... 2Ag(NH3)2+ + Cu 10 - 13,16 C 5,0 .10- 4 [ ] 5,0 .10- 4-x 2x ⇒ (2x)2 = 10 −13,16 (5, 0 .10 −4 − x) x = 5 .10 - 2x = 5x10 −4 10 −13,16 = 10 −8,23 < 5x10 −4 + V y: [Ag(NH )2 ]=2x =10- 8,23 = 5, 9 .10 −9 M 0,5 ... FeF = 5 .10- 3M; C F = 0,485M; C SCN = 5 .10 2 M FeF3 Fe3+ + 3F 10- 13 ,10 Fe3+ + SCNFeSCN2+ 10+ 3,03 − − FeF3 + SCN- FeSCN2+ + 3FK = 10- 10,07 C 5 .10- 3 5 .10- 2 0,485 -3 -2 [ ] (5 .10 -x) (5 .10 -x) x ... -x) x 0,485+3x ⇒ 0,5 x(0, 485 + 3x)3 = 10 10, 07 −3 −2 (5 .10 − x)(5 .10 − x) 0.5 V i x ...