Intro to Practical Fluid Flow Episode 10 pps
Intro to Practical Fluid Flow Episode 10 pps
... test
TiO
2
slurry. 17.3% in batch test
Extended Wilhelm-Naide equation
10
1
10
2
10
–7
3456789
10
–2
10
–6
10
–4
10
–5
10
–3
10
–1
Figure 6.8 Measured settling velocities for unflocculated slurries. ... point of inflection = 109 .5kg/m
3
Figure 6.18 Simulated batch settling curve for a compressible sediment generated
using the FLUIDS toolbox
188 Introduction to Practical...
Intro to Practical Fluid Flow Episode 1 ppsx
... (angle)
1
(p=180) rad
liter L 1 L 10
À3
m
3
metric ton t or tonne 1 t 100 0 kg
bar bar 1 bar 0:1 Mpa 100 kPa 10
5
Pa
4 Introduction to Practical Fluid Flow
//SYS21///INTEGRAS/B&H/IPF/FINAL_13-09-02/0750648856-CH000-PRELIMS.3D ... Data
King, R.P.
Introduction to practical fluid flow
1 Fluid dynamics
I Title
620.1
H
064
Library of Congress Cataloguing...
Intro to Practical Fluid Flow Episode 4 pps
... data
Drag coefficient from the Karamanev equation
10
–2
10
–1
10
1
10
1
10
2
10
2
10
0
10
0
10
3
10
3
10
4
10
5
10
7
10
6
10
8
10
10
10
9
10
11
10
12
10
13
Figure 3.3 Drag coefficient for solid spheres ... from equation 3.8
Dimensionless group = /Φ
1pD
Re C
10
–2
10
–1
10
1
10
1
10
2
10
2
10
0
10
0
10
3
10
3
10
4
10
5
10
7
10...
Intro to Practical Fluid Flow Episode 2 potx
... average
velocity to be known. The use of Q* for practical problem solving is described
in the following illustrative example.
10
4
10
5
10
6
10
7
10
8
10
9
10
10
10
11
10
12
10
-3
10
-2
Dimensionless flowrate ... number
Re
Friction factor
f
Friction factor for Newtonian fluids
10
–3
10
3
10
4
10
5
10
6
10
7
e/D = 0.0500
e/D = 0.0250
e/D = 0. 0100
e/D = 0...
Intro to Practical Fluid Flow Episode 3 docx
... 10
À3
m
3
=s
h
Pu
10: 15 m
"
g
f
h
Pu
Q
P
9:81 Â 100 0 Â 10: 15 Â 8:8325 Â 10
À3
2:983 Â 10
3
0:295
38 Introduction to Practical Fluid Flow
//SYS21///INTEGRAS/B&H/IPF/FINAL_13-09-02/0750648856-CH02.3D ... multiply by
ÁP
Pu
ÀW Â 100 0 3:751 MPa
h
Pu
ÁP
Pu
g
382:4 m of water
To convert to kW, multiply by mass flowrate
Power 3:751 10
3
 6:5 Â...
Intro to Practical Fluid Flow Episode 5 pdf
... is referred to the FLUIDS
74 Introduction to Practical Fluid Flow
//SYS21///INTEGRAS/B&H/IPF/FINAL_13-09-02/0750648856-CH04.3D ± 82 ± [81±116/36] 23.9.2002 4:56PM
which is added to the pressure ... particle and fluid m/s.
p
Volume of particle m
3
.
V
Ã
T
Dimensionless terminal settling velocity.
f
Viscosity of fluid Pa s.
f
Density of fluid kg/m
3
.
10
0
10
1...
Intro to Practical Fluid Flow Episode 6 ppt
... by
C
i
Solid flowrate type i
Total flowrate
"
V
w
À
Ti
q
i
"
V
4:70
The two important types of problem are solved as follows.
110 Introduction to Practical Fluid Flow
//SYS21///INTEGRAS/B&H/IPF/FINAL_13-09-02/0750648856-CH04.3D ... the FLUIDS toolbox as shown in the
102 Introduction to Practical Fluid Flow
//SYS21///INTEGRAS/B&H/IPF/FINAL_13-0...
Intro to Practical Fluid Flow Episode 7 pot
... known
Dimensionless flowrate *
Q
Friction factor
f
Friction factor for Bingham plastics
Hedstrom number
10
–1
10
–2
10
–3
10
3
10
4
10
4
10
5
10
5
10
6
10
6
10
7
10
7
10
8
10
9
10
10
10
1
1
10
3
10
8
Figure ... having toknow the slurry velocity or flowrate.
Reynolds number
Re
B
10
0
Friction factor
f
sl
10
–1
10
–2
10
–3
10
3
10
4
10
5
10
6...
Intro to Practical Fluid Flow Episode 8 ppt
... suspension He=4.7 10
4
Thorium oxide suspension He=7.1 10
3
10
2
10
3
10
4
10
5
10
6
10
7
10
8
10
9
Laminar-turbulent transition
10
0
10
1–
10
2–
10
3–
10
2
10
3
10
4
10
5
10
6
10
7
Reynolds number ... factor
H
= 0.1 – 0.2
H
–= 0.3 0.6
H
–= 1.0 1.5
H
–= 2.0 3.0
H
–= 4.0 8.0
H
–= 8.0 10. 0
10
1
10
3
10
2
10
5
10
4
10
6
10
–3
10
–1
10
–...
Intro to Practical Fluid Flow Episode 9 docx
... 650(C/700) + 4x10 (C/700) + 10 (C/700)
vV
1.58 4 5.02 5 9.3
T
Calculated settling velocity. / = 1 + 40.6(C /100 0) + 960(C /100 0)
vV
T
0.341 2.73
10
1
10
2
10
3
10
1
10
0
10
–1
10
–2
10
–3
10
–4
10
–5
Settling ... Â 10
À3
2
23
1=3
0:05 97:67
1 10 100 100 0
Dimensionless pipe diameter *
D
Slurry friction factor
10
–3
10
–2
10
–1
10
0
H =
0.15 0.45 1.25 2...