Seamanship Techniques 2 Episode 6 pps
Seamanship Techniques 2 Episode 6 pps
... unfavourable conditions of trim of up to 10° and with
the ship listed not less than 20 ° either way.
20 6 Seamanship Techniques
Every life raft should be capable of withstanding exposure for 30 days
of ... be passed around
the foot of the sail, never around the boom.
WIND
1
2
3
6
7
4
5
Figure 7 .22 Wearing.
1. Boat on port tack.
2. Up helm, ease out main sheets.
3. Wind on port q...
Seamanship Techniques 2 Episode 5 pps
... 6 .23 Cowl ventilators.
Ventilators
closed
Ventilators
open
Ventilators
closed
Ventilators
open
Ventilators
closed
Hold temperature
Outside air (Dewpoint temperature)
°F
74
72
70
68
66
64
62
60
58
123 4 567 891011 121 31415 161 7
Figure ... craft, as built by Aberglen–Welin, is as follows:
Capacity Length (m) Speed (knots)
21 6 .2 6
35 7.3 6
50 8.0 6
66 8.75 6
Speed...
Seamanship Techniques 2 Episode 8 ppsx
... lines 22 7
Fairleads 22 7
Bollard (bitts) 22 7
Rigging slip wires or ropes 22 8
Berthing 23 0
Clearing a berth 23 0
Entering dock 23 2
Securing to buoys 23 2
Mooring 23 3
Letting go from buoys 23 3
Turning ... 20 7
Abbreviations 20 9
9. SHIP-HANDLING
Terms and general definitions 21 0
Factors in ship-handling 21 2
Rudders 21 3
Propellers 21 5
Turning circles 21 9
Bow/stern th...
Seamanship Techniques 2 Episode 10 pps
... towing.
Sources of reference: Rules 21 , 22 , 24 and Annex 1.
Figure 5. 12 Towing.
Figure 5.13 Vessels towing inconspicuous, partly
submerged objects.
72 Seamanship Techniques
Figure 4.7 Vessel with ... 0.5–1 .25
Moderate 1 .25 2. 5
Rough 2. 5–4.0
Very rough 4.0 6. 0
High 6. 0–9.0
Very high 9.0–14.0
Phenomenal over 14.0
Length of swell Length in metres
Short 0–100
Average 100 20...
Seamanship Techniques 2 Episode 13 ppsx
...
330
100
2 + 330×
= 3 36. 6 nautical miles.
Engine distance
=
4.5 115 18 60
18 52
+
4.5 100 6 60
18 52
××× ×××
= 301.8 + 85.33
= 387.13 nautical miles
Propeller slip =
387.1 – 3 36. 6
387.1
... sea
Wind north, Force 2
Relative wind
direction
10°
15°
30°
60 °
90°
120 °
150°
180°
21 0°
24 0°
27 0°
300°
330°
360 °
Starboard
90° – 2 m 53 secs
180° – 5 m 57 s...
MODELLING OF MECHANICAL SYSTEM VOLUME 2 Episode 6 ppsx
... 6 ℓ 0 − 12 6 ℓ
0 6 ℓ 4γℓ
2
06 ℓ 2 ℓ
2
−10 0 1 0 0
0 − 12 6 ℓ 0 12 6 ℓ
0 6 ℓ 2 ℓ
2
06 ℓ 4γℓ
2
⇒ K
(2)
= K
ℓ
1000
0 12 6 ℓ 6 ℓ
0 6 ℓ 12 2 ℓ
2
0 6 ℓ 2 ℓ
2
4γℓ
2
Then, ... found to be:
K
(1)
α
= K
ℓ
4γℓ
2
6 ℓS 6 ℓC 2 ℓ
2
6 ℓS C
2
+ 12 S
2
CS( 12 −1) 6 ℓS
6 ℓC CS( 12 −1)S
2
+ 12 C
2
6 ℓC
2 ℓ
2
6 ℓS 6 ℓC 4γℓ
2
...
Gas Turbine Engineering Handbook 2 Episode 6 pps
... used:
V
2
V
2I
6- 8
(a) (b)
Figure 6 -20 . Impeller channel flow.
Centrifugal Compressors 23 7
//INTEGRA/B&H/GTE/FINAL ( 26 -10-01)/CHAPTER 6. 3D ± 24 1 ± [21 9 27 4/ 56] 29 .10 .20 01 3:59PM
Several ... Type,''
NACA TN - 26 04, 19 52.
27 4 Gas Turbine Engineering Handbook
//INTEGRA/B&H/GTE/FINAL ( 26 -10-01)/CHAPTER 6. 3D ± 23 5 ± [21 9 27 4/ 56] 29 .10 ....
KUNDU Fluid Mechanics 2 Episode 6 ppsx
...
dc/h
=
0
in
Eq.
(7 .66 ),
and assuming
the
deep-water
approximation tanh(2aHlA)
2
I
valid for
H
>
0 .28 A,
we obtain
(7 .67 )
For
an &-water interface at
20
"Cy
the surface ...
cos(k2x
-
Wt).
Applying the trigonometric identity
for
cos
A
+
cos
B,
we obtain
I
r]
=
24 2
cos
[$(k.
-
kl)X
-
z(*
-
w,)f]
cos
[$il
+
k2)x
-
i(O1
+
w2)...
Seamanship Techniques 2 Episode 1 pptx
... conference
Linen
22 222 222 222 2
2
2
2
2
2
2
2
2
2
2
2
2
2
2
2
2
2
2
2
2
2
2
2
2
2
2
2
2
2
2
2
2
2
2
2
2
2
2
2
2
2
2
2
2
2
2
2
2
2
2
2
2
2
2
2
2
2
2
2
2
2
4
2
4
4
4
22 222 222 2
2
222
STR
Store
17The Ship
Gusset Plate
Triangular ... 4
Lift
No .2
Lift
No.3
STR
Engine casing
STR
Bar
STR
Lift No. 5
Ramp
Car deck
vent
Store
Ca...
Seamanship Techniques 2 Episode 2 doc
... shackle
length
12. 5 4.7 6. 7 6. 7 9.4 9.4 13.5 0.105
50.0 70 100 100 140 140 20 0 1.445
60 .0 98.8 141 141 198 198 28 2 2. 075
70 1 32 188 188 26 3 26 3 3 76 2. 85
90 20 9 29 8 29 8 417 417 5 96 4.705
122 357 510 ... breaking strain of 86 tonnes
Rope type Diameter (mm) Circumference (in.)
Nylon 72 9
Polyester 80 10
Polypropylene 88 11
Manilla (grade 1) 1 12 14
Wire (6 ×...