INTRODUCTION TO ALGORITHMS 3rd phần 4 ppt
INTRODUCTION TO ALGORITHMS 3rd phần 4 ppt
... 385
1 4
1 1 2 4 1 2 3 4 1 3 4 4
2 2 3 4 2 3 4 4 1 1 2 2 3 3 4 4 1 1 2 3 1 2 3 3
3 3 4 4 2 2 3 3 2 2 3 3 1 1 2 2
Figure 15.7 The recursion tree for the computation of RECURSIVE-MATRI X-CHAIN.p;1 ;4/ .
Each ... Algorithms
012 345 678910111213 14
time
235
306
45 7
539
659
7610
8811
9812
102 14
11 12 16
1 14
k s
k
f
k
a
1
a
2
a
1
a
3
a
1
a
4
a
1
a
4
a
5
a
1
a
4
a
6
a
1...
INTRODUCTION TO ALGORITHMS 3rd phần 8 pptx
... 941
012 345
0
1
2
3
4
5
012 345
012 345
012 345
012 345
012 345
012 345
(a)
1 2 4 7 8 11 13 14
1
2
4
7
8
11
13
14
1 2 4 7 8 11 13 14
2 4 8 14 1 7 11 13
48 1132 147 11
7 141 341 12 1 8
8 1 21 141 3 147
117 142 131 ... of p in the list. For example, since the prime divisors of 45 are 3
and 5,
.45 / D 45
Â
1
1
3
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1
1
5
Ã
D 45
Â
2
3
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If p is...
Introduction to Fracture Mechanics phần 4 ppt
... laboratory
scale tests to be applied to large scale fracture problems.
)2()1(
II
KK
Si
3
N
4
Al
2
O
3
Glass
K
c
(MPa )Material
m
1
43
8
4
35
Steels
Al alloys
Polymers
Si
3
N
4
8
4
25.0
10010
30030
Plastic ... Problem
Similitude
For a crack of length 2a
1
in an infinite plate, subjected
to an applied stress
σ
1
the stress intensity factor is
known...
INTRODUCTION TO ALGORITHMS 3rd phần 1 docx
... Huffman codes 42 8
? 16 .4 Matroids and greedy methods 43 7
? 16.5 A task-scheduling problem as a matroid 44 3
17 Amortized Analysis 45 1
17.1 Aggregate analysis 45 2
17.2 The accounting method 45 6
17.3 ... Ford-Fulkerson method 7 14
26.3 Maximum bipartite matching 732
? 26 .4 Push-relabel algorithms 736
? 26.5 The relabel -to- front algorithm 748
VII Selected Topics
Introductio...
INTRODUCTION TO ALGORITHMS 3rd phần 2 pdf
... we
have
6 .4 The heapsort algorithm 161
(a) (b) (c)
(d) (e) (f)
(g) (h) (i)
(j) (k)
12 347 8910 141 6
10
2
13
47 89
16 14
1
23
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16 141 0
3
21
98 74
10 14 16
4
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10 14 16
8
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10 ... we wish to hire.
158 Chapter 6 Heapsort
1
23
45 67
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1
23
45 67
8910
1
23
45 67
8910
1
23
45 67
8910
1
23
45 67
8910
1
23
45 67
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14 8 7...
INTRODUCTION TO ALGORITHMS 3rd phần 3 potx
... key k not already
stored in the table is equally likely to hash to any of the m slots. The expected time
to search unsuccessfully for a key k is the expected time to search to the end of
list ... keys)
K
(actual
keys)
0
m–1
k
1
k
2
k
3
k
4
k
5
h(k
1
)
h(k
4
)
h(k
3
)
h(k
2
) = h(k
5
)
Figure 11.2 Using a hash function h to map keys to hash-table slots. Because keys k
2
and k...
INTRODUCTION TO ALGORITHMS 3rd phần 5 pdf
... 41
(h)
17
30
242 3
26
35
46
7 21 18 52 38
39 41
17
30
242 3
26
35
46
7 21 18 52 38
39 41
17
30
242 3
26
35
46
7 21 18 52 38
39 41
17
30
242 3
26
35
46
7 21 18 52 38
39 41
17
30
24
23 26
35
46
7 21 18 ... summary
proto-vEB(16)
0 1
cluster
u
4
summary
proto-vEB (4)
0
1
A
proto-vEB(2)
1
1
0 1
cluster
u
4
summary
proto-vEB (4)
0 1
cluster
u
4
summary
proto-vEB (4...
INTRODUCTION TO ALGORITHMS 3rd phần 6 pdf
... difference constraints:
x
1
x
2
Ä 4 ,
x
1
x
5
Ä 5 ,
x
2
x
4
Ä6 ,
x
3
x
2
Ä 1 ,
x
4
x
1
Ä 3 ,
x
4
x
3
Ä 5 ,
x
4
x
5
Ä 10 ,
x
5
x
3
Ä 4 ,
x
5
x
4
Ä8 .
24. 4-3
Can any shortest-path weight ... from s to in G
0
is a shortest path from s
to in G.
24. 4 Difference constraints and shortest paths 667
0
0
0
0
0
0–1
1
5
4
–1
–3
–3
0
–5
–3
0–1
4
v
3
v
2
v
1...
INTRODUCTION TO ALGORITHMS 3rd phần 7 pps
... example,
a call to FIB.6/ recursively calls FIB.5/ and then FIB .4/ . But, the call to FIB.5/
also results in a call to FIB .4/ . Both instances of FIB .4/ return the same result
(F
4
D 3). Since the ... comes
into the picture, executing instructions 4 6. Processor 2 reads x from memory into
register r
2
; increments it, producing the value 1 in r
2
; and then stores this value
into...
INTRODUCTION TO ALGORITHMS 3rd phần 9 docx
... as another, to within a polynomial-time factor. That is, if
L
1
Ä
P
L
2
,thenL
1
is not more than a polynomial factor harder than L
2
,whichis
1066 Chapter 34 NP-Completeness
34. 2 -4
Prove that ... language HAM-PATH DfhG; u; iWthere is a hamiltonian
path from u to in graph Gg belongs to NP.
34. 2-7
Show that the hamiltonian-path problem from Exercise 34. 2-6 can be solved in
pol...
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