Intro to Naval Architecture 3E Episode 1 pptx

... published as Naval Architecture for Marine Engineers, 19 75Reprinted 19 78, 19 81 Second edition published as Muckle's Naval Architecture, 19 87Third edition 19 96Reprinted 19 97, 19 99, ... intentionally left blankIntroduction to Naval Architecture Introduction to Naval Architecture Third EditionE. C. Tupper, BSc, CEng, RCNC, FRINA, WhSchOXFORD AMSTERDAM BOSTON LONDON NEW ... viiAcknowledgements ix 1 Introduction 1 2 Definition and regulation 53 Ship form calculations 19 4 Flotation and stability 305 The environment 81 6 Seakeeping 10 07 Strength 12 18 Resistance...

... 7.2(l>e00,40.8 1, 2 1. 62.02.45(o)J00 .10 60.3250.3000 .14 50.0600RAO0 10 3 12 0 10 6957764(RAO)20 10 609 14 400 11 236902559294096E(ti>J A0 11 24.64680.03370.8 13 08.6355.70Simpson's ... as in Figure 7 .10 . Further, laboratory tests 14 of a range of 15 4 STRENGTHTable 7.3Weat her groupI 11 HIIVvBeauj0468 10 fort m to to to to to umber3579 12 &a conditions;Calm ... routesTanker routes 1 51 71 II 31 23Weather groupIII 14 5.5IV3.50.4V0.50 .1 Figure 7 .14 Probability curvebending moment or stress any new ship should be able to withstand. Ifthe...

... NationalPhysical Laboratory Ship Division Report No. 10 .2. Carlton, J. S. (19 94) Marine propellers and propulsion. Butterworth-Heinemann.3. Gawn, R. W. (19 53) Effect of pitch ... Maritime Defence, June. 11 . Glover, E. f. (19 66-67) Contra rotating propellers, for high speed cargo vessels.TNECL 12 . Burrill, L. C. and Emerson, A. (19 62-63) Propeller cavitation.' ... also difficult to measure the initialreaction to the rudder accurately in this manoeuvre. On the otherhand a ship does often need to turn through angles of 10 ° to 30°. It isMANOEUVRING...

... 3 .1 X0 1 2345678y 1. 0 1. 2 1. 5 1. 6 1. 5 1. 3 1. 10.90.6SM 1 4242424]TotalsF(A) 1. 04.83.06.43.05.22.23.60.629.8xy0 1. 23.04.86.06.56.66.34.8f(My)04.86.0 19 .2 12 .026.0 13 .225.24.8 11 1.2x*y0 1. 26.0 14 .424.032.539.644 .1 38.4Fry04.8 12 .057.648.0 13 0.079.2 17 6.438.4546.4f 1. 0 1. 442.252.562.25 1. 69 1. 21 0. 81 0.36f(Mx) 1. 05.764.50 10 .244.506.762.423.240.3638.78/ 1. 0 1. 7283.3754.0963.3752 .19 7 1. 3 31 0.7290. 216 F(4) 1. 06. 912 6.750 16 .3846.7508.7882.6622. 916 0. 216 52.378First ... 3 .1 X0 1 2345678y 1. 0 1. 2 1. 5 1. 6 1. 5 1. 3 1. 10.90.6SM 1 4242424]TotalsF(A) 1. 04.83.06.43.05.22.23.60.629.8xy0 1. 23.04.86.06.56.66.34.8f(My)04.86.0 19 .2 12 .026.0 13 .225.24.8 11 1.2x*y0 1. 26.0 14 .424.032.539.644 .1 38.4Fry04.8 12 .057.648.0 13 0.079.2 17 6.438.4546.4f 1. 0 1. 442.252.562.25 1. 69 1. 21 0. 81 0.36f(Mx) 1. 05.764.50 10 .244.506.762.423.240.3638.78/ 1. 0 1. 7283.3754.0963.3752 .19 7 1. 3 31 0.7290. 216 F(4) 1. 06. 912 6.750 16 .3846.7508.7882.6622. 916 0. 216 52.378First ... 3 .1 X0 1 2345678y 1. 0 1. 2 1. 5 1. 6 1. 5 1. 3 1. 10.90.6SM 1 4242424]TotalsF(A) 1. 04.83.06.43.05.22.23.60.629.8xy0 1. 23.04.86.06.56.66.34.8f(My)04.86.0 19 .2 12 .026.0 13 .225.24.8 11 1.2x*y0 1. 26.0 14 .424.032.539.644 .1 38.4Fry04.8 12 .057.648.0 13 0.079.2 17 6.438.4546.4f 1. 0 1. 442.252.562.25 1. 69 1. 21 0. 81 0.36f(Mx) 1. 05.764.50 10 .244.506.762.423.240.3638.78/ 1. 0 1. 7283.3754.0963.3752 .19 7 1. 3 31 0.7290. 216 F(4) 1. 06. 912 6.750 16 .3846.7508.7882.6622. 916 0. 216 52.378First moment...

... 9.3 m, MCT 1 m = 10 5 MNm,LCF = 2.7m aft of amidships.SolutionTrim lost when touching downDistance from heel of sternframe to LCFMoment applied to ship when touching downTrimming ... curve, up to a given angle, is proportional to the energyneeded to heel it to that angle. It is a measure of the energy it canabsorb from wind and waves without heeling too ... of tanks should be kept to aminimum. One way of reducing them is to subdivide wide tanks intotwo or more narrow ones. In Figure 4 .17 a double bottom tank is shownwith a...

... Strong gale 10 Storm 1 1 Violent storm 12 HurricaneLimits oj(knots)I 1 to 34 to 67 to 10 11 to 16 17 to 21 22 to 2728 to 3334 to 40 41 to 4748 to 5556 to 6364 and ... and overspeed(m/s)0.30.3 to 1. 5 1. 6 to 3,33.4 to 5.45.5 to 7.98.0 to 10 .7 10 .8 to 13 .8 13 .9 to 17 .1 17,2 to 20.720.8 to 24,424.5 to 28.428.5 to 32.632.7 and overgeneration ... highPhenomenal00 to 0 .10 0 .10 to 0,500.50 to 1. 25 1. 25 to 2,502.50 to 4.004.00 to 6.006.00 to 9.009.00 to 14 .00Over 14 description of a sea state, related to significant...

... due to thestructure: (1) Becoming distorted due to being strained past the yield point.This will lead to permanent set and the distortion may lead to systems being unable to ... the still water and wavemoments, giving:Sagging = 797+ 718 = 15 15MNmHogging = 797- 718 = 79MNmHad the mass of 5000 tonnes been distributed uniformly over thewhole ship length ... roll. The same principlesapply to calculating vibration frequencies as discussed in Chapter 11 . To validate new theories or where theory is judged to be not accurateenough, and...

... ]()7Q0.0083330.0054820.0046880.0033970.0030000.002309Reynolds' number1C)85 X 10 8 10 95 X 10 9 10 1( )5 X 10 '°Q0.0020850.0 016 71 0.0 015 3!0.0 012 650.0 011 720.0009 91 Froude methodUsing Froude's 'circular'or ... ITTC 19 57 linesTable 8.2 Comparison of coefficients from Schoenherr and ITTC formulaeReynolds ' number 10 ° 10 7 10 s 10 9 10 ioSchoenherr0.004 41 0.002930.002070.0 015 30.0 011 7me ... number 10 ° 10 7 10 s 10 9 10 ioSchoenherr0.004 41 0.002930.002070.0 015 30.0 011 7me 19 570.0046880.0030000.0020830.0 015 31 0.0 011 72RESISTANCE 18 1will be less. Whilst it is convenient to picture two wave systemsinteracting,...

... at three displacements ranging from 11 61 tonf (11 .57 MN) to 938 tonf (9.35 MN), and over a speed range of 3 to 12 .5 knots.The pull in the towrope was measured by dynamometer ... W. (18 74) On experiments with HMSGreyhound. TINA. 14 . Denny, Sir Maurice E. (19 51) BSRA resistance experiments on the Lucy Ashton, Part. 1; Full scale measurements. TINA. 15 . ... towed by HMS Active, a vesselof about 310 0 tonf (30.9 MN) displacement, using a 19 0ft (58m)towrope attached to the end of a 45ft (13 .7m) outrigger in Active. Testswere...

... loadingLightLoadedLightLoadedLightLoadedAverageaction2node5952 10 4 15 0 13 5 10 68585Frequency <Vertical3 4 :node node nc 12 1 18 8 2< 10 8 16 6 2$ 17 7290283 210 16 8 18 0 240yf vibrationf5 2tde nodeIS 10 3 10 83 15 5230200 18 0 13 5 12 0larizontal3 ... SHOCK 279Figure 11 ,1 Magnification factordisplacement to the static displacement is termed the magnificationfactor, Q. Q is given by:Curves of magnification factor can be plotted ... plotted against tuning factor fora range damping coefficients as in Figure 11 .1. At small values of A, Qtends to unity and at very large values it tends to zero. In between...