THEORY AND PROBLEMS OF PROGRAMMING WITH Second Edition phần 2 pptx

THEORY AND PROBLEMS OF PROGRAMMING WITH Second Edition phần 2 pptx

THEORY AND PROBLEMS OF PROGRAMMING WITH Second Edition phần 2 pptx

... the beginning of the first field and the end of the last field in each line.) : 123 12 -3.3e+00: : 123 12 -3.3e+00 : : + 123 + 12 -3,3e+00 : :+ 123 + 12 -3.3e+00 : 12 12. -3.3 -3.30000: ... detection of EOF in this manner offers a convenient way to detect an end of file, whenever and wherever it may occur. Appropriate corrective action can then be taken. Bot...

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THEORY AND PROBLEMS OF PROGRAMMING WITH Second Edition phần 1 pot

THEORY AND PROBLEMS OF PROGRAMMING WITH Second Edition phần 1 pot

... W 24 CAN 56 8 88 X 120 X 25 EM 57 9 89 Y 121 Y 26 SUB 58 90 Z 122 z 27 E SC 59 1 91 123 { 28 FS 60 C 92 \ 124 I 29 GS 61 93 I 125 } A 30 RS 62 > ... 1 12 P 17 DC 1 49 1 81 Q 113 q 18 DC2 50 2 82 R 114 r 19 DC3 51 3 83 S 115 S 20 DC4 52 4 84 T 116 t 21 NAK 53 5 85 U 117 U 22 SY N 54 6 86...

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THEORY AND PROBLEMS OF PROGRAMMING WITH Second Edition phần 3 doc

THEORY AND PROBLEMS OF PROGRAMMING WITH Second Edition phần 3 doc

... 1 .47577 )2] 0 .2 = 1 .28 225 Continuing this procedure, we obtain x = [ 10 - 3( 1 .21 322 5)~IO.~ = 1.38344 x = [10 - 3(1.38344 )2] 0 *2 = 1.33613 and so on. Notice that the successive values of ... between 0 and 12; Good Afternoon will be displayed if time has a value between 12 and 18; and Good Evening will be displayed if time has a value betwe...

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THEORY AND PROBLEMS OF PROGRAMMING WITH Second Edition phần 4 doc

THEORY AND PROBLEMS OF PROGRAMMING WITH Second Edition phần 4 doc

... throw of a pair of dice */ { float xl, x2; /* randomfloating-point numbers between 0 and 1 */ int nl, n2; /* random integers between 1 and 6 */ xl = rand() / 327 68.0; x2 = rand() ... End of Year 1 Depreciation: 25 00.00 Current Value: 25 00.00 End of Year 2 Depreciation: 125 0.00 Current Value: 125 0.00 End of Year 3 Depreciation: 625 .00...

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THEORY AND PROBLEMS OF PROGRAMMING WITH Second Edition phần 5 ppt

THEORY AND PROBLEMS OF PROGRAMMING WITH Second Edition phần 5 ppt

... number of small rectangles and calculating the area of these rectangles. (This is known as the trupezoidul rule.) The appropriate formula is A = b1 +y2)(x2 - x1) /2 + b2 +y3)(x3 - x2) /2 ... having 50 rows and 50 columns (hence 50 x 50 = 25 00 elements), and the second line establishes page as a character array with 24 rows and 80 columns (24 x 80 =...

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THEORY AND PROBLEMS OF PROGRAMMING WITH Second Edition phần 6 ppsx

THEORY AND PROBLEMS OF PROGRAMMING WITH Second Edition phần 6 ppsx

... the following set of data. yi :] 615 0 -2 113 2 -113 0 5 7 12 314 -3 12 B= 0 - 1 1 0 0 3 -917 617 413 9 12 317 -3 3 4 -1 12 0 314 Display the elements of A, B and C. Be sure ... elements: 10 12 14 0 0 20 22 0 0 30 32 0 (g) Define a two-dimensional, 3 x 4 integer array called n. Assign the following values to the array elements: 10 12 14...

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THEORY AND PROBLEMS OF PROGRAMMING WITH Second Edition phần 7 pps

THEORY AND PROBLEMS OF PROGRAMMING WITH Second Edition phần 7 pps

... static float table [2] [3) = { tl.1, 1 .2, 1.3), {2. 1, 2. 2, 2. 3) 1; What is the meaning of table? What is the meaning of (table + 1 )? What is the meaning of * (table + 1 ... character of the customer's name can be accessed by writing any of the following (see Sec. 10.4). customer.name [2] pc->name [2] (*pc).name [2] *(customer. name + 2) p...

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THEORY AND PROBLEMS OF PROGRAMMING WITH Second Edition phần 8 doc

THEORY AND PROBLEMS OF PROGRAMMING WITH Second Edition phần 8 doc

... 4 12 DATA FILES [CHAP. 12 Steve Johnson 123 Mountainview Drive Denver, CO 420 8 C 24 7.88 22 2.88 25 .00 121 291 1998 Susan Richards 4383 Alligator Blvd Fort Lauderdale, FL 22 1 ... 135.00 121 291 1998 Martin Peterson 1787 Pacific Parkway San Diego, CA 84 52 0 387. 42 3 52. 42 35.00 1 2 129 11 998 Phyllis Smith 1000 Great White Way New York, N...

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THEORY AND PROBLEMS OF PROGRAMMING WITH Second Edition phần 9 ppt

THEORY AND PROBLEMS OF PROGRAMMING WITH Second Edition phần 9 ppt

... beginning of a second word of storage. Separate b and c with 2 vacant bits. Programming Problems 13.45 Modify the program presented in Example 13 .2 (repeated calculation of a sequence of ... beginning of the second word. Fig. 13 .2 shows the layout of the bit fields within the two 16-bit words. word 2 word 1 bitno. 15 14 13 12 11 10 9 8 7 6...

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THEORY AND PROBLEMS OF PROGRAMMING WITH Second Edition phần 10 ppsx

THEORY AND PROBLEMS OF PROGRAMMING WITH Second Edition phần 10 ppsx

... 24 2. 24 4 subscript, 34 Arrays. 34, 24 1 and pointers. 28 6, 29 1 and strings. 35, 26 5 automatic, 21 5. 24 3, 26 0 character, 24 4 extcmal. 2 15. 24 3, 26 0, 26 5 initialimtion, 24 3, 24 5, 24 7, ... external, 2 10, 22 4, 22 7 floating-point, 10 global, 20 7, 2 10, 22 4, 22 7 local. 20 7 register, 424 static, 2 16, 22 7 structur~, 338...

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