Tài liệu Integration of Functions part 6 pptx

Tài liệu Integration of Functions part 6 pptx

Tài liệu Integration of Functions part 6 pptx

... range of integration. { int j; float xr,xm,dx,s; static float x[]={0.0,0.1488743389,0.4333953941, The abscissas and weights. First value of each array not used. 0 .67 9409 568 2,0. 865 063 366 6,0.9739 065 285}; static ... used. 0 .67 9409 568 2,0. 865 063 366 6,0.9739 065 285}; static float w[]={0.0,0.2955242247,0. 269 266 7193, 0.2190 863 625,0.1494513491,0. 066 6713443}; xm=0.5*(b+a)...

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Tài liệu Integration of Functions part 7 pptx

Tài liệu Integration of Functions part 7 pptx

... ≡  y 2 (x) y 1 (x) G(x, y)dy (4 .6. 5) and finally our answer as an integral over H(x) I =  x 2 x 1 H(x)dx (4 .6. 6) In an implementation of equations (4 .6. 4)–(4 .6. 6), some basic one-dimensional integration routine ... shape of the boundary of the region of integration simple or complicated? Inside the region, is the integrand smooth and simple, or complicated, or locally str...

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Tài liệu Evaluation of Functions part 6 pptx

Tài liệu Evaluation of Functions part 6 pptx

... it will look (in part) like this: f(x)=··· +[y 8 −α(8,x)y 9 −β(9,x)y 10 ]F 8 (x) +[y 7 −α(7,x)y 8 −β(8,x)y 9 ]F 7 (x) +[y 6 −α (6, x)y 7 −β(7,x)y 8 ]F 6 (x) +[y 5 −α(5,x)y 6 −β (6, x)y 7 ]F 5 (x) +··· +[y 2 −α(2,x)y 3 −β(3,x)y 4 ]F 2 (x) +[y 1 −α(1,x)y 2 −β(2,x)y 3 ]F 1 (x) +[c 0 +β(1,x)y 2 −β(1,x)y 2 ]F 0 (x) (5.5.22) Notice ... 2 of The Art of Computer Programming (Reading, MA: A...

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Tài liệu Integration of Functions part 3 docx

Tài liệu Integration of Functions part 3 docx

... 1 36 Chapter 4. Integration of Functions Sample page from NUMERICAL RECIPES IN C: THE ART OF SCIENTIFIC COMPUTING (ISBN 0-521-43108-5) Copyright ... READING: Abramowitz, M., and Stegun, I.A. 1 964 , Handbook of Mathematical Functions , Applied Mathe- matics Series, Volume 55 (Washington: National Bureau of Standards; reprinted 1 968 by Dover Publications, New ... even values (o...

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Tài liệu Integration of Functions part 4 docx

Tài liệu Integration of Functions part 4 docx

... 140 Chapter 4. Integration of Functions Sample page from NUMERICAL RECIPES IN C: THE ART OF SCIENTIFIC COMPUTING (ISBN 0-521-43108-5) Copyright (C) ... North America). 4.3 Romberg Integration We can view Romberg’s method as the natural generalization of the routine qsimp in the last section to integration schemes that are of higher order than Simpson’s ... total number of st...

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Tài liệu Integration of Functions part 5 docx

Tài liệu Integration of Functions part 5 docx

... it,j; b=sqrt(bb-aa); a=0.0; if (n == 1) { The rest of the routine is exactly like midpnt and is omitted. 1 46 Chapter 4. Integration of Functions Sample page from NUMERICAL RECIPES IN C: THE ART OF SCIENTIFIC COMPUTING ... answer; answer=qromo(bessy0,0.0,2.0,midpnt); 144 Chapter 4. Integration of Functions Sample page from NUMERICAL RECIPES IN C: THE ART OF SCIENTIFIC COM...

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Tài liệu Evaluation of Functions part 3 pptx

Tài liệu Evaluation of Functions part 3 pptx

... I.A. 1 964 , Handbook of Mathematical Functions , Applied Mathe- matics Series, Volume 55 (Washington: National Bureau of Standards; reprinted 1 968 by Dover Publications, New York), § 3 .6. Mathews, ... 1970, Mathematical Methods of Physics , 2nd ed. (Reading, MA: W.A. Benjamin/Addison-Wesley), § 2.3. [2] 5.2 Evaluation of Continued Fractions Continued fractions are often powerful...

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Tài liệu Evaluation of Functions part 4 pptx

Tài liệu Evaluation of Functions part 4 pptx

... America). Thompson, I.J., and Barnett, A.R. 19 86, Journal of Computational Physics , vol. 64 , pp. 490–509. [5] Lentz, W.J. 19 76, Applied Optics , vol. 15, pp. 66 8 67 1. [6] Jones, W.B. 1973, in Pad´e Approximants ... the evaluation of the polynomial and nd of its derivatives simultaneously: void ddpoly(float c[], int nc, float x, float pd[], int nd) Given the nc+1 coefficients o...

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Tài liệu Evaluation of Functions part 10 pptx

Tài liệu Evaluation of Functions part 10 pptx

... degree of approximation (length of c to be used), this routine returns the array cint[0 n-1] ,the Chebyshev coefficients of the integral of the function whose coefficients are c . The constant of integration ... the constant of integration. fac = -fac; Will equal ±1. } cint[n-1]=con*c[n-2]/(n-1); Special case of (5.9.1) for n-1. sum += fac*cint[n-1]; cint[0]=2.0*sum; Set the con...

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Tài liệu Minimization or Maximization of Functions part 6 pptx

Tài liệu Minimization or Maximization of Functions part 6 pptx

... members of a set of vectors, they are said to be a conjugate set. If you do successive line minimization of a function along a conjugate set of directions, then you don’t need to redo any of those ... in your application,calculation of the gradient is out of the question. You might first think of this simple method: Take the unit vectors e 1 , e 2 , e N as a setofdirections.Usi...

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