Aircraft Structures 3E Episode 3 potx

... 2 13 0 0 160 13 0 0 0 - 160J2 /3 0 FB 4000J2 -20000J2 d2pB.f 13 ~2 13 DC 4000 80 000 PB,f 13 1 13 pDsf 1 32 0 13 320 PD,f 1 32 0 13 320 1 480 13 240 BA 4000 60 000 2pB,f /3 2 13 ... -2J2pB,f /3 -2J2 13 0 0 32 0J2 0 EF 4000 -60 000 -2pB,f /3 -2 13 0 0 160 0 FD 4000J2 -80000J2 -d2PB.f /3 - ~2 13 0 0 640J2 13 0 CB 4000 80...

Ngày tải lên: 13/08/2014, 16:21

... instability 1 53- 97 Structural idealization 32 7-41 beams 33 1 ,33 2 33 6-8 beams 34 0 Aircrafi Structures for Engineering Students provides a comprehensive self- contained course in aircraft structures. ... beam 36 3-6 bending 38 1 -3 deflections 404,405 idealized three-boom shell 38 0, 38 1 method of successive approximations shear 38 7-92 shear centre 39 2...

Ngày tải lên: 13/08/2014, 16:21

... by bd3 where I = - VL3 ti=- 3EI 12 ti=-{ FL3 1-ptana } 3EI p + tana Insertion force F= (Lfd)l { :-:E:} (2.21) For polypropylene in the situation given, Fig. 2. 23 shows ... Plastics Thickness = 1.2 mm Fig. 2.14 Acetal bottle cap given by 3pR2(1 + u) - 3 x 0 .37 5 x ( 13) 2(1 .33 ) - 8h2 8( 1 .2)2 o = 22 m/m2 o= After 1 month (2.6 x...

Ngày tải lên: 13/08/2014, 09:20

... 235 238 244 248 25 1 257 27 1 272 272 276 276 29 1 295 30 0 30 7 31 6 32 2 32 7 33 1 34 2 34 5 36 2 3 62 3 74 1.9 Strain 17 Fig. 1.12 Displacement of line elements OA, ... ‘flutter’ References Problems 38 0 406 415 425 432 432 432 4 43 4 43 445 449 455 465 485 486 494 495 496 497 500 507 507 509 516 533 533 533 540...

Ngày tải lên: 13/08/2014, 16:21

... The torsion constant J follows from the substitution of Eq. (3. 26) into Eq. (3. 13) , giving St3 J=- 3 (3. 29) and 3T - - St3 rzy,max - These equations represent exact solutions when ... conditions are satisfied. PX ax = - [5y(x2 - z2) - ioy3 + 6dZy] 20d3 ay = E( - 3yd2 - 2d3) 4d3 -P 40d3 Txy = - [5(3x2 - Z2)(y2 - d2) - 5y4 + 6y2d2 - $1...

Ngày tải lên: 13/08/2014, 16:21

... z Fig. 5.8 Plate supporting a distributed transverse load. 5 .3 Distributed transverse load 133 _1___1_1__ 5 .3. 2 The built-in edge If the edge x = 0 is built-in or firmly ... the plate is 3: 4:5. Calculate the deflection at the point of application due to a lOON load placed at a point equidistant from the three sides of the plate. Ans. 0 .33 mm. P.4 .3 The p...

Ngày tải lên: 13/08/2014, 16:21

... of the minor axis. 3PU - 3) 2~t3 -+-+- 32 Am. wO= (d a2b2 b4 f3pa2b2(b2 + v2) 9(3b4 + 2a2b2 + 3d) ’ k3pa2b2(d + vb2) uyulmax = t2(3b4 + 2a2b2 + 3d) Centre, ~;r,,.,= ... (6 .34 ) becomes d2v Wa -+A v= dz2 EII the general solution of which is (6 .36 ) Wa PI w = A cos Xz + Bsin XZ - -z Similarly, the general solution of Eq. (6 .35 ) is (...

Ngày tải lên: 13/08/2014, 16:21

... their high strength. Covered by Specification DTD 36 3 issued in 1 937 , these alloys had a nominal composition: 2.5 per cent copper, 5 per cent zinc, 3 per cent magnesium and up to 1 per cent nickel ... the web is 2000 mm4; E = 70 000 N/mm2. From Eq. (6.108) = 0.71 43 4 1 +2 x 400/(2 x 35 0) 1 + 2 x 30 0 /30 0 tan a= Problems 199 tv I vo Fig. P.6.4 P.6...

Ngày tải lên: 13/08/2014, 16:21

... 130 APU exhaust 131 Engine fuel control unit 132 Engine bay venting ram air Intake 133 Rotary nozzle bearing 134 Nozzle fairing construction 135 Ammunition tank, 100 rounds 136 ... 30 Aft fuselage frames 31 Rudder hydraulic actuator 32 Avionics equlpment alr conditionlng plant 33 Avlonlcs equlpment racks 34 Heat exchanger ram air intake 35 Electrical system c...

Ngày tải lên: 13/08/2014, 16:21

... t uz = - (6.8 63, - 10 .30 ~) uz = - (3. 43h - 10 .30 ~) which is linear. Hence 1.72Mx h3 t UZJ = -~ (compressive) 3. 43Mx uz,2 = +- (tensile) h3 t In the web h/2 < y ... linear form and is given by the equation uz = %6.86y ht whence 3. 43M, h3 t cz,2 = +- (tensile) and 3. 43Mx h3 t a, ,3 = (compressive) The distribution in the lower...

Ngày tải lên: 13/08/2014, 16:21