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... between sa al su aal la la naba amm baa id imaara alam ayyad and : to ask question to shine news or perished emirate pain to support saal suaal lala naba amm baaid imaara alam ayyad to ... Student : masaa il-kheer Jamiila masaa in-nuur Kamaal shloona Mahmuud? huwwa zeen, il-hamdu lilaah wi-shloonha Basma? hiyya tabaana ween hiyya? hiyya bil-beet ma a s-salaama ma a s-salaama...
Ngày tải lên: 03/04/2014, 12:52
A textbook of Computer Based Numerical and Statiscal Techniques part 62 docx
... 598 COMPUTER BASED NUMERICAL AND STATISTICAL TECHNIQUES Enter the value of y2 – 392 Enter the value of y3 – 1452 Enter the value of y4 – 2366 Enter the value of y5 – 5202 Enter the value of x ... of the program and start of section func 599 600 COMPUTER BASED NUMERICAL AND STATISTICAL TECHNIQUES Step 13 temp = 1/ (1+(x * x)) Step 14 Return temp Step 15 End...
Ngày tải lên: 04/07/2014, 15:20
A textbook of Computer Based Numerical and Statiscal Techniques part 1 ppt
... Daryaganj, New Delhi - 11 0002 Visit us at www.newagepublishers.com Preface The present book Computer Based Numerical and Statistical Techniques is primarily written according to the unified syllabus ... understand the subject A unique feature of this book is to provide with an algorithm and computer program in Clanguage to understand the steps and methodology used in writi...
Ngày tải lên: 04/07/2014, 15:20
A textbook of Computer Based Numerical and Statiscal Techniques part 2 ppsx
... numerical answer can be obtained even when a problem has no analytical solution However, result from numerical analysis is an approximation, in general, which can be made as accurate as desired ... 0 .28 5714 a quotient which is a nonterminating decimal fraction For using such a number in practical computation, it is to COMPUTER BASED NUMERICAL AND STATISTICAL TECHNIQUES...
Ngày tải lên: 04/07/2014, 15:20
A textbook of Computer Based Numerical and Statiscal Techniques part 3 ppsx
... approximation True value x = = 0 .33 333 When approximate value x′ is 0 .30 the Absolute Error is given by: Ea = x − x ′ = 0 .33 333 − 0 .30 = 0. 033 33 COMPUTER BASED NUMERICAL AND STATISTICAL TECHNIQUES ... Approximate value (x′) = 0 .33 3 Therefore, Absolute Error, Ea = x − x′ = Relative Error, Er = , then find its absolute, relative and percentage − 0 .33 3 = 0 .33 333 3 − 0...
Ngày tải lên: 04/07/2014, 15:20
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