Statistics for Environmental Engineers Second Edition phần 10 doc
... 55 Predicted 10. 4 10. 3 10. 2 10. 1 10. 1 Observed 10. 6 10. 6 10. 0 10. 3 11.7 11.8 Forecast error 0.18 −0.3 −0.1 1.6 1.7 Z ˆ t 5() 10. 0 0.72 5 10. 6 10. 0–()+ 10. 10== Z ˆ t ᐉ() η ≈ 10= e t 1() z t+1 z ˆ t 1()– φ z t a t+1 φ z t –+ ... 1–() η –[]+= for ᐉ 2≥ Z t ᐉ() ηφ ᐉ Z ˆ t η –()+= σ ˆ a 2 0.89 . = Z ˆ t 1() 10. 0 0.72 10. 6 10. 0–()+ 10. 43== Z ˆ t 2() 10. 0 0.72...
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... 9.1 8.9 12.1 11.7 11.7 8.4 10. 4 9.5 9.0 9.2 7.8 11.1 9.0 10. 9 9.7 10. 1 10. 4 11.2 10. 4 10. 4 10. 6 12.1 9.3 11.9 9.7 10. 3 8.6 11.3 9.2 11.2 8.7 9.6 9.4 10. 6 11.6 10. 6 10. 4 10. 0 9.1 y L1592_Frame_C02 ... In addition to Statistics for Environmental Engineers, 1st Edition (1994, Lewis Publishers), Professor Brown has been the author or co-author of numerous pub...
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... test. Student A Student B Student C Student D 10. 08 9.88 10. 19 10. 04 10. 11 10. 14 9.79 9.98 10. 09 10. 02 9.69 10. 02 10. 10 9.80 10. 05 9.97 10. 12 10. 21 9.78 10. 04 Laboratory 123456789 Low Level 700 770 ... 129 32 197 191 68 91 98 104 115 102 140 152 148 34 167 165 70 115 108 106 136 127 142 140 127 36 179 178 72 124 119 108 154 141 144 125 113 0 20 40 60 80 Frequenc...
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Statistics for Environmental Engineers Second Edition phần 3 pdf
... 11.8 11.8 11.8 13 10. 5 10. 5 10. 5 10. 5 10. 8 38 12.7 12.7 12.7 12.7 12.7 14 10. 9 11.4 10. 9 10. 9 11.2 39 12.8 12.8 12.8 12.8 12.8 15 10. 5 11.4 10. 5 7.4 10. 8 40 10. 9 10. 9 10. 9 10. 9 10. 9 16 11.5 12.4 ... 13.0 13.0 13.0 28 10. 6 11.5 14.1 10. 6 11.2 4 11.1 11.1 11.1 11.1 11.1 29 11.3 11.8 14.8 11.3 11.9 5 10. 5 10. 5 10. 5 10. 5 10. 5 30 10. 9 10. 9 14.4 10...
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Statistics for Environmental Engineers Second Edition phần 4 pot
... 47069 −2160 10. 712 10. 759 −0.047 2 42858 50301 −7443 10. 666 10. 826 −0.160 3 35976 40431 −4455 10. 491 10. 607 −0.117 4 20048 24887 −4839 9.906 10. 122 -0.216 5 28273 28385 −112 10. 250 10. 254 −0.004 6 ... 27261 26122 1139 10. 213 10. 171 0.043 7 66149 72039 −5890 11 .100 11.185 −0.085 8 70190 70039 151 11.159 11.157 0.002 9 53611 63228 −9617 10. 890 11.055 −0.165 10 49978 6...
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Statistics for Environmental Engineers Second Edition phần 5 pot
... the performance of the adsorption units? Reactor\Week 1 2345678 9101 1121314151617181920 1 7 444 45646 53461 1101 78788 2 5 810 7 7 9 7 6 6 1 1101 51819222 3102 017 6 3 6 798 7151278118141819 6104 443 4 ... 1 1101 51819222 3102 017 6 3 6 798 7151278118141819 6104 443 4 4 4 4 7 8 910 7 8 101 1121113 813 5111 110 5 7106 3 45566 45766596575 6 3 4 3 9 12 12 14 11 9 10 11 11 13 14 17 19 7 11...
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Statistics for Environmental Engineers Second Edition phần 6 pptx
... 1430 6 B 50 Yes No 10% 580 7 A 100 Yes No 10% 350 8 B 100 Yes No None 55 9 A 50 No Yes None 1420 10 B 50 No Yes 10% 410 11 A 100 No Yes 10% 610 12 B 100 No Yes None 40 13 A 50 Yes Yes 10% 2830 14 B ... ×× ×× 10 10 ) Run No. ( X 1 )( X 2 )( X 3 )( X 4 )( X 5 )( y ) 1 A 50 No No 10% 102 5 2 B 50 No No None 190 3 A 100 No No None 1490...
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Statistics for Environmental Engineers Second Edition phần 7 ppsx
... 137 134 120 144 114 101 7 140 120 182 198 171 170 155 165 131 126 104 86 8 114 83 107 162 140 159 143 129 117 114 123 102 9 144 143 140 179 174 164 188 107 140 132 107 119 10 156 116 179 189 204 ... (right). • • • • • • • • • • • • • • • • • • • • • • • • • • • • • • • • • • • • • • 4 2 0 -2 -4 100 100 0 10, 000 100 ,000 1,000,000 Predicted Peak for Nitrate Weighted Residuals...
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Statistics for Environmental Engineers Second Edition phần 8 pps
... 140 0 6.02 1 140 1 110 1 0 110 0 6.17 1 110 1 110 1 0 110 0 6.31 1 110 1 120 1 0 120 0 6.27 1 120 1 110 1 0 110 0 6.42 1 110 1 110 1 0 110 0 6.28 1 110 1 110 1 0 110 0 6.43 1 110 2 140 0 1 0 140 ... 120 2 110 0 1 0 110 6.37 1 110 2 110 0 1 0 110 6.73 1 110 2 100 0 1 0 100 6.89 1 100 2 100 0 1 0 100 6.87 1 100 2 120 0 1 0 120 6.30 1 120 2 120 0 1 0 120 6.52 1 120 2...
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Statistics for Environmental Engineers Second Edition phần 9 ppt
... residuals for each method of estimation. Explain why the estimates differ and explain which are best. Data Set 1: x = 246 810 y = 11.2 1.3 0.9 0.5 0.4 Data Set 2: x = 2244668 8101 0 y = 11.2 10. 0 1.3 ... computation for Model 2 gives R 2 = (0.175/0.184) 0.5(13−2) = 0.78. The computed posterior probabilities indicate a 50% probability for the Tiessier model being correct and a 10%...
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