Plastics Engineering 3E Episode 3 potx

... 45 48 61 66 71 74 81 84 95 95 10 3 11 0 11 6 11 9 12 1 12 1 12 7 13 1 13 4 13 6 13 7 13 8 14 0 14 2 14 2 14 3 14 5 14 5 14 7 14 8 15 0 15 2 15 2 15 4 16 8 16 8 16 8 xiv Preface to the ... G 0.97- 1. 34 1. 1 1 - 1. 21 -50 -13 0 -40 -13 0 40D to 72D 30A to 45D 43 to62 60 to 70 21 to 45 25 to 45 E E E F G P E PIE 1....

Ngày tải lên: 13/08/2014, 09:20

... 0 .25 0 .2 0 .2 0 .2 0.15 0.14 0 .23 0 .22 0 .24 0. 52 - - 0 .2 0.5 0 .25 Ob2 0 .2 0 .22 1.18 - - - 0 .20 0.15 0 .24 0 .25 0 .25 0.16 0.14 0.17 0 .2 0 .2 0.0 32 0.0 32 90 12 111 ... 30 25 70 45 70 115 62 24 0 75 180 55 185 65 105 84 72 33 70 40 10 32 25 50 14 72 40 70 2. 2 2. 8 2. 6 2. 9 1.7 1.3 3.0 2....

Ngày tải lên: 13/08/2014, 09:20

... by bd3 where I = - VL3 ti=- 3EI 12 ti=-{ FL3 1-ptana } 3EI p + tana Insertion force F= (Lfd)l { :-:E:} (2.21) For polypropylene in the situation given, Fig. 2. 23 shows ... 18 mm. 60 Mechanical Behaviour of Plastics Thickness = 1.2 mm Fig. 2.14 Acetal bottle cap given by 3pR2(1 + u) - 3 x 0 .37 5 x ( 13) 2(1 .33 ) - 8h2 8( 1 .2)2 o...

Ngày tải lên: 13/08/2014, 09:20

... above, a4 = 10 MN/m2 at r4 = 300 s SO, ~(350) = 0.003 = 0.3% (iv) and in the same way ~ (45 0) = 0.0 04 = 0 .4% The predicted strain variation is shown in Fig. 2 .43 (b). The ... Behaviour of Plastics 0.1 0.08 Sp 65 - B 0.06 0. 04 0.02 0 0 50 100 150 200 (SI Fig. 2 .46 Variation of strain with time Stress (MN/m*) 0 100 - Time (s) Fig....

Ngày tải lên: 13/08/2014, 09:20

... Steel 5 1.2-2 0. 35- 1.6 0.1 -0.3 5- 7 6 .5 3 .5- 6 .5 0. 25- 4 0.4 -5 0.3-0.8 1.3-1.4 0.01 -0.02 100 8 2-4 4 0.9-1.6 0.3-0 .5 5- 7 1 0 .5- 5 3 1-2.6 3-4 .5 0.7-1.1 1-4 0. 75 140 ... 0.014-0.023 0.0 05- 0.008 0.12 0.1 25 0.0 25- 0. 25 0.06 0.02-0 .5 0. 15- 0.2 0.02 0.03-0.13 0.01 0 .5 17 6 0.2-0 .5 0.02-0.06 14 16 5- 100 3.6 0.4-2...

Ngày tải lên: 13/08/2014, 09:20

... -sc ] Then 1.12.10-~ -6. 3.10-~ -1.87.10-~ -i.87.10-~ 5.89. io -6 4.35.10-~ s= [ -6. 3. 2 .65 . 5.89 Directly by matrix manipulation E, = 1.1 26. cy = -6. 309 * yxy = -1.878 - ... nylon 66 Weight fraction, Wf property 0 0.10 0.20 0.30 0.40 0.50 0 .60 Density 1140 1210 1280 1370 1 460 1570 1700 Tensile strength (GN/m2) 0.07 0.09 0.13 0.18 0.21 0.23...

Ngày tải lên: 13/08/2014, 09:20

... = -2.09 x 10-~ 1.49 x 10-~ 2.01 10-~ 3 .77 x 10-4 5.34 x 10-5 -2.03 x 10-4 1 1.05 x lo3 235.2 -1 67. 1 239.2 -79 .2 -1 67. 1 -79 .2 233.0 [ D = [ 235.2 2.15 x 10-3 -1.60 ... 104 14. 37: io4 1.41 io4 A = 1.41 x lo4 1. 27 x 104 0 6.65 10-~ -5 .73 10-~ -6.81 -6.81 x -2.05 x 1.02 x 1 -1.46 x io3 604.5 -1. 67 x io3 -16 .7 x lo3...

Ngày tải lên: 13/08/2014, 09:20

... TI2 El = 1.144 E2 = 1.1 28 io? y12 = -1. 688 x 10-~ ~ 583 , ?I2 - 188 i2T - = 1659, - El E2 Y12 ;IT Thus once again, an applied stress of 188 MN/m2 would cause shear failure ... Westport, CT (1 980 ). Folkes, M.J. Short Fibre Reinforced Thermoplastics, Research Studies Press, Somerset (1 982 ). Mathews, F.L. and Rawlings, R.D. Composite Materials:...

Ngày tải lên: 13/08/2014, 09:20

... lo00 lo00 loo0 loo0 lo00 loo0 825/25/150 8251501125 3001401660 1050 1 390 91 0 1360 92 0 96 0 1050 1070 93 0 30 5 60 1 140 60 5t 1 It 2 0.75 0.25 2 0.5 0.3 1.6 0.4 0.25 ... been considerable 266 Processing of Plastics Controlled temperature (1) Fig. 4. 19( a) Sheet extrusion (1) thick sheet (2) thin sheet Fig. 4. 19( b) Pipe extrusion (1) r...

Ngày tải lên: 13/08/2014, 09:20

... volume of the sheet is given by Aihj = 150 x 100 x 2 = 3 x lo4 mm3 The surface area of the final product is Aj = (150 x 100 ) + 2 (100 x 60) + 2(150 x 60) = 4.5 io4 mm2 ... would leave a volume of (3 x 104 -2.52 x lo4) to form the walls. The area of the walls is A,=(2 ~100 ~60)+(2~150~60)=3~ lO4~* 320 Processing of Plastics CharQino area -...

Ngày tải lên: 13/08/2014, 09:20

... E.G, Extrusion of Plastics, Newnes-Butterworth, 1976. Schenkel, G, Plastics Extrusion Technology and Practice, Iliffe, 1966. Fisher, E.G, Blow Moulding of Plastics, Iliffe, 1971. ... ( dr' dr - dr )) 350 Analysis of polymer melt flow V= 211 dz Now at y = 0, V = VO so 1dP H 211 dz vo = (z) Substituting aP/az in the expression for V g...

Ngày tải lên: 13/08/2014, 09:20

... check the value of Bi. In this case 20 x 1.5 x 10-3 Bi = = 0 .12 0.25 Analysis of polymer melt flow 5 .12 Analysis of Heat Transfer during Polymer Processing Most polymer ... data on the thermal diffusivity of their plastics but in the absence of any information a value of 1 x lov7 m2/s may be used for most thermoplastics (see Table 1.8 and Table 5.1). .....

Ngày tải lên: 13/08/2014, 09:20

... Orientation can be introduced into plastics such as polyethylene and polypropy- lene (both semi-crystalline) by cold drawing at room temperature. Other brittle plastics such as polymethyl methacrylate ... use of these rules: Structure of Plastics 423 Fig. A. 12 Qpical illustration of spherulites Twisted tddcd chain growth from nucleus Fig. A .13 Structure of...

Ngày tải lên: 13/08/2014, 09:20

... so 4x 20 1 .142 +1 AR=m{ (1 .142 -1)-0’4} AR = 0.29 ITM (b> AR = a.R.AT = 143 °C 0.29 loo x 10-6 x 20 AT = Hence the nylon bush would need to be cooled by 143 °C to achieve ... specimen fracture = 0.44 + 3.947 = 4. 414 J Remaining energy = 11.036 - 4. 414 = 6.6218 J = 0.15 m 6.6218 So height of swing = - 44 .145 (2.59) K = p(m~)&a...

Ngày tải lên: 13/08/2014, 09:20

... (4.16) so, mass 150 x m3 1 200 volume = - = P 150 x 10-3 x 109 1 200 XR~H = = 1.77 mm 150 x 106 H= a x 1200 x (150 )2 = 19 s 3 x 104 x (150 x - 3qv2 Also ... Calendering, 313, 315 Capillary viscometer 369 Carbon fibres, 28, 39, 168, 181, 189, Carreau, 352 Celluloid, 2 Cellulose, 1 Centrifugal casting, 337 Charpy impact, 152 , 155 , 1...

Ngày tải lên: 13/08/2014, 09:20