Tài liệu Target score chapter 05 pptx

... tension T, .N 1054 .2 0.01sin 2 )sm(9.80kg)0.90( sin 2 3 2      w T b) When the tension is at its maximum value, solving the above equation for the angle θ gives .01.1 N) 1050 .2(2 sm(9.80kg)(90.0 arcsin 2 arcsin 4 2                   T w  5.4: ... inward direction is upward. b) The forces on the ball are tension and gravity, so ,mamgT  N. 1051 sm80.9 sm4.64...

Ngày tải lên: 10/12/2013, 12:15

... HREF=” locationOrURL ” [NAME=” anchorName ”] [TARGET= ” windowName ”] [onClick=” handlerTextOrFunction ”] [onDblClick=” handlerTextOrFunction ”] [onMouseDown=” handlerTextOrFunction ”] 17 17 CHAPTER ✦ ✦ ✦ ✦ In This Chapter Scripting ... the target for a link. But, as with most transient object properties, the setting does not survive soft reloads. Rather than altering the target this...

Ngày tải lên: 10/12/2013, 15:15

... by Allan R. Hambley, ©2 005 Pearson Education, Inc. Chapter 1 Introduction ELECTRICAL ENGINEERING: PRINCIPLES AND APPLICATIONS, Third Edition, by Allan R. Hambley, ©2 005 Pearson Education, Inc. ELECTRICAL ... by Allan R. Hambley, ©2 005 Pearson Education, Inc. ELECTRICAL ENGINEERING: PRINCIPLES AND APPLICATIONS, Third Edition, by Allan R. Hambley, ©2 005 Pearson Education, Inc. Chapte...

Ngày tải lên: 13/12/2013, 06:15

... 9.1: a) .34.4rad60.0 m502 m50.1  . b) cm.27.6 )180rad)((128 cm)0.14(   π c) m.1.05rad)m)(0. 7050 .1(  9.2: a) s.rad199 s60 min1 rev rad2 min rev 1900                     π ... be 9.72hkm35  m s.rad652c) J.51.8)21(b) 2K 2  I mv 9.68: a) s.rad300.0)00.6)(srad(0.05b) .srad050.0 22 m0.60 sm00.3 2 tan  sαtα r a c) .sm5.40m)(60.0s)rad300.0( 222 rad ...

Ngày tải lên: 21/12/2013, 03:15

... m)1092.5)(248.01( 12  m,1045.4 12  y.248c) m.104.55m) 1050 .4)(010.01( 1212  T 12.36: a) m.1007.7 10 21  F mGm r b) From Eq. (12.19), using the result of part (a), days.121s1 005. 1 kg)1090.1)(kgmN10673.6( m)1007.7(2 7 302211 2310       T ... GM r T T r v 32 42   m100.3 2 km000,30 7   C Rr kg) 1056 .4)(kgNm1067.6( m)100.3(4 252211 37 2 m1000.2 2 8  ...

Ngày tải lên: 21/12/2013, 03:15

... J101.95)mPa)(0.6010150Pa 1050 0( 5333 2 1 W TnCU V  nR VpVp TTT nR VP T nR Vp T 1122 12 22 2 11 1 so,   ))(( 1122 VpVpRCU V  10015.5)]mPa)(0.8010150()mPa)(0.20 1050 0)[(315.885.20( 3333 U Then ... J.1095.1 3  19.49: a) T a = T c 19.50: a) mol.5.21 K)K)(40.0molJ07.29( J) 105. 2( 4     TC Q p n b) J.1079.1J) 105. 2( 4 29.07 20.76 4  P V C...

Ngày tải lên: 21/12/2013, 03:16

... so J.10400.0)m0300.0mPa)(0.01001000.2()(0 4335  daddacdca VVpWWW From (b), J. 105. 88J 105. 48J100.400so J,1048.5 444 C 4  QUU acca (d) The work is the area enclosed by the rectangular path abcd, J.8000J 105. 86J1068.6or ),)(( 44 CH  ... (the high-temperature reservoir) goes from 373 K to 273 K. J.106.2J104.19J 1057 .3Then J 1057 .3 so engine, theofo...

Ngày tải lên: 21/12/2013, 03:16

... entirety several times after the targets are met. 661 Chapter 31 ✦ Control Structures But in the labeled version, the inner loop breaks out of the outer loop when the targets are met. Far fewer lines ... to loop through two different index variables until both values equal the target values set outside the loop. When those targets are met, the entire nested loop construction should break...

Ngày tải lên: 21/12/2013, 05:17

... column-shifting actions on the binary (base-2) representations of two operands 32 32 CHAPTER ✦ ✦ ✦ ✦ In This Chapter Understanding operator categories Role of operators in script statements ✦ ✦ ... individual expressions and try them out by themselves, if you can. See additional debugging tips in Chapter 45. ✦ ✦ ✦ Note 667 Chapter 32 ✦ JavaScript Operators 10 == 10 // true 10 == 10.0...

Ngày tải lên: 21/12/2013, 05:17

... by Allan R. Hambley, ©2 005 Pearson Education, Inc. ELECTRICAL ENGINEERING: PRINCIPLES AND APPLICATIONS, Third Edition, by Allan R. Hambley, ©2 005 Pearson Education, Inc. Chapter 13 Bipolar Junction ... Third Edition, by Allan R. Hambley, ©2 005 Pearson Education, Inc. ELECTRICAL ENGINEERING: PRINCIPLES AND APPLICATIONS, Third Edition, by Allan R. Hambley, ©2 005 Pearson Education, Inc...

Ngày tải lên: 23/12/2013, 01:18