Interpolation and Extrapolation part 3
... started with R i = y i (3. 2.4) and with R ≡ [R i(i+1)...(i+m) with m = −1] = 0 (3. 2.5) Now, exactly as in equations (3. 1.4) and (3. 1.5) above, we can convert the recurrence (3. 2 .3) to one involving ... NJ: Prentice-Hall), § 6.2. Cuyt, A., and Wuytack, L. 1987, Nonlinear Methods in Numerical Analysis (Amsterdam: North- Holland), Chapter 3. 3. 3 Cubic Spline Interpolation Given...
Ngày tải lên: 17/10/2013, 22:15
Interpolation and Extrapolation part 4
... replacing (3. 3.1) by y = Ay j + By j+1 + Cy j + Dy j+1 (3. 3 .3) where A and B are defined in (3. 3.2) and C ≡ 1 6 (A 3 − A)(x j+1 − x j ) 2 D ≡ 1 6 (B 3 − B)(x j+1 − x j ) 2 (3. 3.4) Notice ... attention on one particular interval, between x j and x j+1 . Linear interpolation in that interval gives the interpolation formula y = Ay j + By j+1 (3. 3.1) 114 Chapter 3....
Ngày tải lên: 20/10/2013, 17:15
Interpolation and Extrapolation part 5
... see in Chapter 16, call 118 Chapter 3. Interpolation and Extrapolation Sample page from NUMERICAL RECIPES IN C: THE ART OF SCIENTIFIC COMPUTING (ISBN 0-521- 431 08-5) Copyright (C) 1988-1992 by ... call 1-800-872-74 23 (North America only),or send email to trade@cup.cam.ac.uk (outside North America). hunt phase bisection phase 1 710 8 14 22 32 38 32 1 (a) (b) 51 64 Figure 3....
Ngày tải lên: 20/10/2013, 17:15
Interpolation and Extrapolation part 6
... 120 Chapter 3. Interpolation and Extrapolation Sample page from NUMERICAL RECIPES IN C: THE ART OF SCIENTIFIC COMPUTING (ISBN 0-521- 431 08-5) Copyright (C) 1988-1992 by ... x N N · c 0 c 1 . . . c N = y 0 y 1 . . . y N (3. 5.2) This is a Vandermonde matrix, as described in §2.8. One could in principle solve equation (3. 5.2) by standa...
Ngày tải lên: 24/10/2013, 15:15
Interpolation and Extrapolation part 7
... 1,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0, 0,0,0,0,0,0,0,0,1,0,0,0,0,0,0,0, -3, 0,0 ,3, 0,0,0,0,-2,0,0,-1,0,0,0,0, 2,0,0,-2,0,0,0,0,1,0,0,1,0,0,0,0, 0,0,0,0,1,0,0,0,0,0,0,0,0,0,0,0, 0,0,0,0,0,0,0,0,0,0,0,0,1,0,0,0, 0,0,0,0, -3, 0,0 ,3, 0,0,0,0,-2,0,0,-1, 0,0,0,0,2,0,0,-2,0,0,0,0,1,0,0,1, -3, 3,0,0,-2,-1,0,0,0,0,0,0,0,0,0,0, 0,0,0,0,0,0,0,0, -3, 3,0,0,-2,-1,0,0, 9,-9,9,-9,6 ,3, -3, -6,6,-6, -3, 3,4,2,...
Ngày tải lên: 07/11/2013, 19:15
... otherwise takes on all positive and negative values. Any interpolation based on the values x =3. 13, 3. 14, 3. 15, 3. 16, will assuredly get a very wrong answer for the value x =3. 1416, even though a graph ... function f(x)=3x 2 + 1 π 4 ln (π − x) 2 +1 (3. 0.1) 105 106 Chapter 3. Interpolation and Extrapolation Sample page from NUMERICAL RECIPES IN C: THE ART OF SCIENTIFIC...
Ngày tải lên: 21/01/2014, 18:20
... right. For example, with N =4, x 1 : y 1 =P 1 P 12 x 2 : y 2 = P 2 P 1 23 P 23 P 1 234 x 3 : y 3 = P 3 P 234 P 34 x 4 : y 4 = P 4 (3. 1.2) Neville’s algorithm is a recursive way of filling in the numbers ... higher-orderpolynomials, up toP 1 23 N , which is the value of the unique interpolatingpolynomialthrough all N points, i.e., the desired answer. 3. 1 Polynomial Interpola...
Ngày tải lên: 26/01/2014, 15:20
Tài liệu Ielts preparationg and practice rading and writing part 3 docx
Ngày tải lên: 14/12/2013, 13:15
Tài liệu International Economics Theory and Policy Part 3 doc
Ngày tải lên: 14/12/2013, 15:15
Tài liệu Timing and Delay part 3 doc
... Negative input timing constraints can also be specified. 10 .3. 1 $setup and $hold Checks $setup and $hold tasks are used to check the setup and hold constraints for a sequential element in the design. ... converted to layout by a place and route tool. The post-layout delay values are computed from the resistance (R) and capacitance (C) information in the layout. The R and C...
Ngày tải lên: 15/12/2013, 03:15