A textbook of Computer Based Numerical and Statiscal Techniques part 5 ppsx
... 0. 454 5e1, c = 0. 453 5e1 then (b – c) = 0.0010e1 = 0.1000e – l a( b – c) = (0 .55 55e1) × (0.1000e – 1) = (0. 055 5e0) = 0 .55 50e – ab = (0 .55 55e1) × (0. 454 5e1) = 0. 252 4e2 ac = (0 .55 55e1) × (0. 453 5e1) ... the normalized floating-point representation the associative and the distributive laws of arithmetic are not always valid The example given below proves the above statement...
Ngày tải lên: 04/07/2014, 15:20
A–Z of Haematology - part 5 potx
... locus) -2 -L-fucosyltransferase (encoded by Se at FUT2 locus) Lea H type -3 -N-acetyl-Dgalactosaminyltransferase (encoded by A at ABO locus) -3 /4-L-fucosyltransferase Leb A type -3 /4-L-fucosyltransferase ... mutation of which explains 65 70% of cases of Fanconi’s anaemia FANCC a gene at 9q22.3, mutation of which explains 10– 15% of cases of Fanconi’s anaemia FANCD2 a clo...
Ngày tải lên: 10/08/2014, 08:20