KUNDU Fluid Mechanics 2 Episode 2 potx

... A F AB a a 2 c 2 + F AE + 0= F AB c a 2 c 2 + F 1 − 0= Joint E F ED F AE − 0= F EB F 2 − 0= Joint B F BC F BD b b 2 c 2 + + F AB a a 2 c 2 + − 0= F EB − F BD c b 2 c 2 + − F AB c a 2 c 2 + − 0= F AB F AE F EB F BC F BD F ED ⎛ ⎜ ⎜ ⎜ ⎜ ⎜ ⎜ ⎜ ⎜ ⎝ ⎞ ⎟ ⎟ ⎟ ⎟ ⎟ ⎟ ⎟ ⎟ ⎠ Find ... publisher. Engineering Mechanics - Statics Chapter 6 Solution: Initial Guesses: F CB...

Ngày tải lên: 21/07/2014, 17:20

... in 25 0 300 110 22 0 320 305 26 0 370 absence of oxygen (EC) Maximum temperature in 21 0 24 0 110 180 25 0 23 0 20 0 310 presence of oxygen (EC) Maximum temperature due to 150 180 100 20 0 25 0 28 0 20 0 ... between cSt and SUS viscosities at standard temperatures can also be obtained from ASTM D 21 61. EM 1110 -2- 1 424 28 Feb 99 4-1 Chapter 4 Hydraulic Fluids 4-1. Purpo...

Ngày tải lên: 12/08/2014, 16:20

... Organo-Clay Dropping point (EC) Dropping point (EF) 110 23 0 1 63- 177 32 5 -35 0 096-104 20 5 -22 0 135 -1 43 27 5 -29 0 177 -20 4 35 0-400 26 0+ 500+ 26 0+ 500+ 26 0+ 500+ 24 3 470 26 0+ 500+ Maximum usable temperature (EC) Maximum ... usable temperature (EC) Maximum usable temperature (EF) 79 175 121 35 0 93 20 0 110 23 0 135 27 5 177 35 0 177 35 0 177 35 0 1...

Ngày tải lên: 12/08/2014, 16:20

... Mapping 14 8 15 0 1 52 15 4 15 6 15 7 15 7 15 9 16 0 16 3 16 6 17 0 17 1 17 3 17 5 17 6 18 1 18 4 18 5 18 7 18 8 .I 89 19 0 1 92 1 92 chi!pter 7 Gravity Waves 1 . Introduction 19 4 2 . ... 2 . Analogy between Heat and Vorticity Diffusion 3 . Pressure Change Due to Dynamic Effects 20 9 21 3 21 6 21 8 22 1 22 5 22 7 23 0...

Ngày tải lên: 13/08/2014, 16:21

... whcrc the two are related as (2. 26) (2. 27) As a check, Eq. (2. 27) givcs R11 = 0 and R 12 = -~ 123 ~3 = -w, which is in agree- ment with Eq. (2. 26). (In Chapter 3 we shall call ... (Figure 2. 7). Using Eq. (2. 12) , the components of he stress tensor in the rotated frame are 431 I& -43 .;I = CllC21t 12 + C2ICllt21 = TZU + TlU - TU, ti...

Ngày tải lên: 13/08/2014, 16:21

... il, i2, and i3 changc with time. To this observer the time derivative of P is d ( $)F = Z(plil+ P2i2 + - . dPi . dP2 . dP3 dir di2 di3 - 11 - + 12- + 1 .3 - + ... that a@ aY u -, (3. 34) a$ ax ' v E then Eq. (3. 33) is automatically satisfied. Therefore, a streamfunction JI can be defined whenever Eq. (3. 33) is valid. (A...

Ngày tải lên: 13/08/2014, 16:21

... 'Itucsdcll, C. A. (19 52) . Stokes' principle of viscosity. JoumZ oJRationol Mechanics ud Analysi.s 1: physical Journul131: 4 42 4 47 . Univemity Press. 22 8 -23 1. Supplernim?al Reading ... (5 .22 ) can be written as -V&nqi&ijkWk,jq = -V(&jSqk - &~haqj)wk.jq = -vWk,nk + vOn,jj = v%,jj. (5 .25 ) If we use Eqs. (5 .23 H5 .25 ),...

Ngày tải lên: 13/08/2014, 16:21

... ha2, 25 r 2n 2n m m 25 r 2? r =- 1n(x~-y*-u~+i2xy) 11na~. (6.48) Wc know that the logarithm of any complex quantity C = I< I exp (iQ) can be written as In 5 = In 15 ... 22 1 Logcr of ( hsiant Depth 22 3 Laycr of Vnriahle Depth H (.r) 22 4 Yotilir!fnr Stwpeniirg it1 CI .Voriili'pmii .v Mi~iiinti 22 5 H!rlruulir Jiunp 2...

Ngày tải lên: 13/08/2014, 16:21

... dc/h = 0 in Eq. (7 .66 ), and assuming the deep-water approximation tanh(2aHlA) 2 I valid for H > 0 .28 A, we obtain (7 .67 ) For an &-water interface at 20 "Cy the surface ... the flow. To see this, consider the mechanical energy of a fluid particle at the surrace. E = u2 /2 + gH = Q2/2H2 + gH. Eliminatjng Q by Eq. (7.88) we obtain,...

Ngày tải lên: 13/08/2014, 16:21

... 26 8 Intcrd Fmiidt: Number 26 8 RiclmnLqm Aimher. 26 9 Mwh Niuihs 27 0 I’ra~idtl R’i~nhrx. 27 0 ficrc&es 27 0 Litemlure Cited 27 0 Siipplementul Reading 27 0 ... usccl p” = 6’ N4p ,2/ 2w2g2, found from Eq. (7. 166) after taking its real part. Use of thc dispersion rclation w2 = k2N2/(k2 + m’) shows that Ek = Ep. (7. 169) w...

Ngày tải lên: 13/08/2014, 16:21

... = y/sin0, (1 5.6) where Eq. (15. 4) has been used. We now eliminate 0 between Eqs. (15. 5) and (15. 6). First note from Eq. (15. 6) that cos2e = (2btan fi - y)/2btan p, ... obtain (1 5.4) x2 sinze - y2 cosze = 4b2 sin% cos2e. (15. 5) To understand the shape of the curve represented by Eq. (15. 5) we must express 0 in terms of x, y,...

Ngày tải lên: 13/08/2014, 16:21

... 13.715 I 13.9549 14.1 984 14.4456 14.6965 14.9513 15.2099 15.4724 15.7388 16. 0092 16. 2837 16. 5622 16. WY 17.1317 17.4228 17.71 81 18.01 78 18.3218 18.6303 18.9433 19.2608 19.5828 ... involving thc hc Lwo powers of (M: - 1) do not appear in Bq. (16. 36). U.siug the pressure ratio (16. 31), Eq. (16. 36) can be written 85 3 &-Si y2- 1...

Ngày tải lên: 13/08/2014, 16:21

... mapping, 171 -173 douhlet/dipole. 157-159 forces on two-dimensional body, imp, mclhod or, 143, 170 -171 numcrical zolulion orplanc, 176 1 81 ovcr elliplic cylinder, 173 -174 past ... - . 1.33E - 7 1.38E - 7 1. 42E - 7 1.468-7 1. 52E- 7 1.58E - 7 CP R J@-'K-' V/K 4 217 13.4 4192 9.5 4182 7.1 4178 5.5 4178 4.3 4180 3.5 Latent heat...

Ngày tải lên: 13/08/2014, 16:21

Ngày tải lên: 13/08/2014, 16:21

Ngày tải lên: 18/01/2015, 09:00