Engineering Tribology 2E Episode 4 pptx

... ratios. 0 0 1 0 .48 2 0.2 0 .46 6 0 .4 0 .45 3 0.6 0 .44 2 0.8 0 .43 1 1.0 0 .42 2 1.2 0 .41 4 1 .4 0 .40 6 1.6 0.399 1.8 0.393 2.0 0.387 2.2 0.381 2 .4 0.376 2.6 0.371 ... h 1 = h 0 (K + 1) (4. 44) Substituting into (4. 43) the constants ‘ h ’ and ‘C’ in terms of ‘K’ are: = 2h 0 (K + 1) h ¯ (K + 2) C = 1 h 0 (K + 2) (4. 45)...

Ngày tải lên: 13/08/2014, 16:21

... discussed in Chapter 2. y z 41 ° 42 ° 43 ° 45 ° 46 ° 48 ° 47 ° 49 °50° 45 ° 44 ° 42 ° 40 ° 37° 35° 30° 27° Shaft Oil film Bush 36.5° 37° 41 ° 43 ° 45 ° 48 ° 49 ° 50° 39° 41 ° 43 ° 37.5° Oil supply groove Shaft Oil film Bush Attitude ... Vol. 102, 1980, pp. 43 9 -44 4. 43 B.A. Gecim, Non-Newtonian Effects of Multigrade Oils on Journal Bearing Performance, Tribology T...

Ngày tải lên: 13/08/2014, 16:21

... Tribology, Vol. 113, 1991, pp. 327-3 34. 116 H.A. Spikes and A. Cameron, A Comparison of Adsorption and Boundary Lubricant Failure, Proc. Roy. Soc., London, Series A, Vol. 336, 19 74, pp. 40 7 -41 9. 117 ... 1970, pp. 1 74- 178. 89 A.W. Batchelor, A. Cameron and H. Okabe, An Apparatus to Investigate Sulfur Reactions on Nascent Steel Surfaces, ASLE Transactions, Vol. 28, 1985, pp. 46 7 -47...

Ngày tải lên: 13/08/2014, 16:21

... ENGINEERING TRIBOLOGY 9 .4 Summary 44 2 References 44 2 10 FUNDAMENTALS OF CONTACT BETWEEN SOLIDS 44 7 10.1 Introduction 44 7 10.2 Surfaces of solids 44 7 Surfaces at a nano scale 44 8 Surface topography 44 9 Characterization ... condition 143 Load capacity 144 4. 5 Journal bearings 146 Evaluation of the main parameters 146 · Bearing geometry 146 · Pressure distribution 148...

Ngày tải lên: 13/08/2014, 16:21

... 000 35 40 45 50 60 70 80 90 2 2.5 3 3.5 4 4.5 5 6 7 8 9 10 15 20 25 30 35 40 45 50 60 70 80 90 1.9 1.8 1.7 1.6 1.5 1 .4 1.3 1.2 25 30 35 40 45 50 60 70 80 90 100 150 200 250 300 350 40 0 45 0 30 35 40 45 50 60 70 80 90 100 150 200 250 300 350 40 0 100 120 FIGURE ... 3.52 ISO VG 5 4. 14 4.6 5.06 ISO VG 7 6.12 6.8 7 .48 ISO VG 10 9.00 10 11.0 ISO VG 15 13.5 15 16.5 ISO VG 2...

Ngày tải lên: 13/08/2014, 16:21

... w h dxdy (4. 13) LUBRICANTS AND THEIR COMPOSITION 79 T ABLE 3.3 NLGI grease classification [28]. 000 44 5 - 47 5 00 40 0 - 43 0 0 355 - 385 1 310 - 340  2 265 - 295 3 220 - 250 4 ... 17, 19 74, pp. 283-289. 49 F.G. Rounds, Some Effects of Amines on Zincdialkyldithiophosphate Antiwear Performance as Measured in 4- Ball Wear Tests, ASLE Transactions, Vol. 24, 198...

Ngày tải lên: 13/08/2014, 16:21

... constant, i.e.: 222 ENGINEERING TRIBOLOGY Substituting (5 .40 ) and (5 .46 ) into (5 .47 ) yields: ∂ ∂x ⌠ ⌡ h 0 M∂z + U ∂ ∂y ⌠ ⌡ h 0 N∂z () ∂p ∂x + ⌠ ⌡ h 0 M∂z ( ∂p ∂y ) = 0 (5 .48 ) This equation can ... bearing is c = 0.00 04 [m], then from equation (5.87) the value of flow ‘Q’ is: Q = 0.5 × 6.8 × 0.2 × 10 × 0.00 04 = 2.72 × 10 -3 [m 3 /s] = 2.72 [litres/s] 2 34 ENGINEERING TR...

Ngày tải lên: 13/08/2014, 16:21

... applied to distinguish between these surfaces: if the centre of curvature 2 54 ENGINEERING TRIBOLOGY 1 3 4 0 0.1 0.2 0.3 0 .4 0.5 0.6 Misalignment parameter t Dimensionless critical frequency 2 FIGURE ... was published by Grubin in 1 949 [1]. It was found that the combination of three effects: 2 84 ENGINEERING TRIBOLOGY p p kk σ 1 σ 1 σ 3 W Body A Body B Interface 45 ° FIG...

Ngày tải lên: 13/08/2014, 16:21

... × 10 −3 ) = 55 .4 [MPa] p average = W 4bl = 5 4 × (5.75 × 10 −6 ) × (5 × 10 −3 ) = 43 .5 [MPa] · Maximum Deflection = 2 .40 × 10 −8 [m] δ= 0.319 W E'l [] 2 3 [)] + ln ( 4R A R B b 2 = 0.319 [] 2 3 [)] + ... steady-state component [45 ]. The flash temperature theory was originally formulated by Blok in 1937 [46 ] and developed further by Jaeger in 1 944 [47 ] and Archard in 1958 [...

Ngày tải lên: 13/08/2014, 16:21

... Tallian and J.I. McCool, An Engineering Model of Spalling Fatigue Failure in Rolling Contact, II. The Surface Model, Wear, Vol. 17, 1971, pp. 44 7 -46 1. 336 ENGINEERING TRIBOLOGY If the contacting ... b = πlE' () 4WR' 0.5 = 4 × (5 × 10 3 ) × (6 × 10 −3 ) π × (5 × 10 −3 ) × (2.308 × 10 11 ) () = 1.82 × 10 4 [m] 0.5 · Thermal Diffusivity χ= ρσ K = 46 .7 7800 × 46 0 =...

Ngày tải lên: 13/08/2014, 16:21