G2e#2 G2K#2 Câu 11.Y*<fpp=>,=R,;5^{#6',=R,;eK{#2S+ i<7Q#f=>5;|<7Q#pp2XlBf !pp'Q#*+x4!C D2Fz92 E25z5;2 125z92 G2z92 Câu 12.Y*<V#0*Iw_k'6 H e F π = Hp=>#p=>23VhM;<V# f 8'p,4*HM}#4@;5"xV#C D2F;592 E2F;F52 12F;5^2 G2^;F52 E C L,R BA Câu 13.[%"#"&#*+#.#$% R'()M;b9: !-7&#* I,<* !'(''6'#",0wx*~2GQ&!V "#*/,01Me25; q^ L23p'A/"'8-"$/]&'&/ R*+#.!#*#"0*6'#",0*h-0 R6=>•25; q^ !x *0w-"=>^~2S'87'=>C D2;9:2 E2;b9:2 12;9:2 G2:22 Câu 14.Y*4\p7,,%fDMe ; 'p21%<74\p R] !p# 444!5^eF !5^K921%#*Q#€&#=@H"] !p# !#=A74\p_ k , R#!2S,"=(] !p#4,']#=A74\p4!C D2K • 2 E25; • 2 125 • 2 G25e • 2 Câu 15.Y* v0*I!,=A*=>e# !o=>;5mM;4!4n vf 8'pT=>_I 0k23+x$<V vh 8'p,4*H 5 M#% 8'pH Me#4!C D2 5 2 F; E2 5 2 e; 12 5 2 9; G2 5 2 ^; Câu 16. 1#"HI%).121*0T, 5 . = π ?/,012B "#" ( ) ;; 5;; = π `2X1V%/-"2S'8-"7%, 4!C D259;`2 E29;`2 125;;`2 G2;;`2 Câu 17.1%hR'p#*Q#'<€#*	!k$Cp# 4#]4/ !2Xk$#!4/4!4!#R R#T#'x23Vk$#! 4/4,'!p4!k$#!C D2p#4#]2 E2] !4#2 12] !2 G24#p#2 Câu 1823, I#* v0*Iw=V!T‚ D24-ƒ I0/4A v=%AIw_x2 E2*\7 v=%A!_x2 12`v7 v=%AIw_x2 G21k\7 v=%A!_x2 Câu 19.X-p#„ I Rk$#!4#f T'A#!2[% k$#!4#=>k$#! ! !I7p#BA62 D2+ T\4A2 E2+ T+#H2 12 8'p T'T#2 G2+ T2 Câu 20.U=V!T, I,h2 D2,h#TB#'x6,,V+H" !nH"2 E2u,h'I'T2 12u,h4!,A,l'I'<'$2 G2X',h60*7'x !7h'x"#*V#4& R2 Câu 21.Y"*(7#&##**0T+#,*-+#.M 9 5; ? F^• − !#*/H,0 1M1 ; … 9c 2X', c 4!,f7/H Y ;c c≤ ≤ 23Il=$,h,=R, † 5;# ≥ 23=$,, † ^;# = 6+H#*, c =>C D2^; ; 2 Eb; ; 2 12e; ; 2 G29; ; 2 Câu 22. ER,4!C D2fWx,'I'52 E2+B=/,,<2 12+BV#7,,4*=>(Q#*xV#2 G2+BV#7,<,Q0*2 Câu 23.X'A#R,&%DE#*"5#0* , R#R"', R=R5^#2Sm14!#*V#'A#RI& !'V#t7"DE#*+K#2 X'A"1tV#0* R&4!C D22 E2e2 12^2 G2K Câu 242Y*4$k"=(#*f+#4"4#M5=* !#*0T#+0!4M;# 0T,(0!†M25; }9 3 }5 214$0*'#*'xI7#*/‡,=+>#x *'xPMaK;;`z#2E]f#m# !4-+21MaK#z 2u,x\*A#5; ; 1 !'I p0kff+21o0*74$ R'R2pf7f74!C D225; }5; 12 E225; }5; 12 1225; }5; 12 G225; }5; 12 Câu 252[xf&&nA9;nˆx,xfV* R v M;KJ< x&"=>C D29n2 E2F;n2 12F^n2 G2e;n2 Câu 26.1#*4$kD0*'R##*4$7&&‰TEo0*74$‰T 4!214$E0*k4$D#*nA,B44$V*QI !'Q R ( 8'pT=>7n'QQ2s<4'QQ%%4!an9;T214$kD ,I0!5#2S'k-0"k4$k0*4!C D2aba#z 2 E2aKa#z 2 12aaF#z 2 G2aaa#z 2 Câu 27.X'A#*0T!&#+DE,I0!# RE-0,#*,0h R^n,2E%0 *70T4!9;?N2X*'I,'A0T4!C D2e#z2 E29#z2 12^#z2 G2K#z Câu 28.Y Š Š fT ‹ # Š # ‹ =A ‹ ‹ k ‹ 0 Š p ‹ Œ 0T • Š kT ‹ T ‹ 4T Œ ‹ Œ 0T • Š ‹ T ‹ 2Gk T ‹ A Š ‹ T ‹ = Š A ‹ # Š ‹ Œ 0T2Y ‹ H ‹ Š ‹ Œ 0TA ‹ A • fT ‹ A ‹ A# Œ Š ‹ T ‹ • Š Œ \ Š Œ T Œ Š ‹ T ‹ # Š A Š ‹ HA Œ ‹ ‹ ' Š A Š 0 Š • ' Œ 0 Œ A ‹ H ‹ Š Ž • ‹ A Š ‹ k • Š ‹ T ‹ A • k • Œ Š kT ‹ 2. ‹ T Œ Ž • ‹ A Š ‹ =\ Œ ;eF2ufT ‹ A# Œ Š ‹ T ‹ e Œ 0TŽ Œ Ž • ‹ A Š ‹ =\ Œ ;e92E • f# Š Ž ‹ '# ‹ =A ‹ ‹ 2A • k Š # ‹ =A ‹ ‹ ‹ 0 Š Š Š Œ • fT ‹ A# Œ fT Š ‹ T ‹ C D2e; Œ 0T2 E2Ke Œ 0T2 125;; Œ 0T2 G2^; Œ 0T2 GWf<e wA wf<A#4!Ke}eM^; Câu 292U4 5; Ke U 4!<,H" α "!"T ;^ K U= 216='W7 ;^ K U= 4!5e;!2XxV#Vl4 B4U= !U4!;K=>C D25;9!2 E25;e9!2 125;59!2 G25;b9!2 Câu 30.Y*4$4wH'A#‡>#wH€,#*8$ R v]# 5 2E B v# 5 " 8'p#!4wH=8ƒK# v]# ,4=>4 v# 5 'A#‡># ! R v# 5 2E€V v=$V*_k7'/4wH2E]f#m#2rxV#4wH ,I0!-"4A6+B v# 5 !# 4! D2e^#2 E2F#2 12F#2 G29b#2 Câu 31.\ Š A Š ‹ HA Œ ( ) 5;; = π Œ T Œ Š # Š #\ ‹ ‹ A ‹ Œ #A Š 'k • T Œ ) Š A Š ‹ A Š 01 Œ Š T Œ • # ‹ Š Š • #. • k Š 2A Œ Ž • .A • A Š ‹ A Š 0 Š T Œ Š • # Š ‹ ' Š Š Š Ž Œ T ‹ ‹ ' Š Š Š ‹ =\ Œ 5;;` Œ A Š ‹ A Š 0 Š T Œ Š A Š =\ Œ F^`2S ‹ ' Š • 4 Œ C D2K;`2 E25F^`2 12^e`2 G2eK`2 Câu 32. X'p# I R_„&'k$,=R, λ 5 M;9µ# λ M ;^µ#2E%_~T59##O#!_5#223+]<B T'Q4!C D2##2 E2F##2 12e##2 G29##2 Câu 33. = ω !#*/6x*0wf,,'80/4!~2X"xV# /4! !x*0wf,4!2?@4AB"44!C D2 5 ~ e + = 2 E2 5 ~ + = 2 12 ~ + = 2 G2 5 ~ + = 2 Câu 34.Xp* 7#*"_*2E%*\7"=>4\4l7,2 D2;a25; K #z2 E2;Ka25; K #z2 12;ea25; K #z2 G2;9a25; K #z2 Câu 35.Y*HIM ; • ; !• !"#"&#'()* +#,*-+#. !/,01#$% R1) •.23•M• 5 •M• 60/ B=+/,Q'823•M• ; 60/B=+/-"2?@4AB• 5 • • ; 4!C D2 ( ) ; 5 5 ω = ω + ω 2 E2 ( ) ; 5 5 ω = ω + ω 2 12 ; 5 ω = ω ω G2 ; 5 5 5 5 5 = + ÷ ω ω ω Câu 36. 1#").1#$% R.2?%(#"4! 5; 5;; = π ` ) F; = Ω e 5; 1 L − = π 21<A/7#"4!UM^;y2S'87.4!C D2^9^^#?2 E2^9^^#?2 12^9^^#?2 G2^9^^#?2 Câu 37. X'p# R_„;9###!+_#21%&x ,=R, λ = ;9µ# ! 5 λ M;^‘#23+$<B TQ#! R TpB2 4!C D25e##2 E25F##2 125##2 G255##2 Câu 38.?f!4!_4_'=8=@']<##4"C D2% !<##4"!#*Q#"T?_2 E21% !<##4"#*=@H"h,=R,p2 120w"f<##4"!2 G2<##4",=(#*&2 Câu 39.Y"0*.14p(-0*h23+xB44A%\4'x 'A/=>\4h'x'*0T4!C D2 X e 2 E2 X F 2 12 X 2 G2 X K 2 Câu 40.EV#tDEQ>#'A#*ix‡H<ht2X"t#*&V#,T#‡ R'#'x</T#2Y@x*T#"D4!^;0E"E4!;0E2Y@x*T#"' V#Y7"DE4!C D25F0E2 E2^0E2 12Fa0E2 90E Câu 41. 17#*%=!f4!#=>_,2DM9_`21% !_,=R, λ M;5K‘# 0wf=Ww~ = M;^e‘#2?%W#V0wf'A4!C D2}5e5`2 E2}5b5`2 12}5a5`2 G2}5^5`2 Câu 42.Y* v0*I! R=A*e#@#*+x5zeT6*\4"=>%\2 sWx]<#! v'+x5z^T4!C D2;5e#2 E2;5Fe#2 12;5ee#2 G2;59e#2 Câu 43.Y*4$k0*Iw R=A*,c ; "k,'m'x4!2E%4-\0T4R< =>5;44-\0T]<2S'87c ; 4!C D2FF ; 2 E2^^ ; 2 129^ ; 2 G2a^ ; 2 Câu 44.X'f "7Ai' "? β 4#@ R_4_'Vh D2fg"[ Ifg".E2fg"Y Ifg". 12fg"U Ifg".G2fg"t Ifg". Câu 45.Y"0*.1&##**0T,*-+#9;#? !/,09{L2[%#",'( 5; − Ω V0'60*'#" R%-"B=+/4!5`6+<#"!#*< '=6=>CD2b#y2 E2b{y2 12F^{y2 G2F^#y Câu 45. 30T&#[M9; wfI'h'xI,+#@hEM25; } X2`_k+#@h E ur , R'/f72Gp7#’ w0T4!uMe;;# 2EA*7<*+#@'4!P ; Me π ` M59^`21mxM;4n%7 !QI R E ur 2S'87<*+#@ (xV#M5ze;4!CD25a^`2 E25^`2 125b^`2 G259^`2 Câu 46. E#"=#p0Q+@C F e 5 5 5 ; G X ?_ + ® + 21# G M;5F^# X MF;5^ # ?_ Me;;59E%,5#4?_"!=%\<+7X[X4!e5“z2[\4]'kk R 4X[X4!D2ebee25; 5; 2 E2eee25; 5; 2 12eaee25; 5; 2 G2e^ee25; 5; 2 Câu 48.Y*"Td@A,H"c=%!"T„2Sm# 5 !# 5 3 5 !3 k@4!4 **\7"c !"T„2@!T4!nC D2 5 5 5 # 3 # 3 = = E2 5 5 5 # 3 # 3 = = 12 5 5 5 # 3 # 3 = = G2 5 5 5 # 3 # 3 = = Câu 49. 1"#").1#$%2X/,0 e 5; 1 L − = π 2'()M5;;Ω2"#" ,=V@ ( ) 5;; `= π 21*0T,*-+#.2Il.M. 6<7#"-" ! =>eKey2EV@0w'#"4!C D2 F55 5;; π = π + ÷ D2 E2 F555;; = π D2 12 F55 5;; π = π + ÷ D2 G2 F55 5;; = π D2 Câu 50.X'p#,'A#R&%DE0* RM5^?N2X"#*V#Y &DEB+0 5 MF;#0 M99#,,=A*-"2SBY !x''-,0W-" 2X*'I,'A#R4!=A2 D2 Me#z2 E2 Me#z2 12 MF^#z2 G2 MF^#z2 -------- HẾT ---------