Automotive mechanics (volume i)(part 1, chapter7) workshop safety

... Hickman and Reaves (20 03) Figure 2. 2—Number and Average Size of Local Police Departments and Number of Officers in 20 00 16 Protecting Emergency Responders Summary The large number of small emergency ... of Firefighters in 20 00 13 2. 2 Number and Average Size of Local Police Departments and Number of Officers in 20 00 15 2. 3 Number of Fire Department...

Ngày tải lên: 15/03/2014, 15:20

... New Trends and Developments in Automotive System Engineering Edited by Marcello Chiaberge Published by InTech Janeza Trdine 9, 510 00 Rijeka, Croatia Copyright © 2 011 InTech All chapters ... obtained from orders@intechweb.org New Trends and Developments in Automotive System Engineering, Edited by Marcello Chiaberge p cm ISBN 978-953-307- 517 -4 free online edit...

Ngày tải lên: 20/06/2014, 07:20

... publisher Engineering Mechanics - Statics Chapter a = ft b = ft x1 = 1. 5 ft x2 = 7.5 ft Solution: The maximum occurs when x = x2 ΣMA = 0; −F x2 + B x a = Bx = F x2 a B x = 1. 462 × 10 lb + → Σ ... publisher Engineering Mechanics - Statics Chapter Units Used: kN = 10 N Given: F = 500 N a = 0 .15 m L = 3m Solution: The initial guesses w1 = kN m w2 = kN m Given + ↑Σ Fy...

Ngày tải lên: 21/07/2014, 17:20

... publisher Engineering Mechanics - Statics w2 = 20 Chapter kN m a = 3m b = 3m c = 4.5 m Solution: (w2 − w1)c + w1 c + w1 b + FR = w1 a F R = 95 .6 kN MRo = − c c b (w2 − w1)c − w1 c − w1 b⎛c + ⎞ ... = 10 lb Given: w1 = 800 lb w2 = 500 lb ft ft a = 12 ft b = ft Solution: FR = a w1 + (w1 − w2)b + w2 b F R = 10 .65 kip a 1 b b F R x = − a w1 + ( w1 − w2 ) b + w2 b 2 x = a b b − a...

Ngày tải lên: 21/07/2014, 17:20

... publisher Engineering Mechanics - Statics Chapter Given: F = 40 N F = 40 N θ = deg r = 80 mm a = 300 mm θ = 45 deg Solution: F 1v ⎛0⎞ = F1 ⎜ ⎟ ⎜ ⎟ ⎝ 1 ⎠ F R = F1v + F2v ⎛ ⎞ F R = ⎜ − 28. 28 ⎟ N ⎜ ... kip = 10 lb Given: w = 80 0 lb ft a = 15 ft b = 15 ft θ = 30 deg Solution: FR = w a + FR x = w a wa x = a wb F R = 18 kip a wb⎛ b⎞ + ⎜a + ⎟ ⎝ 3⎠ + b⎞ ⎜a + ⎟ ⎝ 3⎠ wb⎛ FR x = 11...

Ngày tải lên: 21/07/2014, 17:20

... N r1 = 17 5 mm r2 = 17 5 mm Solution: ⎛ −F1 r1 ⎞ ⎛ −F2 2r2 cos ( θ ) ⎞ ⎜ ⎟ ⎜ ⎟ M = ⎜ ⎟ + ⎜ −F2 r2 sin ( θ ) ⎟ ⎜ ⎟ ⎜ ⎟ ⎝ ⎠ ⎝ ⎠ ⎛ 16 .63 ⎞ M = ⎜ 7. 58 ⎟ N⋅ m ⎜ ⎟ ⎝ ⎠ M = 18 .3 N⋅ m 280 © 20 07 R C Hibbeler ... writing from the publisher Engineering Mechanics - Statics Chapter Units Used: kN = 10 N Given: x = 1m ⎛6⎞ ⎜ ⎟ F = −2 kN ⎜ ⎟ 1 ⎛ ⎞ ⎜ ⎟ kN⋅ m MO = ⎜ ⎟ ⎝ 14 ⎠ Solution: y = 1...

Ngày tải lên: 21/07/2014, 17:20

... means, without permission in writing from the publisher Engineering Mechanics - Statics Chapter MRP = 11 65 lb⋅ in MRP = 1. 17 kip⋅ in Problem 4 -6 Determine the magnitude of the force F that should ... publisher Engineering Mechanics - Statics Chapter Units Used: kN = 10 N Given: a = 16 mm F = 2.30 kN θ = ( 60 80) Solution: MA ( θ ) = F ( a) cos ( θ deg) N.m 50 MA( θ...

Ngày tải lên: 21/07/2014, 17:20

... the publisher Engineering Mechanics - Statics ⎛ F1 ⎞ ⎜ ⎟ ⎜ F2 ⎟ = Find ( F1 , F2 , F3) ⎜F ⎟ ⎝ 3⎠ Chapter ⎛ F1 ⎞ ⎛ 5. 60 ⎞ ⎜ ⎟ ⎜ ⎟ ⎜ F2 ⎟ = ⎜ 8 .55 ⎟ kN ⎜ F ⎟ ⎝ 9.44 ⎠ ⎝ 3⎠ Problem 3-4 4 Determine ... permission in writing from the publisher Engineering Mechanics - Statics Chapter Units Used: kN = 10 N Given: F = 2 .5 kN a = 3m b = 1m c = 0. 75 m d = 1m e = 1. 5 m...

Ngày tải lên: 21/07/2014, 17:20

... means, without permission in writing from the publisher Engineering Mechanics - Statics Chapter θ = 44 .43 deg T = 10 7 . 14 N M = 15 .60 kg Problem 3-3 0 Prove Lami's theorem, which states that if three ... sin ( θ 3) ⎠ F 2v = F2 ⎜ ⎛ 4. 6 ⎞ ⎜ ⎟N ⎝ 10 4. 6 ⎠ F' = F1v + F3v F' = F R = F' + F2v FR = i = ⎛ 14 .8 ⎞ ⎜ ⎟N ⎝ 17 7 .1 ⎠ F 3v = F3 ⎜ 1 ⎜ ⎟ ⎝0⎠ j = ⎛0⎞ ⎜ ⎟ 1 F R = 17...

Ngày tải lên: 21/07/2014, 17:20

... ⎜d ⎟ ⎜ ⎟ ⎝ −e ⎠ F 1v = F1 F 2v = F2 F 3v = F3 ⎛ 282.4 ⎞ F 1v = ⎜ − 31 7 .6 ⎟ N ⎜ ⎟ ⎝ −4 23. 5 ⎠ rDC rDC ⎛ 230 .8 ⎞ F 2v = ⎜ 17 3 .1 ⎟ N ⎜ ⎟ ⎝ −277 ⎠ rDA rDA ⎛ 19 1.5 ⎞ F 3v = ⎜ 12 7.7 ⎟ N ⎜ ⎟ ⎝ −766.2 ... ⎛ 38 ⎞ F 1v = ⎜ 10 3. 8 ⎟ N ⎜ ⎟ ⎝ 10 1.4 ⎠ rAB rAB ⎛ 11 9.4 ⎞ F 2v = ⎜ 19 .9 ⎟ N ⎜ ⎟ ⎝ 15 9.2 ⎠ rAC rAC Add the forces and find the magnitude of the resultant F R = F1v + F2v ⎛ 15...

Ngày tải lên: 21/07/2014, 17:20

... ⎟ ⎝ 2z ⎠ ⎛ F2x ⎞ ⎜ ⎟ ⎜ F2y ⎟ = Find ( F2x , F2y , F2z) ⎜F ⎟ ⎝ 2z ⎠ ⎛ 17 .1 ⎞ ⎜ 8.7 ⎟ lb F2 = ⎜ ⎟ ⎝ 26 .2 ⎠ F = 32. 4 lb ⎛ 2 ⎞ ⎜ ⎟ ⎛ F2 ⎞ ⎜ β ⎟ = acos ⎜ ⎟ ⎝ F2 ⎠ ⎜γ ⎟ ⎝ 2 ⎛ α ⎞ ⎛ 12 1.8 ⎞ ⎜ ⎟ ⎜ ... ⎛ ⎞ ⎟ 2 ⎝ c +d ⎠ F 1x = F ⎜ F 1v = d ⎛ F1x ⎞ ⎜ ⎟ ⎝ F1y ⎠ F 2x = lb F 2v = ⎛ F2x ⎞ ⎜ ⎟ ⎝ F2y ⎠ ⎛ ⎞ ⎟ 2 ⎝ c +d ⎠ F 1y = F ⎜ F 1v = −c ⎛ 90 ⎞ ⎜ ⎟ lb ⎝ 12 0 ⎠ F 2y = −F F 2v = ⎛ ⎞ ⎜ ⎟ lb ⎝ 27...

Ngày tải lên: 21/07/2014, 17:20

... 93 95 96 97 98 10 0 10 2 10 4 10 5 11 1 11 4 11 6 11 6 11 8 11 9 12 0 12 3 12 5 12 7 13 0 13 5 13 7 14 2 14 4 14 4 14 5 14 9 15 2 15 4 15 8 16 0 16 1 16 3 Chapter Two-dimensional Fields of Limiting Stress 9 .1 9.2 9.3 9.4 ... Conversions for S.L Units Chapter 1. 1 1. 2 1. 3 1. 4 1. 5 1. 6 1. 7 1. 8 1. 9 Chapter 2 .1 2.2 2.3 2.4 2.5 2.6 2.7 2.8 2.9 2 .10...

Ngày tải lên: 07/08/2014, 04:21

... 10 8 94, 95 10 9, 11 0 96 11 1 97 11 2 98, 99 11 3, 11 4 Further literature 11 5 Glossary of technical items 11 6 Selection of automation components ... 10 1, 10 2 Sorting 88, 89 10 3, 10 4 Stopping 90, 91 10 5, 10 6 Tensioning Testing Transferring Transporting Turning Unloading 92 10 7 93 10 8 94, 95 10 9, ... 13 Aligning 01, 02 15 , 16 Assembly 03 to 08 17 to 22...

Ngày tải lên: 08/08/2014, 11:21