... Kiểm tra: CCO2- = 4 -7 ,13 =10 -6,8 < 10 = K s(BaC2O4 ) → BaC2O4 kết tủa 10 −8,75 = −5,83 = 10 −2,92 (M) 10 K 'a1.K 'a2 [CO ] 10 16 ,68.0, 01 = = 1, 53 .10 -17 (M) + 2 [H ] (0 ,11 7) → C'Ca 2+ C'CO2- < ... 4H2O K1 = 10 5 .1, 51/ 0,0592 Mn2+ + 2H2O MnO2↓ + 4H+ + 2e K -1 = 10 −2 .1, 23 / 0,0592 MnO2↓ + 2H2O MnO 2- + 4H+ + 2e -1 K = 10 −2.2,26 / 0,0592 MnO4 MnO 24 +e -1 K = K1.K -1. K → E MnO- /MnO24 K = 10 ... 5 .1, 51 – 2. (1, 23+2,26) = 0,57 (V) MnO- + 8H+ + 5e Mn2+ + 4H2O K1 = 10 5 .1, 51/ 0,0592 Mn2+ + 2H2O MnO2↓ + 4H+ + 2e K -1 = 10 −2 .1, 23 / 0,0592 OH- + H+ K w = 10 14 4× H2O MnO4 - + 2H2O + 3e K = K1.K...