Biomimetic membrane for desalination and water reuse 3
Biomimetic membrane for desalination and water reuse 3
... Tris buffer and dropped on ultrathin carbon film coated copper grids for 15 and then rinsed with ultrapure water dropwise The samples were air dried for 30 before the FETEM imaging 4.2 .3 Vesicle ... PAH-PSS/PAAS-PLL-lipo15-PSS/PAA 5 .33 ±0.10 0.98±0.24 PAH-PSS/PAA-PLL-lipo30-PSS/PAA 6. 13 0.22 1.16±0.18 Membrane No AQPZ AQPZ 78 *Feed: 200ppm MgCl2; three samples were used to ob...
Biomimetic membrane for desalination and water reuse 1
... Introduction 1. 1 Membranes for desalination and water treatment 1. 1 .1 RO, NF and FO 1. 1.2 Traditional membranes 1. 1.3 New generation membranes 1. 2 Aquaporin ... membrane 16 1. 3 .1 Langmuir-Blodgett technique 18 1. 3.2 Vesicle adsorption technique 22 1. 3.3 Block copolymer membrane 24 1. 4 Biomimetic membrane for water treatment ... reach 3.5 × 10 -1...
Biomimetic membrane for desalination and water reuse 2
... 2. 2 Materials and methods 2. 2.1 Materials Nickel-chelating lipids, 1 ,2- di-(9Z-octadecenoyl)-sn-glycero-3-(N-(5-amino-1- carboxypentyl)iminodiacetic acid)succinyl with Nickle (DOGSNTA) and 1,2dipalmitoyl-sn-glycero-3-phosphocholine ... images in Figure 2. 2 Without the addition of BioBeads, the DPPC bilayer loses the original compact structure (Figure 2. 2(a)) and forms a “fluid-...
Biomimetic membrane for desalination and water reuse 4
... robust and highperformance aquaporin-based biomimetic membranes by interfacial polymerizationmembrane preparation and RO performance characterization, J Membrane Sci, 42 3 (2012) 42 2 -42 8 [ 143 ] X.S ... (2007) 49 44- 4 949 [132] K Hoffmann, T Friedrich, B Tieke, Layer-by-Layer Assembled Polyelectrolyte Blend Membranes and Their Use for Ion Separation and Rejection, Polym E...
Tài liệu A resource for reading and words part 3 docx
... woman was a lump of clay READING COMPREHENSION From the passage we understand that a car can kill A) more people than it saves B) as many people as it saves C) fewer people than it saves D) and ... sentences with a suitable form of the words defined above You can at least organize your life around your aims and Army duties included parachuting and of light aircraft I have the...
Review of the Desalination and Water Purification Technology Roadmap pptx
... Review of the Desalination and Water Purification Technology Roadmap http://www.nap.edu/catalog/10912.html Review of the Desalination and Water Purification Technology Roadmap Thermal While thermal ... rights reserved Review of the Desalination and Water Purification Technology Roadmap http://www.nap.edu/catalog/10912.html Review of t...
Supply Chain Management Pathways for Research and Practice Part 3 doc
... transition and information requirements with all suppliers and buyers in a supply chain 38 Supply Chain Management – Pathways for Research and Practice 4 .3 Transition to supply chain quality management ... employee 34 Supply Chain Management – Pathways for Research and Practice relations Effective people skills are a necessity to manage relati...
Request for Offer Project Brief – Financial Audit Acquittal for Land and Water Management Plans doc
... !& ! ) & & ! This is trial version www.adultpdf.com Request for Offer Project Brief – Financial Audit Acquittal for Land and Water Management Plans +& $ $ & !/ " $ ! )! Page of 12 ! /" % # ! $ ... )! ) ! ! ! This is trial version www.adultpdf.com Request for Offer Project Brief – Financial Audit Acquittal for Land and Water Manageme...
Handbook of mathematics for engineers and scienteists part 3 ppsx
... 1 031 20.1.1 Probabilities of Random Events 1 031 20.1.2 Conditional Probability and Simplest Formulas 1 035 20.1 .3 Sequences of Trials ... Method of Quadratures 810 810 811 8 13 815 818 822 8 23 16 .3 Linear Integral Equations of the First Kind with Constant Limits of Integration 16 .3. 1 ... 1175 T3.2.9 Expressions with Special Functions 1176 xx CONTENTS T3 .3 Table...
Chapter 046. Sodium and Water (Part 3) docx
... tubule and interstitial renal disorders are associated with Na+ wasting Excessive renal losses of Na+ and water may also occur during the diuretic phase of acute tubular necrosis (Chap 2 73) and ... Renal Na+ and water loss Diuretics Osmotic diuresis Hypoaldosteronism Salt-wasting nephropathies C Renal water loss Diabetes insipidus (central or nephrogenic) II ECF volume normal...
Advanced Mathematical Methods for Scientists and Engineers Episode 3 Part 1 potx
... domains y1 − y1 = 0, y2 − y2 = 1, y1 (0) = 1, y2 (1) = y1 (1) , 797 for x < for x > -1 Figure 14 .5: Solution to y − y = H(x − 1) With the condition y2 (1) = y1 (1) on the second equation, we demand ... We expand in partial fractions and integrate 1 − y =1 y y 1 ln |y| − ln |y − 1| = x + c 7 81 We have an implicit equation for y(x) Now we solve for y(x) y =x+c y 1 y = ex...
Advanced Mathematical Methods for Scientists and Engineers Episode 3 Part 2 potx
... to form exact derivatives Py = 4yy − xy − y + − 9x2 = d 2y − xy + − 9x2 = dx 2y − xy + x − 3x3 + c = y= x± x2 − 8(c + x − 3x3 ) We consider the differential equation, (2x − 2y)y + (2x + 4y) = 837 ... point d 2 ex /2 y = x2n+1 ex /2 dx y = e−x x /2 ξ 2n+1 eξ /2 dξ + c e−x /2 We choose the constant of integration to satisfy the initial condition y = e−x x /2 ξ 2n+1 eξ 826 /2 dξ + e(1−x...
Advanced Mathematical Methods for Scientists and Engineers Episode 3 Part 3 pptx
... Jordan canonical form of the matrix is J= 3 3 882 The solution of the initial value problem is x = eAt x0 x = eAt x0 = S eJt S−1 x0 = e−3t t e−3t e−3t 1/4 x= −4 3 + 4t −3t e + 4t Solution ... components of η to be zero 3 −2 −6 −4 = c1 0 + c2 3 3 −4 −2 3 = c1 , −4 3 = 2c2 , c1 = c2 , 888 2 3 = 2c1 − 3c2 c1 3 = − We see that we must take c1 = c2 in order ....
Advanced Mathematical Methods for Scientists and Engineers Episode 3 Part 4 pot
... 4x3 To check the theorem, d x x2 d ∆[A(x)] = dx dx x2 x4 2x x x2 = + 2x 4x3 x x = x4 − 2x3 + 4x4 − 2x3 = 5x4 − 4x3 16 .4. 2 The Wronskian of a Set of Functions A set of functions {y1 , y2 , ... Example 16 .4. 1 Consider the the matrix A(x) = x x2 x2 x4 The determinant is x5 − x4 thus the derivative of the determinant is 5x4 − 4x3 To check the theorem, d x x2 d ∆[A(x)] = dx dx x2 x4 2x x ... [...
Advanced Mathematical Methods for Scientists and Engineers Episode 3 Part 5 pdf
... + 13 eλx = λ2 − 4λ + 13 = λ = ± 3i Thus two linearly independent solutions are e(2+3i)x , and 966 e(2−3i)x Noting that e(2+3i)x = e2x [cos(3x) + ı sin(3x)] e(2−3i)x = e2x [cos(3x) − ı sin(3x)], ... an exact equation d 3 ex /3 y = c1 ex /3 dx ex /3 ex y = c1 y = c1 e−x /3 ex /3 /3 9 45 dx + c2 dx + c2 e−x /3 Result 17 .3. 1 If you can write a differential equation in the form d F...
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