Is 456 00 rc sl 001

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Software Verification PROGRAM NAME: REVISION NO.: SAFE EXAMPLE IS 456-00 RC-SL-001 Slab Flexural Design PROBLEM DESCRIPTION The purpose of this example is to verify slab flexural design in SAFE A one-way, simple-span slab supported by walls on two opposite edges is modeled using SAFE The slab is 150 mm thick spans meters between walls To ensure one-way action, Poisson’s ratio is taken to be zero The slab is modeled using thin plate elements The walls are modeled as line supports without rotational stiffnesses and with very large vertical stiffness (1 × 1015 kN/m) The computational model uses a finite element mesh, automatically generated by SAFE The maximum element size is specified as 1.0 meter To obtain factored moments and flexural reinforcement in a design strip, one onemeter-wide strip is defined in the X-direction on the slab, as shown in Figure Simply supported edge at wall Simply supported edge at wall m span Free edge m design strip Y X Free edge Figure Plan View of One-Way Slab One dead load case (DL4KPa) and one live load case (LL5KPa) with uniformly distributed surface loads of magnitudes and kN/m2, respectively, are defined in the model A load combination (COMB5kPa) is defined using the IS 456-00 load combination factors, 1.5 for dead loads and 1.5 for live loads The model is analyzed for both load cases and the load combination The slab moment on a strip of unit width is computed analytically The total factored strip moments are compared with the SAFE results After completing analysis, design was performed using the IS 456-00 code by SAFE and also by hand computation Table shows the comparison of the design reinforcements computed using the two methods EXAMPLE IS 456-00 RC-SL-001 - Software Verification PROGRAM NAME: REVISION NO.: SAFE GEOMETRY, PROPERTIES AND LOADING Thickness Depth of tensile reinf Effective depth Clear span T, h dc d ln, l1 = = = = 150 25 125 4000 mm mm mm mm Concrete strength Yield strength of steel Concrete unit weight Modulus of elasticity Modulus of elasticity Poisson’s ratio fc fsy wc Ec Es ν = = = = = = 30 460 25000 2x106 MPa MPa N/m3 MPa MPa Dead load Live load wd wl = = 4.0 kPa 5.0 kPa TECHNICAL FEATURES OF SAFE TESTED ¾ Calculation of flexural reinforcement ¾ Application of minimum flexural reinforcement RESULTS COMPARISON Table shows the comparison of the SAFE total factored moments in the design strip with the moments obtained by the hand computation method Table also shows the comparison of design reinforcements Table Comparison of Design Moments and Reinforcements Load Level Method Moment (kN-m) SAFE Calculated Reinforcement Area (sq-cm) As+ As- 26.997 5.831 27.000 5.818 Medium A +s ,min = 230.978 sq-mm COMPUTER FILE: IS 456-00 RC-SL-001.FDB CONCLUSION The SAFE results show a very close comparison with the independent results EXAMPLE IS 456-00 RC-SL-001 - Software Verification PROGRAM NAME: REVISION NO.: SAFE HAND CALCULATION The following quantities are computed for the load combination: γs = 1.15 γc = 1.50 α = 0.36 β = 0.42 b = 1000 mm For the load combination, w and M are calculated as follows: w = (1.5wd + 1.5wt) b wl12 M= As ,min = 0.85 bd fy = 230.978 sq-mm COMB100 wd = 4.0 kPa wt = 5.0 kPa w = 13.5 kN/m M = 27.0 kN-m xu ,max d ⎧0.53 ⎪ ⎪0.53 − 0.05 f y − 250 ⎪ 165 =⎨ ⎪0.48 − 0.02 f y − 415 ⎪ 85 ⎪ 46 ⎩ if f y ≤ 250 MPa if 250 < f y ≤ 415 MPa if 415 < f y ≤ 500 MPa if f y ≥ 500 MPa xu ,max = 0.466 d EXAMPLE IS 456-00 RC-SL-001 - Software Verification PROGRAM NAME: REVISION NO.: SAFE The depth of the compression block is given by: m= Mu bd 2αf ck = 0.16 x xu − − β m = 0.172497 < u ,max = d 2β d The area of tensile steel reinforcement is then given by: x ⎫ ⎧ z = d ⎨1 − β u ⎬ = 115.9439 mm d⎭ ⎩ As = Mu , = 582.178 sq-mm > As,min ( fy / γ s ) z As = 5.818 sq-cm EXAMPLE IS 456-00 RC-SL-001 -