... 65 -5 , -3 , -3 , -1 , -3 , -1 , -1 72 73 -3 , -1 ,-1 2, 2, 76 -3 , -1 , -1 77 -1 78 1, 1, -1 81 -3 , -1 , -1 1, 1, 84 -1 85 -1 1, 1, 3, 1, 3, 3, 86 1, 1, -4 , -2 , -2 89 -1 90 1, 1, 3, 1, 3, 3, -2 97 -3 , -1 , ... A1B0-B1A0=q0q1+r1-q0q1=r1 AmBm-1-BmAm-1=( qmAm-1+rmAm-2)Bm- 1-( qmBm-1+rmBm-2)Am-1= -rm(Am-1Bm-2-Bm-1Am-2) By repeating this calculation with m-1, m-2, …, in place of m, we arrive at AmBm-1-BmAm-1= …= (A1B0-B1A0) (-1 )m-1 ... …2 … 12 -1 1 -9 -9 -7 -9 -7 -7 -5 -9 -7 -7 -5 -7 -5 -5 -3 … 4001 4160 References: M Bencze, Smarandache Relationships and Subsequences, Smarandache Notions Journal Vol 11, No 1-2 -3 , pgs 7 9-8 5 44...