Engineering Tribology 2E Episode 10 pptx
Engineering Tribology 2E Episode 10 pptx
... concentrations reaching 5% [49]. 0 50 100 150 10 100 100 0 10 4 10 5 10 6 Number of cycles to disruption Slip amplitude [µm] Vacuum evaporation Sputtering 100 V bias 200V bias Ion Plating FIGURE ... enriched with the additives dibenzyl 410 ENGINEERING TRIBOLOGY 128 C. Kajdas, Physics and Chemistry of Tribological Wear, Proceedings of the 10th International Tribology Co...
Ngày tải lên: 13/08/2014, 16:21
Engineering Tribology 2E Episode 4 pptx
... (4.39) for ‘dx’, 152 ENGINEERING TRIBOLOGY Introducing a variable ‘∆’: () c R ∆= LUη W 2 (4. 110) which is also known as the ‘Sommerfeld Number’ or ‘Duty Parameter’, equation (4 .109 ) becomes: ... 1.0 0.01 0.02 0.03 0.04 0.05 0.06 0.08 0.1 0.2 0.3 0.4 0.5 0.6 0.8 1 2 3 4 5 6 8 10 20 30 40 50 60 80 100 L D = ∞ = 1 1 2 = 1 4 = 1 8 = 0.02 0.03 0.04 0.05 0.06 0.08 0.1 0.2 0.3 0.4...
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Engineering Tribology 2E Episode 5 pptx
... 1.7575 10 4 -0.793 2.033 2.596 1.042 0.884 -1. 510 - - 1 .108 - 8 H [W] 2.7915× 10 3 -0.579 1.530 0.873 2.500 1.642 -0.225 - - 9 ε 1.0516× 10 2 0.399 -1.040 1.372 -0.539 -0.458 0.765 - - 10 T max ... ε 1 W [N] 2.7861 × 10 1 -1 .100 2.460 2.512 0.563 0.528 -1.090 -0.383 - - - 1.385 - 2 H [W] 3.9307× 10 3 -0.706 1.577 0.477 2.240 1.287 0.249 -0.204 - 1 .324 - - 3 ε 1.2666× 10 -2...
Ngày tải lên: 13/08/2014, 16:21
Engineering Tribology 2E Episode 1 pot
... logs, equation (2.6) should be in the form: log 10 log 10 (υ cS + 0.6) = log 10 (log 10 b + 1/T c ) consequently, a' − clog 10 T ≠ log 10 (log 10 b + 1/T c ) Despite this the ASTM chart is ... Oil 20 VI Mineral Oil 100 VI Mineral Oil 150 VI -40 -20 0 20 40 60 80 100 120 140 160 Di-ester 140 VI Chlorinated Silicone 185 VI 100 000 10 000 5 000 1 000 500 200 100 50 20...
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Engineering Tribology 2E Episode 2 ppsx
... footprints are always dry. υ Kinematic viscosity 100 200 500 1 000 2 000 10 100 1 000 10 000 100 000 350 cS silicone SAE 30 SAE 20W/50 100 0 cS silicone Shear rates -1 [cS] [s ] u/h FIGURE ... 1st World Congress in Bioengineering, San Diego, Vol. II, 1990, pp. 269. 21 Z. Rymuza, Tribology of Miniature Systems, Elsevier, Tribology Series 13, 1989. 40 ENGINEERING TRIBOLOGY...
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Engineering Tribology 2E Episode 3 potx
... [27]. 10 0 10 1 10 2 10 3 10 4 10 5 B A C D Soap content [%] A 0.0 B 3.0 C 10. 1 D 22.5 Apparent viscosity [P] 10 -2 10 -1 10 0 10 1 10 2 10 3 10 4 10 5 10 6 Shear ... average contact load limit for oil is 2020 [kN/m] and for grease 1344 [kN/m]). 100 ENGINEERING TRIBOLOGY 80 ENGINEERING TRIBOLOGY these applications. In space...
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Engineering Tribology 2E Episode 6 pdf
... the value of flow ‘Q’ is: Q = 0.5 × 6.8 × 0.2 × 10 × 0.0004 = 2.72 × 10 -3 [m 3 /s] = 2.72 [litres/s] 234 ENGINEERING TRIBOLOGY Start Acquire parameters Maximum film thickness Minimum film ... of the rigid pad. At the pad thickness of 100 [mm], load capacity is only reduced by about 10% as compared to a rigid pad. It can thus be concluded that 100 [mm] is close to the optimum...
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Engineering Tribology 2E Episode 7 doc
... 10th Leeds-Lyon Symp. on Numerical and Experimental Methods in Tribology, Sept. 1983, editors: D. Dowson, C.M. Taylor, M. Godet and D. Berthe, Butterworths, 1984, pp. 60-70. 258 ENGINEERING TRIBOLOGY In ... non-dimensional quantities gives the non-dimensional damping coefficient, i.e.: ∆W* w*W* C* = (5 .102 ) 274 ENGINEERING TRIBOLOGY Equating flow through the orifice to the total...
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Engineering Tribology 2E Episode 8 ppt
... 100 200 500 100 0 2000 5000 10 4 2 × 10 4 5 × 10 4 10 5 2 × 10 5 5 × 10 5 10 6 2 × 10 6 5 × 10 6 10 7 200 500 100 0 2000 5000 10 4 2 × 10 4 5 × 10 4 10 5 2 × 10 5 5 × 10 5 10 6 100 50 20 10 Piezoviscous-elastic Piezoviscous-rigid Lubrication ... by [15]: 316 ENGINEERING TRIBOLOGY Ellipticity parameter k = 1.25 -2 -1 0 1 x = x b 2.5 6 1.25 Ellip...
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Engineering Tribology 2E Episode 9 potx
... 1748.96 [MPa] π(1.82 × 10 −4 ) × (5 × 10 −3 ) 5 × 10 3 hence: 2.45 × 0.2 × (1748.96 × 10 6 ) 1.5 (46.7 × 7800 × 460) 0.5 2 − 1 = 184.91 [°C] T f maxc = 6 × 10 −3 2.308 × 10 11 () 0.5 Frictional ... (1.82 × 10 −4 ) 2 × (13.02 × 10 −6 ) = 13.98 372 ENGINEERING TRIBOLOGY 0.4µ 0.3 0.2 0.1 Concentration of additive [Moles/m 3 ] 0.01 0.02 0.05 0.1 0.2 0.5 1 2 5 10 20...
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