Tài liệu Minimization or Maximization of Functions part 3 pdf

... prohibited. To order Numerical Recipes books,diskettes, or CDROMs visit website http://www.nr.com or call 1-800-872-74 23 (North America only), or send email to trade@cup.cam.ac.uk (outside North America). 1 4 2 3 parabola ... cycle. In the worst possible case, where the parabolic steps are acceptable but 404 Chapter 10. Minimization or Maximization of Functions Sample page...

Ngày tải lên: 15/12/2013, 04:15

... the form (10.8 .3) or (10.8.4), but rather only equality constraints of the form (10.8.5) and nonnegativity constraints of the form (10.8.2). 432 Chapter 10. Minimization or Maximization of Functions Sample ... x 4 , x 4 =8 +3  1 3 − 1 6 x 1 + 1 6 x 3  −4x 3 =9− 1 2 x 1 − 7 2 x 3 (10.8. 13) 430 Chapter 10. Minimization or Maximization of Functions Sam...

Ngày tải lên: 24/12/2013, 12:16

... a one-dimensional minimization sub-algorithm such as Brent’s method (see above). Storage is of order N 2 . There are two major families of algorithms for multidimensional minimization with calculation of first ... computation of first derivatives. • You must choose between methods that require storage of order N 2 and those that require only of order N,whereNis the number of d...

Ngày tải lên: 15/12/2013, 04:15

... minimum to an interval 39 8 Chapter 10. Minimization or Maximization of Functions Sample page from NUMERICAL RECIPES IN C: THE ART OF SCIENTIFIC COMPUTING (ISBN 0-521- 431 08-5) Copyright (C) 1988-1992 ... prohibited. To order Numerical Recipes books,diskettes, or CDROMs visit website http://www.nr.com or call 1-800-872-74 23 (North America only), or send email to trade@cu...

Ngày tải lên: 15/12/2013, 04:15

... consideration of multidimensional minimization, that is, finding the minimum of a function of more than one independent variable. This section stands apart from those which follow, however: All of the algorithms after ... prohibited. To order Numerical Recipes books,diskettes, or CDROMs visit website http://www.nr.com or call 1-800-872-74 23 (North America only), or send email...

Ngày tải lên: 15/12/2013, 04:15

... consideration of multidimensional minimization, that is, finding the minimum of a function of more than one independent variable. This section stands apart from those which follow, however: All of the algorithms after ... simplex method of linear programming, 412 Chapter 10. Minimization or Maximization of Functions Sample page from NUMERICAL RECIPES IN C: THE ART OF SC...

Ngày tải lên: 15/12/2013, 04:15

... a multidimensionalminimizationstrategy and a one-dimensional minimizationroutine results in some unnecessary copying of vectors hither and yon. That should not 420 Chapter 10. Minimization or Maximization of Functions Sample ... equivalent information content, of order N 2 numbers. In the direction set methods of §10.5, we collected the necessary information by making on the o...

Ngày tải lên: 15/12/2013, 04:15

... knowledge of the Hessian matrix A, nor even the storage necessary to store such a matrix. A sequence of directions h i is constructed, using only line minimizations, evaluations of the gradient vector, ... prohibited. To order Numerical Recipes books,diskettes, or CDROMs visit website http://www.nr.com or call 1-800-872-74 23 (North America only), or send email to trade@cup.cam.a...

Ngày tải lên: 24/12/2013, 12:16

... in the way that it stores 430 Chapter 10. Minimization or Maximization of Functions Sample page from NUMERICAL RECIPES IN C: THE ART OF SCIENTIFIC COMPUTING (ISBN 0-521- 431 08-5) Copyright (C) ... updates the information that is accumulated. Instead of requiring intermediate storage on the order of N, the number of dimensions, it requires a matrix of size N × N. General...

Ngày tải lên: 24/12/2013, 12:16

... back into iorder. iorder[j]=jorder[j]; 444 Chapter 10. Minimization or Maximization of Functions Sample page from NUMERICAL RECIPES IN C: THE ART OF SCIENTIFIC COMPUTING (ISBN 0-521- 431 08-5) Copyright ... ncity); jorder[nn++]=iorder[jj]; } for (j=1;j<=m3;j++) { Finally, the segment from n[6] to n [3] . jj=1 + ((j+n[6]-2) % ncity); jorder[nn++]=iorder[jj]; } for (j=1;j<=nci...

Ngày tải lên: 24/12/2013, 12:16