Tài liệu Open channel hydraulics for engineers Chapter 2 uniform flow docx

... 0.070 OPEN CHANNEL HYDRAULICS FOR ENGINEERS Chapter 2: UNIFORM FLOW 25 Chapter  UNIFORM FLOW 2. 1. Introduction 2. 2. Basic equations in uniform open- channel flow 2. 3. Most ... words, when: dP 0 dh  (2- 23) We know that P = b + 2h = A 2h h  (2- 24) h b OPEN CHANNEL HYDRAULICS FOR ENGINEERS Chapter 2: UN...

Ngày tải lên: 20/12/2013, 19:15

... amount: steady uniform flow steady non -uniform flow unsteady non -uniform flow 1 2 h +z Q 1 Q 2 x datum OPEN CHANNEL HYDRAULICS FOR ENGINEERS Chapter 7: UNSTEADY FLOW 136 Continuity: ...    OPEN CHANNEL HYDRAULICS FOR ENGINEERS Chapter 7: UNSTEADY FLOW 146 and 2 (tan )cos      (7-41) whence 2 s t tan x...

Ngày tải lên: 20/12/2013, 19:15

... L 2 L 3 T LT -1 LT -2 LT -2 T -1 L 3 T -1 LMT -2 ML 2 T -3 ML 2 T -2 ML -1 T -2 M ML -3 ML -2 T -2 ML -1 T -1 L 2 T 1 MT -2 ML -1 T -2 ML -1 T -2 OPEN CHANNEL ... Uniform flow in open channel Discharge through an open channel: RiACVAQ  (1-13) Q VA Q i L h OPEN CHANNEL HYDRAULICS FOR ENGINEERS...

Ngày tải lên: 20/12/2013, 19:15

... h 2 )(h 1 – h 2 ) = 2 1 2 1 2 2q (h h ) g.h h  h 1 + h 2 = 2 1 2 2q g.h h 2 2 2 1 2 1 2q h h h gh   or 2 2 2 1 2 1 2q h h h 0 gh    Solving the above quadratic equation for ... second  change of velocity F = 2 1 .q (V V ) g   (3-14) or 2 2 1 2 (h h ) 2   = 2 1 .q (V V ) g   2 2 1 2 (h h ) = 2 1 2 2 1 2 1 1 2...

Ngày tải lên: 20/12/2013, 19:15

... -10.06 1 .22 12. 737 0.947 2. 355 1.503 3.73E-03 3.84E-03 8 .24 E-03 -2. 898 - 12. 96 1 .24 12. 995 0.959 2. 309 1.5 12 3.52E-03 3.63E-03 8.87E-03 -3.377 -16.33 1 .26 13 .25 5 0.9 72 2 .26 3 1. 521 3.32E-03 3.42E-03 ... 2. 40E-03 2. 46E-03 1 .22 E- 02 -8.368 -57.97 1.4 15. 120 1.060 1.984 1.601 2. 28E-03 2. 34E-03 1 .26 E- 02 -9.430 -67.40 1. 42 15.393 1.073 1.949 1.614 2. 16E-03...

Ngày tải lên: 20/12/2013, 19:15

... 3 3 2 2 2 2 3 o o 2 c d V V2 2 q C 2g H C 2g.H 3 2g 2g 3                         (5-6) where the discharge coefficient: 3 3 2 2 2 2 o o d c V V C C 1 2gH 2gH    ... point such as C is equal to 2gh (Henderson, 1966), and the discharge q per unit width accordingly equal to: 2 o 2 o 3 3 V 2 2 2 2 H 2g o o V 2g V V2 2ghdh 2g H 3 2g 2g  ...

Ngày tải lên: 20/12/2013, 19:15

... flow (a) Pipe flow flow h 1 h 2 ? z 2 1 V 2g 2 2 V ? 2g  (b) Open channel flow OPEN CHANNEL HYDRAULICS FOR ENGINEERS Chapter 6: TRANSITIONS AND ENERGY DISSIPATORS 129 ... 1 c E y 2 c E h j c E h L c E h o c z h  c E h 0 2 2 4 4 6 6 8 8 10 10 12 12 14 14 OPEN CHANNEL HYDRAULICS FOR ENGINEERS Chapter 6:...

Ngày tải lên: 20/12/2013, 19:15

... uniform open channel flow 28 2. 2.1. Chezy’s formula 28 2. 2 .2. Manning’s formula 30 2. 2.3. Discussion of factors affecting f and n 32 2. 3. Most economical cross-section 32 OPEN CHANNEL HYDRAULICS ... 1.4. 12. Comparison of a distorted model and its prototype 23 Chapter 2: UNIFORM FLOW 25 2. 1. Introduction 25 2. 1.1. Definition 25 2. 1 .2. Momentum...

Ngày tải lên: 20/12/2013, 19:15

... result is shown in Figure 2- 6. Figure 2- 6. The source code window for the HelloWorld.cpp source code file 66 Chapter 2: BeIDE Projects Now that the relationship between the Chapter 1 SimpleApp example ... store it in the /boot/home folder—as I’ve done in Figure 2- 3. To Figure 2- 2. The window displayed by the HelloWorld program 46 Chapter 2: BeIDE Projects An application’s si...

Ngày tải lên: 26/01/2014, 07:20

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Ngày tải lên: 25/01/2014, 23:20