Fundamentals of Digital Television Transmission phần 5 pot
Fundamentals of Digital Television Transmission phần 5 pot
... 50 9 54 .12 0.140 54 713 44.38 0.172 21 51 5 53 . 75 0.141 55 719 44.16 0.173 22 52 1 53 .38 0.142 56 7 25 43.94 0.174 23 52 7 53 .03 0.143 57 731 43.73 0.174 24 53 3 52 .68 0.144 58 737 43 .51 0.1 75 25 539 ... 677 45. 76 0.167 15 479 56 .06 0.1 35 49 683 45. 52 0.167 16 4 85 55. 66 0.136 50 689 45. 29 0.168 17 491 55 .26 0.137 51 6 95 45. 06 0.169 18 497 54 .87...
Ngày tải lên: 14/08/2014, 16:20
Fundamentals of Digital Television Transmission phần 3 pot
... spectra. 50 .00 − 45. 00 −40.00 − 35. 00 −30.00 − 25. 00 −20.00 − 15. 00 −10.00 5. 00 0.00 3. 75 3.80 3. 85 3.90 3. 95 4.00 Relative level (dB) Relative frequency (MHz) Guard interval = 0 Figure 3-9. COFDM spectrum, upper ... systems support a wide range of payload bit rates. The average transmitter power is much less than that required for analog TV transmission. Fundamentals of...
Ngày tải lên: 14/08/2014, 16:20
Fundamentals of Digital Television Transmission phần 6 potx
... 53 9 77.16 0.137 26 54 5 76.62 0.138 27 55 1 76.08 0.139 28 55 7 75. 56 0.140 29 56 3 75. 05 0.141 30 56 9 74 .54 0.142 31 57 5 74. 05 0.143 32 58 1 73 .56 0.144 33 58 7 73.08 0.1 45 34 59 3 72.60 0.146 35 599 ... 51 .91 0. 155 48 677 41.73 0.194 15 479 51 .52 0. 156 49 683 41 .51 0.1 95 16 4 85 51.13 0. 158 50 689 41.29 0.196 17 491 50 . 75 0. 159 51 6 95 41.07 0....
Ngày tải lên: 14/08/2014, 16:20
Fundamentals of Digital Television Transmission phần 7 pot
... 102. 176 TRANSMITTING ANTENNAS FOR DIGITAL TELEVISION Array diameter = 0. 75 wavelength 0 .50 0 .55 0.60 0. 65 0.70 0. 75 0.80 0. 85 0.90 0. 95 1.00 0 50 100 150 200 250 300 350 400 Relative field Azimuth ... (degrees) Array diameter = 0 .5 wavelength Figure 7-21. Four-around array factor. 0.0 0 .5 1.0 1 .5 2.0 2 .5 3.0 3 .5 0.00 0. 05 0.10 0. 15 0.20 0. 25 0.30 0. 35 0.4...
Ngày tải lên: 14/08/2014, 16:20
Fundamentals of Digital Television Transmission phần 9 potx
... 20 −0.20 −0.10 0.00 0.10 0.20 0.30 0.40 0 .50 0.60 Phase (rad) Frequency (MHz) 50 6 50 7 50 8 50 9 51 0 51 1 51 2 Figure 8-27. Phase response, R3 05. CHARLOTTE, NORTH CAROLINA 229 Ch 53 −30 − 25 −20 − 15 −10 5 0 0 1020304 050 60708090 Equalizer ... 1020304 050 60708090 Field strength (dBu) Distance (km) FCC (50 ,90) Calculated (50 ,10) (50 ,50 ) (50 ,90) Figure 8-20. Compari...
Ngày tải lên: 14/08/2014, 16:20
Fundamentals of Digital Television Transmission phần 1 doc
... originality for much of the material included in this book. In fact, the story of digital television builds on the many contributions of workers since the beginning of radio and television transmission. ... Ratio Mode Guard Interval Ratio 1 2 3 1 4 64.26 128 .52 257 .04 1 8 57 .83 1 15. 67 231.34 1 16 54 .62 109.24 218.46 1 32 53 .01 106.03 212.06 transmission mode and the...
Ngày tải lên: 14/08/2014, 16:20
Fundamentals of Digital Television Transmission phần 2 pptx
... typical of many practical amplifiers. 20 25 30 35 40 45 50 −20 − 15 −10 50 51 0 Output (dB) Input (dB) Nonlinear Linear Figure 2-10. Nonlinear amplification. 28 PERFORMANCE OBJECTIVES FOR DIGITAL TELEVISION (NF ... function of carrier-to-interference ratio, C/I,for a pair of 8 VSB DTV stations operating on the same channel, assuming an 15. 00 16.00 17.00 18.00 19.00 20.00 21....
Ngày tải lên: 14/08/2014, 16:20
Fundamentals of Digital Television Transmission phần 8 docx
... An ANTENNA IMPEDANCE 189 Induced emf method −200.0 − 150 .0 −100.0 50 .0 0.0 50 .0 100.0 150 .0 200.0 250 .0 300.0 0.40 0.42 0.44 0.46 0.48 0 .50 0 .52 0 .54 0 .56 0 .58 0.60 Impedance (ohms) Length (wavelengths) R in X in , ... sake of illustration, the results of calculation of the mutual impedance of parallel half-wavelength dipoles as a func- tion of separation are plotted i...
Ngày tải lên: 14/08/2014, 16:20
Fundamentals of Digital Television Transmission phần 10 doc
... keying: BST-OFDM, 14 COFDM, 11, 15, 24, 37, 43, 52 , 56 , 58 , 59 , 61, 62, 64, 77 DQPSK, 16, 63 8 VSB, 4, 6, 10, 28–31, 33, 34, 37, 38, 43, 51 53 , 56 , 77, 87, 246, 250 FDM, 56 quadrature, 12, 15, 43, 52 QAM, ... 192 slot, 156 , 161, 172, 176, 180, 181, 192–194, 196–198 stability, 155 , 166, 171, 197 transmit, 219 ATSC, 3, 4, 8, 18, 24, 29, 31, 43– 45, 47 52 , 54 , 55 , 75 77,...
Ngày tải lên: 14/08/2014, 16:20
Fundamentals of Spread Spectrum Modulation phần 5 pot
... Q ) −1 R z=1 . (5. 25) Using the result of (5. 18), the average time to reject an incorrect phase cell is the sum of the elements of the first row of the final matrix of (5. 25) . Since incorrect ... intervals) and T s ≈ T c N + MT c 2 = 10 −6 2 + ( 50 00 ) 10 −6 2 = 1 2 ( 50 01 ) 10 −6 = 0.00 25 s. The advantage of matched filter acquisition in terms of acquisition...
Ngày tải lên: 07/08/2014, 21:20