INTRODUCTION TO ALGORITHMS 3rd phần 4 ppt
... 385 1 4 1 1 2 4 1 2 3 4 1 3 4 4 2 2 3 4 2 3 4 4 1 1 2 2 3 3 4 4 1 1 2 3 1 2 3 3 3 3 4 4 2 2 3 3 2 2 3 3 1 1 2 2 Figure 15.7 The recursion tree for the computation of RECURSIVE-MATRI X-CHAIN.p;1 ;4/ . Each ... Algorithms 012 345 678910111213 14 time 235 306 45 7 539 659 7610 8811 9812 102 14 11 12 16 1 14 k s k f k a 1 a 2 a 1 a 3 a 1 a 4 a 1 a 4 a 5 a 1 a 4 a 6 a 1...
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... 941 012 345 0 1 2 3 4 5 012 345 012 345 012 345 012 345 012 345 012 345 (a) 1 2 4 7 8 11 13 14 1 2 4 7 8 11 13 14 1 2 4 7 8 11 13 14 2 4 8 14 1 7 11 13 48 1132 147 11 7 141 341 12 1 8 8 1 21 141 3 147 117 142 131 ... of p in the list. For example, since the prime divisors of 45 are 3 and 5, .45 / D 45 Â 1 1 3 ÃÂ 1 1 5 Ã D 45 Â 2 3 ÃÂ 4 5 Ã D 24 : If p is...
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... laboratory scale tests to be applied to large scale fracture problems. )2()1( II KK Si 3 N 4 Al 2 O 3 Glass K c (MPa )Material m 1 43 8 4 35 Steels Al alloys Polymers Si 3 N 4 8 4 25.0 10010 30030 Plastic ... Problem Similitude For a crack of length 2a 1 in an infinite plate, subjected to an applied stress σ 1 the stress intensity factor is known...
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INTRODUCTION TO ALGORITHMS 3rd phần 1 docx
... Huffman codes 42 8 ? 16 .4 Matroids and greedy methods 43 7 ? 16.5 A task-scheduling problem as a matroid 44 3 17 Amortized Analysis 45 1 17.1 Aggregate analysis 45 2 17.2 The accounting method 45 6 17.3 ... Ford-Fulkerson method 7 14 26.3 Maximum bipartite matching 732 ? 26 .4 Push-relabel algorithms 736 ? 26.5 The relabel -to- front algorithm 748 VII Selected Topics Introductio...
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INTRODUCTION TO ALGORITHMS 3rd phần 2 pdf
... we have 6 .4 The heapsort algorithm 161 (a) (b) (c) (d) (e) (f) (g) (h) (i) (j) (k) 12 347 8910 141 6 10 2 13 47 89 16 14 1 23 47 89 16 141 0 3 21 98 74 10 14 16 4 23 9871 10 14 16 8 37 42 19 16 141 0 7 43 9821 10 ... we wish to hire. 158 Chapter 6 Heapsort 1 23 45 67 8910 1 23 45 67 8910 1 23 45 67 8910 1 23 45 67 8910 1 23 45 67 8910 1 23 45 67 8910 4 13 2910 14 8 7...
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INTRODUCTION TO ALGORITHMS 3rd phần 3 potx
... key k not already stored in the table is equally likely to hash to any of the m slots. The expected time to search unsuccessfully for a key k is the expected time to search to the end of list ... keys) K (actual keys) 0 m–1 k 1 k 2 k 3 k 4 k 5 h(k 1 ) h(k 4 ) h(k 3 ) h(k 2 ) = h(k 5 ) Figure 11.2 Using a hash function h to map keys to hash-table slots. Because keys k 2 and k...
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INTRODUCTION TO ALGORITHMS 3rd phần 5 pdf
... 41 (h) 17 30 242 3 26 35 46 7 21 18 52 38 39 41 17 30 242 3 26 35 46 7 21 18 52 38 39 41 17 30 242 3 26 35 46 7 21 18 52 38 39 41 17 30 242 3 26 35 46 7 21 18 52 38 39 41 17 30 24 23 26 35 46 7 21 18 ... summary proto-vEB(16) 0 1 cluster u 4 summary proto-vEB (4) 0 1 A proto-vEB(2) 1 1 0 1 cluster u 4 summary proto-vEB (4) 0 1 cluster u 4 summary proto-vEB (4...
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INTRODUCTION TO ALGORITHMS 3rd phần 6 pdf
... difference constraints: x 1 x 2 Ä 4 , x 1 x 5 Ä 5 , x 2 x 4 Ä6 , x 3 x 2 Ä 1 , x 4 x 1 Ä 3 , x 4 x 3 Ä 5 , x 4 x 5 Ä 10 , x 5 x 3 Ä 4 , x 5 x 4 Ä8 . 24. 4-3 Can any shortest-path weight ... from s to in G 0 is a shortest path from s to in G. 24. 4 Difference constraints and shortest paths 667 0 0 0 0 0 0–1 1 5 4 –1 –3 –3 0 –5 –3 0–1 4 v 3 v 2 v 1...
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INTRODUCTION TO ALGORITHMS 3rd phần 7 pps
... example, a call to FIB.6/ recursively calls FIB.5/ and then FIB .4/ . But, the call to FIB.5/ also results in a call to FIB .4/ . Both instances of FIB .4/ return the same result (F 4 D 3). Since the ... comes into the picture, executing instructions 4 6. Processor 2 reads x from memory into register r 2 ; increments it, producing the value 1 in r 2 ; and then stores this value into...
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INTRODUCTION TO ALGORITHMS 3rd phần 9 docx
... as another, to within a polynomial-time factor. That is, if L 1 Ä P L 2 ,thenL 1 is not more than a polynomial factor harder than L 2 ,whichis 1066 Chapter 34 NP-Completeness 34. 2 -4 Prove that ... language HAM-PATH DfhG; u; iWthere is a hamiltonian path from u to in graph Gg belongs to NP. 34. 2-7 Show that the hamiltonian-path problem from Exercise 34. 2-6 can be solved in pol...
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