... aa2 -a a+ aa -a2 +a+ a > 0, which is a consequence of aa( a - a) + (1 + a) a ( + a) a > a2 - a Hence we can replace x, and a by a - and (3, repeating this transformation until cases or apply Another ... the easily proved identity a ( a - b ) - (b + II)” (a+ llEemb< = oP (b+l)k bk as well as to the operator formula a - b = (4 + a) - (4 + b) Similarly, we have al ,a2 ,a3 , (al - a2 1 F = alF am ... express F(al , , , a, ,,; bl , , b,; z) as a linear combination of F( a2 + j, a3 , , a, ,,; b2, , b,; z) for j d, thereby eliminating an upper parameter and a lower parameter Thus, for example,...