Computational Statistics Handbook with MATLAB phần 5 pot
Computational Statistics Handbook with MATLAB phần 5 pot
... bootstrap.
[bhat,seboot,bvals]=csboot(x','median' ,50 0);
q
ˆ
0 .5
84 .5=
x 74=
q
ˆ
0 .5
84 .5=
q
ˆ
0 .5
85=
SE
ˆ
Jack
q
ˆ
0 .5
()12=
© 2002 by Chapman & Hall/CRC
254 Computational Statistics Handbook with M
ATLAB
will implement ...
h
4
Rf″()+=
f
″
f
x()
h
FP
*
2
15
49nR f ″()
15
=
f
x()
Rf″() 38πσ
5
()⁄=
© 2002 by Chapman & Hall/CRC
27...
Computational Statistics Handbook with MATLAB phần 2 pot
... resulting estimates are
qhat = -0.6928 0. 057 4 0.6 453 .
The reader is asked to explore this further in the exercises.
q
0. 25
0. 25=
q
0 .5
0 .5= q
0. 75
0. 75=
j 0 .5 ()n⁄
Y
I
X
I
X
obs
Y
obs
F
1–
X
obs
X
j()
Y
obs
© ... corresponding to the theoretical probability
density function with . The histogram and the curve match quite well.
0 0 .5 1 1 .5 2 2 .5 3 3 .5 4 4 .5 5
0
0.2
0...
Computational Statistics Handbook with MATLAB phần 4 potx
... reasonable.
4 35 440 4 45 450 455 460 4 65
0.01
0.02
0. 05
0.10
0. 25
0 .50
0. 75
0.90
0. 95
0.98
0.99
Data
Probability
Normal Probability Plot
t
o
2 .56 –=
H
0
© 2002 by Chapman & Hall/CRC
Chapter 5: ... & Hall/CRC
170 Computational Statistics Handbook with M
ATLAB
Posse [1995a, 1995b] uses a random search to locate the global optimum of the
projection ind...
Computational Statistics Handbook with MATLAB phần 8 potx
... 1000;
X(1: 250 ,1) = unifrnd(0,1, 250 ,1);
X(1: 250 ,2) = unifrnd(0 .5, 1, 250 ,1);
y(1: 250 ) = 2+sqrt(2)*randn(1, 250 );
X( 251 :50 0,1) = unifrnd(-1,0, 250 ,1);
X( 251 :50 0,2) = unifrnd(-0 .5, 1, 250 ,1);
y( 251 :50 0) = ...
418 Computational Statistics Handook with M
ATLAB
X (50 1: 750 ,1) = unifrnd(-1,0, 250 ,1);
X (50 1: 750 ,2) = unifrnd(-1,-0 .5, 250 ,1);
y (50 1: 750 ) = 10+s...
Computational Statistics Handbook with MATLAB phần 3 pps
... Example 5. 11 using the scatter function with filled
markers.
0 0 .5 1 1 .5 2 2 .5 3 3 .5
2
2 .5
3
3 .5
4
4 .5
0 0 .5 1 1 .5 2 2 .5 3 3 .5
2
2 .5
3
3 .5
4
4 .5
© 2002 by Chapman & Hall/CRC
Chapter 5: Exploratory ... model the data.
0 1 2 3 4 5 6 7 8 9 10
−10
−9 .5
−9
−8 .5
−8
−7 .5
−7
−6 .5
−6
5. 5
5
1
1
1
Number of Females − k
φ (n
*
k
)
q
ˆ
0. 25
q
ˆ
0 .5
q...
Computational Statistics Handbook with MATLAB phần 6 doc
... 8
0
0. 05
0.1
0. 15
0.2
0. 25
Feature − x
x 0. 75 =
ω
1
ω
2
P x ω
j
()P ω
j
() P x ω
i
()P ω
i
();= ij≠
x 0 .5 =
x 0 .5 <
© 2002 by Chapman & Hall/CRC
320 Computational Statistics Handbook with ... method.
5 −4 −3 −2 −1 0 1 2 3
0
.1
.2
.3
.4
.5
.6
Mean
Mixing Coefficient
−10 −8 −6 −4 −2 0 2 4 6 8 10
0
0. 05
0.1
0. 15
0.2
0. 25
0.3
0. 35
x
© 2002 by Chapman & Hal...
Computational Statistics Handbook with MATLAB phần 7 pdf
... Statistical Pattern Recognition 3 65
ind2 = 2 :5: 50;
ind3 = 3 :5: 50;
ind4 = 4 :5: 50;
ind5 = 5: 5 :50 ;
Next we set up all of the testing and training sets. We use the MATLAB eval
function to do this in ... using Euclidean distances and complete linkage.
1 2 3 4 5
0
0 .5
1
1 .5
2
2 .5
Clustering − Single Linkage
1 2 3 4 5
0
0 .5
1
1 .5
2
2 .5
3
3 .5
4
4 .5
Clustering − Comp...
Computational Statistics Handbook with MATLAB phần 9 docx
... Uganda.
0 50 0 1000 150 0 2000 250 0 3000
50 0
1000
150 0
2000
250 0
3000
350 0
4000
450 0
Volcanic Craters in Uganda
© 2002 by Chapman & Hall/CRC
488 Computational Statistics Handbook with M
ATLAB
We ... = [0 0 1 1 0];
rxp = [ 05 1. 05 1. 05 05 05] ;
ryp = [ 05 05 1. 05 1. 05 05] ;
% Get all of the parents.
[xp,yp] = csbinproc(rxp, ryp, npar);
We use a Poisson dist...
Computational Statistics Handbook with MATLAB phần 10 ppsx
... 55 0 Computational Statistics Handbook with M
ATLAB
Descriptive Statistics
Function Purpose
bootstrp Bootstrap statistics for any function.
corrcoef Correlation ... quadl(fnr,sqrt(2*log(6)) /5,
2*sqrt(2*log(6)) /5) /8;
ck(17:24) = quadl(fnr,2*sqrt(2*log(6)) /5,
3*sqrt(2*log(6)) /5) /8;
ck( 25: 32) = quadl(fnr,3*sqrt(2*log(6)) /5,
4*sqrt(2*log(6)) /5) /8;
ck(33:40) = quadl(fnr,...
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