... 0,02mol→mMg = 1, 3g • mHCl = 18 ,25 . 12 /10 0 = 2 ,19 g • → nHCl = m/M =2 ,19 /36,5 = 0,06 mol → 2x +2y = 0,06 →y = 0. 01 → ZnO = 0, 01 . 81 = 0. 81 g Vậy m = 0, 81 + 1, 3 = 2 ,11 g m ZnCl 2 = (x+y) .13 6 = 4,08 ... m ZnCl 2 = (x+y) .13 6 = 4,08 g m dd = mhh +mHCl – mH 2 = 2 ,11 + 12 – 0, 02 .2 = 14 ,15 g C% ZnCl 2 = 4,08 /14 ,15 .10 0 = 28 ,83% 3.5 2. 0 0 ,25 0 ,25 0,5 0,5 0,5 0,5 5.0 5.0 ... > Br >I • Pt: Cl 2 + 2 NaBr → 2NaCl + Br 2 Br 2 + 2 NaI → 2NaBr + I 2 0.5 0.5 0,5 3 3.0 1 . MnO 2 +4 HCl đđ → MnCl 2 + Cl 2 +2 H 2 O 2. FeCl 2 + Cl 2 → FeCl 3 (Cl 2 + Fe t → FeCl 3 ) 3....