... =0areS3,4 =1, n−moddS3,5 =1, n−meven (17 .4.32)At x =1we haveE 1, M +1 = y2,M−y3,M− c22(m +1) y 1, M (17 .4.33)E2,M +1 = y 1, M− γ (17 .4.34)ThusS 1, 4= −y3,M− c22(m +1) ,S 1, 5 =1, S 1, 6=−y 1, M2(m +1) (17 .4.35)S2,4 =1, S2,5=0,S2,6=0 ... µ (17 .4 .14 )Theny 1 = y2 (17 .4 .15 )y2= 1 1 − x22x(m +1) y2−(y3−c2x2)y 1 (17 .4 .16 )y3=0 (17 .4 .17 )780Chapter 17 . Two Point Boundary Value Problems Sample page from NUMERICAL ... interval 0 ≤ x ≤ 1. Foratotal of M mesh points, we haveh = 1 M − 1 (17 .4. 21) xk=(k 1) h, k =1, 2, ,M (17 .4.22)At interior points k =2,3, ,M, equation (17 .4 .15 ) givesE 1, k= y 1, k− y 1, k 1 −h2(y2,k+...