... 5,0 .10- 4 [ ] 5,0 .10- 4-x 2x ⇒ K = β−2 K β4 = 101 3,16 10 - 13,16 (2x)2 = 10 −13,16 (5, 0 .10 −4 − x) x = 5 .10 - 2x = 5x10 −4 10 −13,16 =10 −8,23 Vậy: [Ag(NH )+ ]=2x =10- 8,23 = 5, 9 .10 −9 M < 5x10 ... FeF = 5 .10- 3M; C F = 0,485M; C SCN = 5 .10 M FeF3 Fe3+ + 3F 10- 13 ,10 Fe3+ + SCN- FeSCN2+ 10+ 3,03 − C [] ⇒ − FeF3 + SCN- FeSCN2+ + 3FK = 10- 10,07 5 .10- 3 5 .10- 2 0,485 -3 -2 (5 .10 -x) (5 .10 -x) ... (5 .10 -x) x 0,485+3x 0,5 đ x(0, 485 + 3x)3 = 10 10, 07 (5 .10 −3 − x)(5 .10 −2 − x) 0.5đ -3 Với x ...