Intro to Practical Fluid Flow Episode 1 ppsx

... d 1 d  24 h  86400 s degree (angle)  1   (p =18 0) rad liter L 1 L  10 À3 m 3 metric ton t or tonne 1 t  10 00 kg bar bar 1 bar  0 :1 Mpa  10 0 kPa  10 5 Pa 4 Introduction to Practical Fluid ... Prefix Symboll 10 12 tera T 10 9 giga G 10 6 mega M 10 3 kilo k 10 À2 centi c 10 À3 milli m 10 À6 micro m 10 À9 nano n 10 12 pico p Introduction 3...

Ngày tải lên: 13/08/2014, 16:21

... average velocity to be known. The use of Q* for practical problem solving is described in the following illustrative example. 10 4 10 5 10 6 10 7 10 8 10 9 10 10 10 11 10 12 10 -3 10 -2 Dimensionless flowrate ... head, V 2 1 /2   D 1 /D 2 Contraction <45  Re 1 < 2500 K f  1: 6 (1: 2  16 0 Re 1 )( 4 À 1) sin(/2) Re 1 > 2500 K f  1: 6(0:...

Ngày tải lên: 13/08/2014, 16:21

... the FLUIDS toolbox. Power  P  4HP  2:983 Â 10 3 W Q  8:8325 10 À3 m 3 =s h Pu  10 :15 m "  g f h Pu Q P  9: 81 Â 10 00 Â 10 :15 Â 8:8325 Â 10 À3 2:983 Â 10 3  0:295 38 Introduction to ... 16 .67 25 .1 7.65 5.80 0.588 12 00 20.00 36 .1 11. 00 5.79 0.587 14 00 23.33 49.3 15 .03 5. 81 0.589 16 00 26.67 64.3 19 .60 5.80 0.588 18 00 30.00 82.0 24.69 5.84 0.592...

Ngày tải lên: 13/08/2014, 16:21

... data Drag coefficient from the Karamanev equation 10 –2 10 1 10 1 10 1 10 2 10 2 10 0 10 0 10 3 10 3 10 4 10 5 10 7 10 6 10 8 10 10 10 9 10 11 10 12 10 13 Figure 3.3 Drag coefficient for solid spheres ... from equation 3.8 Dimensionless group = /Φ 1pD Re C 10 –2 10 1 10 1 10 1 10 2 10 2 10 0 10 0 10 3 10 3 10 4 10 5 10 7 10...

Ngày tải lên: 13/08/2014, 16:21

... (Regime 1) must lie along the solution locus of the equation 12 :13 C 0:7389 f 0:7 717 w C Ã D À0:4054 Fr 1: 096  10 7 :1 C 1: 018 f 1: 046 w C Ã D À0:4 213 Fr 1: 354 4: 21 90 Introduction to Practical Fluid ... bed (Regime 0) f sl À f w  12 :13 C 0:7389 f 0:7 717 w C ÃÀ0:4054 D Fr 1: 096 4 :17  Saltation (Regime 1) f sl À f w  10 7 :1 C 1: 018 f 1: 046 w C...

Ngày tải lên: 13/08/2014, 16:21

... is V r  4:6 1: 41  3:26 The relative excess pressure drop can now be calculated. C r  0:0 714 0:6  0 :11 9  I  0:5 Â 0 :11 9 Â 1  0 :11 9 0:66   0:07 41 q  3:6 À 5:2 Â 0 :11 9 Â 1 À 0 :11 93:05   0:07 41 ... sphericity 0.98 Fluid density 10 00.0 kg/m Fluid viscosity 0.0 010 kg/ms Solid content 32.0 % 3 R 01 = 1 R 12 = 1 R 02 = 1 R 13 = 1 R 03 =...

Ngày tải lên: 13/08/2014, 16:21

... known Dimensionless flowrate * Q Friction factor f Friction factor for Bingham plastics Hedstrom number 10 1 10 –2 10 –3 10 3 10 4 10 4 10 5 10 5 10 6 10 6 10 7 10 7 10 8 10 9 10 10 10 1 1 10 3 10 8 Figure ... slurry velocity or flowrate. Reynolds number Re B 10 0 Friction factor f sl 10 1 10 –2 10 –3 10 3 10 4 10 5 10 6 10 7 10 8 10...

Ngày tải lên: 13/08/2014, 16:21

... He=4.9 10 × 5 Thorium oxide suspension He=4.7 10 × 4 Thorium oxide suspension He=7 .1 10× 3 10 2 10 3 10 4 10 5 10 6 10 7 10 8 10 9 Laminar-turbulent transition 10 0 10 1 10 2– 10 3– 10 2 10 3 10 4 10 5 10 6 10 7 Reynolds ... 0:60 X 2 0 :14 29 X 3 ÀÁ Re y nolds number Re ∞ Slurry friction factor H = 0 .1 – 0.2 H –= 0.3 0.6 H –= 1. 0 1. 5 H –= 2.0 3.0...

Ngày tải lên: 13/08/2014, 16:21

... is calculated D Ã  11 84 Â 91: 8 2 Â2:7 Â 10 À3  2 23 1= 3 0:05  97:67 1 10 10 0 10 00 Dimensionless pipe diameter * D Slurry friction factor 10 –3 10 –2 10 1 10 0 H = 0 .15 0.45 1. 25 2.5 6 9 Figure ... of time 16 0 Introduction to Practical Fluid Flow //SYS 21/ //INTEGRAS/B&H/IPF/FINAL _13 -09-02/0750648856-CH05.3D ± 15 2 ± [11 7 15 8/42] 23.9.2002 4:41PM...

Ngày tải lên: 13/08/2014, 16:21

... C U  12 96 kg=m 3 ; a  18 2:6 and m  1: 61. Figure 6 .15 Fluids toolbox data input screen that generates figure 6 .14 18 6 Introduction to Practical Fluid Flow //SYS 21/ //INTEGRAS/B&H/IPF/FINAL _13 -09-02/0750648856-CH06.3D ... at steady state 17 2 Introduction to Practical Fluid Flow //SYS 21/ //INTEGRAS/B&H/IPF/FINAL _13 -09-02/0750648856-CH06.3D ± 17 1 ±...

Ngày tải lên: 13/08/2014, 16:21