... algorithms are applied to a non-linear optimal control problem of an optimal financing model, which was original introduced by Davis and Elzinga [22, 1970] In that paper, Davis and Elzinga had an analytical ... necessary to complete the research agenda Optimal control models have applications to a wide range of different areas in finance: optimal portfolio choice, opti...
Ngày tải lên: 08/05/2014, 10:01
... residual data set the ML-PDA algorithm is applied and the resulting track estimate validated If a new target is validated, its associated measurements are also edited out to form a new residual data ... frames of data, track estimates separated by fewer than Nw frames are correlated in that they use common data frame(s) EURASIP Journal on Advances in Signal Processing Table 3: Sce...
Ngày tải lên: 22/06/2014, 19:20
Electromagnetic Field Theory: A Problem Solving Approach Part 75 pdf
... +Ax(VxB)+Bx(VxA) V (fA)= fV A+ (A - V)f V * (A x B)= B (V x A) -A -(V x B) v x (A x B) = A( V B) - B(V - A) +(B V )A- (A - V)B Vx(fA)= VfxA+fVxA (V x A) x A = (A V )A - 'V (A A) Vx (Vx A) = V(V - A) - V A INTEGRAL ... Cartesian (rectangular) coordinates, 260 cylindrical coordinates, 271 and magnetic scalar potential, 365 spherical coordinates, 284 Laplacian of reciprocal d...
Ngày tải lên: 03/07/2014, 02:20
Electromagnetic Field Theory: A Problem Solving Approach Part 1 ppsx
... CartesianCoordinates(x, y, z) af af Vf = - , + O i, + af i, ax Oz ay aA, aA, + aA, V A= a+ ax az ay (LAX, A AaA\ ay z V2f a' +f Ox jy + az a, O aA ax Ox ay a' f az CylindricalCoordinates ... •af4 + af r04 az Vf = arr 1a iA, aA, rr rr a Oz V *A= - -(rAr)+M +M I a BA, rr) r V~ f la0 af\ r- rr aA 82f + I(rAs) ar 'L ,+ a2 f ae+I r •O af If -14 r sin aO A (r a( sin OAo) oA* V" -A...
Ngày tải lên: 03/07/2014, 02:20
Electromagnetic Field Theory: A Problem Solving Approach Part 3 pot
... 9 .3 POINT DIPOLE ARRAYS 9 .3. 1 A Simple Two Element Array (a) BroadsideArray (b) End-fireArray (c) ArbitraryCurrentPhase 9 .3. 2 An N DipoleArray 9.4 LONG DIPOLEANTENNAS 9.4.1 FarFieldSolution 9.4.2 ... Voltage 8.2 .3 Approach to the dc Steady State 8.2.4 Inductors and Capacitorsas Quasi-static Approximations to Transmission Lines 8.2.5 Reflections from Arbitrary Terminations 8 .3 SI...
Ngày tải lên: 03/07/2014, 02:20
Electromagnetic Field Theory: A Problem Solving Approach Part 4 potx
... proportional to its magnitude The vector A = A~ i +A, i, +Ai, in Figure 1 -4 has magnitude A= IA = [A +A +AI Note that each of the components in (1) (A. , A, , and A, ) are themselves scalars The direction ... by the _AY A = A I IAI =A = (A Figure 1 -4 directions + Ayly+ AI1, +A +A. ]' A vector is described by its components along the three coordinate Vector Algebra scalar I...
Ngày tải lên: 03/07/2014, 02:20
Electromagnetic Field Theory: A Problem Solving Approach Part 5 ppsx
... infinitesimally small, each of the bracketed terms defines a partial derivative aA 3A ýAMz lim ( = + + AV (4) ax-o \ax ay az where AV = Ax Ay Az is the volume enclosed by the surface S The coefficient ... of AV in (4) is a scalar and is called the divergence of A It can be recognized as the dot product between the vector del operator of Section 1-3-1 and the vector A: aAx aA, + aA, di...
Ngày tải lên: 03/07/2014, 02:20
Electromagnetic Field Theory: A Problem Solving Approach Part 6 pdf
... and the vector A This operation is called the curl of A and it is also a vector: i, a i, ax ay az A curl A= Vx A= det i, A, A, _A, A * (a ay az ) tA• + aA) aA, aAM\ az ax aAz•x (6) The cyclical ... yield A - dl (Vx A) , = lim Ar-O rAr AO =C - rr aA\ - (rA) 84 (14) ) The curl of a vector in cylindrical coordinates is thus VxA= IM (A, aA r a4 az aA )ir+ (A = az + aA A...
Ngày tải lên: 03/07/2014, 02:20
Electromagnetic Field Theory: A Problem Solving Approach Part 7 docx
... (VxA) a, aA, aA, \ a aA az / y az -ax\y xaA, a2 A -\xay avax , aA, aA) a aA, aA\ ax I az\ ax ay / A a2 A, a2 Ax \ayaz azay) \azax ax(z ( where again the order of differentiation does not matter PROBLEMS ... +,( af ayaz azay 2f) a/ + i(.I2- azax axaz af).0 axay ayax) (28) Each bracketed term in (28) is zero because the order of differentiation does not matter (b) The Divergence of...
Ngày tải lên: 03/07/2014, 02:20
Electromagnetic Field Theory: A Problem Solving Approach Part 8 pdf
... Vx(AxB) =A( V B)-B(V A) +(B.V )A- (A Problems 47 (f) Vx(fA)=VfxA+fVxA (g) (VxA)xA= (A- V)AV (A. A) (h) Vx(VxA)=V(V -A) -V A 25 Two points have Cartesian coordinates (1, 2, - 1) and (2, -3, 1) (a) What is ... (al A charged rod near a neutral ball will induce an opposite charge on the near surface Since the ball is initially neutral, an equal amount of positive charge remains on the far...
Ngày tải lên: 03/07/2014, 02:20
Electromagnetic Field Theory: A Problem Solving Approach Part 9 pdf
... 2-8 Two equal magnitude point charges are a distance a apart along the z axis (a) When the charges are of the same polarity, the electric field due to each is radially directed away In the z ... show that particular field components are zero The distance rQp is always positive In taking square roots, always make sure that the positive square root is taken The solution to a particula...
Ngày tải lên: 03/07/2014, 02:20
Electromagnetic Field Theory: A Problem Solving Approach Part 10 ppsx
... elements 180* apart have z components that add but radial components that cancel The z-directed electric field along the z axis is then E f2w Aoa d4 cos Aoaz (14) 2 E2= 47rEo(z +a ) 2eo (a +Z2 The ... being the same as for a Charge Distributions 69 surface charged sheet with the same total charge per unit area, 0o = po 2a At the boundaries y = a, the field is continuous, changing lin...
Ngày tải lên: 03/07/2014, 02:20
Electromagnetic Field Theory: A Problem Solving Approach Part 11 potx
... symmetrically located charge elements at -0 have equal field magnitude components that add radially but cancel in the direction Realizing from the symmetry that the electric field is purely radial and ... called a Faraday cage, after Faraday's measurements of actually climbing into a closed hollow conducting body charged on its surface to verify the zero field results To appreciate...
Ngày tải lên: 03/07/2014, 02:20
Electromagnetic Field Theory: A Problem Solving Approach Part 13 pot
... of differing radii R and R having their centers a distance D apart as in Figure 2-26 We place a line charge A a distance b, from the center of cylinder and a line charge -A a distance b2 from ... The total charge per unit length on the plane is obtained by integrating (9) over the whole plane: a( x=0) dy ATr= Aa +00 dy r JI- y' +a2 = _,y I +0 Aa - tanir a a -0o = -A (10) and just...
Ngày tải lên: 03/07/2014, 02:20