Mechanics Analysis Composite Materials Episode 3 docx

... l)8;] e-’.<? , (3. 40) 1= I where, in accordance with Eq. (3. 36) (3. 41) Qi A; = 2psin- 2 and Oj are determined with Eq. (3. 39). Using Eq. (3. 38) we can transform Eq. (3. 40) to the ... be seen in Fig. 3. 35, not only first-order model, Eq. (3. 76), but zero-order model, Eqs. (3. 61), as well, provide fair prediction for E,, while Figs. 3. 36 an...

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... 0.1 0 .3 0 .35 0. 13 conductivity Longitudinal 7.4 -0 .3 -3. 6 4.1 8 0.8 CTE 10' XI (]/"a Transverse 22.4 34 60 19.2 8 0.8 CTE IO" (1PC) 4 W/m K) (W/m K) 31 6 1- 0.8 ... corresponding to mechanical model in Fig. 7.16. 30 8 Mechanics and analysis of composite materials These equations generalize Eqs. (3. 76)- (3. 79) for the case of...

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... bending or stretching 10 30 -mm-long Fig. 3. 30. Specimens of matrix material. Fig. 3. 31. Testing of the matrix specimen. 86 Advanced mechanics of composite materials 3. 3. Micromechanics of a ply Consider ... of Eqs. (3. 2) and (3. 4) to calculate v f . 76 Advanced mechanics of composite materials −6 −4 −2 0 1 234 z = tan kq z q, ra d z = –tan 2 q 0 Fig. 3. 18. Geometric in...

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... 35 00 35 0 3 IO 910 740 240 3 50 890 2860 150 240 190 220 36 0 30 0 250 400 1 430 130 730 480 130 0 39 60 33 60 33 00 Aramid (12-15) 35 00-5500 140-180 1.4-1.47 39 0 12800 Chapter ... 2.7 10.7 4.5 33 .3 1.8-1.85 80.5 19-19 .3 21.1 10.2 21.5 1.2-1 .3 7.5 1.2-1 .35 5.8 1.2-1 .3 5.8 1 .35 -1.4 3. 7 1 .3- 1. 43 8.5 1.2 6.7 0.95 4.7 1.05 4 ....

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... Reinforced Composites, Vadliev, V.V. and Tarnopol'skii, Yu.M. (1990). Composite Materials, Handbook (V.V. Vasiliev and 271-276; September, 31 3 -31 6; October, 34 3 -34 6; November, 38 5 -38 9. (in ... This condition yields the following cubic equation for a ~3- 1,a2-40- 13= 0 , (2.12) 40 Mechanics and analysis of composite materials 2.7. Compatibility equati...

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... diameter), 94 Mechanics and analysis of composite materials where Substituting Eqs. (3. 101) into Eq. (3. 93) and performing integration in accordance with Eq. (3. 92) we get Here (3. 102) and ... deformation. Chapter 3. Mechanics of a unidirectional ply Then, Eqs. (3. 92H3.94) yield 93 (3. 97) Substituting Eqs. (3. 96) and (3. 97) into inequality (...

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... 1998). Material Glass-epoxy Carbon-poxy Aramid-epoxy Boron-AI G 23 GPa) 4.1 3. 2 1.4 49.1 132 Mechanics and analysis of composite materials accordance with Eq. (4.21). To do this, we need ... + d28 + 2d3a1o2 + d4~: + 3ds01o22 + dko:a2 + d7al + 3di3o:a$ + 2d14a:a; + 5dlsolo; + rn1022:~ +k20lz:~ + 3rnz~+:~ + 4rn30:z:~ + 2rn4ozz?,, YU = ~1712 + ~ 2 4 ~ + c3z...

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... Mechanics and analysis of composite materials where EXi = Ex3 = E1 KX2 = E2, Ezi = E2, GXzi = Gxz3 = G 131 Gxz2 = G 23, vx2i = vxz3 = VI31 v,2 = v 23 and El, E2, G 13, G 231 ... 2 630 1420 2000 890 1100 a?l 225 690 1125 590 840 400 100 520 c:l 3 1. 43 1.5 2. 63 0.62 0.50 0.47 0.27 82 0 .31 0.45 0.75 0.2 0 .37 0.1 0.05 0. 13 El /E2 9....

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... frame IS1 = sllll SI122 SI 133 SI112 SI1 13 SI1 23 32 222 s2 233 s2212 s22 13 s22 23 s 333 3 S 331 2 S 331 3 s 332 3 SI212 SI2 13 SI2 23 SYm SI3 13 SI3 23 s 232 3 is the stiffness matrix in which ... aid of Eqs. (4.1 73) for the material with El = 12.9 GPa, E2 = 5.2 GPa, E3 = 3 GPa, G12 = G 13 = 1.5 GPa, G 23 = 1 GPa, v21 = 0.15, ~31...

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... typical advanced composites. Property Glass-epoxy Carbon-poxy Aramid-epoxy Boron+poxy Boron-AI Modulus, E, GPa 27.0 54.8 34 .8 80 .3 1 83. 1 Poisson’s ratio, v 0 .34 0 .3 1 0 .33 0 .33 0.28 Specific ... = 100 mm, BI~ = 7.7 GPa mm, E12 = 3. 2 GPa mm2, 822 = 35 .3 GPa mm, c22 = 26.5 GPa mm2 . 232 Mechanics and analysis of composite materials Conside...

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