C1 introduction to pe

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POWER ELECTRONICS

HCMC University of Technology and Education

Faculty for High Quality Training

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▪ Course title: Power Electronics▪ Course code: POEL330262

▪ Credit hours: 45 (45:0:125)

I Introduction to PE

2

▪ Prerequisites/ prior courses: Electrical Circuits,

Electronic Principles, Electrical Machines –Devices, Electrical Measurement

▪ Instructor: Nguyen Thoi, M.Eng.▪ Contact: Phone: 0982.612.805;

Email: thoinguyen@hcmute.edu.vn

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8 Design

6Chapters

Extra

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1 Basic Electronics: ➔ diode, transistor,

…op-amp; circuit: rectifiers, voltage regulator, biasing circuit, oscillator, feedback circuit, amplifiers,Comparator,….➔ low voltage, low current, low power, for controlling, generating signal to

control,…2 PowerElectronics: ➔ high power, high voltage/current, to transfer or control or switch on/of or conver the power : ac-dc, dc-dc, dc-

ac,…the high voltage/current for the power source to power loads directly

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POWER ELECTRONICS

CONVERTER

POWER SOURCE

2 What is Power Electronics?

-Convert electric power from one form to another using electronic devices, thereby controlling or modifying a voltage or current

-Applications: from high-power conversion equipment (milliwatts or Megawatts) such as DC

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CHAPTER 1 OVERVIEW

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CHAPTER 2 UNCONTROLLED RECTIFIERS

AC – DC CONVERTER

Input

- AC

- U1,f1= constant

Output

- DC

- U2= DC

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Some applications

DC Motor▪ Adapter

▪ Batterty Charger▪ DC Voltage source

Generator Exciter

8

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UPSWind energy

AC – DC -AC

VFD

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CHAPTER 3 CONTROLLED RECTIFIERS

AC – DC CONVERTER

Input

- AC

Output

- DC

- U2, = Variable

Controller

10

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CHAPTER 4 AC – AC CONVERTERS

AC – AC CONVERTER

Input

- AC

Output

- AC

- U2, f1= Variable

Controller

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FACTS

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TCSCI Introduction to PE

Applications

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CHAPTER 5 DC – DC CONVERTERS

DC – DC CONVERTER

Input

- DC- Uin

= constant

Output

- DC- U0

= Variable

16

Controller

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CHAPTER 5 DC – DC CONVERTERS

▪ Communication equipment, ▪ Cell phones and digital cameras,▪ Computer hardware circuits,

▪ Dental apparatus, ▪ Other industrial applications such as

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CHAPTER 6 INVERTER AND VFD

DC – AC CONVERTER

Input

- DC- Uin

= constant

Output

- AC- U0, f2

= Variable

Controller

18

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Inverter

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Wind energyAC – DC -ACSolar energy

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REFERENCES

[2] Fang Lin Luo, Hong Ye,

Power Electronics –Advanced Conversion Technologies, CRC Press

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Assessment

26

1 Formative assessment (F) (50%):- Class test (F1);

- Assignment (F2); Multi-choice, simulation Mid-term test (F3): Multiple choices, Essay

Grading: F = (F1 + F2 + F3 x 2)/4

2 Summative assessment (50%):- Final test: Multiple choices, Essay

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II AVERAGE VALUE

1 Average values of voltage and current

Average voltageA periodic instantaneous pulsed voltage waveform

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28

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A periodic instantaneous pulsed voltage waveform

Average voltage

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➔ Average value:

+=

=

Tt

tAV

d

0

dt)t(vT

1U

U

t [ms]50

vi(t) [V]

2050 60

The instantaneous voltageis expressed as:





=

ms30t

20,V0

ms20t

0,V50)

t(vi

➔ Average voltage:

V33,33V

V

dt0dt

5030

1V

V

dAVG

20

0

30

20d

AVG

==





+=

For V(t) with period time: T

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+=

=

Tt

tAV

d

0

dt)t(vT

1U

U

V33,13V

V

dt0tdt

230

1V

V

dAVG

20

0

30

20d

AVG

==





+=

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t [ms]50

=

Tt

tAV

d

0

dt)t(vT

1U

U

➔ Find average voltage?

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+=

=

Tt

tAV

d

0

dt)t(vT

1U

U

t [ms]40

vi(t) [V]

20

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34II AVERAGE VALUE

+=

=

Tt

tAV

d

0

dt)t(vT

1U

U

➔ Find average voltage?

t [ms]4

vi(t) [V]

9

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Break time: 19:50 - 20:05

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For sinusoidal waveform V() with period time: p



=

pp

AVd

0

d)(v1

UU

V8,31V

V

d0d

sin1002

1V

V

dAVG

0

2d

AVG

==





+

p

=

p

]rad[tWhere

]rad[2

]V[0

]rad[0

]V[sin

100)

(vi

w=

pp

p

=

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

=

pp

AVd

0

d)(v1

UU

100

0

 = wt [rad]vi() [V]

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average of p(t) over one or more periods.

Average power P is computed from

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2 Power value

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III RMS VALUE

V(t), period time: T

RMS value = Effective value:

+=

Tt

t

2RMS

0

dt)]

t(v[T

1U

t [ms]50

vi(t) [V]

Root Mean Square

V

dt0dt

)50(30

1V

RMS

=





+

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=

p

2p

RMS

0

d)](

v[1

d0d

)sin100(2

1V

RMS

0

22

RMS

=





+



p

]rad[tWhere

]rad[2

]V[0

]rad[0

]V[sin

100)

t(vi

w=

pp

p

=

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III POWER DIODE

Basic Structure

Symbol

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III POWER DIODE

Diodes in Industrial Applications

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DIODE Commutation Conditions:

The condition must be met before the Diode can be conducting :

▪ The DIODE must be forward biased (VA VK).

Diode

VKVA

III POWER DIODE

Operation

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III POWER DIODE

Operation: Forward Bias

VAK = VF = 0

Practical model: VFup to 1.25 V

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III POWER DIODE

Operation: Reverse Bias

A ID = 0 K

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III POWER DIODE

V-I Characteristic curve

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III POWER DIODE

DESIGN?

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52

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Water tank

Water flow

CB

2 B = Fully Open ➔ Water flow = 100%

3 B = Partially Open a% ➔C

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IV BJT

Basic Structure and Symbol: NPN

NPN

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BJT in Industrial Applications

IV BJT

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CE Configuration

IV BJT

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ICsat

amplification

IV BJT

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Switching operation: BJT as a switch

Practical model: VCEsat0.5 to 2.5 V

IV BJT

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IV BJT

5 V

SwitchSwitch

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Applications

IV BJT

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Protection

+VCC

IV BJT

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IV BJT

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- THYRISTOR

V SCR

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V SCR

Basic Structure and Symbol: PNPN

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SCR in Industrial Applications

V SCR

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SCR in Industrial Applications

V SCR

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Operation

SCR equivalent circuit

V SCR

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V SCR

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Operation: ON

V SCR

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SCR Commutation Conditions:

Two conditions must be met before the thyristor can be conducting :

▪ The thyristor must be forward biased (VA VK).

▪ A current must be applied to the gate of the

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ISCR Commutation Conditions:

72

And… Only one condition must be met before the thyristor can be switched off:

➔higher than the latched value

(holding current), irrespective of whether the thyristor is forward or reverse biased.

Operation: ON

V SCR

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SCR Commutation Conditions:

▪ VA  VK▪ IG > 0

SCR

VKVA

IG> 0

Operation: ON

V SCR

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Operation: OFF

V SCR

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V SCR

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Protection

+VCC

V SCR

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V SCR

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VI WHY YOU STUDY

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VI WHAT YOU WILL LOOK LIKE

T-shaped Engineer

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80VII 6 LEVELS OF COGNITION

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VIII LEARNING PYRAMID

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IX THE 4thINDUSTRIAL REVOLUTON

gg

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Phá vỡ trần thủy tinh

GIAI ĐOẠN 1Sản xuất đơn giản theo sự hướng dẫn của

nước ngoài

GIAI ĐOẠN 2Có công nghiệp hỗ trợ,

vẫn cần sự hướng dẫn của nước

ngoàiViệt NamThái lan-

Tích tụ

Hấp thụ công

nghệ

GIAI ĐOẠN 4Đầy đủ năng lực để sáng tạo

và thiết kế sản phẩm dẫn đầu trên thị trường

toàn cầuNhật bản-Mỹ-EUSáng tạo

Trần thủy tinh của Hàn Quốc

Đài LoanGIAI ĐOẠN 3

Nắm vững công nghệ và quản lý, có thể

sản xuất sản phẩm chất

lượng cao

Bản đồ nền công nghệ thế giới

X YOUR MISSION

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Tiêu đề	Introduction to PE
Người hướng dẫn	Nguyen Thoi, M.Eng.
Trường học	HCMC University of Technology and Education
Chuyên ngành	Power Electronics
Thể loại	Course Description

Định dạng
Số trang	84
Dung lượng	2,8 MB