A numerical study of heat and mass transfer in porous fluid coupled domains

... Ochoa-Tapia and Whitaker’s stress jump conditions for the flow, heat and mass transfer in porous/ fluid coupled domains, and to investigate their effects on local and global heat and mass transfer; ... incorporated with heat or mass transfer There are also limited numerical experiments and systematic results for heat and mass transfer in porou...

Ngày tải lên: 12/09/2015, 21:13

... 3.4 Mô hình toán học trình trao đổi nhiệt ẩm vùng chứa trứng Từ mô hình động học (6) phơng trình nhiệt độ độ ẩm dòng khí trứng (35), (36) (38) ta xác định đợc hệ phơng trình mô tả trạng thái nhiệt ... lợng trứng: 224 (1 ) drT h fT t = hcTa Av (Ta TT ) + (1 ) drT hP + (1 ) drT hD (TT ) X t (34) 3.3 Đơn giản hoá mô hình nhiệt ẩm vùng chứa trứng Mô...

Ngày tải lên: 28/08/2013, 08:31

... d/y = 5.80 10 11 J With a furnace energy consumption of Ef = E/ηf = 6.45 10 11 J, the annual cost of the loss is C = Cg Ef = 0. 01 $/MJ × 6.45 10 5MJ = $6450 < COMMENTS: The heat loss and related ... value of the heat rate PROBLEM 1. 10 KNOWN: Thickness, diameter and inner surface temperature of bottom of pan used to boil water Rate of heat transfer to the pan FIN...

Ngày tải lên: 08/08/2014, 17:20

... reductions in q and m are achieved with r2 = 0 .26 -3  m With increasing r2, q and m decrease from values of 17 02 W and 8×10 kg/s at r2 = 0 .25 m to 0. 627 W and 2. 9×10-6 kg/s at r2 = 0.30 m COMMENTS: ... surface of the insulation, it follows that q′ cond = q′ conv + q′ rad Ts,1 − Ts ,2 ln ( r2 r1 ) 2 k ( = Ts ,2 − T∞ + Ts ,2 − Tsur ( 2 r2 h ) ( 2 r2 h r ) where h r = ε...

Ngày tải lên: 08/08/2014, 17:20

... 0.6 939 T11 + 7.65 The initial estimates (k = 0) are carefully chosen to minimize calculation labor; let ε < 1.0 k T1 34 0 33 8.9 33 8 .3 338 .8 33 9.4 33 9.8 34 0.1 34 0 .3 T2 33 0 33 6 .3 337 .4 33 8.4 33 8.8 33 9.2 ... 282.4 31 0.9 34 0.0 25 180.2 2 03. 6 228 .3 254.4 281.8 31 0.5 34 0.0 50 178.4 201.6 226.2 252.4 280.1 30 9 .3 339 .6 75 175.4 198.2 222.6 248.7 276.9...

Ngày tải lên: 08/08/2014, 17:20

... 356.9 357 .4 357.9 358 .4 358.9 359 .4 T02 3 54. 9 355 .4 355.9 356 .4 356.9 357 .4 T03 351.6 352.1 352.6 353.1 353.6 3 54. 1 T 04 346 .9 347 .4 347 .9 348 .4 348 .9 349 .3 T05 340 .9 341 .4 341 .9 342 .3 342 .8 343 .2 ... 20 30 40 45 T0 85 85 85 85 76.9 76.9 68.8 68.8 61.7 61.7 T1 85 85 85 76.9 76.9 68.8 68.8 61.7 61.7 55.6 T2 85 85 68.8 68.8 60.7 60.7 54. 6 54. 6 49 .5 49 .5 T...

Ngày tải lên: 08/08/2014, 17:20

... 75. 5 W m ⋅ K q′ = hπ D ( Ts − T∞ ) = 75. 5 W m ⋅ K π ( 0.01m ) (50 − 20 ) C = 71.1W m  Fluid: Saturated Water (5 m s ) 0.01m VD = = 68, 55 2 Re D = ν 7 25 × 10−6 N ⋅ s m 994 kg m3 0.62 ( 68, 55 2 ... ≈ 0 .51 ( 9 25) ( 0.686) k 0.0373 W/m ⋅ K h = Nu D = 13 .5 = 50 .4 W/m2 ⋅ K Do 0.01 m 0 .5 0.37 1/4 0 .5 0.37 ×1 = 13 .5 Hence ( ) 1/2  50 .4 W/m2 ⋅ K 0.0314 m   m =  5 m   (...

Ngày tải lên: 08/08/2014, 17:20

... 8 .60 was used The effects of m are as follows Continued PROBLEM 8.30 (Cont.) 67 70 69 .8 Outlet temperature, Tmo(C) Outlet temperature, Tmo(C) 66 65 64 63 62 61 60 0.005 69 .6 69.4 69 .2 69 0.0 06 ... rate and properties of hot fluid Initial temperature, volume and properties of pharmaceutical Heat transfer coefficient at outer surface and dimensions of coil F...

Ngày tải lên: 08/08/2014, 17:20

... Node Tm(K) 391 .70 385.95 380 .70 375 .92 371 .56 10 3 67. 61 364.03 360.81 3 57. 91 355.32 11 12 13 14 15 353.02 351.00 349.25 3 47. 75 346.50 16 17 18 19 20 345.49 344 .70 344.15 343.82 343 .71 From these ... 12.2 343 − Ts,i = 0. 175 0.60 + 2.64 Ts,i − 273 )1/ } (Ts,i − 273 ) + 0.5 × 5. 67 × 10−8 Ts,i − ( 273 )4    Ts,i ≈ 314 .7 K ≈ 41 .7 C A trial -and- error solution gives < The...

Ngày tải lên: 08/08/2014, 17:20

... 11.14 and 11.15 where ∆T1 = Th,i - Tc,o = 80 °C and ∆T2 = Th,o - Tc,i = 120°C Hence, ∆T1m = (120 80 )°C/ln(120 /80 ) = 98. 7°C and L= q 3000 W = = 0.9 68 m (π D ) U∆T1m (π × 0.02 m ) 500 W m2⋅ K × 98. 7 ... Cmin/Cmax = (5,000 × 41 78) /(10,000 × 4 188 ) = 0.499 Combining Eqs (1) and (2), find Th,o = 80 °C − 0.7 × 3 48. 2 × 103 W / (10,000/3600 ) k g / s × 4 188 J / k g ⋅ K ( Th,o...

Ngày tải lên: 08/08/2014, 17:20

... PROBLEM 12 .99 (Cont.) t= ( −11 2.4504 ×10 K −1 −1 ⋅s ) ( 292 8 K )  3  ln 292 8 + 2741 292 8 + 300 − ln 292 8 − 2741 292 8 − 300   2741  −1  300   +2  tan −1   − tan  292 8    292 8   ... 4.17E-5 0.0417 6.39E-5 0.702 600 5.179E-5 0.0446 7.39E-5 0.701 700 6.671E-5 0.0 499 9. 44E-5 0.706 800 8.29E-5 0.0548 0.000116 0.715 90 0 0.0001003 0.0 597 0.0001 39 0.721 1000 0.0001...

Ngày tải lên: 08/08/2014, 17:20