... 5000 replications, each replication generating a primary and antitheticwaiting time for five customers, the mean such time was 1.2 87 and the standarderror was 0.0 077 7. The estimated variance ... 0. 67, 0.25, 0.16,0.13, 0 .77 , 0 .46, 0. 67, 0. 47, 0.22,0.49, 0.16, 0 .08, 0.85, 0.38, 0.23, 0.94, 0.83, 0.45,0. 87, 0.22, 0 .99, 0.20, 0.64, 1.39,0.62, 0.22, 0 .15, 2.21, 0 .76 , 0.80, 0. 97, ... losses.½> with( stats);d:=transform[statsort]([a]):#sorts thedata. d[i]is now the i th. order statistic[anova, describe, fit, importdata, random, statevalf, statplots, transform]26664Construct...